SudokuSolver Forum

A forum for Sudoku enthusiasts to share puzzles, techniques and software
It is currently Sat Apr 27, 2024 2:25 pm

All times are UTC




Post new topic Reply to topic  [ 75 posts ]  Go to page Previous  1, 2, 3, 4, 5, 6 ... 8  Next
Author Message
PostPosted: Sun Jun 08, 2008 11:55 pm 
Offline
Grand Master
Grand Master

Joined: Wed Apr 16, 2008 1:16 am
Posts: 1044
Location: Sydney, Australia
Old SSv3.2 scores:
Killer rating table      
Rounded Score from SSv3.2
pg# on this thread
(E) = Easy (H) = Hard
======================================================================
|A ## Rate Score|A ## Rate Score|A ## Rate Score|
|----------------------+----------------------+----------------------|
|A.25 0.80|SKX3 1.35|A.32 0.90|
|A.25v2 1.65|A.30 0.70|A.32v2 0.80|
|A.26 H1.25 1.40|Bullseye3 2.0(t&E)2.15|A.32v3 0.85|
|A.27 0.90|A New One 2.40| |
|A.28 0.75|A.31 H1.0 0.95| |
|A.29 0.90|Last06 H1.25 1.20| |
|====================================================================|
page #3
Old scores SSv3.3.0:
Killer rating table      
Rounded Score from SSv3.3.0
! = 0.10 change from previous version of score
pg# on this thread
(E) = Easy (H) = Hard
======================================================================
|A ## Rate Score|A ## Rate Score|A ## Rate Score|
|----------------------+----------------------+----------------------|
|A.25 0.80|SKX3 !0.90|Last06 H1.25 !1.10|
|A.25v2 H1.00 !2.40|A.30 0.75|A.32 !1.00|
|A.26 H1.25 1.40|Bullseye3 2.0 !3.80|A.32v2 !1.05|
|A.27 !1.05|A New One H1.5 !3.00|A.32v3 !1.05|
|A.28 0.80|A New Onev2 H1.75 2.05| |
|A.29 0.95|A.31 H1.0 0.95| |
|====================================================================|
page #3
Killer rating table
SudokuSolver Target range v3.6.3
Rating.....Score
0.50 = 0.85
0.75 = 0.90-0.95
1.00 = 1.00-1.20
1.25 = 1.25-1.45
1.50 = 1.50-1.70 (E) = Easy (H) = Hard
===========================================================================================
|A ## by Rate Score|A ## by Rate Score|A ## by Rate Score|
|-----------------------------+-----------------------------+-----------------------------|
|A.25 Ruud 0.90|SKX3 Ruud 1.10|Last06 Ruud H1.25 1.25|
|A.25v2 Ed H1.00 1.85|A.30 Ruud 0.85|A.32 Ruud 1.00|
|A.26 Ruud H1.25 1.25|Bulls3 Ed 2.0 2.55|A.32v2 frank 1.00|
|A.27 Ruud 1.00|A NewOne nd H1.5 2.30|A.32v3 Ed 0.95|
|A.28 Ruud 0.90|ANOv2 nd H1.75 1.70| |
|A.29 Ruud 1.05|A.31 Ruud H1.0 1.20| |
|=========================================================================================|
page #3


Assassin 25 by Ruud (Nov 06)
Puzzle pic:
Image
Code: Select, Copy & Paste into solver:
3x3::k:7936:2305:2305:2305:4868:5381:5381:5381:4872:7936:7936:7936:1036:4868:3342:4872:4872:4872:3858:3858:7936:1036:4868:3342:4872:3609:3609:3858:3858:7197:6686:6686:6686:5153:3609:3609:5924:5924:7197:7197:6686:5153:5153:4651:4651:5924:4142:4142:7197:1329:5153:3891:3891:4651:1078:4142:6712:7197:1329:5153:6972:3891:2622:1078:6712:6712:5442:5442:5442:6972:6972:2622:6712:6712:3914:3914:5442:1613:1613:6972:6972:
Solution:
+-------+-------+-------+
| 7 3 1 | 5 2 4 | 8 9 6 |
| 5 9 4 | 3 8 6 | 7 1 2 |
| 8 2 6 | 1 9 7 | 3 5 4 |
+-------+-------+-------+
| 4 1 5 | 7 6 8 | 9 2 3 |
| 9 8 2 | 4 5 3 | 1 6 7 |
| 6 7 3 | 9 1 2 | 4 8 5 |
+-------+-------+-------+
| 1 6 7 | 8 4 5 | 2 3 9 |
| 3 5 8 | 2 7 9 | 6 4 1 |
| 2 4 9 | 6 3 1 | 5 7 8 |
+-------+-------+-------+
Quote:
PsyMar: I found this one pretty easy -- solved it in under half an hour, without any hints
sudokuEd: Ruud must be going soft on us this week after last week's Tetris
First-ever Walkthrough by PsyMar:
Walkthrough follows

4/2 in C1 = {13} (naked pair)
4/2 in C4 = {13} (naked pair)
23/3 in N4 = {689} (naked triple)
Innies of C6789 = R48C6 = 17/2 = {89} (naked pair)
Innies of C6 = R15679C6 = 15/5 = {12345} (naked quintuple!) -> 13/2 in C6 = {67} (naked pair)
Innies of N2 = R1C46 = 9/2 without 1367 = {45} (naked pair) -> 19/3 in C5 = {289} (naked triple)
5/2 in C5 -> {14} (naked pair)
Innies of C1234 = R48C4 = 9 = {27|45} but {45} would contradict R1C4 so R48C4 = {27} (naked pair)
6/2 in R9 = {15|24} -> 3 in C6 locked in cage 20/5 -> R45C7 <> 3
21/3 in R1 = {579|489} -> 9 not in rest of R1
9/3 in R1 = {135|234} -> 3 not in rest of R1
Innies of R1 = R1C159 = 15 with no 3459 = {168|267} -> R1C19 = {16|67}
15/2 in R9 = [69|78|96]
Outies of R123 = R4C1289 = 10 = {1234} (naked quad) -> R4C4 = 7 -> R8C4 = 2, R4C3 = 5 -> R4C5 = 6
21/4 in N8 = {2379} -> R8C6 = 9 -> 26/4 in N5 = [7685] -> R4C7 = 9
20/5 in C67 = 9/1+11/4 = {12359} -> R7C6 = 5 -> R1C6 = 4 -> R1C4 = 5, 6/2 in R9 = [15], 5/2 in C5 = [14]
Innies of N9 = R7C8 = 3 -> 4/2 in C1 = [13] -> 21/4 in N8 = [2793]
Innies of C789 = R5C7 = 1
9/3 in R1 = {135} -> R1C5 = 2 (hidden single)
R1C23 = {13} (naked pair)
21/3 in R1 = [489]
Innies of N6 = R4C89 = 5 = [23] -> R4C12 = [41] -> R1C23 = [31]
28/5 in C34 = 5+{49}+2|3|7+6|8 -> R5C3+R7C4 = 10 = [28] -> 15/2 in R9 = [96] -> 20/5 in C67 = [93125] -> 16/3 in R67 = [736] -> R7C3 = 7 -> R7C7 = 2 -> 10/2 in C9 = [91]
15/4 in R34C12 = 4+1+10/2 -> R3C12 = {28} (naked pair) -> R23C3 = {46} (naked pair) -> R1C1 = 7, 26/5 in N7 = [75824] -> R1C9 = 6, R3C12 = [82] -> R2C12 = [59], R5C2 = 8, 19/3 in C5 = [289]
14/4 in R34C89 -> R3C89 = 9 = {45} (naked pair) -> lots of naked singles
R6C147 = naked triple {469}
15/3 in R67C78 = [483] -> naked singles solve it

Thanks to SudokuEd and Andrew for the proofreads.
Assassin 25 v2 by sudokuEd (Nov 06)
Puzzle pic:
Attachment:
a25v2.JPG
a25v2.JPG [ 95.96 KiB | Viewed 9946 times ]
Code: Select, Copy & Paste into solver:
3x3::k:7936:6657:6657:6657:6917:6917:6917:6917:4872:7936:7936:7936:6917:6657:3342:4872:4872:4872:3858:3858:7936:6917:6657:3342:4872:3609:3609:3858:3858:7197:6686:6686:6686:5153:3609:3609:5924:5924:7197:7197:6686:5153:5153:4651:4651:5924:4142:4142:7197:1329:5153:3891:3891:4651:1078:4142:6712:7197:1329:5153:6972:3891:2622:1078:6712:6712:5442:5442:5442:6972:6972:2622:6712:6712:3914:3914:5442:1613:1613:6972:6972:
Solution:
+-------+-------+-------+
| 7 3 1 | 5 2 4 | 8 9 6 |
| 5 9 4 | 3 8 6 | 7 1 2 |
| 8 2 6 | 1 9 7 | 3 5 4 |
+-------+-------+-------+
| 4 1 5 | 7 6 8 | 9 2 3 |
| 9 8 2 | 4 5 3 | 1 6 7 |
| 6 7 3 | 9 1 2 | 4 8 5 |
+-------+-------+-------+
| 1 6 7 | 8 4 5 | 2 3 9 |
| 3 5 8 | 2 7 9 | 6 4 1 |
| 2 4 9 | 6 3 1 | 5 7 8 |
+-------+-------+-------+
Quote:
sudokuEd, in lead-in: I found this one a lot harder. But still has a logical solve path
PsyMar: I'll see just how much harder this is...Edit: It's quite a bit harder. Took several hours
Andrew: I'll rate A25V2 at Hard 1.0, rather than 1.0
Walk-through by PsyMar:
sudokuEd wrote:
Great walk-through PsyMar.
Thanks! It's actually my first.
Quote:
Hope you like to do harder Killers PsyMar :twisted:
I enjoy trying them, at least. I'll see just how much harder this is...Edit: It's quite a bit harder. Took several hours. Can't do any more today as I have too much homework, but here's a walkthrough for v2...

1. 4/2 in C1 = {13} (naked pair)
2. 5/2 in C5 = {14|23}
3. 6/2 in R9 = {15|24}
4. 10/2 in C9 <> 5
5. 13/2 in C6 = {49|58|67}
6. 15/2 in R9 = {69|78}
7. 23/3 in N4 = {689} (naked triple)
8. 14/4 in R34C89 <> 9 (min with 9 is 1+2+3+9 = 15)
9. 26/4 in N5 <> 1 (max with 1 is 1+7+8+9 = 25)
10. 19/5 in N3 = {1...} -> not elsewhere in N3
11. 31/5 in N1 = {9...} -> not elsewhere in N1
12. Innies of C6789 = R1C678+R48C6 = 38
13. R1C5678+R23C4 = 27, R1C5+R23C4 >= 6 -> 21 >= R1C678
14. combine 12 and 13: R1C678+R48C6+21 >= 38+R1C678 -> R48C6 >= 17 -> R48C6 = 17 = {89} (naked pair)
15. Combine 12 and 14: R1C678 = 38-17 = 21/3 split cage; R1C5+R23C4 = 6/3 split cage = {123} (naked triple)
16. 13/2 in C6 = {67} (naked pair)
17. Outies/Innies of N2 -> R1C23 = R1C6 -> R1C23 = {13|23} (cannot be {14} because 4 is either in R1 or cage 26/5)
18. 3 locked in R1C23 -> 3 not in rest of R1 or N1
19. R1C235 = naked triple {123}
20. split cage 21/3 in R1C678 = [489|498|579|597] -> no 9 in rest of R1 or N3
21. 3 of N2 locked in C4 -> not in rest of C4
22. 9 of N2 locked in C5 -> not in rest of C5
23. Outies of N3 = 9 -> R4C89 = {13|14|23}
24. Outies of N1 = R1C4+R23C5+R4C12 = 27, R1C4+R23C5 = {(4|5)89} = 21|22 -> R4C12 = 27-21|27-22 = 5|6 -> R4C1 <> 7 && R4C2 <> 5|7
25. Innies of N7 = 15 -> R7C2+R9C3 = {69|78}
26. Innies of N9 = 8 -> R7C8+R9C2 = [71|62|35] -> R9C6 <> 2
27. Innies of N58 = R5679C46 = 38; R5679C6 = 10|11 -> R5679C4 = 27|28 = {9...} <> {(1|2)...} -> 9 not in rest of C4
28. C5: 1 and 2 must be in R167C5 -> not in rest of column
29. 2 and 3 of C6 locked in cage 20/5 in C67 -> R45C7 <> 2|3
30. R567C6 = {123|234|235} = 6|9|10 -> R45C7 = 10|11|14 = {19|46|56|59|68} <> 7
31. If R6C2 = 1 then R6C3+R7C2 = 15 -> R6C3 = 7 and R7C2 = 8 -> R9C3 = 7, CON
32. Outies of R123 = R4C1289 = 10 (why didn't I see this earlier?) = {1234} (naked quad)
33. Quints for 28/5 in C34 -> R5C3 = {123}
34. R4C3+R6C23 = {57...} -> R6C4 <> 5|7
35. R238C4 = hidden triplet {123}
36. Innies of C1234 = R1C234+R4C4 = 16, R1C234 = {135|138|234|238} = 9|12|13 -> R4C4 = 7 (First number placed finally!) -> R4C3 = 5
37. R1C234 = 9 = {135|234} -> 8 of N2 locked in C5 -> not in rest of C5 -> R4C5 = 6
38. R23C5 = hidden pair on {89} in N2
39. R79C4+R8C6 = slightly hidden triple {689} in N8
40. R1C4 = hidden single on 5 in C4 -> R1C6 = 4 -> R1C23 = {13} naked pair, R1C78 = {89} naked pair
41. R14C7 = naked pair {89}
42. Outies of N1 = R4C12 = 5 = [23|41] -> R14C2 = naked pair {13} -> R1C5 = 2
43. R4C6+R56C4 = naked triple {489}
44. 26/4 in N5 = [7685] -> R4C7 = 9, R8C6 = 9 -> R1C78 = [89]
45. 6/2 in R9 = {15} naked pair
46. 7 of N4 locked in R6C23 -> R6C789+R7C2 != 7
47. 5/2 in C5 = [14]
48. 20/5 in C67: R5C7 = 1, R7C6 = 5 -> 6/2 in R9 = [15] -> R8C4 = 2
49. innies of N9 = R7C8 = 3 -> 4/2 in C1 = [13] -> 21/4 in N8 = [2793]
50. R4C2 = hidden single on 1 -> R1C23 = [31]
51. 1 of N3 locked in R2 -> R23C4 = [31]
52. Outies of N1 = R4C1 = 4 -> R4C89 = [23]
53. 15/3 in R67C78 = [483] -> LOTS of naked singles
54. 14/4 -> R3C8 = 5
55. 28/5 in C34 = [52498] -> five more naked singles
56. 15/2 in R9 = [96] -> naked singles solve it


Whoo! What a rush. My head is spinning. But it's done. 8-)
Walk-through by Andrew in March '10:
Once I'd found the 45s in steps 6 and 8, particularly step 8, I found this puzzle straightforward.

I'll rate A25V2 at Hard 1.0, rather than 1.0, because the innies-outies for step 8 were fairly well hidden.

Here is my walkthrough for A25V2.

Prelims

a) R23C6 = {49/58/67}, no 1,2,3
b) R67C5 = {14/23}
c) R78C1 = {13}
d) R78C9 = {19/28/37/46}, no 5
e) R9C23 = {69/78}
f) R9C67 = {15/24}
g) 23(3) cage in N6 = {689}
h) 14(4) cage at R3C8 = {1238/1247/1256/1346/2345}, no 9
i) 26(4) cage in N4 = {2789/3689/4589/4679/5678}, no 1

Steps resulting from Prelims
1a. Naked pair {13} in R78C1, locked for C1 and N7
1b. Naked triple {689} in 23(3) cage, locked for N4
1c. 31(5) cage in N1 must contain 9, locked for N1
1d. 19(5) cage in N3 must contain 1, locked for N3

2. 45 rule on N7 2 innies R7C2 + R9C3 = 15 = {69/78}

3. 45 rule on R123 4 outies R4C1289= 10 = {1234}, locked for R4

4. 45 rule on N1 2 outies R4C12 = 2 innies R1C23 + 1
4a. Max R4C12 = 7 -> max R1C23 = 6, no 6,7,8,9 in R1C23

5. 45 rule on R1234 2 innies R4C37 = 1 outie R5C5 + 9
5a. Max R4C37 = 16 -> max R5C5 = 7

6. 45 rule on C1234 2 outies R23C5 = 4 innies R2348C4 + 4
6a. Min R2348C4 = 11 (cannot be 10 because R4C4 doesn’t contain any of 1,2,3,4) -> min R23C5 = 15, no 1,2,3,4,5 in R23C5
6b. Max R23C5 = 17 -> max R2348C4 = 13, no 8,9, 1 locked for C4
6c. R4C4 = {567} -> no 5,6,7 in R238C4

7. 45 rule on N3 2 innies R1C78 = 2 outies R4C89 + 12
7a. Min R4C89 = 3 -> min R1C78 = 15, no 2,3,4,5

8. 45 rule on C6789 2 innies R48C6 = 3 outies R1C5 + R23C4 + 11
8a. Min R1C5 + R23C4 = 6 -> min R48C6 = 17 -> R48C6 = 17 = {89}, locked for C6, R1C5 + R23C6 = 6 = {123}, locked for N2 and 27(6) cage at R1C5, clean-up: no 4,5 in R23C6

9. Naked pair {67} in R23C6, locked for C6 and N2
9a. Naked pair {89} in R23C5, locked for C5 and N2
9b. Naked pair {45} in R1C46, locked for R1
9c. Naked triple {123} in R1C235, locked for R1

10. R1C5 + R23C4 = 6 (step 8a) -> R1C678 = 21 = {489/579} (cannot be {678} because R1C6 only contains 4,5), no 6, 9 locked for R1 and N3

11. R23C5 = {89} = 17 -> R1C234 = 9 = {135/234}, 3 locked for R1 and N1
11a. 3 in N2 only in R23C4, locked for C4
11b. R23C5 = R2348C4 + 4 (step 6) -> R2348C4 = 13 = {1237} (cannot be {1345} which clashes with R1C4) -> R238C4 = {123}, 2 locked for C4, R4C4 = 7, R4C3 = 5, R4C5 = 6, clean-up: no 8 in R9C3

12. R1C4 = 5 (hidden single in C4), R1C6 = 4, R1C23 (step 11) = {13}, locked for R1 and N1 -> R1C5 = 2, clean-up: no 7 in R1C78 (step 10), no 3 in R67C5, no 2 in R9C7
12a. Naked pair {89} in R1C78, locked for R1 and N3

13. Naked pair {13} in R23C4, locked for C4 -> R8C4 = 2, clean-up: no 8 in R7C9, no 4 in R9C7
13a. Naked pair {15} in R9C67, locked for R9

14. Naked pair {14} in R67C5, locked for C5
14a. 26(4) cage in N5 = {5678} (only remaining combination) -> R5C5 = 5, R4C6 = 8, R4C7 = 9, R1C78 = [89], R8C6 = 9, clean-up: no 1 in R7C9, no 6 in R9C3

15. Naked pair {49} in R56C4, locked for C4, N5 and 28(5) cage at R4C3 -> R6C5 = 1, R7C5 = 4, clean-up: no 6 in R8C9
15a. R4C3 = 5, R56C4 = {49} = 13 -> R5C3 + R7C4 = 10 = [28], R9C4 = 6, R9C3 = 9

16. R56C6 = [32] = 5, R4C7 = 9 -> R5C7 + R7C6 = 6 = [15], R9C67 = [15]

17. R4C1 = 4
17a. Naked pair {23} in R4C89, locked for R4, N6 and 14(4) cage at R3C8 -> R4C2 = 1, R1C23 = [31], R6C23 = [73], R7C2 = 6, R7C3 = 7, clean-up: no 3,4 in R8C9

18. R4C89 = {23} = 5 -> R3C89 = 9 = {45}, locked for R3 and N3

19. R4C12 = [41] = 5 -> R3C12 = 10 = {28}, locked for R3 and N1

20. 45 rule on N9 1 remaining innie R7C8 = 3, R7C7 = 2, R7C9 = 9, R8C9 = 1

21. R7C8 = 3 -> R6C78 = 12 = [48]

and the rest is naked singles.


Last edited by Ed on Sat Mar 27, 2010 11:02 pm, edited 8 times in total.

Top
 Profile  
Reply with quote  
PostPosted: Mon Jun 09, 2008 12:02 am 
Offline
Grand Master
Grand Master

Joined: Wed Apr 16, 2008 1:16 am
Posts: 1044
Location: Sydney, Australia
Assassin 26 by Ruud (Nov 06)
Puzzle pic:
Image
Code: Select, Copy & Paste into solver:
3x3::k:5120:3841:3841:3841:4868:4868:4868:5639:5639:5120:5120:3083:3852:3852:3852:5639:5639:3857:4370:5120:3083:2325:2325:3351:3351:3351:3857:4370:2844:3083:3102:3615:4640:4640:2338:3857:4370:2844:2854:3102:3615:3625:4640:2338:3884:4909:2844:2854:2854:3615:3625:2099:2338:3884:4909:3127:3127:3127:4410:4410:2099:6461:3884:4909:5184:5184:4162:4162:4162:2099:6461:6461:5184:5184:3658:3658:3658:3405:3405:3405:6461:
Solution:
+-------+-------+-------+
| 2 6 5 | 4 9 3 | 7 8 1 |
| 1 8 3 | 7 6 2 | 9 4 5 |
| 4 9 7 | 8 1 5 | 2 6 3 |
+-------+-------+-------+
| 8 1 2 | 9 5 4 | 6 3 7 |
| 5 7 4 | 3 2 6 | 8 1 9 |
| 9 3 6 | 1 7 8 | 4 5 2 |
+-------+-------+-------+
| 7 5 1 | 6 8 9 | 3 2 4 |
| 3 2 8 | 5 4 7 | 1 9 6 |
| 6 4 9 | 2 3 1 | 5 7 8 |
+-------+-------+-------+
Quote:
Ruud, lead-in: it is one long stream of innie-outie differences
sudokuEd: More like an annoying drip - This solution is a joint effort between me and Peter. We had a terrible time with this puzzle - got tricked and totally stumped so many times
Andrew, in A27 & A34 threads: for really difficult puzzles such as Assassins.. 26...I haven't finished..
Andrew, in A71 thread: I'm surprised that the SS scores for A26 (0.94)..is that low [edit: see table above for current SSscore]
Andrew, in Jan '09: (had) another go... the breakthrough...was difficult to spot but apart from that A26 wasn't particularly difficult....I'll rate A26 at Hard 1.25 because of step 18.. but (also) IMHO we tend to rate outies (or innies) like 3+1 and 4+1 a bit too low
Joint walkthrough by Nasenbaer & sudokuEd:
Ruud wrote:
it is one long stream of innie-outie differences.
More like an annoying drip - before the dam finally broke. :D

This solution is a joint effort between me and Peter. We had a terrible time with this puzzle - got tricked and totally stumped so many times. In the end, found a way through that avoided most of the innie-outie nightmares (step 20).

I'll be taking a break for a while. Going to NZ next Monday for a couple of weeks doing adventure stuff. Need a total break from anything to do with Ruud for a long while after the last month :wink: .

Please let me know if there is anything not valid, accurate or clear in this walk-through.

See you all anon. Ed

1. "45" n78 -> r6c1 - 8 = r9c6 -> r6c1 = 9, r9c6 = 1

2. n8: 17(2) = {89}, locked in N8 and r7

3. n8: 16(3) = {367/457} = 7{36/45} (no 2): 7 locked for n8,r8

4. r78c1 = 10 = [28/73/{46}] = [3/6/8] & (no 1,5)

5. c1:17(3) = {278/458/467} ({368} blocked by r78c1-step 4) (no 1,3)

6. 1 in c1 locked in 3 innies r129c1 = 9 = {126|135} (no 4,7,8)

7. 1 in c1 also locked in 20(4) n1 = {1289/1379/1469/1568} ({1478} blocked because no {478} in r12c1)
7a. ->1 locked for n1 in r12c1

8. c6:14(2) = [95/{68}] = [5/6,8/9..] -> 8 & 9 locked for c6 in r567c6

9. 45 on n5: r6c4 + r4c6 = 5 = [14/{23}]

10. n56: 18(3) must have {234}(r4c6) = {279|369|378|459|468} =[2/3/4]not two of -> r45c7 = {56789}

11.a. 8 in r7c5 -> no 8 in 14(3) in N5
b. 8 in r7c6 -> 14(2) in N5 = {59} -> 12(2) in N5 = {48}
-> no 8 in 14(3) in N5

12. n5:14(3) = {149/167/239/257} ({347} blocked by 12(2), {356} blocked by 14(2))

13. c7: 8(3) = {125|134} -> 1 locked in c7

14. r9c78 = 12 = {39/48/57} (no 2,6)

15. "45" n9 -> 3 innies: r78c7 + r7c9 = 8 = {125/134} = 1{25/34} no(67):1 locked for n9

16. n9:6 locked in 25(4) = 6{289/379/478} (no 5)

17. "45" n8 -> r9c3 - 3 = r7c4 -> r9c3 = {56789}
17a. when 6 in r9c3, 3 must be in r7c4 and rest of 14(3) in n8 must be {35}. Two 3's in n8 -> no 6 in r9c3, no 3 in r7c4

17b. In summary
[5] in r9c3 -> 2 in r7c4
-> rest of 14(3) = {36} ({27} blocked by 2 in r7c4)
[7] in r9c3 -> 4 in r7c4
-> rest of 14(3) = {25} ({34} blocked by 4 in r7c4)
[8] in r9c3 -> 5 in r7c4
-> rest of 14(3) = {24}
[9] in r9c3 -> 6 in r7c4
-> rest of 14(3) = {23}

18. "45" n14 -> r16c4 = 5 = [41/23/32]

19. "45" n147 -> 5 outies = 16

20. Combining steps 17b, 18 and 19 -> r1678c4 + r9c5 = 16 = [412{36}/41524/416{23}], ([23452/23542/32452/32542] all blocked by 12(2) c4)
-> r16c4 = [41], r7c4 = {256}, r9c3 = {589}, r9c4 = {236}, r9c5 = {2346}, 14(3) = {239/248/356} = [5{36}/824/9{23}]

21. n5: r4c6 = 4 (step 9), 12(2) = {39/57}, 14(3) must have 2 for n5 = 2{39/57}(no 6): 2 locked for c5 and {39/57} are locked in these 2 cages -> 14(2) = {68}: locked for c6 -> r7c56 = [89]

22. "45" n2 -> r1c7 - 2 = r3c6: r1c7 = {579}, r3c6 = {257}

23. r1:19(3). the only valid combination left is {379}: locked for r 1, and 3 also locked for n2. r3c6 = {57}(step 22)

24. "45" n2: 3 innies r1c56 + r3c6 = 17 and must have 3 and made up of candidates {3579} which sums to 24 -> 24 - 17 = 7.-> no 7 -> r3c6 = 5, r1c567 = [937], r8c6 = 7, r2c6 = 2, r2c45 = {67}:locked for n2, r2, r3c45 = {81}

25. n5:14(3) = {257}:locked for n5, c5 -> r2c45 = [76], r45c4 = {39}:locked for c4

25. n2:15(3) must have 2 or 7 (r2c6) = {267}

24. r1c23 = 11 = {56}:locked for r1,n1. 20(4) = 1{289/379} = 19{28/37}(no 4): 9 locked for n1, c2. r23c2 = {789},

25. "45" n1-> r4c3 + 2 = r3c1: r3c1 = {47}, r4c3 = {25}

26. c3:12(3) = {237/345} = 3{27/45} (no 8) with 3 locked in n1 -> r12c1 = [21], r23c2 = [89], r3c3 = 7 (single n1), r24c2 = [32], r3c1 = 4, r78c1 = [73], r1c89 = {18} -> r2c78 = {49}:locked for n3, r3c78 = {26}:locked for n3:....the rest is straight-forward
Jan '09 Walkthrough by Andrew:
As I commented in the A34 and A71 threads on Ruud's site, I didn't manage to solve three of Ruud's Assassins when they first appeared. Now having caught up with my backlog of other walkthroughs I'm having another go at them. Having posted my walkthroughs for A31 and A34, here is the the last one.

I thought the breakthrough in step 18 was difficult to spot but apart from that A26 wasn't particularly difficult although it took me quite a lot of moves after that to finish it.

I'll rate A26 at Hard 1.25 because of step 18, not only because it was difficult to spot but IMHO we tend to rate outies (or innies) like 3+1 and 4+1 a bit too low.

Here is my walkthrough. With hindsight the breakthrough step 18 could have been done after step 9.

Prelims

a) R3C45 = {18/27/36/45}, no 1
b) R45C4 = {39/48/57}, no 1,2,6
c) R56C6 = {59/68}
d) R7C56 = {89}, locked for R7 and N8
e) R1C567 = {289/379/469/478/568}, no 1
f) R456C2 = {128/137/146/236/245}, no 9
g) R456C8 = {126/135/234}, no 7,8,9
h) 11(3) cage at R5C3 = {128/137/146/236/245}, no 9
i) R678C1 = {289/379/469/478/568}, no 1
j) R678C7 = {125/134}, 1 locked for C7

1. Killer pair 8,9 in R56C6 and R7C6, locked for C6

2. 45 rule on N78 1 outie R6C1 = 1 innie R9C6 + 8 -> R6C1 = 9, R9C6 = 1, clean-up: no 5 in R5C6
2a. R6C1 = 9 -> R78C1 = 10= [28]/{37/46}, no 5, no 2 in R8C1
2b. R9C6 = 1 -> R9C78 = 12 = {39/48/57}, no 2,6

3. 45 rule on N9 3 remaining innies R7C79 + R8C7 = 8 = {125/134}, 1 locked for N9
3a. 45 rule on N9 1 remaining outie R6C7 = 1 innie R7C9
3b. Max R67C9 = 13 -> min R5C9 = 2

4. R8C456 = {367/457}, no 2, 7 locked for R8 and N8, clean-up: no 3 in R7C1 (step 2a)

5. 45 rule on N23 1 outie R4C9 = 1 innie R1C4 + 3, no 7,8,9 in R1C4, no 1,2,3 in R4C9

6. 45 rule on N5 2 innies R4C6 + R6C4 = 5 = [23/32/41], R4C6 = {234}, R6C4 = {123}
6a. Max R4C6 = 4 -> min R45C7 = 14, no 2,3,4 in R45C7

7. 45 rule on N8 1 outie R9C3 = 1 remaining innie R7C4 + 3, no 2,3,4 in R9C3

8. 45 rule on C1 3 innies R129C1 = 9 = {126/135} (cannot be {234} which clashes with R78C1), no 4,7,8, 1 locked in R12C1 for C1 and N1
8a. Max R12C1 = 7 -> min R23C2 = 13, no 2,3 in R23C1
8b. Min R23C3 = 5 -> max R4C3 = 7

9. 45 rule on N14 2 remaining outies R16C4 = 5 = [23/32/41], R1C4 = {234}, clean-up: no 4,8,9 in R4C9 (step 5)

10. 1 in R1 locked in R1C189
10a. 45 rule on R1 3 innies R1C189 = 11 = {128/137/146}, no 5,9

11. R1C234 = {249/258/357/456} (cannot be {267/348} which clash with R1C189)
11a. 3 of {357} must be in R1C4 -> no 3 in R1C23

12. R1C567 = {289/379/469/478/568}
12a. 2 of {289} must be in R1C6 -> no 2 in R1C57

13. 45 rule on R9 3 innies R9C129 = 18 = {279/369/468/567} (cannot be {378/459} which clash with R9C78)
13a. 2 of {279} must be in R9C1 -> no 2 in R9C29

14. R345C1 = {278/458/467} (cannot be {368} which clash with R129C1), no 3

15. 45 rule on C9 2 outies R78C8 = 1 innie R1C9 + 10
15a. Max R78C8 = 16 -> max R1C9 = 6

16. 45 rule on N69 3 remaining innies R4C79 + R5C7 = 21 = {579/678}, 7 locked for N6

17. 45 rule on C9 3 innies R189C9 = 15 -> C9 has three 15(3) cages which must be {159/267/348} or {168/249/357} (cannot be {258/456} which clash with all other 15(3) combinations)
17a. R234C9 = {159/168/267/357} (cannot be {249/348} because R4C9 only contains 5,6,7), no 4
17b. R567C9 = {159/168/249/348}
17c. 9 of {159/249} must be in R5C9 -> no 2,5 in R5C9

18. 45 rule on C123 5(4+1) outies R1679C4 + R9C5 = 16
First I did 4+1 combination analysis, then I found
18a. Min R9C5 = 2 -> max R1679C4 =14 which must contain 1 (cannot be {2345} which clashes with R45C4) -> R6C4 = 1, R1C4 = 4 (step 9), R4C6 = 4 (step 6), R4C9 = 7 (step 5), clean-up: no 6 in R1C189 (step 10a), no 5 in R3C4, no 5,8 in R3C5, no 8 in R4C4, no 5,8 in R5C4, no 7 in R9C3 (step 7)
18b. 8 in C4 locked in R23C4, locked for N2
18c. 2 in N5 locked in R456C5, locked for C5, clean-up: no 7 in R3C4
18d. 2 in N8 locked in R79C4, locked for C4, clean-up: no 7 in R3C5
18e. 1 in C7 locked in R78C7, locked for N9

19. 2 locked in R456C5 = {239/257}, no 6,8
19a. R56C6 = {68} (hidden pair for N5), locked for C6 -> R7C56 = [89]

20. R1C4 = 4 -> R1C23 (step 11) = {29/56}, no 7,8

21. R4C9 = 7 -> R23C9 (step 17a) = {26/35}, no 1,8,9

22. R1C9 = 1 (hidden single in C9)
22a. R1C18 (step 10a) = [28/37]
22b. R2C1 = 1 (hidden single in C1)
22c. R3C5 = 1 (hidden single in R3), R3C4 = 8

23. R12C1 = [21/31] = 3,4 -> R23C2 = 16,17 = {79/89}, 9 locked for C2 and N1, clean-up: no 2 in R1C23 (step 20)
23a. Naked pair {56} in R1C23, locked for R1 and N1

24. R6C4 = 1 -> R56C3 = 10 = {28/37/46}, no 5

25. R1C9 = 1 -> R89C9 (step 17) = {59/68}, no 2,3,4
25a. Killer pair 5,6 in R23C9 and R89C9, locked for C9, clean-up: no 5 in R6C7 (step 3a)
25b. R89C9 = 14 -> R78C8 = 11 = [29/38/74] (cannot be {56} which clashes with R89C9), R7C8 = {237}, R8C8 = {489}

26. 1 in N6 locked in R456C8 = {126/135}, no 4

27. R678C7 = {125/134}
27a. 2 of {125} must be in R6C7 -> no 2 in R78C7
27b. 2 in N9 locked in R7C89, locked for R7, clean-up: no 8 in R8C1 (step 2a), no 5 in R9C3 (step 7)

28. R9C4 = 2 (hidden single in C4) , R9C35 = [84/93], clean-up: no 3 in R7C4 (step 7)

29. 45 rule on N1 1 innie R3C1 = 1 remaining outie R4C3 + 2, no 2 in R3C1, no 1,3,6 in R4C3
29a. 1 in N4 locked in R45C2, locked for C2
29b. R456C2 = {128/137/146}, no 5

30. 8 in C1 locked in R45C1, locked for N4, clean-up: no 2 in R456C2 (step 29b), no 2 in R56C3 (step 24)
30a. Naked quint {13467} in R456C3 + R56C3, locked for N4

31. R7C234 = {156/345}, cannot be {147} because R7C4 only contains 5,6), no 7, 5 locked for R7
31a. 1 of {156} must be in R7C3, 5 of {345} must be in R7C4 -> no 5 in R7C3

32. 45 rule on N2 1 outie R1C7 = 1 remaining innie R3C6 + 2, no 3,8 in R1C7, no 2,3 in R3C6

33. R1C567 = {379} (only remaining combination), locked for R1, 3 locked in R1C56, locked for N2 -> R1C1 = 2, R1C8 = 8, R9C1 = 6 (step 8), clean-up: no 4 in R78C1 (step 2a), no 3 in R7C8 (step 25b), no 8 in R8C9 (step 25), no 4 in R9C7 (step 2b)
33a. R78C1 = [73], R3C1 = 4, R4C3 = 2 (step 29), R7C8 = 2, R8C8 = 9 (step 25b), clean-up: no 6 in R456C8 (step 26), no 2 in R6C7 (step 3a), no 5 in R89C9 (step 25), no 3 in R9C78 (step 2b)
35c. R89C9 = [68], R9C3 = 9, R9C5 = 3 (step 28), R7C4 = 6 (step 7), R7C23 = [51] (step 31), R1C23 = [65], R9C2 = 4, R8C23 = [28], clean-up: no 2 in R23C9 (step 21), no 9 in R45C5 (step 19)

36. R4C5 = 5, R45C1 = [85], R56C5 = {27}, locked for C5 and N5, R1C567 = [937], R2C5 = 6, R8C5 = 4, R8C7 = 1, R9C78 = [57]

37. R2C5 = 6 -> R2C46 = 9 = [72]

and the rest is naked singles


Last edited by Ed on Tue Nov 10, 2009 8:48 am, edited 4 times in total.

Top
 Profile  
Reply with quote  
PostPosted: Mon Jun 09, 2008 12:12 am 
Offline
Grand Master
Grand Master

Joined: Wed Apr 16, 2008 1:16 am
Posts: 1044
Location: Sydney, Australia
Assassin 27 by Ruud (Dec 06)
Puzzle pic:
Image
Code: Select, Copy & Paste into solver:
3x3::k:4096:4096:4096:5891:5891:5891:3590:3590:3590:5129:3594:3594:3594:5891:3598:3598:3598:4113:5129:1555:3348:3348:5891:4119:4119:1305:4113:5129:1555:5149:3348:4895:4119:5921:1305:4113:3620:3620:5149:5149:4895:5921:5921:2091:2091:3117:1838:5149:3376:4895:3122:5921:1844:5173:3117:1838:3376:3376:5178:3122:3122:1844:5173:3117:3648:3648:3648:5178:5444:5444:5444:5173:5448:5448:5448:5178:5178:5178:4430:4430:4430:
Solution:
+-------+-------+-------+
| 2 6 8 | 9 1 5 | 7 4 3 |
| 9 7 3 | 4 2 8 | 1 5 6 |
| 4 5 1 | 7 6 3 | 9 2 8 |
+-------+-------+-------+
| 7 1 6 | 5 9 4 | 8 3 2 |
| 5 9 2 | 8 3 6 | 4 7 1 |
| 8 3 4 | 2 7 1 | 5 6 9 |
+-------+-------+-------+
| 3 4 5 | 6 8 9 | 2 1 7 |
| 1 2 9 | 3 5 7 | 6 8 4 |
| 6 8 7 | 1 4 2 | 3 9 5 |
+-------+-------+-------+
Quote:
Ruud, lead-in: This Assassin combines an aesthetically pleasing cage layout with an excellent package of possible solving techniques. It should be named by the first to post a walkthrough
nd: Nothing too fancy, though the overlap technique is needed to make things easier
PsyMar: I'll call this one "Hourglass Sudoku" due to the pattern of the cages.
Andrew: Hourglass is a good title from PsyMar. I'd been thinking of Flower Burst
Walkthrough by nd:
Nothing too fancy, though the overlap technique is needed to make things easier.

Assassin 27 walkthrough

1. 45 rule on R9 => R9C456 = 7 = {124}, R78C5 = 13 = {58|67}, 3 is locked in the 17(3) cage in R9/N9 => R9C789 = {3(59|68)}, R9C123 = {7(59|68)}. 45 rule on R8 => R8C159 = 10 => R8C159 = [154] (only valid possibility because of 20(3) cage & locking of the 3 in N9), R7C5 = 8, R8C678 = {678} (8 locked within N9), R9C789 = {359}, R67C9 = [97], R9C123 = {678}, R8C6 = 7, R7C78 = {12}, R8C234 = {239} (2 locked within N7).

2. 45 rule on R1..4 => R4C357 = 23 = {689}. Overlap rule on R19+C5 => R19C5 = 5 = {14} or [32]. 45 rule on C1..4 => R19C4 = 10 => R1C4 = {689}. 45 rule on C5 => R19C6 = 7 => R1C6 = {356}. 45 rule on R1 => R1C456 = 15, R23C5 = 8 => R1C5 cannot = 3 (no valid combos for split 15(3) cage) => R19C5 = {14}, R23C5 = {26}, R4C5 = 9, R56C5 = {37}.

3. R5C12 = {59} (because {68} contradicts R4C3 = {68}). 45 rule on C9 => R159C1 = 13 => R5C12 = [59] (otherwise R159C1 would be > 13). 45 rule on C9 => R159C9 = 9 = {135} => R5C89 = [71], R56C5 = [37], R4C1 = 7, R23C1 = {49}, R19C1 = [26] (because the cells must add to 13 - 5 = 8), R67C1 = [83].

4. Mop-up. R234C9 = {268} => R4C9 = 2. R8C4 = 3, R8C23 = [29]. R34C2 = [51], R67C2 = [34], R1C23 = {68}, R1C456 = [915], R9C456 = [142], R7C346 = [569], R6C46 = [21], and you carry on.....
Verbose & newbie-friendly Walkthrough by PsyMar:
Eh, I'll go ahead and post my own walkthrough anyway -- IMO, it's a bit more verbose and newbie-friendly.

Also, if you're not going to claim the naming rights, I'll call this one "Hourglass Sudoku" due to the pattern of the cages. Although if you look at the left and right quarters instead it looks kinda like a ship from "Star Wars" -- but then "X-wing sudoku" would confuse people ;)

1. Placing pencilmarks, checking for cages with disallowed numbers:
1a. 5/2 in C7 = {14|23}
1b. 6/2 in C2 = {15|24}
1c. 7/2s in C2 and C8 both = {16|25|34}
1d. 8/2 in R5/N6 = {17|26|35}
1e. 14/2 in R5/N4 = {59|68}
1f. 19/3 in C5/N5 <> 1
1g. 20/3s in C1 and C9 <> 1|2
1h. 21/3s in R8 and R9/N7 = {489|579|678}
No maximal/minimal/near-maximal/near-minimal cages.

2. outies of R1 = R23C5 = 8 = {17|26|35}
3. Innies of R1234 = R4C357 = 23 = {689} naked triple
4. Innies of R9 = R9C456 = 7 = {124} naked triple
5. 21/3 in R9 has no 4 -> {579} or {678} -> must have 7, elim from rest of R9/N7
6. 17/3 in R9 has no 1247 -> {359} or {368} -> must have 3, elim from rest of N9
7. Outies of R9 = R78C5 = 13 = {58|67} (no 4 due to step 4)
8. Innies of C6789 = 7 = [34|52|61]
9. Innies of C1234 = 10 = [64|82|91]
10. 19/3 in C5/N5 cannot be {478} or {568} as these conflict with R78C5=13 (see step 7)
11. 19/3 must be {(28|37|46)9} -> eliminate 9 from rest of C5/N5
12. Innies of C1 = R159C1 = 13 -> [157|256|265] -> elim 5 from rest of C1
13. 20/3 in C1 does not have 5 -> 20/3 in C1 is {389} or {479} -> elim 9 from rest of C1
14. Outies-innies of R89 = R7C5-R8C19 = 3 -> only possibility is R7C5 = 8, R8C1 = 1, R8C9 = 4 -> naked single 2 in R1C1
15. outies of R9 = R8C5 = 5
16. 21/3 in R8 without 4 or 5 = {678} naked triple
17. 8 of R8 locked in N9 -> elim from rest of N9
18. 2 of R8 locked in N7 -> elim from rest of N7
19. combinations for 17/3 in R9/N9 = {359} naked triple -> naked triple {678} in R9C123
20. Hidden pair {12} in R7/N9 in R7C78
21. only combination for 20/3 in C9 with 4 in R8C9 is [974]
22. Hidden single 7 in R8/N8 in R8C6
23. Innies of N9 = 9 = {135} naked triple -> R4C9 = naked single 2 -> naked pair {68} in R23C9
24. R5C1 = hidden single 5 in C1 -> R5C2 = 9 due to sum
25. Only combination for 6/2 in C2 is [51]
26. Only combination for 8/2 in R5/N6 is [71]
27. R4C5 = hidden single 9 in R4
28. R7C12 = naked pair {34} -> 14/3 in C8 = [293] -> R7C3 = 5
29. only combination for 13/3 in R67C34 is [256] -> R7C6 = 9
30. Only combination for 12/3 in R67C67 is [192] -> 7/2 in C8 = [61] -> R4C7 = 8
31. only combination for 23/4 in R456C67 is [8645] -> a gajillion naked singles and last-digit-in-cage moves
32. only combination for 16/3 in R1/N1 is [268] -> R2C2 = 7 -> 21/3 in R9 = [687]
33. Only combination for 14/3 in R1/N3 = [743] -> naked singles and last-digit-in-cage solves it
Verbose Walk-through for those who don't like elimination solving by Andrew:
Ruud wrote:
This Assassin combines an aesthetically pleasing cage layout with an excellent package of possible solving techniques. It should be named by the first to post a walkthrough.

Yes, a pleasant cage pattern. It looked even better after I had coloured the cages in my Excel file to make it easier to distinguish between them. Hourglass is a good title from PsyMar. I'd been thinking of Flower Burst but I didn't solve it quickly enough to earn the right to name it.

A good variety of possible solving techniques. That made for the differences between the walkthroughs already posted by nd and PsyMar and my one so here goes with my walkthrough, pretty well in the order that I solved it. This is the verbose walkthrough for those of us who prefer not to use elimination solving. I know I have to use it for really difficult puzzles such as Assassins 24 and 26 but prefer not to if I can help it.

1. 45 rule on R9, 3 innies R9C456 = 7 = {124}

2. R78C5 = 13 = {58/67} (4 blocked in N8)

3. 21(3) cage cannot contain 3 -> 3 in R9 locked in 17(3) cage = 3{59/68}, 3 locked for R9, N9

4. 21(3) cage in R9 -> 7{59/68}, 7 locked for R9, N7

5. 45 rule on R1 3 innies R1C456 = 15 -> R23C5 = 8 = {17/26/35}

6. 45 rule on C5 2 innies R19C5 = 5, R9C5 = {124} -> R1C5 = {134}

7. 9 in C5 locked in 19(3) cage, also locked for N5

8. 45 rule on C1234 2 innies R19C4 = 10, R9C4 = {124} -> R1C4 = {689}

9. 45 rule on C6789 2 innies R19C6 = 7, R9C6 = {124} -> R1C6 = {356}

10. R1C5 = {14}(3 cannot form any valid 15(3) combinations with R1C4 and R1C6), the only valid combinations are [645]/[816]/[843]/[915]

11. R9C5 = {14}(step 6), 1,4 locked for C5, R23C5 = {26/35}

12. Killer pair 5/6 in R2378C5, no other 5/6 in C5 -> 19(3) cage in N5 = 9{28/37}

13. R1C456 cannot be [645] because that would clash with R23C5 -> R1C4 = {89}, R9C4 = {12} (step 8)

14. 45 rule on R1234 3 innies R4C357 = 23 = {689} with 6 blocked from R4C5, no other 6,8,9 in R4

15. 45 rule on R8 3 innies R8C159 = 10 -> max. 7 in each cell -> R8C5 = {567}, R7C5 = {678}

16. R8C19 = {12}/{13}/{14/23} -> R8C1 = {1234}, R8C9 = {124}(3 blocked in N9)

17. R8C9 = 4 (cannot have 1,2 in 20(3) cage), R67C9 = {79}, no other 7,9 in C9

18. R8C15 = [15] is only valid combination -> R7C5 = 8

19. R4C5 = 9, R56C5 = {37}, R4C37 = {68}

20. R23C5 = {26} -> R1C6 = {35}, R9C6 = {24}

21. R34C8 = {14/23}

22. R67C8 = {16/25}(cannot be {34} which would clash with R34C8)

23. Killer pair 1/2 in R34C8 and R67C8, no other 1,2 in C8

24. R5C89 = {17/26/35} but no 1,2 in R5C8 -> R5C8 = {3567}, R5C9 = {1235}

25. 45 rule on C9 3 innies R159C9 = 9 = 1{26/35} -> R9C9 = {356}, R1C9 = {1235}, 1 locked
in R15C9 for C9

26. 8 in C9 must be in R234C9 = 8{26/35}, with 8 locked in R23C9 for C9 and N3

27. 21(3) cage in R8 = {678} with the 8 in R8C78, locked for R8 and N9

28. 14(3) cage in R8 = {239} with the 2 in R8C23, locked for R8 and N7

29. 1,2 in R7 locked in R7C78 for R7 and N9 -> R7C78 = {12}, R6C8 = {56}

30. 5 in N9 must be in R9 -> R9C789 = {359}, R7C9 = 7, R6C9 = 9, R8C78 = {68}, R8C6 = 7

31. R9C9 = {35} -> R234C9 = {268}, R4C9 = 2, R23C9 = {68}, 8 in N3 locked in C9 -> 8 in N6 locked in C7 -> R8C78 = [68], R4C37 = [68], X-wing with 6 in R23C59, no other 6 in R23,
6 in R1 locked in N1

32. R1C9 = {135}, R5C9 = {135}, R5C8 = {357}

33. R9C123 = {678}, R5C12 = {59}, R5C89 = [71], R56C5 = [37], R1C9 = {35}

34. Killer pair 3/5 in R1C69, no other 3,5 in R1

35. 45 rule on C1 3 innies R159C1 = 13, min. R59C1 = 11 -> R1C1 = 2 (1 blocked in C1), R5C12 = [59], R9C1 = 6, R9C23 = {78}, R1C23 = [68]

36. R1C456 = [915], R1C9 = 3, R1C78 = [74], R9C456 = [142] (steps 8, 9 and 11)

37. R34C8 = [23], R67C8 = [61], R7C7 = 2

38. R56C7 = [45], R5C6 = 6

39. R9C8 = {59} -> R2C8 = {59}

40. 1 in N3 locked in C7, cannot be in R3C7 because 6,7 blocked from R34C6 -> R2C7 = 1, R3C7 = 9 (5 blocked in C7), R2C8 = 5, R2C6 = 8, R23C9 = [68], R9C789 = [395], R34C6 = [34], R67C6 = [19], R23C5 = [26]

41. 45 rule on R2 R2C1 = 9, R2C234 = {347}

42. R34C1 = [47], R67C1 = [83], R2C23 = {37}, R2C4 = 4, R3C4 = 7

43. R3C3 + R4C4 = 6 = [15] (1 blocked in C4), R34C2 = [51]

44. R67C2 = [34] (hidden 4 in C2), R56C3 = [24], R5C4 = 8, R6C4 = 2, R7C34 = [56] and the rest is simple elimination


Now to have another go at trying to finish Assassin 26


Last edited by Ed on Sat Jun 14, 2008 8:55 am, edited 1 time in total.

Top
 Profile  
Reply with quote  
PostPosted: Mon Jun 09, 2008 12:20 am 
Offline
Grand Master
Grand Master

Joined: Wed Apr 16, 2008 1:16 am
Posts: 1044
Location: Sydney, Australia
Assassin 28 by Ruud (Dec 06)
Puzzle pic:
Image
Code: Select, Copy & Paste into solver:
3x3::k:4608:4608:3074:3074:2564:2564:3334:3334:3336:4873:4608:5131:5131:2564:4878:3087:3334:3336:4873:3603:5131:5131:4374:4878:3087:3353:3336:4873:3603:3603:4374:4374:4878:3087:3353:3353:1316:3877:3877:2599:2600:3625:3625:3625:4396:1316:2094:2094:2599:2600:5170:5170:4396:4396:5686:5686:2094:5433:5433:5170:1340:5437:5437:1855:5686:4161:5433:5433:3908:1340:5437:5437:1855:5686:4161:4161:3908:3908:4942:4942:4942:
Solution:
+-------+-------+-------+
| 9 6 7 | 5 1 3 | 8 4 2 |
| 4 3 2 | 9 6 8 | 7 1 5 |
| 8 1 5 | 4 2 7 | 3 9 6 |
+-------+-------+-------+
| 7 5 8 | 6 9 4 | 2 3 1 |
| 3 9 6 | 2 7 1 | 5 8 4 |
| 2 4 1 | 8 3 5 | 9 6 7 |
+-------+-------+-------+
| 5 2 3 | 1 8 6 | 4 7 9 |
| 6 8 4 | 7 5 9 | 1 2 3 |
| 1 7 9 | 3 4 2 | 6 5 8 |
+-------+-------+-------+
Quote:
Your quote here
Walkthrough by Andrew:
Ruud wrote:
No price for symmetry. Instead, you may need your lateral sensor array to find an opening in this Assassin.

Indeed. I like symmetry because it gives a pleasant layout and makes it easier to colour the cages. However one doesn't need symmetry to solve puzzles. There's nothing symmetrical about 1 - 9.

Since nobody else has yet posted one, here is my walkthrough. As usual, it is essentially the order in which I solved this one.

1. R56C1 = {14/23}

2. R78C7 = {14/23}

3. No 5 in the two 10(2) cages in N5

4. No 1 in 19(3) cages in N14, N25 and N9

5. No 1,2 in 20(3) cage in N658

6. No 8,9 in 10(3) cage in N2

7. R89C1 = {16/25}(cannot be {34} which would clash with R56C1, as pointed out by nd in his message below), killer pair 1/2 in R5689C1, no other 1,2 in C1

8. 8(3) cage in N47 = 1{25/34}

9. R1C34 = {39/48/57}

10. R5C23 = {69/78}

11. 45 rule on R789 2 innies R7C36 = 9 -> R7C6 = {45678}

12. 45 rule on N8 2 innies R7C6 + R9C4 = 9 -> R9C4 = R7C3 = {12345}

13. 45 rule on N3 3 outies R4C789 = 6 = {123}, no other 1,2,3 in R4 or N6

14. Only valid combinations for 13(3) cage in N36 are {139/238} = 3{19/28} -> R3C8 = {89}, R4C7 = {12}, killer pair 1/2 in R478C7, no other 1,2 in C7

15. 45 rule on C12345 1 innie R9C5 – 1 = 1 outie R1C6 -> no 1,9 in R9C5

16. 45 rule on C789 3 innies R5C78 + R6C7 = 22 = 9{58/67}, no 4, 9 locked for N6, 17(3) cage in N6 = 4{58/67}

17. 9 cannot be in R5C78 (no valid combination in R5C678) -> R6C7 = 9, R5C78 = {58/67} -> R5C6 = 1 -> no 4 in R6C1, no 9 in R5C45, no 2 in R9C5 (step 15)

18. 9 in N5 locked in R4, no other 9 in R4, 9 in N4 locked in R5 -> R5C23 = {69}, no other 6 in R5 or N4 -> R5C78 = {58}, no other 5,8 in R5 or N6, no 2,4 in R6C45

19. 2 in N5 locked in R5, no other 2 in R5 -> R56C1 = [32]/[41]

20. 17(3) cage in N6 = {467} -> 6 in N6 locked in R6, no other 6 in R6, no 4 in R5C45, 6 in N5 locked in R4

21. 20(3) cage in N658 = 9 [38]/{47}/[56], no 8 in R6C6, no 5 in R7C6

22. 14(3) cage in N14 min. R4C23 = 9 = {45} -> max. R3C2 = 3 (4,5 already used in cage)

23. 45 rule on N4 1 innie R4C1 – 3 = 2 outies R3C2 + R7C3 -> min. R4C1 = 5, max. R7C3 = 4

24. Looking at combinations in 5(2) cage in N4 and 8(3) cage in N47
24a. If R56C1 = [32], R6C23 = {145}, R7C3 = {23}
24b. If R56C1 = [41], R7C3 = 1, R6C23 = {25}({34} would clash with 4 in R5C1)
-> No 3 in R6C23, -> R5C1 = 3 (hidden single in N4), R6C1 = 2, R6C23 = {145}, R7C3 = {23}, R9C4 = {23} (step 12), no 4,5 in R89C1

Is there a logical way to eliminate 3 from R6C23 without using a contradiction move? Maybe this elimination should have been left until later when there may be a more logical way?

25. R4C1 – 3 = R3C2 + R7C3 (step 23) -> no 5 in R4C1 = {78}

26. R89C1 = {16}, no other 1,6 in C1 or N7 -> R9C1 = 1 (hidden single in R9), R8C1 = 6

27. Only valid combination for 19(3) cage in N14 R234C1 = {478}, 4 locked in R23C1, no other 4 in C1 and N1, no other 7,8 in C1, no 8 in R1C4

28. R56C4 = [28]/[73], R56C5 = [28]/[73], no other 3,7,8 in N5

29. R5C9 = 4 (hidden single in R5), R6C89 = {67}

30. R67C6 = [47]/[56]

31. R9C4 = {23}, only possible combinations for 16(3) cage in N78 = {259/349/358} [8/9 in R89C3], no 2,3,7 in R89C3

32. 17(3) cage in N25, only valid combinations {269/359/467} (not {458} which would clash with {45} in R6C6) -> R3C5 = {237}

33. R17C1 = {59}, 22(4) cage in N7 contains 7, 2 or 3, 8 or 9 and must have 5 or 9 in R7C1 -> {2479/2578}

34. 7 in N7 locked in C2, no other 7 in C2, 22(4) cage in N7 (step 33) = 27{49/58}, no 3, 2 locked in 22(4) cage -> R7C3 = 3, R9C4 = 3 (step 12), no 9 in R1C34, 2 in N9 locked in C2, no other 2 in C2

35. R56C4 = [28], R56C5 = [73], R3C5 = 2, R4C45 = {69}, no other 6,9 in N5

36. R46C6 = {45}, no other 4,5 in C6

37. R4C1 – 3 = R3C2 + R7C3 (step 23 again, for the last time, a very useful step) -> R4C1 = 7, R3C2 = 1, R23C1 = {48}, no other 8 in N1, no 4 in R1C4

38. R6C3 = 1 (hidden single in R6 and N4) -> R6C2 = 4, R6C6 = 5, R4C6 = 4, R4C23 = {58}

39. R1C34 = {57}, no other 5,7 in R1 -> R1C1 = 9, R7C1 = 5

40. R12C2 = {36}, no other 6 in C2 or N1, R5C23 = [96], R2C3 = 2 (hidden single in N1)

41. R13C3 = {57}, no other 5 in C3 -> R4C23 = [58], R89C3 = {49}, R789C2 = {278}

42. R1C26 = {36}, no other 3,6 in R1

43. Only valid combination for 10(3) cage in N2 = [136] -> R1C2 = 6, R2C2 = 3

44. R23C6 = {78}, no other 7,8 in N2 or C6, R1C34 = [75], R3C3 = 5, R23C4 = {49}, no other 4,9 in C4 -> R4C45 = [69]

45. R7C6 = 6 (naked single in C6), R89C6 = {29}, R9C5 = 4, R78C4 = {17}, R78C5 = [85], R89C3 = [49], R89C6 = [92]

46. Only valid combination for 19(3) cage in N9 = {568}, no other 8 in N9 -> R789C2 = [287]

47. R78C7 = [41] (only remaining valid combination), R78C4 = [17], R7C89 = {79}, R8C89 = {23}

48. R1C7 = 8, R1C9 = 2, R1C8 = 4, R2C8 = 1, R3C8 = 9

49. R4C7 = 2, R4C8 = 3, R4C9 = 1, R5C78 = [58]

and the rest is simple elimination

[Step 7 edited, {34} deleted with reason for this and killer pair added for completeness although it doesn't make any difference to later moves. For other more elegant moves suggested by nd, see his message below; I haven't changed my moves for those steps]
Assassin 29 by Ruud (Dec 06)
Puzzle pic:
Image
Code: Select, Copy & Paste into solver:
3x3::k:3840:3840:3840:6915:6915:6915:3334:3334:3334:4873:4873:3840:6915:4621:6915:3334:6160:6160:3602:4873:4372:4372:4621:2327:2327:6160:2842:3602:3602:4372:8734:4621:8734:2327:2842:2842:3620:3620:3620:8734:8734:8734:5418:5418:5418:3117:3117:4143:8734:4657:8734:4659:3636:3636:3117:4151:4143:4143:4657:4659:4659:4413:3636:4151:4151:6465:3906:4657:3906:4677:4413:4413:6465:6465:6465:3906:3906:3906:4677:4677:4677:
Solution:
+-------+-------+-------+
| 3 2 9 | 8 5 7 | 4 6 1 |
| 5 6 1 | 4 9 3 | 2 8 7 |
| 4 8 7 | 6 2 1 | 5 9 3 |
+-------+-------+-------+
| 9 1 4 | 5 7 8 | 3 2 6 |
| 2 7 5 | 3 1 6 | 9 4 8 |
| 8 3 6 | 9 4 2 | 1 7 5 |
+-------+-------+-------+
| 1 4 3 | 7 6 9 | 8 5 2 |
| 7 5 2 | 1 8 4 | 6 3 9 |
| 6 9 8 | 2 3 5 | 7 1 4 |
+-------+-------+-------+
Quote:
Ruud, lead-in: A chain is running through the center. Lots of quad moves in this Assassin
nd: While this one doesn't require exotic techniques, the endgame requires a fair bit of finesse. I didn't see any spots where chains were needed, though, which Ruud's comment seems to imply
Andrew: started making more use of remaining valid combinations, which I had started doing on some of the more difficult puzzles, although they are not as necessary here... I didn't need any "finesse in the endgame"
Andrew, on A30 thread: I was surprised to find could be solved without using them (innies/outies)
Walkthrough by nd:
While this one doesn't require exotic techniques, the endgame requires a fair bit of finesse. I didn't see any spots where chains were needed, though, which Ruud's comment seems to imply--what spot do you have in mind for this?


1. 15(5) in N8 = {12345}, and the remaining cells of N8 = {6789}. 24(3) in N3 = {789}. 45 rule on R1 => R2C3467 = 10 = {1234}. 45 rule on N147 => R37C4 = 13 => R3C4 = {4567}.

2. 45 rule on N3 => R3C79 = 8 = {26|35}. The 1 in N3 is locked in the 13(4) cage (it's required in all possible combos). 45 rule on N1 => R3C13 = 11 = {29|38|47} ({56} is blocked by the 8(2) cage we just found). 1 in N1 is locked in the 15(4) cage (because it cannot go in the 19(3) cage, obviously). Between the two of them, the 15(4) cage in N1 and 13(4) cage in N3 produce an x-wing on 1 in R12 => 1 is blocked from R12C456.

3. Min. value of each cell in R1C456 = 5, because if any cell in R1C456 were 4 or less the max sum of that cell + R2C46 = 9 and so the remaining two cells would add to 18 or greater, which is impossible.

4. 45 rule on C5 => R159C5 = 9 = {126|135|234} => R1C5 = {56}, R59C5 = {1(2|3)} (locking 1 in those cells in C5).

5. The only place for the 1 in N2 to go is now R3C6! 45 rule on N369 => R7C6 = 9.

6. R6C5 = {345} (difference between 18 and possible sums of remaining two cells = {678}). 45 rule on N5 => R4C5 = {678}. 9 is locked in C5/N2 in R23C5 => R23C5 = {(2|3)9}, R4C5 = {67}.

7. 4 is locked in C5 in R6C5 => R78C5 = {68}, R37C4 = [67], R4C5 = 7, R1C5 = 5, R23C5 = {29}, R2C46 = {34}, R2C37 = {12}, R23C5 = [92], R3C8 = 9, R59C5 = {13}, R1C46 = [87], R2C12 = {56}, R3C2 = 8, R3C79 = R4C7 = {35}, R34C3 = [74], R3C1 = 4.

8. 45 rule on R5 => R5C456 = 10 = {136} or {235}, with 3 locked in those cells in N5/R5. 45 rule on R6789 => R6C46 = 11 = [92], R5C45 = {13}, R5C6 = 6, R4C46 = [58], R34C7 = [53], R3C9 = 3, R4C89 = {26}, R4C12 = {19}. 4 is locked in 21(3) cage in R5C789 => it is {489}, R5C123 = {257}.

9. R6C7 = {17}, R7C7 = {28}. 45 rule on N9 => R7C79 = 10 = {28} => R78C5 = [68]. 45 rule on N7 => R7C13 = {13}, R6C3 = {68}, R7C28 = {45}.

10. 3 is locked in N4/R6 in R6C12 => R7C1 = 1, R6C12 = [83], R67C3 = [63], R1C1 = 3, R9C3 = 8.

11. 45 rule on R9 => R8C3467 = 13 => they can only contain the numbers 1..7 => in C3 the only spot for the 9 is R1C3, R8C3 = {25}, R2C3 = 1, R1C2 = 2, R2C7 = 2, R67C7 = [18], R7C9 = 2, R4C89 = [26], 7 is locked in N9/C7 in R89C7 => the remaining cells of the 18(4) cage = 11 => the 9 cannot go in it => R8C9 = 9, R5C7 = 9, R78C8 = [53], R7C2 = 4, R6C89 = [75], R2C89 = [87], R5C89 = [48]. Only possible combo in the hidden 13(4) cage in R8C3467 = {1246} => R9C7 = 7, R8C6 = 4, and you carry on.....
Walkthrough by Andrew:
My solution followed a fairly similar path. However in places my moves were in a different order and in some cases my logic was different. It was possibly due to doing some things in a different order, essentially the order in which I saw the next moves, that I didn't need any "finesse in the endgame".

Here is my walkthrough. You will see that I have started making more use of remaining valid combinations, which I had started doing on some of the more difficult puzzles, although they are not as necessary here. The "Killer Configuration Tables" link on the Weekly Assassin page is very helpful and easy to use. Thanks for that, Ruud!

1. 15(5) cage in N8 = {12345}, remaining cells in N8 = {6789}

2. 45 rule on R1 4 outies R2C3467 = 10 = {1234}, naked quad for R2

3. 24(3) cage in N3 = {789}, naked triple for N3

4. 13(4) cage in N3 = {1246/1345} = 14{26/35}, 1,4 locked for N3, 5/6 in R1

5. R3C79 = {26/35}

6. 45 rule on N7 2 innies R7C13 = 4 = {13}

7. 45 rule on N9 2 innies R7C79 = 10 = {28/46}, hidden quad {6789} locked in R7C45679, 7,9 in R7 locked in R7C456, R8C5 = {68}, R7C28 = {245}

8. 45 rule on C123 2 outies R37C4 = 13, R7C4 = {6789} -> R3C4 = {4567}

9. 45 rule on C789 2 outies R37C6 = 10, R7C6 = {6789} -> R3C6 = {1234}

10. R7C5 = {6789}, R8C5 = {68} -> R6C5 = {1345}

11. 45 rule on N5 2 innies R46C5 = 11 -> R6C5 = {345}, R4C5 = {678}

12. 45 rule on R1234 2 innies R4C46 = 13 = {49/58/67}

13. 45 rule on R6789 2 innies R6C46 = 11 = {29/38/47/56} -> 1 in N5 locked in R5

14. 45 rule on R5 3 innies R5C456 = 10 = 1{27/36/45}

15. 45 rule on C5 3 innies R159C5 = 9 = {126/135/234} -> max. 6 in R1C5 or R5C5

16. Only valid combinations for 27(5) cage in N2 with R1C5 = max. 6 and R2C46 = {1234} are {13689/14589/14679/23589/23679/24579/24678/34569/34578} -> R1C5 = {56}, R1C46 = {6789}

17. Killer pair 5/6 in R1C5789, no other 5,6 in R1

18. R1C5 = {56} -> R159C5 = 1{26/35} (step 15) -> R59C5 = 1{2/3}, 1 in C5 locked in R59C5

19. 15(4) cage in N1 = {1239/1248/1347} = 1{239/248/347}, 1 locked for N1 -> 1 in R3 locked in N2 -> R3C6 = 1, R34C7 = {26/35}, R7C6 = 9 (step 9), R7C45 = {678}, R3C4 = {567} (step 8)

20. Naked triple {678} in R478C5 -> R1C5 = 5, R3C4 = {67}, R7C4 = {67}(step 8), killer pair 6,7 in C4

21. R6C5 = {34}, R4C5 = {78} (step 11), 6 in C5 locked in R78C5 -> R7C4 = 7, R78C5 = {68}, R6C5 = 4, R4C5 = 7, R3C4 = 6 (step 8), 6 in C6 locked in N5

22. R3C79 = {35}, 13(4) cage in N3 = {1246}, R4C7 = {35}

23. 9 in C5 locked in R23C5 -> R23C5 = {29}, R2C46 = {34}, R2C37 = {12}, R23C5 = [92], R2C89 = {78}, R3C8 = 9

24. 27(5) cage = {34578} -> R1C4 = 8, R1C6 = 7

25. R2C12 = {56}, R3C2 = 8

26. Only remaining combination for 15(4) cage in N1 (step 19) = {1239}, R3C13 = {47}, R4C3 = {47} -> R4C3 = 4, R3C3 = 7, R1C3 = 4

27. R4C46 = 13 (step 12) = [58], 5 in C6 locked in R89C6, R34C7 = [53], R3C9 = 3, R4C89 = {26}, R4C12 = {19}

28. R6C4 = 9 (single in C4) -> R6C6 = 2 (step 13), R289C6 = naked triple {345}, R5C6 = 6, R5C45 = {13}

29. 4,9 in N6 locked in C5 -> 21(3) cage = {489}, 14(3) cage in R5 = {257}

30. R7C4 = 7 (step 21), R7C3 = {13} -> R6C3 = {68} -> 3 in N4 locked in R6C12 -> R7C1 = 1, R6C12 = [83], R67C3 = [63], R4C12 = [91]

31. 8 in C3 locked in R89C3, only valid combination for 25(4) in N7 = {2689} ({4678} blocked by 4,6,7 in C3) -> R9C1 = {26}, R9C2 = {269}, R89C3 = {289}, 16(3) cage in N7 = {457}

32. 45 rule on R9 4 outies R8C3467 = 13 = 1{237/246/345}, 1 locked for R8, no 8,9 -> R8C3 = 2, R9C1 = 6, R9C2 = 9, R9C3 = 8, R9C4 = 2 (single in N8)

33. R1C2 = 2, R1C1 = 3, R2C3 = 1, R1C3 = 9, R2C7 = 2, R1C789 = {146}

34. 7 in R9 locked in N9, only valid combination for 18(4) cage = {1467} -> R8C7 = 6, R9C789 = {147}

35. R7C79 = 10 {step 7) = [82], R7C8 = 5, R8C89 = [39], R6C7 = 1, R6C89 = [75]

and the rest is simple elimination


Last edited by Ed on Sat Jun 14, 2008 8:57 am, edited 1 time in total.

Top
 Profile  
Reply with quote  
PostPosted: Mon Jun 09, 2008 12:22 am 
Offline
Grand Master
Grand Master

Joined: Wed Apr 16, 2008 1:16 am
Posts: 1044
Location: Sydney, Australia
Special Killer X December 16 (aka SKX3) by Ruud (Dec 06)
Puzzle pic: 1-9 cannot repeat on the diagonals; & Solution:
Image
Code: Select, Copy & Paste into solver:
3x3:d:k:7168:1025:1025:10755:10755:10755:1542:1542:5128:7168:7168:10755:10755:781:10755:10755:5128:5128:7168:5139:5139:3349:781:2071:6168:6168:5128:3355:5139:5139:3349:4383:2071:6168:6168:6179:3355:3355:3110:3110:4383:1065:1065:6179:6179:3355:7214:7214:2096:4383:1842:4147:4147:6179:4918:7214:7214:2096:3642:1842:4147:4147:3646:4918:4918:9537:9537:3642:9537:9537:3646:3646:4918:2889:2889:9537:9537:9537:3406:3406:3646:
Solution:
+-------+-------+-------+
| 6 1 3 | 8 7 5 | 2 4 9 |
| 8 5 4 | 3 2 9 | 6 1 7 |
| 9 7 2 | 4 1 6 | 5 8 3 |
+-------+-------+-------+
| 1 3 8 | 9 6 2 | 4 7 5 |
| 4 6 7 | 5 8 1 | 3 9 2 |
| 2 9 5 | 7 3 4 | 1 6 8 |
+-------+-------+-------+
| 5 8 6 | 1 9 3 | 7 2 4 |
| 7 4 1 | 2 5 8 | 9 3 6 |
| 3 2 9 | 6 4 7 | 8 5 1 |
+-------+-------+-------+
Quote:
Ruud, lead-in: A combination of Killer and regular Sudoku techniques is required, unless you manage to find a shortcut that I have missed
Andrew in SKX4 thread: Assassin level
Walkthrough by Andrew:
Ruud wrote:
Here is my third Killer-X. A combination of Killer and regular Sudoku techniques is required, unless you manage to find a shortcut that I have missed. As usual, the forum welcomes your walkthrough.

Thanks Ruud for another great Killer-X. I know that others solved this one before I did but, since they haven't posted their walkthroughs, here is my one for SKX3.

I look forward to the next SKX after Ed's current tag killer-X PANIV has been solved. I know from Ed's comment of SKX1 that he is looking forward to it too.

As with SKX1, many thanks to Ed for reviewing my walkthrough. I've included his comments below.


Clean-up is used in various steps, using the combinations in steps 1 to 12 for further eliminations from these two cell cages. In some of the later steps, clean-up is followed by further moves and sometimes more clean-up.

1. R1C23 = {13}, locked for R1 and N1

2. R1C78 = {24}, locked for R1 and N3

3. R23C5 = {12}, locked for C5 and N2

4. R5C67 = {13}, locked for R5

5. R5C34 = {48/57}, no 2,6,9

6. R9C23 = {29/38/47/56}, no 1

7. R9C78 = {49/58/67}, no 1,2,3

8. R78C5 = {59/68}, no 3,4,7

9. R34C4 = {49/58/67}, no 1,2,3

10. R34C6 = {17/26/35}, no 4,8,9, no 6,7 in R4C6

11. R67C4 = {17/26/35}, no 4,8,9

12. R67C6 = {16/25/34}, no 7,8,9

13. 28(4) cage in N1 = {4789/5689} = 89{47/56}, no 2, 8,9 locked for N1

14. 28(4) cage in N47 = {4789/5689} = 89{47/56}, no 1,2,3

15. 13(4) cage in N4 = {1237/1246/1345}, no 8,9, 1 locked in R46C1, locked for C1 and N4

16. 14(4) cage in N9 = {1238/1247/1256/1346/2345}, no 9, must contain at least two of 1,2,3

17. 1 in N7 locked in R8C23, locked for R8

18. 42(7) cage in N123 = {3456789}, no 1,2
18a. 3,4 locked in R2C3467, locked for R2

19. R2C5 = 2 (hidden single in R2), R3C5 = 1

20. Only valid combinations for 20(4) cage in N3 are 1{379/568} -> R2C7 + R3C78 = {379/568}

21. If {1379} combination in 20(4) cage in N3, 3 must be in R3C9 -> no 7,9 in R3C9

22. 2 in R3 locked in R3C23, no 2 in R4C23

23. 2 in N4 locked in 13(4) cage = {1237/1246} = 12{37/46}, no 5
23a. The {1237} would have {13} in R46C1 -> no 7 in R46C1

24. 37(7) cage in N789 must contain 4,8,9 [Note that the two excluded numbers form a 8(2) pair {17/26/35} so that if one of these numbers is locked in the 37(7) cage in a later step, the other number will also be locked in the 37(7) cage.]
-> no {89} in R8C5 [Thanks Ed, missed that.]

25. 14(2) cage in N8 = {59/68} -> the part of the 37(7) which is in N8 must contain 8 or 9 and R8C37 must contain 8 or 9
[If Ed’s addition to step 24 had been used, this would be 12(2) = [95/86] (see note on step 24). The conclusion about R8C37 = [8/9] is correct.]

26. Only remaining {34} in C5 are in R4569C5, they cannot both be in the 17(3) cage in R456C9 -> R9C5 = {34} with 3 or 4 in R456C5

27. R456C5 = 3{59/68} or {467} ({458} would clash with R78C5, if R456C5 = {467}, then R78C5 = {59}), killer triple 5/6/9 in R45678C5, no 5,6,9 in R1C5 = {78} [Alternatively I could have used 45 rule on C5 but I spotted the more interesting and complicated way first]

28. 45 rule on R12 2 remaining outies R3C19 = 12, no 6, no 5,8 in R3C1

29. 45 rule on C789 3 innies R258C7 = 18, R5C7 = {13} (step 3), R258C7 = {189/369/378}, no 2,3,4,5 in R28C7

30. 3 in 42(7) cage locked in R2C46, locked for N2, clean-up: no 5 in R4C6

31. 45 rule on C123 3 innies R258C3 = 12, min R25C3 = 9 -> R8C3 = {123}, min R28C3 = 5 -> R5C3 = {457}, clean-up: R5C4 = {578}

32. R8C3 = {123} -> R8C7 = {89} (step 25)

33. 4 in 37(7) cage locked in N8, locked for N8, clean-up: no 3 in R6C6

34. 45 rule on N8 2 outies R8C37 – 6 = 2 innies R7C46, max R8C37 = 12 -> max R7C46 = 6, no 6,7 in R7C46, clean-up: no 1,2 in R6C4, no 1 in R6C6

35. 1 in N5 locked in C6, locked for C6, clean-up: no 6 in R6C6, 1 in N8 locked in C4

36. 7 in N8 locked in 37(7) cage -> 37(7) cage must contain 1 = 14789{26/35}

37. 45 rule on C6 5 innies R12589C6 = 30 and must contain 8,9 which aren’t in R3467C6 = {15789/34689}(cannot be {24789/25689} which don’t have {13}) = 89{157/346} -> no 2 in R89C6, for the {34689} combination the 3 must be in R5C6 -> no 3 in R289C6

38. R4567C6 must contain 123{4/5}, R1289C6 must contain 4/5 (step 37), killer pair 4/5 -> no 5 in R3C6, clean-up: no 3 in R4C6
Ed commented “An easier way to show that no 5 in R3C6. R34C6 = [53] blocks 7(2) in C6 -> R34C6 cannot be [53]”. I’ll accept that as an alternative way. Whether it’s easier depends on what one happens to see.

39. 2 in N5 locked in C6 -> no 2 in R7C6, clean-up: no 5 in R6C6

40. R2C4 = 3 (hidden single in N2), clean-up: no 5 in R67C4

41. R456C6 must contain 12{3/4}, R456C5 must contain 3/4 (step 27), no 4 in R4C4, clean-up: no 9 in R3C4

42. 9 in N2 locked in 42(7) cage -> no 9 in R2C7

43. R2C7 + R3C78 = {379/568} (step 20) -> no 7 in R3C78

44. 45 rule on N36 4 innies R25C7 + R6C78 = 16, min R25C7 = 7 -> max R6C78 = 9, no 9 in R6C78

45. 45 rule on N14 4 innies R25C3 + R6C23 = 25, min R25C3 = 9 -> max R6C23 = 16 -> R6C23 cannot contain 8 and 9, 20(4) cage in N14 does not contain 1 so R4C23 cannot contain 8 and 9, R46C23 must contain 8 and 9 -> R4C23 must contain 8 or 9, R6C23 must contain 8 or 9, R7C23 must contain 8 or 9 [Sorry that’s rather complicated, hope people understand it.]

46. 20(4) cage in N14 must contain 2 and 8 or 9 = 2{369/378/459/468} [3/4, 5/6/7]

47. 45 rule on R89 3 outies R7C159 = 18, R7C23 must contain 8 or 9 (step 45) so R7C15 cannot be {89} -> no 1 in R7C9

48. 14(4) cage in N9, min R7C9 + R8C78 = {234} = 9 -> max R9C9 = 5

49. 45 rule on N3 1 innie R2C7 + 5 = 2 outies R4C78, min R2C7 = 6 -> min R4C78 = 11, no 1

50. 45 rule on N9 1 innie R8C7 – 2 = 2 outies R6C78, R8C7 = {89} -> R6C78 = 6 or 7, no 7,8

51. 45 rule on N7 1 innie R8C3 + 13 = 2 outies R6C23 -> min R6C23 = 14, no 4

52. 28(4) cage in N47 = 89{47/56} (step 14), the 8 and 9 must be in different rows (step 45) so cannot have {47} in R7C23 -> no 7 in R7C23

53. 45 rule on N1 1 innie R2C3 + 7 = 2 outies R4C23, R2C3 = {4567} -> R4C23 must total 11 to 14, R4C23 must contain 8 or 9 (step 45) -> no 7 in R4C23

54. 45 rule on C1 3 outies R258C2 = 15, min R25C2 = 7, max R8C2 = 8, no 9

55. 45 rule on R1234 3 innies R4C159 = 12, min R4C15 = 4, max R4C9 = 8, no 9

56. 28(4) cage in N1 = 89{47/56} (step 13), 4 only in R3C1 -> no 7 in R3C1, no 5 in R3C9 (step 28)

57. 20(4) cage in N3 = 1{379/568} (step 20), for the {1568} combination the 8 must be in R3C9 -> no 8 in R1C9 + R2C89

58. In R9 the 11(2) and 13(2) cages form a 24(4) cage which must contain 8 and/or 9

59. Valid combinations for R9C14569, which must contain {34} in R9C5 and must contain 1 are {12369/12378/12459/12468/13458/13467}

60. 37(7) cage must have 5/6 in N8, R78C5 must have 5/6 -> 5 locked for N8, R7C6 = 3, clean-up: R6C6 = 4, 4 locked for D\, R5C67 = [13], R4C6 = 2, 2 locked for D/, clean-up: R3C6 = 6, no 7 in R4C4

61. R9C5 = 4, clean-up: no 7 in R9C23, no 9 in R9C78, R456C5 = 3{59/68}, no 7 -> R1C5 = 7, R3C4 = 4 (hidden singles in N2), clean-up: R4C4 = 9, 9 locked for D\, R3C1 = 9 (naked single in N1)

62. 9 locked in R12C6 for N2, locked for C6, 9 in N8 locked in R78C5 -> R78C5 = {59}, 5 locked for C5 and N8 -> no 3 in 37(7) cage (step 24), R456C5 = {368}, locked for N5, R6C4 = 7, locked for D/, clean-up: R7C4 = 1, R5C4 = 5, R5C3 = 7, R1C4 = 8 (naked single), R12C6 = {59}, locked for the 42(7) cage, R2C7 = 6, R2C3 = 4, clean-up: no 7 in R9C8

63. 37(7) cage = {1246789}, R89C4 = {26}, R89C6 = {78}, R8C3 = 1, R8C7 = 9, R1C23 = [13], clean-up: no 8 in R9C2, R78C5 = [95]

64. R9C9 = 1 -> R2C8 = 1 -> R6C7 = 1 -> R4C1 = 1 (all hidden singles)

65. No 9 in R7C23 -> 8 locked in R7C23 (step 45), no other 8 in R7, N7 and R6C23, clean-up: no 3 in R9C2, 9 locked in R6C23 (step 45), locked for R6

66. 28(4) cage in N1 = {5689} (subtraction combo) -> R1C1 = 6, locked for D\, R2C12 = {58}, locked for R2 and N1

67. R3C23 = [72], 2 locked for D\, clean-up: no 9 in R9C2

68. R5C5 = 8 (naked single), locked for both diagonals, R2C2 = 5, R7C7 = 7, R8C8 = 3, (naked singles on D\), R2C1 = 8, R46C5 = {36}, clean-up: no 6 in R9C8, R9C78 = {58}, locked for R9 and N9, more clean-up: no 6 in R9C23 = [29]

69. R2C6 = 9, R1C6 = 5, R1C9 = 9, R2C9 = 7, R3C9 = 3

70. R3C78 = [58], 5 locked for D/, no 5,8 in R4C78 -> R4C78 = [47]

71. R7C3 = 6, R8C2 = 4, R9C1 = 3 (naked singles on D/)

72. R8C1 = 7, R89C6 = [87]

and the rest is simple elimination


Last edited by Ed on Sat Jun 14, 2008 8:58 am, edited 2 times in total.

Top
 Profile  
Reply with quote  
PostPosted: Mon Jun 09, 2008 12:36 am 
Offline
Grand Master
Grand Master

Joined: Wed Apr 16, 2008 1:16 am
Posts: 1044
Location: Sydney, Australia
Assassin 30 by Ruud (Dec 06)
Puzzle pic:
Image
Code: Select, Copy & Paste into solver:
3x3::k:2816:2816:4098:4098:5124:3333:3333:3079:3079:2816:4106:4106:4106:5124:5134:5134:5134:3079:2578:4106:3092:3092:5124:3863:3863:5134:3354:2578:4106:3092:11550:11550:11550:3863:5134:3354:4388:4388:4388:11550:11550:11550:3114:3114:3114:2605:7982:4655:11550:11550:11550:5683:4404:2357:2605:7982:4655:4655:3386:5683:5683:4404:2357:5951:7982:7982:7982:3386:4404:4404:4404:5191:5951:5951:842:842:3386:1869:1869:5191:5191:
Solution:
+-------+-------+-------+
| 2 4 9 | 7 6 8 | 5 3 1 |
| 5 3 6 | 4 9 1 | 2 7 8 |
| 7 1 8 | 3 5 2 | 6 4 9 |
+-------+-------+-------+
| 3 2 1 | 5 8 9 | 7 6 4 |
| 4 8 5 | 6 3 7 | 1 9 2 |
| 9 6 7 | 2 1 4 | 8 5 3 |
+-------+-------+-------+
| 1 7 3 | 8 4 5 | 9 2 6 |
| 8 5 4 | 9 2 6 | 3 1 7 |
| 6 9 2 | 1 7 3 | 4 8 5 |
+-------+-------+-------+
Quote:
Andrew: This one started easily but then kept me thinking. Nice to see that innie/outie differences were back again
sudokuEd: came out a little too easy for my liking
Para: That center nonet is interesting. Putting together all hidden cages gives you a puzzle usually called microsums
Walkthrough by Andrew:
This one started easily but then kept me thinking. Nice to see that innie/outie differences were back again after Assassin 29 which I was surprised to find could be solved without using them.

Here is my walkthrough, as always effectively in the order that I solved the puzzle.

1. R1C34 = {79}, no other 7,9 in R1

2. R1C67 = {58}, no other 5,8 in R1

3. R9C34 = {12}, no other 1,2 in R9

4. R9C67 = {34}, no other 3,4 in R9

5. 23(3) cage in N7 = {689}, no other 6,8,9 in N7

6. 11(3) cage in N1, no 9

7. R34C1 = {19/28/37/46}, no 5

8. R67C1 = {19/28/37/46}, no 5, no 1,2,4 in R6C1

9. R34C9 = {49/58/67}, no 1,2,3

10. R67C9 = {18/27/36/45}, no 9

11. 16(5) cage in N214 = {12346}

12. 17(5) cage in N698 = 123{47/56}, no 8,9

13. 31(5) cage in N478 must contain 9 in R6C2 or R8C4

14. 22(3) cage in N698 = 9{58/67}

15. 20(3) cage in N2, no 1,2

16. 20(3) cage in N9, no 1,2

17. 45 rule on R6789 3 innies R6C456 = 7 = {124}, no other 1,2,4 in R6 or N5, no 5,7,8 in R7C9 (step 10)

18. 45 rule on R1234 3 innies R4C456 = 22 = 9{58/67}, 9 locked for R4 and N5, no 1 in R3C1 (step 7), no 4 in R3C9 (step 9)

19. R5C456 = 3{58/67}, 3 locked for R5 and N5

20. 45 rule on C5 3 innies R456C5 = 12, min. R56C5 = 4, max. R4C5 = 8

21. 45 rule on C6789 3 innies R456C6 = 20, no 1,2 in R6C6 -> [974] -> R6C45 = {12}, R5C45 = {36}, no other 6 in R5, R4C45 = {58}, no other 5,8 in R4, no 2 in R3C1 (step 7), no 5,8 in R3C9 (step 9)

22. R9C6 = 3, R9C7 = 4, no 5 in R6C9 (step 10)

23. R456C5 = 12 (step 20), only valid combinations = [561]/[831] -> R6C5 = 1, R6C4 = 2 -> R9C34 = [21], no 8 in R6C1 (step 8)

24. 2 in C5 locked in N8, no other 2 in N8, 13(3) cage in N8 = 2{47/56}, no 8,9

25. 9 in C5 locked in N2, no other 9 in N2 -> R1C34 = [97], no 1 in R4C1 (step 7)

26. 7 in C5 locked in N8, 13(3) cage = {247} -> R9C5 = 7, R78C5 = {24}, no other 4 in C5 or N8

27. 5 in R9 locked in R9C89, no other 5 in N9

28. 2 in 16(5) cage in N214 locked in R234C2, no other 2 in C2

29. 9 in 22(3) cage in N698 locked in R67C7, no other 9 in C7

30. 45 rule on R9 2 remaining outies R8C19 = 15 = {69}/[87], no 3,8 in R8C9

31. 45 rule on C1 2 outies R19C2 - 9 = 1 innie R5C1, max. R19C2 = 15 -> max. R5C1 = 6 = {1245}

32. 45 rule on C9 2 outies R19C8 - 9 = 1 innie R5C9, max. R19C8 = 15 -> max. R5C9 = 6 = {1245}

33. 12(3) cage in N3, max. R1C89 = 10 -> no 1 in R2C9, also there is no valid combination with 3 in R2C9

34. 17(5) cage in N698 (step 12) = {12356}, no 7, 1,2 in 17(5) cage locked in N9, no other 1,2 in N9 -> R67C9 = {36} (step 10), no other 3,6 in C9, no 7 in R34C9 (step 9) -> R34C9 = [94], no 6 in R3C1 (step 7)

35. R2C5 = 9 (hidden single in N2), R13C5 = [38]/[56], R1C6 and R3C5 both {58}, no other 5,8 in N2

36. Naked triple {568} in R178C6, no other 6 in C6

37. Naked triple {346} in R235C4, no other 6 in C4

38. R8C9 = 7 (naked single) -> R9C89 = {58}, no other 8 in R9 or N9, R9C12 = {69}, R8C1 = 8, no 2 in R4C1 (step 7)

39. R7C7 = 9 (hidden single in N9), no 7 in R7C6 -> no 6 in R6C7

40. R8C4 = 9 (hidden single in N8), no 9 in R6C2

41. R5C8 = 9 (hidden single in N6), R5C79 = {12}, no other 1,2 in R5 or N6

42. R6C7 = 8 (hidden single in N6), R7C6 = 5, R1C67 = [85]

43. R8C6 = 6 (hidden single in N8), no other 6 in 17(5) cage, R7C8 + R8C78 = {123}, no other 3 in N9, R6C8 = 5, R9C89 = [85], R7C9 = 6, R6C9 = 3, no 7 in R7C1 (step 8)

44. Killer pair 1,2 in R15C9 -> R2C9 = 8, R1C89 = [31], R5C9 = 2, R5C7 = 1, R78C8 = {12}, no other 1,2 in C8, R8C7 = 3

45. R1C5 = 6 (naked single), R3C5 = 5, R4C45 = [58], R5C45 = [63]

46. R1C2 = 4 (naked single), R1C1 = 2, R2C1 = 5

47. R5C1 = 4 (naked single), no 6 in R4C1 (step 7), no 6 in R6C1 (step 8), R5C23 = {58}

48. R34C1 = {37}, no other 3,7 in C1 -> R67C1 = [91], R9C12 = [69]

49. Naked triple {467} in R234C8, no other 6,7 in 20(5) cage -> R2C67 = [12]

50. Naked triple {346} in R2C234, no other 3,4,6 in R2 or in 16(5) cage -> R34C2 = [12]

and the rest is naked and hidden singles, simple elimination and cage totals for 18(3) and 31(5) cages in N478

Happy Christmas to all Assassin solvers and especially to Ruud for his wonderful efforts in composing these puzzles
Bullseye 3 (aka A30 V2.1) by sudokuEd (Dec 06)
Puzzle pic:
Image
Code: Select, Copy & Paste into solver:
3x3::k:4352:4352:4098:4098:5124:1797:1797:1543:1543:4352:5642:5642:5642:5124:6670:6670:6670:1543:2578:5642:1556:1556:5124:5399:5399:6670:3354:2578:5642:1556:10782:10782:10782:5399:6670:3354:2852:2852:2852:10782:769:10782:4650:4650:4650:2605:7982:3119:10782:10782:10782:4147:5940:2357:2605:7982:3119:3119:4922:4147:4147:5940:2357:4415:7982:7982:7982:4922:5940:5940:5940:3655:4415:4415:2378:2378:4922:1869:1869:3655:3655:
Solution:
+-------+-------+-------+
| 8 4 9 | 7 6 2 | 5 3 1 |
| 5 3 6 | 4 9 1 | 8 7 2 |
| 7 1 2 | 3 5 8 | 6 4 9 |
+-------+-------+-------+
| 3 8 1 | 5 2 9 | 7 6 4 |
| 4 2 5 | 6 3 7 | 1 9 8 |
| 9 6 7 | 8 1 4 | 2 5 3 |
+-------+-------+-------+
| 1 7 3 | 2 4 5 | 9 8 6 |
| 2 5 4 | 9 8 6 | 3 1 7 |
| 6 9 8 | 1 7 3 | 4 2 5 |
+-------+-------+-------+
Quote:
sudokuEd, lead-in: a very very difficult V2...requires many contradiction moves between nonets
Para: Had to resort one trick and a "Richard-style 45-tests" but happy with the general result. Those big 45-tests are pretty cool to do, but a monster to analyze, so you have to carefully set your restrictions to get the proper results
Para: I feel it is 1.75 somewhere in the vicinity of A60RP-lite. Some tricky moves and careful analysis did the trick just like A60RP-Lite
sudokuEd: (tag solution) uses 1 hypothetical so should be rated a 2.0. However, Para's solution is much better (just leave out step 27 since it's not needed) ... He uses a 'trick' chain move to unlock it - so I would give a 2.0 rating for Para's WT as well
tag solution: by Caida, sudokuEd & Nasenbaer
2011 Walkthrough by Andrew: I probably wouldn't have posted it if it hadn't been listed as one of the Unsolvables.
Walkthrough by Para:
Hi all

Here's my walk-through for Bullseye 3. Had to resort one trick and a "Richard-style 45-tests" but happy with the general result. Those big 45-tests are pretty cool to do, but a monster to analyze, so you have to carefully set your restrictions to get the proper results.

[edit] As Afmob wondered about the rating and Mike mentioned something about Ed doing a rating bit for everything under 50 i'll add my rating advice. I feel it is 1.75 somewhere in the vicinity of A60RP-lite. Some tricky moves and careful analysis did the trick just like A60RP-Lite.

Walk-through Bullseye 3

1. R5C5 = 3

2. 20(3) at R1C5 = {479/569/578} = {8|9..}: no 1,2

3. R1C67 and R9C67 = {16/25/34}: no 7,8,9

4. R34C1 and R67C1 = {19/28/37/46}: no 5

5. 6(3) at R3C3 = {123}

6. 21(3) at R3C6 = {489/579/678}: no 1,2,3

7. R34C9 = {49/58/67}: no 1,2,3

8. 11(3) at R5C1 = {128/146/245}: no 7

9. R67C9 and R9C34 = {18/27/36/45}: no 9

10. 19(3) at R7C5 = {469/478/568}: {289} blocked by 20(3) at R1C5: no 1,2

11. R1C34 = {79} -> locked for R1

12. 6(3) at R1C8 = {123} -> locked for N3
12a. Clean up: R1C6: no 4,5,6
12b. Naked Triple {123} in R1C689 -> locked for R1

13. 17(3) at R1C1 = {46}[7]/{68}[3]/{458}: R2C1: no 1,2,6,9

14. Hidden Pair {12} in R46C5 -> R46C5 = {12} -> locked for N5

15. 45 on R5: 2 innies: R5C46 = 13 = {49/58/67}
15a. 18(3) at R5C7 = {189/279/459/567}: {468} blocked by 11(3) at R5C1

16. 45 on R1234: 3 innies: R4C456 = 16 = {6[1]9/7[1]8/5[2]9/6[2]8}: no 4

17. 45 on R6789: 3 innies: R6C456 = 13 = {4[1]8/5[1]7/4[2]7/5[2]6}: no 9

18. 45 on C1234: 3 innies: R456C4 = 19 = {469/478/568} = [964]/{7[4]8}/{5[6]8}: {78}[4] blocked by R6C456(needs 7 or 8 when R6C4 = 4); others blocked by step 15: R46C4: no 6; R5C4 = {46}
18a. 11(3) at R5C1 = {128/245}: {146} blocked by R5C4: no 6; 2 locked for R5 and N4
18b. 2 in 6(3) at R3C3 locked for R3
18c. Clean up: R5C6 = {79}; R34C1: no 8; R7C1: no 8

19. 45 on C6789: 3 innies: R456C6 = 20 = [974]/[695]/{5[7]8}: [794] blocked by R5C46; [596] blocked by R6C456(needs 5 when R6C6 = 6): R6C6: no 6,7; R4C6: no 7

20. R4C456 = {5[2]9}/[826]: {6[1]9} blocked by R5C46; [718] blocked by R456C6(when R4C6 = 8, they also need 7): R4C5 = 2; R4C4 = {589}; R4C6 = {569}
20a. R6C5 = 1
20b. R456C4 = [964/568/847]: R6C4 = {478}
20c. R456C6 = [974/695/578]
20d. clean up: R7C1: no 9; R7C9: no 8

21. 20(3) at R1C5 = {569/578} = {7|9..},{6|7..}: {479} blocked by R1C4: no 4; 5 locked for C5 and N2
21a. 4 in C5 locked for N8
21b. Killer Pair {79} in R1C4 + 20(3) at R1C5 -> locked for N2
21c. Clean up: R9C3: no 5; R9C7: no 3

22. 45 on R1: 2 outies and 1 innie: R1C5 + 1 = R2C19: R2C19 = 6/7/9 = [42/51/43/52/81/72]: R2C1: no 3
22a. 17(3) at R1C1 = {458}/{46}[7]: 4 locked for N1
22b. Clean up: R4C1: no 6

23. 45 on C9: 2 outies and 1 innie: R5C9 = R19C8 + 3: Min R19C8 = 3 -> Min R5C9 = 6: no 1,4,5; Max R5C9 = 9 -> Max R19C8 = 6: R9C8: no 6,7,8,9

24. 12(3) at R6C3 = [9]{12}/{138/147/156/237/246/345}: R7C34: no 9

25. 21(3) at R3C6 = [4]{89}/[6]{78}/[8]{49}/[8]{67}: R34C7: no 5

26. 20(3) at R1C5 = [5]{69/78}/[6]{59}/[8]{57}

27. 45 on R1: R1C5 + 1 = R2C19 = [5]-[51]/[6]-[43/52]/[8]-[72/81]: [5]-[42] blocked by 17(3) at R1C1
27a. 45 on R1: 4 outies: R2C19 + R23C5 = 21 = [51]-{69/78}/[43]-{59}/[52]-[95]/[81]-{57}: [72]-{57} blocked by R1C34(leaves no 7 in R1): R2C1: no 7
27b. 17(3) at R1C1 = {458} -> locked for N1

28. 19(3) at R7C5 = {469/478} = {8|9..}; R456C4 = [964/568/847] = {8|9..}
28a. Killer y-wing on 9 in N2: R789C5(89) and R456C4(89) see all 9's in N2, so can't both use 9, one of them needs an 8 -> eliminate 8 from all peers of R456C4 and R789C5: R789C4: no 8
28b. R9C3: no 1

29. 45 on N236: 6 innies: R123C4 + R6C789 = 24: Min R6C789 = 9 -> Max R123C4 = 15
29a. R12C4 = [98/96/78] blocked by step 29; R12C4 = [76] blocked by 20(3) at R1C5: R2C4: no 6,8
29b. 8 in C4 locked in R46C4 for N5
29c. R456C4 = [568/847]: R4C4: no 9; R6C4: no 4
29d. 9 in N5 locked within R45C6 for C6
29e. R456C6 = [974/695]: R4C6: no 5

30. 45 on N2: 6 innies: R123C4 + R123C6 = 25 = {123469/123478}
30a. When {123478}: R1C4 = 7: No 4 in C6 as this is blocked by R6C46 = [75/84]: R2C4 = 4
30b. When {123469}: Can't have both {46} in C6 as this is blocked by R456C6 = [695/974]: R2C4 = 4
30c. Conclusion: R2C4 = 4
30d. R5C46 = [67]; R4C46 = [59]; R6C46 = [84]
30e. Clean up: R3C1: no 1; R3C9: no 4,8; R7C1: no 2,6; R7C9: no 1,5; R9C3: no 3,4

31. Hidden Triple {123} in N2: R12C6 + R3C4 = {123}

32. 4 in N1 locked for R1
32a. Clean up: R1C6: no 3
32b. 3 in R1 lockd for N3

33. 21(3) at R3C6 = [6]{78}/[894]/[8]{67}: R3C7: no 4
33a. R3C8 = 4(hidden)

34. 26(5) at R2C6 = 4-[1]{59}[7]/[1]{678}/[2]{89}[3]/[2]{59}[6]/[2]{578}/[3]{568}: R4C8: no 1
34a. 1 in R4 locked for N4

35. 11(3) at R5C1 = {245} -> locked for R5 and N4
35a. R4C2 = 8(hidden)
35b. 6 and 9 in N4 locked for R6
35c. Clean up: R3C1: no 6; R3C9: no 5; R7C9: no 3

36. R3C5 = 5(hidden)
36a. Naked Pair {68} in R1C5 + R3C6 -> locked for N2

37. 6 in N1 locked within 22(5) at R2C2: 22(5) = 48{136}: R2C23 + R3C2 = {136} -> locked for N1
37a. R3C3 = 2
37b. 2 in C4 locked for N8
37c. Clean up: R4C1: no 7; R9C4: no 7; R9C7: no 5

38. Naked Pair {13} in R4C13 -> locked for R4 and N4
38a. Naked Triple {467} in R4C789 -> locked for N6
38b. Clean up: R7C1: no 7; R7C9: no 2

39. Hidden Pair {13} in R3C24 -> R3C2 = {13}
39a. 6 in N1 locked for R2

40. 45 on R12: 2 outies: R3C2 + R4C8 = 7 = [16]
40a. R3C4 = 3; R4C13 = [31]; R3C1 = 7; R1C34 = [97]
40b. R12C5 = [69]; R1C67 = [25]; R23C6 = [18]; R2C9 = 2
40c. R1C12 = [84]; R2C1 = 5; R8C4 = 9(hidden); R6C1 = 9(hidden)
40d. R7C1 = 1; R79C4 = [21]; R9C3 = 8; R9C2 = 9{hidden)
40e. Clean up: R7C9: no 7; R9C67: no 6

41. 17(3) at R8C1 = 9{26} -> R89C1 = {26} -> locked for C1 and N7
41a. R5C123 = [425]

42. 31(5) = 9{4567} -> R6C2 = 6; R8C3 = 4; R78C2 = {57} -> locked for N7
42a. R2C23 = [36]; R67C3 = [73]

43. Killer Pair {46} in R34C9 + R7C9 -> locked for C9

44. 14(3) at R8C9 = {257}: {158} blocked as R8C9 only cell with {18}: R9C8 = 2; R89C9 = {57} -> locked for C9 and N9

And the rest is all naked singles.


greetings

Para
condensed walkthrough of tag solution by sudokuEd:
Here is a simplified version of the Bullseye 3 tag solution. It uses 1 hypothetical so should be rated a 2.0. However, Para's solution is much better (just leave out step 27 since it's not needed) because he found a "45" that we missed. Great work Para :D . He uses a 'trick' chain move to unlock it - so I would give a 2.0 rating for Para's WT as well.

Great to have this one solved properly.

Bullseye 3 simplified tag WT
Preliminaries
0. r5c5 = 3

a) 6(3)n124 and n3 = {123} (no 4..9) -> {123} locked for n3
b) 16(2)n12 = {79} (no 1..6,8) -> {79} locked for r1
c) 10(2)n14 and n47 = {19/28/37/46} (no 5)
d) 20(3)n2 = {479/569/578} (no 1,2)
e) 7(2)n23 = [16/25/34] (no 7,8) -> r1c6 no 4,5,6; -> {123} locked for r1 in c689
e1) 7(2)n89 = {16/25/34} (no 7..9)
f) 21(3)n236 = {489/579/678} (no 1..3)
g) 13(2) n36 = {49/58/67} (no 1..3)
h) 11(3)n4 = {128/146/245} (no 7,9)
i) 9(2)n46 and n78 = {18/27/36/45} (no 9)
j) 19(3)n8 = {289/469/478/568} (no 1)

1. Innies c5: r46c5 = 3(2) = {12} (no 4..9)
1a. -> {12} locked for n5 and c5

2. 20(3)n2 = {569/578}(no 4) (combo {479} blocked by r1c4)
2a. -> 5 locked in 20(3)n2 for c5 & n2
2b. -> 4 locked in 19(3)n8 for n8
2c. cleanup: 7(2)n89: r9c7 no 3
2d. cleanup: 9(2)n78: r9c3 no 5

3. killer pair {79} locked for n2 in 20(3) and r1c4

4. 17(3)n1
4a. min r1c12 = 9 -> max r2c1 = 8 (no 9)
4b. max r1c12 = 14 -> min r2c1 = 3 (no 1,2)
4c. -> r2c1 no 6 (no valid permutations)

5. Innies r1234: r4c456 = h16(3) & must have 1/2 = {169/178/259/268}
5a. -> r4c46 no 4

6. Innies r6789: r6c456 = h13(3) = {148/157/247/256}
6a. -> r6c46 no 9

7. Innies c1234: r456c4 = h19(3) = {469/478/568}
7a. Innies c6789: r456c6 = h20(3) = {479/569/578}

8. "45" r5: r5c46 = h13(2) = {49/58/67} = [4/6/8..]
8a. {468} blocked from 18(3)n6

9. from steps 1 & 8: In n5 a Very hidden cage Vh26(4)r46c46 = {4589/4679/5678}
9a. Each combo must have exactly 2 numbers overlap with the 2 hidden cages in c4 & 6
i. {4589} -> h19(3)c4 & h20(3)c6 = {568-479} -> the 2 left-over candidates must be in r5c46 = 13 = [67]
ii. ........-> h19(3)c4 & h20(3)c6 = {469-578} -> the 2 left-over candidates must be in r5c46 = 13 = [67]
iii.........-> h19(3)c4 & h20(3)c6 = {478-569} -> the 2 left-over candidates must be in r5c46 = 13 = [76]
iv. {4679} -> h19(3)c4 & h20(3)c6 = {478-569} -> the 2 left-over candidates must be in r5c46 = 13 = [85]
v. {5678} -> h19(3)c4 & h20(3)c6 = {478-569} -> the 2 left-over candidates must be in r5c46 = 13 = [49]

10. 6 in Vh26(4) in {4679/5678} must be in c6 (see 9iv & v) -> no 6 in r46c4
10a. 7 in Vh26(4) in {4679/5678} must be in c4 (see 9iv & v) -> no 7 in r46c6
10b. r5c4 = {4678}(no 59)(step 9a.i..v)
10c. r5c6 = {5679}(no 48)(h13(2)r5c46)

11. Same thing with r46 in n5. Very hidden Vh26(4)r46c46 = {4589/4679/5678}
11a. Each combo must have exactly 2 numbers overlap with the 2 hidden cages in r4 & r6
i. {4589} -> h16(3)r4 & h13(3)r6 = {259-148} = {5[2]9-4[1]8}
ii. {4679} Blocked: Like this: h16(3)r4 & h13(3)r6 = {169-247} = [916-724] but r46c4 = [79] clashes with r1c4
iii. {5678} -> h16(3)r4 & h13(3)r6 = {178-256} = [718-526] BUT BLOCKED: h19(3)c4 cannot have [75]
iv.....................................= {268-157} = [826-715]

12. In summary, h16(3)r4 & h13(3)r6 = {259-148/268-157} = 8{..}
12a. r46c5 = [21]
12b. 8 locked for n5 -> h13(2)r5c46 = {49/67}(no 5)
12c. h16(3)r4 = [2]{59}/[826](no 7)(no 8 in r4c6)
12d. h13(3)r6 = 1{48/57}(no 6) = {4[1]8}/[715](no 5 in r6c4)
12e. clean-ups:no 8 in r3c1
12f. no 9 in r7c1
12g. no 8 in r7c9
12h. 2 in 6(3)n1 must be in r3: 2 locked for r3
12i. no 8 in r4c1

13. 21(3)n236 = {489/678}(no 5) ({579} blocked by no digits in r3c6)

14. Outties and Innie c9: r5c9 less r19c8 = 3
14a. min r19c8 = 3 -> min r5c9 = 6 (no 1,2,4,5)
14b. max r5c9 = 9 -> max r19c8 = 6 (no 6..9)

Now the trick that Caida spotted. Maybe this is one for Sudoku SolverV3
15. Outies c9: r159c8 + r5c7 = 15 AND empty rectangle/generalized X-Wing on 1 for c89 between 6(3)n3 & r9c8 IF r19c8 = 1 -> min r19c8 = 5. Like this.
15a. If r19c8 = [12/13] = 3/4 -> 1 in c9 must be in n9 -> 1 in n6 must be in r5c7 which is in outies of c9. But since outies of c9 = 15 and 3/4 + 1 = 4/5 -> r5c8 would have to be 10/11! therefore r19c8 must be min of 5 = [14]/{23}
15b. If r19c8 = [21/31] = 3/4 -> Grouped X-Wing on 1 with 6(3)n3 -> 1 in n6 must be in r5c7. But since outies c9 = 15, this would force r5c8 = 10/11.

Therefore, r19c8 cannot be [21/31]
15c. -> min r19c8 = 5 -> max r5c78 = 10 (outies c9)
15d. -> min r5c9 = 8 (cage sum) (no 6,7)
15e. min r19c8 = 5 -> min r9c8 = 2

16. 18(3)n6 must have 8/9 = {189/459}(no 2,6,7) ({279} blocked by h13(2)r5c46)
16a. = 9{18/45}: 9 locked for r5 & n6
16b. no 4 in r5c4 (h13(2)r5c46) or r3c9
16c. 9 in {489} in 21(3)n2 must be in r3c7 -> no 4 in r3c7

17. NP {67} in r5c46: both locked for r5 & n5

18. h16(3)r4c456 = [2]{59}: all locked for r4 & n5
18a. no 1 r3c1
18b. no 8 in r3c9

19. NP {48} in r6c46: both locked for r6
19a. no 2 or 6 in r7c1
19b. no 1 or 5 in r7c9

20. 2 locked for r5 in 11(3)n4 = 2{18/45}
20a. 2 locked for n4
20b. no 8 in r7c1
20c. min r6c3 = 3 -> max r7c34 = 9 (no 9)

21. h19(3)r456c4 = {469/568}
21a. r5c4 = 6
21b. r5c6 = 7
21c. no 3 in r9c3

22. deleted

23. Outies and Innie r1: r2c19 – r1c5 = 1
23a. min r1c5 = 5 -> min r2c19 = 6 -> r2c1 no 3

24. 17(3)n1 = {458/467} -> 4 locked in n1, not elsewhere in n1
24a. r4c1 no 6

Para calls this next move a killer Y-wing in his WT
25. r456c4 must contain either 8 or 9 – if they contain a 9 then r123c5 must contain 9 and r789c5 contains an 8; otherwise r456c4 contains an 8
25b. -> r789c4 no 8 (either 8 is in r456c4 or it is in r789c5)
25c. -> r9c3 no 1
(note: Para's "45" on n236 eliminates 8 from r2c4 which would have now left hidden single 8 in r6c4 for us)

Now a very productive hypothetical - which means we should rate this puzzle as a 2.0
26. "45" i/o c9: r19c8 = 5/6 = {23}/[14/15/24] -> r1289c9 = 14/15 (cage sums = 20) AND must have 1 for c9
26a. r19c8 = [23] -> r1289c9 = 15: r12c9 = {13} = 4 -> r89c9 = 11 = {29/56} ({47} blocked by [1/3/4/7] needed by 9(2)c9)
26b. r19c8 = [32] -> r1289c9 = 15: r12c9 = {12} = 3 -> r89c9 = 12 = {39/57} ({48} blocked by [4/8] needed by 9(2) & 13(2)c9)
26c. r19c8 = [14] -> r1289c9 = 15: r12c9 = {23} = 5 -> r89c9 = 10 = {19} ({46} blocked - r89 must have 1 for c9)
26d. r19c8 = [15] -> r1289c9 = 14: r12c9 = {23} = 5 -> r89c9 = 9 = {18} ({45} blocked - 1 must be in r89 for c9)
26e. r19c8 = [24] -> r1289c9 = 14: r12c9 = {13} = 4 -> r89c9 = 10 = {28} ({46} blocked by 4 in r9c8)

27. In summary, r1289c9 = 1{356/239/238/257}(no 4)
27a. 14(3)n9 = {149/158/239/248/257/356} ({347} blocked by no {37} possible in r89c9 steps 26a..e.)

28. {459} is blocked from 18(3)n6 by 4s in c9. Like this.
28a. 4 in r7c9 -> 5 in r6c9 -> {459} blocked from 18(3)
28b. 4 in r4c9 -> {459} blocked from 18(3)
28c. 18(3)n6 = {189}: all locked for r5 & n6
28d. no 5 in r3c9
28e. 8 must be in 21(3)n2: only in r3: 8 locked for r3

29. 11(3)n4 = {245}: all locked for n4
29a. no 6 in r3c1

30. r4c2 = 8 (hsingle n4)

31. r6c4 = 8 (hsingle c4)

32. 8 in n1 only in 17(3) = {458}: 5 locked for n1
32a. 8 locked for c1
32b. 17(3)n7: no 8 = {179/269/359/467}

33. r2c4 = 4 (hsingle c4)
33b. 4 in n1 only in r1: 4 locked for r1
33c. no 3 r1c6
33d. 3 in r1 only in c89: no 3 in r2c9

34. r4c4 = 5 (cage sum h19(3)c4)
34a. no 4 in r9c3

35. r46c6 = [94]

36. 22(5)n1 must have 4 & 8 (& no 5) = 48{127/136}(no 9) = 1{..} = [2/3..]
36a. 1 required in 22(5)n1 only in n1: 1 locked for n1

37. Killer pair 2/3 between 22(5)n1 & r3c3: no 3 in r3c1
37a. no 7 in r4c1

38. NP {13} in r4c13: both locked for r4 and n4
38a. no 7 in r7c1

39. NTriple {467} in r4c789: all locked for n6
39a. no 2,3 in r7c9

40. r3c8 = 4 (hsingle r3)

41. NP {79} in n1 in r3c1 & r1c3: 7 locked for n1

42. 22(5)n1 = 48{136}(no 2): 3 locked for n1

43. r3c3 = 2
43a. no 7 in r9c4

44. 2 in n2 only in c6: locked for c6
44a. no 5 in r9c7

45. hidden pair {13} in r3c24:no 6 in r3c2
45a. 6 in n1 only in r2: 6 locked for r2

46. hidden triple {123} in n2: no 8 in r2c6

47. r3c5 = 5 (hsingle r3)

48. NP {68} in n2: no 8 in r2c5

49. "45" c1: 4 outies r159c2 & r5c3 = 20
49. max r15c2 + r5c3 = [545] = 14 -> min r9c2 = 6

50. 17(3)n7 must have 1 of 6/7/9 for c1 and 1 of 6/7/9 in r9c2 -> must have 2 of {679}
50a. = {179/269/467}(no 3,5)

51. 3 in c1 in 1 of 10(2) cages -> 7 locked for c1

No way to go - time for some creativity from Peter
52. 26(5)n236 must contain a 4 and only 1 of {123}
52a. 26(5)n236 = {14678/24569/24578}(no 3) ({23489} blocked by 2,3 only in r2c6)
i. {14579} blocked: r2c6 = 1 -> r1c67 = [25] -> can’t place 5 in 26(5)
ii. {34568} blocked: r2c6 = 3 -> r3c4 = 1 -> r1c67 = [25] -> can’t place 5 in 26(5)
52b. r2c6 no 3
52c. hsingle: r3c4 = 3: no 6 in r9c3
52d. r4c3 = 1
52e. r4c1 = 3: no 7 in r6c1
52f. r3c1 = 7: no 6 in r4c9
52g. r1c34 = [97]
52h. r12c5 = [69](cage sum)
52i. r3c6 = 8
52j. r1c7 = 5
52k. r1c6 = 2
52l. r1c2 = 4
52m. r1c1 = 8
52n. r2c1 = 5
52o. r2c6 = 1: no 6 in r9c7
52p. r2c9 = 2: no 7 in r7c9
52q. r3c2 = 1

53. Naked pair {78} locked for 26(5)n236 in r2c78

54. r3c8 = 6

55. r8c4 = 9 (hsingle c4)

56. r6c1 = 9 (hsingle n4)

57. r7c1 = 1
57a. r7c4 = 2
57b. r9c34 = [81]:no 6 in r9c6

58. r67c3 = [73/64] = [3/6..]
58a. r7c3 = {34}

59. Killer pair {36} in r267c3: both locked for c3

60. 31(5)n478: = [9]{4567}(no 2,3) (only permutation without 8)

61. r7c3 = 3 (hsingle n7), r6c3 = 7(cage sum), r6c2 = 6, r2c23 = [36], NP {57} at r78c2: both locked for c2 & n7
r59c2 = [29], r5c13 = [45], r8c3 = 4

62. 16(3)n689 = [259/268/358/367]
r7c7 = {789}

63. 14(3)n9 = {257/356}(no 1,8)
63a. = 5{..}: 5 locked for n9

64. r1c9 = 1 (hsingle c9)

Rest is simple. Whew
2011 Walkthrough by Andrew:
Another old puzzle which I only recently tried for the first time.

sudokuEd wrote:
Para's solution is much better (just leave out step 27 since it's not needed) because he found a "45" that we missed.
Yes, a much better solution than the "tag" or my solving path. Steps 28 and 29 were two neat steps which I also missed. An alternative way to look at step 28 is
Consider placements for 9 in N2
9 in R1C4 => R456C4 = [568/847], 8 locked for C4
or 9 in 20(3) cage at R1C5, locked for C5 => 19(3) cage at R7C5 = {478}, locked for N8
-> no 8 in R789C4

I'm not sure about SudokuEd's comment that step 27 isn't needed. When I omitted that step I then had two 5s in R3 so step 36 didn't work and step 37 didn't work because 6 was still in the 17(3) cage in N1. I think my step 20 was a simpler way to achieve the same result as Para's 27, using a short forcing chain instead of permutation analysis.

sudokuEd wrote:
This V2puzzle requires many contradiction moves between nonets.
I didn't consciously take account of that introductory comment while working on this puzzle; however it's a valid comment on my solving path after step 25 when I started using contradiction moves.

Here is my walkthrough for A30 V2 Bullseye 3. I probably wouldn't have posted it if it hadn't been listed as one of the Unsolvables.

Prelims

a) R1C34 = {79}, locked for R1
b) R1C67 = {16/25/34}, no 8
c) R34C1 = {19/28/37/46}, no 5
d) R34C9 = {49/58/67}, no 1,2,3
e) R67C1 = {19/28/37/46}, no 5
f) R67C9 = {18/27/36/45}, no 9
g) R9C34 = {18/27/36/45}, no 9
h) R9C67 = {16/25/34}, no 7,8,9
i) 20(3) cage in N2 = {389/479/569/578}, no 1,2
j) 6(3) cage in N3 = {123}
k) 6(3) cage at R3C3 = {123}
l) 21(3) cage at R3C6 = {489/579/678}, no 1,2,3
m) 11(3) cage at R5C1 = {128/137/146/236/245}, no 9
n) 19(3) cage in N8 = {289/379/469/478/568}, no 1
o) 31(5) cage at R6C2 must contain 9

Steps resulting from Prelims
1a. Naked pair {79} in R1C34, locked for R1
1b. Naked triple {123} in N3, locked for N3, clean-up: R1C6 = {123}
1c. R5C5 = 3, clean-up: no 7 in 11(3) cage at R5C1

2. Naked triple {123} in R1C689 locked for R1

3. 45 rule on C5, 2 innies R46C5 = 3 = {12}, locked for C5 and N5

4. 20(3) cage in N2 = {569/578} (cannot be {479} which clashes with R1C4), no 4, 5 locked for C5 and N2
4a. Killer pair 7,9 in R1C4 and 20(3) cage, locked for N2
4b. 4 in C5 only in 19(3) cage, locked for N8, clean-up: no 5 in R9C3, no 3 in R9C7

5. 21(3) cage at R3C6 = {489/678} (cannot be {579} because R3C6 only contains 4,6,8), no 5

6. 45 rule on R1234, 3 innies R4C456 = 16 = {169/178/259/268} (cannot be {457} which doesn’t contain 1 or 2), no 4

7. 45 rule on R5, 2 innies R5C46 = 13 = {49/58/67}

8. 45 rule on R6789, 3 innies R6C456 = 13 = {148/157/247/256}, no 9

9. 45 rule on C1234, 3 innies R456C4 = 19 = {469/478/568}

10. 45 rule on C6789, 3 innies R456C6 = 20 = {479/569/578}

11. Min R1C12 = 9 -> max R2C1 = 8
11a. Max R1C12 = 14 -> min R2C1 = 3
11b. 17(3) cage in N1 = {368/458/467}
11c. 3,7 of {368/467} must be in R2C1 -> no 6 in R2C1

12. R456C4 (step 9) = {469/478/568}, R456C6 (step 10) = {479/569/578}, R5C46 (step 7) = {49/58/67}, R4C456 (step 6) = {169/178/259/268}
12a. Consider combinations for R456C4
(details of locked cages and CCC clashes have been omitted as they are easy to see within N5; for clarity permutations have been left until the next step.)
12aa. R456C4 = {469} => R456C6 = {578} => R5C46 = {67} => R4C456 = {259}
12ab. R456C4 = {478} => R456C6 = {569} => R4C456 = {268} => R5C46 = {49}
12ac. R456C4 = {568} => R456C6 = {479} => R5C46 = {67} => R4C456 = {259}
12b. -> R4C456 = {259/268}, no 7 -> R4C5 = 2, R6C5 = 1, R5C46 = {49/67}, no 5,8, clean-up: no 8 in R3C1, no 9 in R7C1, no 8 in R7C9
12c. R6C456 (step 6) = {148/157}, no 6
12d. 2 in 6(3) cage at R3C3 only in R3C34, locked for R3, clean-up: no 8 in R4C1

[Now consider the above combinations as permutations.]
13. R456C4 = {469/478/568}, R456C6 = {479/569/578}, R5C46 = {49/67}, R4C456 = {259/268}, R6C456 = {148/157}
13aa. R456C4 = {469} = [964] => R4C456 = [925], R456C6 = [578]
13ab. R456C4 = {478} = [847] => R4C456 = [826], R456C6 = [695]
13ac. R456C4 = {568} = [568] (cannot be [865] which clashes with R4C456 = [826], CCC) => R4C456 = [529], R456C6 = [974]
13b. -> R4C4 = {589}, R4C6 = {569}, R5C4 = {46}, R5C6 = {79}, R6C4 = {478}, R6C6 = {458}

14. 11(3) cage at R5C1 = {128/245} (cannot be {146} which clashes with R5C4), no 6,7, 2 locked for R5 and N4, clean-up: no 8 in R7C9
14a. 18(3) cage at R5C7 = {189/459/567} (cannot be {468} which clashes with R5C4)

15. 45 rule on C1 2 outies R19C2 = 1 innie R5C1 + 9
15a. Min R19C2 = 10 -> no 1 in R9C2

16. 45 rule on C9 1 innie R5C9 = 2 outies R19C8 + 3
16a. Min R19C8 = 3 -> min R5C9 = 6
16b. Max R19C8 = 6 -> max R9C8 = 5

17. 12(3) cage at R6C3 = {129/138/147/156/237/246/345}
17a. 9 of {129} must be in R6C3 -> no 9 in R7C34
17b. 8 of {138} must be in R67C3 (R67C3 cannot be [31] which clashes with R4C3) -> no 8 in R7C4

18. 45 rule on R1 2 outies R2C19 = 1 innie R1C5 + 1
18a. Min R1C5 = 5 -> min R2C19 = 6 -> no 3 in R2C1 (because R2C19 cannot be [33])

19. 17(3) cage in N1 (step 11b) = {458/467}, 4 locked for N1, clean-up: no 6 in R4C1

20. 20(3) cage in N2 (step 4) = {569/578}, 17(3) cage in N1 (step 19) = {458/467}
20a. Consider the combinations for the 20(3) cage
20aa. 20(3) cage = {569} => 8 in R1 only in R1C12 => 17(3) cage = {458}
20ab. 20(3) cage = {578}, locked for N2 => R1C4 = 9, R1C3 = 7 => 17(3) cage = {458}
20b. -> 17(3) cage = {458}, locked for N1

21. Hidden killer pair 3,7 for R34C1, R67C1 and R89C1 for C1, R34C1 and R67C1 must each contain both or neither of 3,7 -> R89C1 must contain both or neither of 3,7 but R89C1 cannot be {37} (because 17(3) cage in N7 cannot be {37}7) -> no 3,7 in R89C1

22. 17(3) cage in N7 = {179/269/278/359/368/467} (cannot be {458} which clashes with 17(3) cage in N1, ALS block)
22a. Consider permutations for 17(3) cage in N1 = {458}
22aa. 5 in R12C1, locked for C1
22ab. R12C1 = {48}, locked for C1 => R34C1 = {19/37}, R67C1 = {19/37} => naked quad {1379} in R3467C1, locked for C1
22b. -> R89C1 cannot contain both of 5,9 -> 17(3) cage in N7 = {179/269/278/368/467} (cannot be {359} because 3 only in R9C2), no 5
22c. 7 of {467} must be in R9C2 -> no 4 in R9C2

23. 17(3) cage in N7 (step 22b) = {179/269/278/368/467}
23a. R19C2 = R5C1 + 9 (step 15)
23b. Consider R9C2 = 7 => R19C2 = [47] (R19C2 cannot be [57/87] = 12,15 because no 3,6 in R5C1) = 11 => R5C1 = 2 -> 17(3) cage cannot be {278} = {28}7 (because cannot have 2 in R89C1 and 7 in R9C2)
23c. -> 17(3) cage in N7 = {179/269/368/467}
23d. 3 of {368} must be in R9C2 -> no 8 in R9C2

24. 17(3) cage in N7 (step 23c) = {179/269/368/467}
24a. Consider the combinations for 17(3) cage
24aa. 17(3) cage = {179/467} => R9C2 = 7 => R19C2 = [47] => R5C1 = 2 (working in step 23b)
24ab. 17(3) cage = {269}, 2 locked for N7
24ac. 17(3) cage = {368} => R9C2 = 3, R89C1 = {68}, locked for C1
24b. -> R67C1 = {37/46}/[91], no 2,8

25. Consider placements for 2 in C1
25aa. R5C1 = 2 => R19C2 = 11 (step 15) => min R9C2 = 3
25ab. 2 in R89C1, locked for N7
25b. -> no 2 in R9C2

[Looks like I need to start looking at contradiction moves or big hypotheticals.
I’ve noticed 45 rule on N1 6(3+3) outies R123C4 + R4C123 = 26 but cannot see any way to use this.]
26. 22(5) cage at R2C2 = {12379/12469/12478/13459/13468/13567/23467} (cannot be {12568/23458} because R2C4 + R4C2 = [85] clashes with R4C456)
26a. 22(5) cage at R2C2 cannot be {12478}, here’s how
22(5) cage = {12478} => R3C1 = 6 (hidden single in N1), R4C1 = 4, R2C4 = 4, R4C2 = 8, R4C12 = [48] clashes with 11(3) cage at R5C1
26b. -> 22(5) cage at R2C2 = {12379/12469/13459/13468/13567/23467}
26c. 22(5) cage = {13468} => R1C3 + R3C1 = {79} (hidden pair in N1) => R3C1 = {79}, R4C1 = {13} => naked pair {13} in R4C13, locked for N4 => 11(3) cage at R5C1 (step 14) = {245}, locked for N4 => 4 of {13468} must be in R2C4 -> no 8 in R2C4
26d. 4 of {12469/23467} must be in R2C4 or R4C2
26da. R2C4 = 4
26db. R4C2 = 4 => no 4 in R4C1 => no 6 in R3C1 => 6 of {12469/23467} must be in N1 => no 6 in R2C4
26dc. 4 of {13468} must be in R2C4 (step 26c)
26e. -> no 6 in R2C4

27. Consider placements for 6 in N2
27aa. 6 in 20(3) cage at R1C5 = {569}, locked for C5 => 19(3) cage at R7C5 = {478}, locked for N8
27ab. 6 in R23C6 => R456C6 (step 10) = {479/578}, 7 locked for C6
27b. -> no 7 in R78C6

28. 22(5) cage at R2C2 (step 26b) = {12379/12469/13459/13468/13567/23467}
28a. Consider the combinations which contain 3
28aa. 7 or 9 of {12379} must be in R4C2 (cannot both be in N1 because of clash with R1C3), 5 of {13459/13567} must be in R4C2, 8 of {13468} must be in R4C2
28ab. 4 of {23467} must be in R2C4 or R4C2
28abi. R2C4 = 4 => R5C4 = 6, R4C456 (step 12b) = {259}, locked for R4, no 9 in R4C1 => no 1 in R3C1 => R3C3 = 1 (hidden single in N1) => R4C3 = 3 => no 3 in R4C2
28abii. R4C2 = 4
28b. -> no 3 in R4C2

29. 22(5) cage at R2C2 (step 26b) = {12379/12469/13459/13468/13567/23467} cannot be {12379}, here’s how
22(5) cage = {12379} => R3C1 = 6 (hidden single in N1), R4C1 = 4, R1C2 = 4 (hidden single in N1), 11(3) cage at R5C1 (step 14) = {128}, locked for N4 => R4C3 = 3, R3C34 = {12}, R3C2 = 3 (hidden single in R3), R2C4 = {12}, naked pair {12} in R23C4, locked for N2 => R1C6 = 3, R1C7 = 4 clashes with R1C2
29a. -> 22(5) cage at R2C2 = {12469/13459/13468/13567/23467}

30. 22(5) cage at R2C2 (step 29a) = {12469/13459/13468/13567/23467} cannot be {13459}, here’s how
22(5) cage = {13459} => R3C1 = 6 (hidden single in N1), R4C1 = 4, 11(3) cage at R5C1 (step 14) = {128}, locked for N4 => R4C3 = 3, R3C3 = 2 (hidden single in N1), R3C4 = 1, R1C3 = 7 (hidden single in N1), R1C4 = 9, 20(3) cage in N2 (step 4) = {578} => R1C7 = 6 (hidden single in R1), R1C6 = 1 clashes with R3C4
30a. -> 22(5) cage at R2C2 = {12469/13468/13567/23467}

31. 22(5) cage at R2C2 (step 30a) = {12469/13468/13567/23467} cannot be {13567}, here’s how
22(5) = {13567} => R4C2 = 5, 11(3) cage at R5C1 (step 14) = {128}, locked for N4 => R4C3 = 3, R3C3 = 2 (hidden single in N1), R3C4 = 1, R2C4 = 3, R3C1 = 3 (hidden single in N1), R1C3 = 9 (hidden single in N1), R1C4 = 7, 20(3) cage in N2 (step 4) = {569}, locked for N2, R23C6 = {48} (hidden pair in N2), locked for C6 => R6C6 = 5, R4C456 (step 12b) = {268} => R4C4 = [826], R5C4 = 4, R6C4 = 7 (step 9) clashes with R1C4
31a. -> 22(5) cage at R2C2 = {12469/13468/23467}, no 5

32. 22(5) cage at R2C2 (step 31a) = {12469/13468/23467}
32a. 7 of {23467} cannot be in R4C2, here’s how
R4C2 = 7 => R1C3 + R3C1 = {79} (hidden pair in N1) => R3C3 = 1 (hidden single in N1), R4C3 = 3 => no 3,7 in R46C1 => no {37} in R34C1 or R67C1 => cannot place 3,7 in C1
32b. 9 of {12469} cannot be in R4C2, here’s how
R4C2 = 9 => R4C456 (step 12b) = {268}, R2C4 = 4, R5C4 = 6, clashes with R4C456
32c. 1 cannot be in R4C2, here’s how
32ca. R4C2 = 1 of {12469} => 11(3) cage at R5C1 (step 14) = {245}, 8 in N4 only in R6C23, R2C4 = 4 => R456C4 (step 9) = {568} = [568] => R6C4 = 8 clashes with R6C23
32cb. 8 of {13468} must be in R4C2 (step 26c)
32d. 6 cannot be in R4C2, here’s how
32da. R4C2 = 6 of {12469} => R3C1 = 6 (hidden single in N1), R4C1 = 4, R3C3 = 3 (hidden single in N1), R4C3 = 1 => R4C13 = [41] clashes with 11(3) cage at R5C1
32db. 8 of {13468} must be in R4C2 (step 26c)
32dc. R4C2 = 6 of {23467} => R2C4 = 4, R4C456 (step 12b) = {259}, locked for R4, R3C1 = 6 (hidden single in N1), R4C1 = 4, R1C3 = 9 (hidden single in N1), R1C4 = 7, 20(3) cage in N2 (step 4) = {569}, locked for N2 => R3C6 = 8 => R34C7 = 13 but {49} blocked by R4C1 + R4C456 and {67} blocked by R3C1 + R4C2 both 6
32e. -> R4C2 = {48}, no 1,6,7,9

33. Killer pair 4,8 in R4C2 and 11(3) cage at R5C1, locked for N4, clean-up: no 6 in R3C1, no 6 in R7C1
33a. 6 in N4 only in R6C123, locked for R6, clean-up: no 3 in R7C9

34. Consider placements for R4C2
R4C2 = 4 => 11(3) cage at R5C1 = {128}, locked for N4 => R4C3 = 3
R4C2 = 8 => 22(5) cage at R2C2 (step 31a) = {13468} => R1C3 + R3C1 = {79} (hidden pair in N1) => R4C1 = {13} => naked pair {13} in R4C13
-> 3 must be in R4C13, locked for R4 and N4, clean-up: no 7 in R7C1

35. R6C456 (step 12c) = {148} (cannot be {157} which clashes with R6C123, ALS block) -> R6C46 = {48}, locked for R6 and N5 -> R5C4 = 6, naked pair {59} in R4C46, locked for R4 and N5 -> R5C6 = 7, clean-up: no 1 in R3C1, no 4,8 in R3C9, no 1,5 in R7C9, no 3 in R9C3
35a. 9 in R5 only in R5C789, locked for N6

36. R5C9 = R19C8 + 3 (step 16)
36a. Min R5C9 = 8 -> min R19C8 = 5, no 1 in R9C8

37. 21(3) cage at R3C6 (step 5) = {489/678}
37a. 9 of {489} must be in R3C7 -> no 4 in R3C7

38. 12(3) cage at R6C3 = {129/156/237/246/345} (cannot be {138} because no 1,3,8 in R6C3, cannot be {147} = [741] which clashes with R67C1, cage blocker), no 8
38a. 7 of {237} must be in R6C3 -> no 7 in R7C34

39. 22(5) cage at R2C2 (step 31a) = {12469/13468/23467}
39a. Consider placement for R4C2
39aa. R4C2 = 4 => 22(5) cage at R2C2 = {12469/23467}, killer pair 7,9 in R1C3 and 22(5) cage for N1 => R3C1 = 3
39ab. R4C2 = 8 => 22(5) cage at R2C2 = {13468} => R3C3 = 2 (hidden single in N1)
39b. -> no 3 in R3C3

[Looks like I need to use some more contradiction moves.]
40. 22(5) cage at R2C2 (step 31a) = {12469/13468/23467} cannot be {12469}, here’s how
22(5) cage = {12469}, 9 locked for N1 => R1C3 = 7, R1C4 = 9 => 20(3) cage in N2 (step 4) = {578} => R1C5 = {58}, R3C1 = 3 (hidden single in N1) => naked triple {123} in R3C134, locked for R3 => R3C2 = {69} => 1,2 of {12469} must be in R2C234, locked for R2 => R2C9 = 3, R1C6 = 3 (hidden single in R1), R1C7 = 4 => R1C57 = {58}4 clashes with R1C12, ALS block
40a. -> 22(5) cage at R2C2 = {13468/23467}, no 9

[I looked at placements for 6 in R4 but couldn’t quite make anything from this work. 6 in R4C7 or R4C9 forces 7 in R3C7 or R3C9 but I couldn’t get anything from 6 in R4C8 which can still have 7 in R3C7.]

41. 26(5) cage at R2C6 = {12689/13589/13679/14579/14678/24569/24578/34568} (cannot be {23489/23579/23678} because 2,3 only in R2C6)
41a. 26(5) cage cannot be {12689}, here’s how
26(5) cage = {12689} => R2C6 = 2, R1C7 = 4 (hidden single in N3), R1C6 = 3, R3C9 = 5 (hidden single in N3), R4C9 = 8, R4C2 = 4, R3C4 = 1, R2C4 = 4 clashes with R4C2
41b. 26(5) cage cannot be {13589/13679}, here’s how
26(5) cage = {13589/13679} => R2C6 = 3, R1C7 = 4 (hidden single in N3), R1C6 = 3 clashes with R2C6
41c. 26(5) cage cannot be {14579}, here’s how
Either 26(5) = {14579} with R2C6 + R4C8 = {14}, 5,7,9 locked for N3 => R3C9 = 6, R4C9 = 7, R3C7 = 8 (hidden single in N3) => 21(3) cage at R3C6 (step 5) = {678} => R4C7 = 7 clashes with R4C9
or 26(5) = {14579} with R4C8 = 7, R2C6 = 1, 4,5,9 locked for N3 => R1C7 = 6, R1C6 = 1 clashes with R2C6
41d. 26(5) cage cannot be {34568}, here’s how
26(5) cage = {34568} => R2C6 = 3 => no 3 in R1C6 => no 4 in R1C7 => 4,5,8 must be in N3 (cannot be 4,5,6 or 5,6,8 which would clash with R1C7), locked for N3, R4C8 = 6, R1C7 = 6, R3C9 = 9 (R34C9 cannot be [76] which clashes with R4C8), R4C9 = 4, R4C2 = 8, R3C7 = 7 => 21(3) cage at R3C6 (step 5) = {678} => R4C7 = {68} clashes with R4C28
41e. -> 26(5) cage at R2C6 = {14678/24569/24578}, no 3

42. 26(5) cage at R2C6 (step 41e) = {14678/24569/24578}
42a. Consider combinations for the 26(5) cage
42aa. 26(5) cage = {14678/24578} => 9 in N3 only in R3C79
42aai. R3C7 = 9 => 21(3) cage at R3C6 (step 5) = {489} => R4C7 = {48}, naked pair {48} in R4C27, locked for R4
42aaii. R3C9 = 9 => R4C9 = 4 => R4C2 = 8
42ab. 26(5) cage = {24569} doesn’t contain 8
42b. -> no 8 in R4C8

43. 26(5) cage at R2C6 (step 41e) = {14678/24569/24578}
43a. Consider combinations for the 26(5) cage
43aa. 7 of 26(5) cage = {14678} must be in N3 or in R4C8
43aai. 7 of {14678} in N3 => no 7 in R3C9 => no 6 in R4C9, 21(3) cage at R3C6 (step 5) = {489/678} => R4C7 = {48} or R4C7 = 7 => R4C8 = 6 (hidden single in R4) => no 1 in R4C8
43aaii. 7 of {14678} in R4C8 => no 1 in R4C8
43ab. 26(5) cage = {24569/24578} don’t contain 1
43b. -> no 1 in R4C8

44. 1 in N6 only in 18(3) cage at R5C7 (step 14a) = {189} (only remaining combination), locked for R5 and N6, clean-up: no 5 in R3C9
44a. Naked triple {245} in 11(3) cage at R5C1, locked for N4 -> R4C2 = 8
44b. Naked triple {467} in R4C789, locked for R4 and N6, clean-up: no 3 in R3C1, no 2 in R7C9

45. Naked pair {79} in R1C3 + R3C1, locked for N1
45a. 8 in N1 only in R12C1, locked for C1, clean-up: no 3 in R9C2 (step 23c)

46. 22(5) cage at R2C2 (step 31a) = {13468} (only remaining combination), no 2 -> R2C4 = 4, R6C46 = [84], R4C4 = 5 (step 9), R6C6 = 9, clean-up: no 1,4 in R9C3
46a. R3C3 = 2 (hidden single in N1), clean-up: no 7 in R9C4
46b. 4 in N1 only in R1C12, locked for R1, clean-up: no 3 in R1C6

47. R3C4 = 3 (hidden single in N2), R4C3 = 1, R4C1 = 3, R3C1 = 7, R1C3 = 9, R1C4 = 7, clean-up: no 8 in 20(3) cage in N2 (step 4), no 6 in R4C9, no 6 in R9C3

48. Naked triple {569} in 20(3) cage in N2, locked for C5 and N2 => R3C6 = 8

49. R8C4 = 9 (hidden single in C4), R6C1 = 9 (hidden single in R6), R7C1 = 1, R7C4 = 2, R9C4 = 1, R9C3 = 8, clean-up: no 6 in R9C6, no 5,6 in R9C7

50. R9C2 = 9 (hidden single in N7) -> 17(3) cage (step 23c) = {269} (only remaining combination) -> R89C1 = {26}, locked for C1 and N7

51. Naked pair {56} in R1C57, locked for R1 -> R1C2 = 4, R1C1 = 8, R2C1 = 5, R5C1 = 4, R5C3 = 5, R5C2 = 2

52. 21(3) cage at R3C6 (step 5) = {489/678}
52a. 7 of {678} must be in R4C7 -> no 6 in R4C7

53. R4C8 = 6 (hidden single in R4)

54. Naked pair {69} in R3C79, locked for R3 and N3 -> R3C2 = 1, R3C5 = 5, R1C5 = 6, R2C5 = 9, R1C7 = 5, R1C6 = 2, R2C6 = 1, R3C8 = 4

55. R2C9 = 2 (hidden single in R2), clean-up: no 7 in R7C9

56. Killer pair 4,6 in R34C9 and R7C9, locked for C9

57. 14(3) cage in N9 = {239/257} (cannot be {158} because 1,8 only in R8C9), no 1,8 -> R9C8 = 2, R9C7 = 4, R9C6 = 3, R9C5 = 7, R9C9 = 5, R8C9 = 7, R6C9 = 3, R7C9 = 6, R7C6 = 5, R6C7 = 2, R7C7 = 9 (cage sum)

and the rest is naked singles.


Last edited by Ed on Sat Jun 14, 2008 9:01 am, edited 1 time in total.

Top
 Profile  
Reply with quote  
PostPosted: Mon Jun 09, 2008 12:41 am 
Offline
Grand Master
Grand Master

Joined: Wed Apr 16, 2008 1:16 am
Posts: 1044
Location: Sydney, Australia
A New One (aka nd#10) by nd (Dec 06)
Puzzle pic:
Image
Code: Select, Copy & Paste into solver:
3x3::k:2816:3073:5378:5378:2820:6149:5126:5126:5126:2816:3073:4875:5378:2820:6149:6149:5126:6161:4875:4875:4875:2325:2325:2325:6149:5126:6161:2331:2331:4875:8990:8990:8990:8990:8990:6161:2331:8485:8485:8990:8485:8485:8746:8746:6161:7469:7469:8485:8485:8485:4914:8746:8746:8746:7469:7469:3128:3128:3128:4914:8746:4413:4413:5439:5439:5439:3650:3128:4914:4914:4413:4423:5439:5439:3650:3650:3660:3660:3660:4423:4423:
Solution:
+-------+-------+-------+
| 6 3 8 | 7 9 4 | 5 2 1 |
| 5 9 1 | 6 2 8 | 3 4 7 |
| 7 4 2 | 1 5 3 | 9 8 6 |
+-------+-------+-------+
| 3 2 5 | 9 4 6 | 7 1 8 |
| 4 1 9 | 8 7 2 | 6 5 3 |
| 8 7 6 | 5 3 1 | 4 9 2 |
+-------+-------+-------+
| 9 5 3 | 2 1 7 | 8 6 4 |
| 1 8 4 | 3 6 9 | 2 7 5 |
| 2 6 7 | 4 8 5 | 1 3 9 |
+-------+-------+-------+
Quote:
nd, in lead-in: It's plenty hard
Nasenbaer: It' all going veeeeerrrry slow, not much of a progress
sudokuEd: Finally worked out how to crack this nut. Used my favourite blunt instrument
Andrew: a tough challenge! Really neat key moves
tag solution: Nasenbaer, sudokuEd & Andrew
nd's blog: edit: unfortunately, is no longer available
Andrew (in 2012): After nd#9 (aka Night of the Living Sudoku), I moved on to nd#10 for the first time apart from a minor role in the "tag". This time I found it a lot easier, and also significantly easier than nd#9.
Rating: Hard 1.5.
tag solution:
This looks like a fantastically difficult one, thanks nd.

I've talked to sudokued and we agreed to do this nice killer in a joined effort. We invite all of you to participate. I'll start the whole thing with the obvious things and as explicite as I can.

Walkthrough nd10 "easy"

1. N1 : 12(2) = {39|48|57} -> no 1,2,6
2. N1 : 11(2) = {29|38|47|56} -> no 1
3. N12 : 21(3) = {489|579|678} -> no 1,2,3
4. N2 : 11(2) = {29|38|47|56} -> no 1
5. N2 : 9(3) = {126|135|234} -> no 7,8,9
6. N4 : 9(3) = {126|135|234} -> no 7,8,9
7. N47 : 29(4) = {5789} -> no 1,2,3,4,6
8. N78 : 12(4) = 12{36|45} -> no 7,8,9 -> 1,2 locked -> no 1,2 possible in r7c6

9. N45 : 33(7) = 126{3489|3579|4578}
10. 45 on N9 (3 innies) : r789c7 = 11(3) = {128|137|146|236|245} -> no 9
11. N14 : 19(5) : must have 1, locked in N1 -> no 1 in r4c3
12. 45 on N1 (1 innie, 1 outie) : r4c3 + 3 = r1c3
12a. r1c3 : min: 5, max: 9
12b. r4c3 : min: 2, max: 6
13. 45 on N2 (2 innies, 1 outie) : r1c3 + 4 = r12c6
13a. r1c3 : min: 5, max: 9
13b. r12c6 : min: 9, max: 13
14. 45 on r12 : r2c39 + 9 = r3c78
14a. r2c39 : min: 3, max: 8 -> no 8,9
14b. r3c78 : min: 12, max: 17 -> no 1,2
15. 45 on r123 (1 outie, 2 innies) : r4c3 + 8 = r23c9
15a. r4c3 : min: 2, max: 6
15b. r23c9 : min: 10, max: 14 -> max. r2c9 = 7 -> min r3c9 = 3 -> no 1,2 in r3c9 (edited, thanks Ed)
16. 45 on r1234 : r5c149 = 15(3)

Edit 1: next addition:

17. N69 : 34(6) : must have 9 -> locked in N6 for 34(6) (see also step 10)
18. N56 : 35(6) = 89{1467|2367|2457|3456} -> 9 locked in r4c456 for N5
19. 45 on r123 (3 outies) : r4c3 + r45c9 = 16 (doubles possible!)
19a. r4c3 : min: 2, max: 6
19b. r45c9 : min: 10, max: 14 -> no 1

Edit 2: one more:

20. 45 on r89 (4 innies) : r8c5678 = 24(4)
21. 45 on r789 (3 outies, 1 innie) : r7c7 + 8 = r6c126
21a. r7c7 : min: 5, max: 8 -> no 1,2,3,4
21b. r6c126 : min: 13, max: 16 -> no 5,6,7,8 in r6c6

Edit 3: I think I found some good moves:

22. n9 : (step 10) 11(3) has only one of {5678} -> locked in r7c7 -> r89c7 = {1234}
23. N589 : 19(4) : r6c6 and r8c7 both have {1234} -> r78c6 = {56789} -> no 1,2,3,4 -> combination {1567} for 19(4) not possible
24. r7 : 5,6,7,8,9 are in r7c1267 plus one of them has to be in r7c89 for 17(3) -> no 5,6 in r7c345 possible -> r8c5 = {56} -> no 1,2 in r7c89 (step 8) -> a 3 or a 4 is in r7c89
25. N9 : 17(3) in r78 has at most one of {56789} in r7c89 -> r8c8 = {56789}
26. r8c5 = {56} -> 11(2) in c5 can't have 5,6
27. r8c5 = {56} -> 14(3) in N89 : combination {356} not possible -> one of {789} is in r9c56
28. 45 on N7 (2 innies, 2 outies) : r79c3 + 5 = r6c12
28a. r6c12 : min: 12, max: 17
28b. r79c3 : min: 7, max: 12 -> no 1,2 in r9c3
29. 45 on c12 (3 innies, 1 outie) : r8c3 + 8 = r3c12 + r5c2 (doubles possible!)
29a. r8c3 : min: 1, max: 9
29b. r3c12 + r5c2 : min: 9, max: 17
30. 45 on c12 (1 innie, 4 outies) : r5c2 + 11 = r2348c3
30a. r5c2 : min: 1, max: 9
30b. r2348c3 : min: 12, max: 20

Edit 4: numbering corrected, thanks Andrew.

In r3 might be something going on with 19(4) an 9(3) and the numbers 1,2,3 but now I'm too tired to think because it's 1.30

So, this is how far I got (still not very much):


.-----------.-----------.-----------------------.-----------.-----------.-----------------------------------.
| 23456789 | 345789 | 56789 456789 | 234789 | 123456789 | 123456789 123456789 123456789 |
| | :-----------. | | '-----------. .-----------:
| 23456789 | 345789 | 1234567 | 456789 | 234789 | 123456789 123456789 | 123456789 | 1234567 |
:-----------'-----------' :-----------'-----------'-----------. | | |
| 123456789 123456789 123456789 | 123456 123456 123456 | 3456789 | 3456789 | 123456789 |
:-----------------------. :-----------------------------------'-----------'-----------: |
| 123456 123456 | 23456 | 123456789 123456789 123456789 12345678 12345678 | 2345678 |
| .-----------'-----------: .-----------------------.-----------------------: |
| 123456 | 123456789 123456789 | 12345678 | 12345678 12345678 | 123456789 123456789 | 2345678 |
:-----------'-----------. '-----------' .-----------: '-----------:
| 5789 5789 | 123456789 12345678 12345678 | 1234 | 123456789 123456789 123456789 |
| :-----------------------------------: | .-----------------------:
| 5789 5789 | 1234 1234 1234 | 56789 | 5678 | 3456789 3456789 |
:-----------------------'-----------.-----------. | '-----------: .-----------:
| 123456789 123456789 123456789 | 123456789 | 56 | 56789 1234 | 56789 | 123456789 |
| .-----------' :-----------'-----------------------+-----------' |
| 123456789 123456789 | 3456789 123456789 | 123456789 123456789 1234 | 123456789 123456789 |
'-----------------------'-----------------------'-----------------------------------'-----------------------'




yow - this one is a typical nd Killer. Havn't found the hidden key(s) yet. Thanks for your efforts too Peter. Unfortunately, I can't add too much at this point. But its been fun trying things while listening to James Hirschfeld's tromboning. Hopefully a good sleep will soften up the brain clog.

Just a few more steps to add.

Quote:
15. 45 on r123 (1 outie, 2 innies) : r4c3 + 8 = r23c9
15a. r4c3 : min: 2, max: 6
15b. r23c9 : min: 10, max: 14

add to 15b. max. r2c9 = 7 -> min r3c9 = 3

31. "45" r789 -> r6c6 + 21 = r7c127.
a. max r7c127 = 24 -> max r6c6 = 3 (no 4)
-> r7c127 = 22-24
= 22 = {89[5]/79[6]/59[8]}
= 23 = {89[6]}
= 24 = {89[7]}
->9 locked in r7c12 n7, r7 and also no 9 in r6c12

32. 9 in n4 locked in 33(7) = 12369{48/57}

Not much at all. Sad Tomorrow will have a look at r1234 outies combined with the 33(7):n456. Here is the marks only pic for this spot which can be pasted into Sudocue.

.-----------.-----------.-----------------------.-----------.-----------.-----------------------------------.
| 23456789 | 345789 | 56789 456789 | 234789 | 123456789 | 123456789 123456789 123456789 |
| | :-----------. | | '-----------. .-----------:
| 23456789 | 345789 | 1234567 | 456789 | 234789 | 123456789 123456789 | 123456789 | 1234567 |
:-----------'-----------' :-----------'-----------'-----------. | | |
| 123456789 123456789 123456789 | 123456 123456 123456 | 3456789 | 3456789 | 3456789 |
:-----------------------. :-----------------------------------'-----------'-----------: |
| 123456 123456 | 23456 | 123456789 123456789 123456789 12345678 12345678 | 2345678 |
| .-----------'-----------: .-----------------------.-----------------------: |
| 123456 | 123456789 123456789 | 12345678 | 12345678 12345678 | 123456789 123456789 | 2345678 |
:-----------'-----------. '-----------' .-----------: '-----------:
| 578 578 | 123456789 12345678 12345678 | 123 | 123456789 123456789 123456789 |
| :-----------------------------------: | .-----------------------:
| 5789 5789 | 1234 1234 1234 | 5678 | 5678 | 345678 345678 |
:-----------------------'-----------.-----------. | '-----------: .-----------:
| 12345678 12345678 12345678 | 123456789 | 56 | 56789 1234 | 56789 | 123456789 |
| .-----------' :-----------'-----------------------+-----------' |
| 12345678 12345678 | 345678 123456789 | 123456789 123456789 1234 | 123456789 123456789 |
'-----------------------'-----------------------'-----------------------------------'-----------------------'


Just one step for now; not as useful as I had first thought because of the doubles possibility but still provides a elimination. I'll look at this puzzle again later and try to find some more.

33. 45 on r12 (5 outies, 1 innies) r2c3 + 33 = r3c789 + r45c9, min r3c789 + r45c9 = 34 (doubles possible, for example 7,8 in r3c78 and in r45c9 so doesn't necessarily contain 9)
33a. Max r3c789 + r45c9 = 39 {78789} -> max r2c3 = 6, no 7
33b. Min r3c789 + r45c9 = 34, max r3c789 = 24, min r45c9 = 10
33c. Min r3c789 + r45c9 = 34, max r345c9 = 24, min r3c78 = 10

I think we will need every bit of information, so I do this:

34. step 31 effects step 28: r6c12 : max: 15 -> r79c3 : max: 10
35. (step 20) r8 : 24(4) : {3489} not possible
36. (step 15) r5 : 15(3) : {159|249} not possible
37. 45 on N2 (3 outies) : r1c3 + r23c7 = 20(3) (doubles possible) -> no 1 in r2c7

Edit 1: Veeerrrry slow going. So I'll show every thought I have, even those with no immediate progress.

38. 45 on c9 (1 outie, 3 innies) : r9c8 + 4 = r167c9
38a. r167c9 : min: 6, max: 13
38b. r9c8 : min: 2, max: 9 -> no 1
39. 45 on c9 (3 outies, 2 innies) : r16c9 + 13 = r789c8
39a. r16c9 : min: 3, max: 10
39b. r789c8 : min: 16, max: 23
The following step 40 is actually unnecessary because step 41 is more precise but I invested too much thought in it so it will stay Wink
40. 45 on N78 (2 innies, 3 outies) : r6c6 + r89c7 + 10 = r7c12 (doubles possible)
40a. r6c6 + r89c7 : min: 4, max: 7
40b. r7c12 : min: 14, max: 17
41. 45 on N78 (5 outies) : r6c126 + r89c7 = 19
41a. r6c12 = 12 {57}, 13 {58} or 15 {78}
41b. r6c6 + r89c7 = 4, 6 or 7 (doubles possible)
= 4 = [121]
= 6 = [141]|[1]{23}|[2]{13}|[3]{12}
= 7 = [1]{24}|[232]|[2]{14}|[313]
42. 45 on N78 (4 innies, 1 outie) : r9c7 + 29 = r8c6 + r7c126
42a. r9c7 : min: 1, max: 4
42b. r8c6 + r7c126 : min: 30, max: 33 -> max. r7c127 = 24 -> min. r8c6 = 6

Edit 2: Found a good one, how could I have overlooked it?!? First cell is filled! Breakthrough!?!

43. 45 on c89 (4 outies, 1 innie) : r4c8 + 22 = r1567c7
43a. r4c8 : min: 1, max: 8
43b. r1567c7 : min: 23, max: 30
44. N2 : 9(3) : {234} not possible, one of them is needed in 11(2) -> no 4 in 9(3) -> 1 locked in 9(3) for N2 and r3 -> single in N1 : r2c3 = 1

Peter

Beat me by one minute Peter. Unbelievable that we found the same move at the same time - after how many hours???!

45. 1 in n3 locked in 20(5) -> {23456} lost
45a. 1 in n7 locked in 21(5) -> {23457} lost
45b. 1 required in 33(7) n45 either in n5 or r5c2 -> no 1 in r5c4

One more before I hit the sack (it's already 2 am, the training for tonight isn't going too well Wink )

Addition to 45: must have exactly one of {789} (might be useful); also must also have two of {234} and one of {56} (thanks Andrew)

46. N8 : 1 locked in r7c45 for r7 and N8

Edit: Step 47 was missing, sent it to Ed to check it tonight before I went to bed, wasn't posted yet.

47. 45 on N4578 (4 outies, 1 innie) : r4c3 + 6 = r489c7 + r4c8 (doubles possible)
47a. r4c3 : min: 2, max: 6
47b: r489c7 + r4c8 : min: 8, max: 12 -> min. r489c7 = 6 -> max. r4c8 = 6 -> no 7,8 in r4c8

Finally worked out how to crack this nut. Used my favourite blunt instrument - contradictions between nonets. Anyone find a subtle way to progress?

Thanks again nd! And really enjoyed working with Peter, Andrew and James H.

Now, back to Assassin 31 - totally defeated at the first attempt Very Happy

48. 4 in r4c3 -> r3c123 = {239/257/356} but these are all blocked by 9(3) in r3 -> no 4 in r4c3 -> no 7 in r1c3
[edit-deleted invalid 48a]

49. "45" n1:r4c3 + 3 = r1c3
2 in r4c3 -> r1c3 = 5 -> r3c123 = {349} ({358/457} blocked by r1c3;{367} blocked by 9(3):r3)
3 in r4c3 -> r1c3 = 6 -> r3c123 = {249} ({267/456} blocked by r1c3; {258/456} blocked by 9(3):r3)
5 in r4c3 -> r1c3 = 8 -> r3c123 = {247} ({238} blocked by r1c3; {346} blocked by 9(3):r3)
6 in r4c3 -> r1c3 = 9 -> r3c123 = {345} ({237} blocked by 9(3):r3)

50 . In summary r3c123 = {349/249/247/345} (no 6,8) = 4{39/29/27/35}
50a. 4 locked for n1, r3

51.12(2)n1 = {39/57} = [3/5, 7/9...]
-> from step 50, {345} is blocked from r3c123 -> no 6 in r4c3 (step 49), no 9 in r1c3, no 5 in r3c123

52. r3c123 now 4{39/29/27} = [7/9..] -> Killer pair with 12(2) -> 7 and 9 locked for n1
52a. 11(2)n1 = {38/56}

53. 2 locked in n1 in 19(5) -> 2 locked for r3 and no 2 in r4c3, no 5 in r1c3

54. 9(3)r3 now {135} only: locked for n2, r3

55.11(2):n2 = {29/47} (no 8) = [4/9..]

56. r1c3 + 4 = r12c6 -> r12c6 = 10,12
r1c3 = 6 -> r12c4 = {78} -> r12c6 = 10 = [46] [edit: note, [64] not possible since 6 already in r1c3 in this hypothetical]
r1c3 = 8 -> r12c4 = {67} ({49} blocked by 11(2) step 55) -> r12c6 = 12 = [48] [edit: note, [84] not possible since 8 already in r1c3 in this hypothetical]
-> r1c6 = 4, r2c6 = {68}, r12c4 = {78/67} = 7{6/8} -> 7 locked for n2, c4,11(2) = {29}:locked for c5

57. rest of 24{4}:n23 now 20(3) = [659/839/857] -> r23c7 = [59/39/57], r2c7 = 35, r3c7 = {79}

58. Killer pair between r3c123 & r3c7 for {79}:locked for r3

59. r3c89 = {68} locked for r3, n3

and on till the end! Yippee.
Walkthrough by nd:
I'm typing this quickly as I have to get to bed (up tomorrow for a plane flight) so hopefully it's not got any errors--I'll doublecheck once I get where I'm going (Halifax) & have access to a computer.

1. 29(4) cage in N47 = {5789}. 45 rule on N789 => R7C127 = R6C6 + 21 => R6C6 = {123}, R7C127 = {5..9}, with 9 locked in those cells in R7. 45 rule on N9 => R789C7 = 11(3) => R7C7 = {5678}, R89C7 = {1234}, and the 9 is locked in R7C12 within N7, R7 and the 29(4) cage.

2. R78C6 must contain {5..9} (because of the {1..4} in R6C6 and R8C7). R7C89 must contain one cell of value 5 or greater (because otherwise the max of R7C89 = 3 + 4 which is impossible in a 17(3) cage). So in R7 we have a hidden quint on {56789} in R7C1267 + one of R7C89. Therefore R7C345 = {1234}. Since 12(4) must contain {56}, R8C5 = {56} and {12} are locked in R7C345 within R7.

3. 11(2) cage in N2 = {29|38|47} => 9(3) cage in N2 cannot be {234} => it is {1(26|35)}. R2C3 = 1 (only spot for it now in N1). 45 rule on R3 => R4C3 = {2..6}, R3C789 = 20..24.

4. In N4, 9 must be in the three cells of the 33(7) cage => the 33(7) cage = {12369(48|57)}, i.e. it must contain {123}. Note that the {123} in R6C6 forces one candidate from {123} to be in the three cells R5C23+R6C3 within N4. The 9(3) cage in N4 must also have two candidates from {123}, so in conjunction with the 3 cells of the 33(7) there is a hidden triplet on {123} in N4! => R4C3 = {456}.

5. This in turn means (by 45 rule on R3) that R3C789 = 22..24, i.e. {5..9}. Therefore the 4 in R3 is locked in R3C123 => R4C3 = {56}, R12C2 = {39|57}. 45 rule on N1 => R1C3 = {89}.

6. If R4C3 = 5 then R3C123 = {247} (only possible combo--{346} would conflict with the 9(3) cage in N2). If R4C3 = 6 then R3C123 = {345} (only possible combo). => R3C123 must contain either 5 or 7 => R12C2 = {39}, R1C3 = 8, R12C1 = {56}, R1C123 = {247}, R4C3 = 5, R3C456 = {135}, R3C789 = {689}, R6C12 = {78}, R7C12 = [95].

There's still more to do but it's straightforward mop-up from here on out so I'll leave the rest to you...... -- JC Godart's just posted a walkthrough on DJApe's site which is substantially the same, though he uses a slightly different version of the key hidden-subset move (he uses the split-off 24(4) cage in R8 to narrow things down to a hidden pair of {34} in R7)
Walkthrough by Andrew (in 2012):
Prelims

a) R12C1 = {29/38/47/56}, no 1
b) R12C2 = {39/48/57}, no 1,2,6
c) R12C5 = {29/38/47/56}, no 1
d) 21(3) cage at R1C3 = {489/579/678}, no 1,2,3
e) 9(3) cage at R3C4 = {126/135/234}, no 7,8,9
f) 9(3) cage at R4C1 = {126/135/234}, no 7,8,9
g) 29(4) cage at R6C1 = {5789}
h) 12(4) cage at R7C3 = {1236/1245}, no 7,8,9

1. 12(4) cage at R7C3 = {1236/1245}, CPE no 1,2 in R7C6

2. 1 in R1 only in R1C6789, CPE no 1 in R23C7

3. 1 in N1 only in R2C3 + R3C123, locked for 19(5) cage at R2C3, no 1 in R4C3
3a. 45 rule on N1 1 innie R1C3 = 1 outie R4C3 + 3, no 4 in R1C3, no 7,8,9 in R4C3

4. 45 rule on N9 3 innies R789C7 = 11 = {128/137/146/236/245}, no 9

5. 34(6) cage at R5C7 must contain 9, locked for N6

6. 9 in R4 only in R4C456, locked for N5

7. 45 rule on R789 3 innies R7C127 = 1 outie R6C6 + 21
7a. Max R7C127 = 24 -> max R6C6 = 3
7b. Min R7C127 = 22, no 1,2,3,4 in R7C7
7c. R7C127 = 22,23,24 = {589/679/689/789}, 9 must be in R7C12, locked for R7, N7 and 29(4) cage at R6C1, no 9 in R6C12

8. R789C7 (step 4) = {128/137/146/236/245}
8a. R7C7 = {5678} -> no 5,6,7,8 in R89C7

9. 19(4) cage at R6C6 cannot contain more than two of 1,2,3,4, R6C6 = {123}, R8C7 = {1234} -> no 1,2,3,4 in R78C6

10. Hidden killer quad 1,2,3,4 in 12(4) cage at R7C3 and 17(3) cage at R7C8 for R7, 12(4) cage cannot contain more than three of 1,2,3,4, 17(3) cage only contains one of 1,2,3,4 -> 12(4) cage must contain three of 1,2,3,4 in R7 and 17(3) cage must contain the other one in R7 -> R7C345 = {1234}
10a. 12(4) cage contains one of 5,6 -> R8C5 = {56}
10b. 12(4) cage = {1236/1245}, 1,2 locked for R7
10c. 17(3) cage contains one of 3,4 in R7C89 = {359/368/458/467}, no 1,2
10d. One of 3,4 in R7C89 -> no 3,4 in R8C8
[And for completeness in N9, at this stage …]
10e. 17(3) cage at R8C9 = {179/269/278/359/467} (cannot be {368/458} which clash with 17(3) cage at R7C8)

11. R12C5 = {29/38/47} (cannot be {56} which clashes with R8C5), no 5,6

12. 9(3) cage at R3C4 = {126/135} (cannot be {234} which clashes with R12C5), no 4, 1 locked for R3 and N2

13. R2C3 = 1 (hidden single in N1)
13a. 1 in R7 only in R7C45, locked for N8

14. 9 in N4 only in 33(7) cage at R5C2 = {1234689/1235679}
14a. R6C6 “sees” all of 33(7) cage except for R5C23, R6C6 = {123}, 33(7) cage contains all of 1,2,3 -> one of 1,2,3 in 33(7) cage must be in R5C23
14b. Killer triple 1,2,3 in 9(3) cage at R4C1 and R5C23, locked for N4, clean-up: no 5,6 in R1C3 (step 3a)
14c. Two of 1,2,3 in 33(7) cage must be in N5, killer triple 1,2,3 in 33(7) cage and R6C6, locked for N5
[Or steps 14b and 14c can be considered to be
Double killer triple 1,2,3 in 9(3) cage at R4C1, 33(7) cage at R5C2 and R6C6, locked for N45.]

15. 19(5) cage at R2C3 = {12457/13456} (cannot be {12349/12358/12367} which clash with 9(3) cage at R3C4), no 8,9
15a. 6 of {13456} must be in R3C123 (R3C123 cannot be {345} which clashes with R12C2) -> no 6 in R4C3, clean-up: no 9 in R1C3 (step 3a)
15b. Killer pair 2,3 in 19(5) cage and 9(3) cage, locked for R3
15c. 8,9 in R3 only in R3C789, locked for N3
15d. 9 in C3 only in R56C3, locked for N4

16. 45 rule on N1 4 remaining innies R1C3 + R3C123 = 21 = {2478/3468} (cannot be {2568/3567} which clash with 9(3) cage at R3C4) -> R1C3 = 8, R4C3 = 5 (step 3a), R3C123 = {247/346}, 4 locked for R3 and N1, clean-up: no 3,7 in R12C1, no 3 in R2C5

17. R1C3 = 8 -> 21(3) cage at R1C3 = {489/678}, no 5
17a. R12C5 = [29/38/92] (cannot be {47} which clashes with 21(3) cage), no 4,7 in R12C5
17b. Killer pair 2,3 in R12C5 and 9(3) cage at R3C4, locked for N2

18. 9(3) cage at R4C1 = {126/234}, 2 locked for N4
18a. 33(7) cage at R5C2 (step 14) = {1234689/1235679}, 2 locked for N5

19. Naked pair {78} in R6C12, locked for R6, N4 and 29(4) cage at R6C1, no 7,8 in R7C12
19a. Naked pair {59} in R7C12, locked for R7 and N7

20. 45 rule on N2 2 remaining innies R12C6 = 12 = [48/57/75], no 6,9, no 4 in R2C6
20a. 45 rule on N2 2 remaining outies R23C7 = 12 = [39/48/57/75], no 2,6, no 8,9 in R2C7

21. 45 rule on R123 2 innies R23C9 = 13 = [49]/{58/67}, no 2,3,9 in R2C9
21a. 45 rule on R123 2 remaining outies R45C9 = 11 = {38/47}/[65], no 1,2, no 6 in R5C9

22. R7C127 (step 7c) contains 5,9 = {589} (only remaining combination) -> R7C7 = 8, clean-up: no 4 in R2C7 (step 20a)
22a. R7C127 = {589} = 22 -> R6C6 = 1 (step 7)

23. R789C7 = 11 (step 4), R7C7 = 8 -> R89C7 = 3 = [21]

24. R6C6 + R8C7 = [12] = 3 -> R78C6 = 16 = [79], clean-up: no 5 in R12C6 (step 20)

25. R12C6 = [48], R4C6 = 6, clean-up: no 9 in 21(3) cage at R1C3 (step 17), no 3 in R1C5
25a. Naked pair {67} in R12C4, locked for C4 and N2
25b. Naked pair {29} in R12C5, locked for C5 and N2
25c. Naked triple {135} in 9(3) cage at R3C4, locked for R3, clean-up: no 7 in R2C7 (step 20a)

26. 33(7) cage at R5C2 (step 14) = {1234689/1235679} -> R5C2 = 1, R56C3 = {69}, locked for C3 and N4
26a. 7,8 of 33(7) cage only in R5C5 -> R5C5 = {78}
26b. R4C8 = 1 (hidden single in R4)
26c. R1C9 = 1 (hidden single in R1)
26d. R8C1 = 1 (hidden single in C1)

27. 17(3) cage at R7C8 (step 10c) = {467} (only remaining combination) -> R8C8 = 7, R7C89 = {46}, locked for R7 and N9

28. 12(4) cage at R7C3 = {1236} (only remaining combination) -> R8C5 = 6

29. R9C7 = 1 -> R9C56 = 13 = [85], R5C5 = 7, R4C5 = 4

30. Naked pair {23} in R4C12, locked for R4 and N4 -> R5C1 = 4, R4C7 = 7, R4C9 = 8, R4C4 = 9, R5C9 = 3 (step 21a), R8C9 = 5, R9C89 = [39], clean-up: no 4 in R2C9 (step 21)

31. Naked pair {67} in R23C9, locked for C9 and N3 -> R7C89 = [64], R6C9 = 2, R3C7 = 9, R2C7 = 3 (step 20a), R1C78 = [52], R23C8 = [48], R12C5 = [92], R1C1 = 6, R2C1 = 5

32. 14(3) cage at R8C4 = {347} (only remaining combination) -> R9C3 = 7, R89C4 = [34]

and the rest is naked singles.

I'll rate my walkthrough for nd#10 at Hard 1.5. I used a large innie-outie difference, a hidden killer quad, triples based on 1,2,3 including a "sees all except" step and pairs based on 5,6.


A New One (aka nd#10) v2 by nd (Dec 06)
Puzzle pic:
Image
Code: Select, Copy & Paste into solver:
3x3::k:2817:8468:8468:8468:2820:6149:5126:5126:5126:2817:8468:4871:8468:2820:6149:6149:5126:6152:4871:4871:4871:2313:2313:2313:6149:5126:6152:2314:2314:4871:8971:8971:8971:8971:8971:6152:2314:8460:8460:8971:8460:8460:8717:8717:6152:7438:7438:8460:8460:8460:4879:8717:8717:8717:7438:7438:3088:3088:3088:4879:8717:4369:4369:5394:5394:5394:3603:3088:4879:4879:4369:4355:5394:5394:3603:3603:3586:3586:3586:4355:4355:
Solution:
+-------+-------+-------+
| 6 3 8 | 7 9 4 | 5 2 1 |
| 5 9 1 | 6 2 8 | 3 4 7 |
| 7 4 2 | 1 5 3 | 9 8 6 |
+-------+-------+-------+
| 3 2 5 | 9 4 6 | 7 1 8 |
| 4 1 9 | 8 7 2 | 6 5 3 |
| 8 7 6 | 5 3 1 | 4 9 2 |
+-------+-------+-------+
| 9 5 3 | 2 1 7 | 8 6 4 |
| 1 8 4 | 3 6 9 | 2 7 5 |
| 2 6 7 | 4 8 5 | 1 3 9 |
+-------+-------+-------+
Quote:
nd: [just made a minor revision to make it a little more elegant--broke a cage in two]
Note the revision above. However, if people are looking for a REAAAL challenge, then you can "undo" the revision to make a V2--the only difference between the two puzzles is that the 12(2) and 21(3) cages in N12 are joined to make a 33(5).
The new one is solvable via pure logic; the 33(5) version requires some T&E, I believe.

Andrew (in 2012): I've only just spotted that this variant had been posted on Ruud's site. Definitely the hardest of nd's puzzles although #9 came close the way I solved it.
This variant took away a useful "45" without giving anything useful instead.
My solving path used several forcing chains but didn't go as far as T&E.

Rating: Hard 1.75.

Forum "Revisit" thread on this puzzle here
Walkthrough by Andrew (in 2012):
When Nate posted #10 he said that he had made a minor revision to make the puzzle more elegant. “However if people are looking for a REAAAL challenge, then you can “undo” the revision to make a V2 – the only difference between the two puzzles is that the 12(2) and 21(3) cages are joined to make a 33(5). The new one is solvable by pure logic; the 33(5) version requires some T&E, I believe.”

I’ll start with as many of my previous steps as possible.

Prelims

a) R12C1 = {29/38/47/56}, no 1
b) R12C5 = {29/38/47/56}, no 1
c) 9(3) cage at R3C4 = {126/135/234}, no 7,8,9
d) 9(3) cage at R4C1 = {126/135/234}, no 7,8,9
e) 29(4) cage at R6C1 = {5789}
f) 12(4) cage at R7C3 = {1236/1245}, no 7,8,9
g) 33(5) cage at R1C2 = {36789/45789}, no 1,2

1. 12(4) cage at R7C3 = {1236/1245}, CPE no 1,2 in R7C6

2. 1 in R1 only in R1C6789, CPE no 1 in R23C7

3. 1 in N1 only in R2C3 + R3C123, locked for 19(5) cage at R2C3, no 1 in R4C3

4. 45 rule on N9 3 innies R789C7 = 11 = {128/137/146/236/245}, no 9

5. 34(6) cage at R5C7 must contain 9, locked for N6

6. 45 rule on R789 3 innies R7C127 = 1 outie R6C6 + 21
6a. Max R7C127 = 24 -> max R6C6 = 3
6b. Min R7C127 = 22, no 1,2,3,4 in R7C7
6c. R7C127 = 22,23,24 = {589/679/689/789}, 9 must be in R7C12, locked for R7, N7 and 29(4) cage at R6C1, no 9 in R6C12

7. R789C7 (step 4) = {128/137/146/236/245}
7a. R7C7 = {5678} -> no 5,6,7,8 in R89C7

8. 19(4) cage at R6C6 cannot contain more than two of 1,2,3,4, R6C6 = {123}, R8C7 = {1234} -> no 1,2,3,4 in R78C6

9. Hidden killer quad 1,2,3,4 in 12(4) cage at R7C3 and 17(3) cage at R7C8 for R7, 12(4) cage cannot contain more than three of 1,2,3,4, 17(3) cage only contains one of 1,2,3,4 -> 12(4) cage must contain three of 1,2,3,4 in R7 and 17(3) cage must contain the other one in R7 -> R7C345 = {1234}
9a. 12(4) cage contains one of 5,6 -> R8C5 = {56}
9b. 12(4) cage = {1236/1245}, 1,2 locked for R7
9c. 17(3) cage contains one of 3,4 in R7C89 = {359/368/458/467}, no 1,2
9d. One of 3,4 in R7C89 -> no 3,4 in R8C8
[And for completeness in N9, at this stage …]
9e. 17(3) cage at R8C9 = {179/269/278/359/467} (cannot be {368/458} which clash with 17(3) cage at R7C8)

10. R12C5 = {29/38/47} (cannot be {56} which clashes with R8C5), no 5,6

11. 9(3) cage at R3C4 = {126/135} (cannot be {234} which clashes with R12C5), no 4, 1 locked for R3 and N2

12. R2C3 = 1 (hidden single in N1)
12a. 1 in R7 only in R7C45, locked for N8

[Now a modified version of one of my original steps, to allow me to use some more of my original steps.]
13. 19(5) cage at R2C3 = {12349/12358/12367/12457/13456}
13a. 2 or 3 of {12349/12358} must be in R4C3 (R3C123 cannot contain both of 2,3 which would clash with 9(3) cage at R4C3) -> no 8,9 in R4C3

14. 9 in R4 only in R4C456, locked for N5
14a. 8 in N4 only in R5C23 + R6C123, CPE no 8 in R6C45

15. 9 in N4 only in 33(7) cage at R5C2 = {1234689/1235679}
15a. R6C6 “sees” all of 33(7) cage except for R5C23, R6C6 = {123}, 33(7) cage contains all of 1,2,3 -> one of 1,2,3 in 33(7) cage must be in R5C23
15b. Killer triple 1,2,3 in 9(3) cage at R4C1 and R5C23, locked for N4
15c. Two of 1,2,3 in 33(7) cage must be in N5, killer triple 1,2,3 in 33(7) cage and R6C6, locked for N5
[Or steps 15b and 15c can be considered to be
Double killer triple 1,2,3 in 9(3) cage at R4C1, 33(7) cage at R5C2 and R6C6, locked for N45.]

16. 19(5) cage at R2C3 = {12457/13456} (cannot be {12349/12358/12367} which clash with 9(3) cage at R3C4 now that 2,3 are no longer in R4C3), no 8,9, CPE no 4,5 in R1C3
16a. 7 of {12457} must be in R3C123 (R3C123 cannot be {245} which clashes with 9(3) cage at R3C4) -> no 7 in R4C3
16b. Killer pair 2,3 in 19(5) cage and 9(3) cage, locked for R3
16c. 8,9 in R3 only in R3C789, locked for N3
[Now I’m getting more into new steps.]
16d. 7 in N4 only in R5C23 + R6C123, CPE no 7 in R6C45

17. 19(5) cage at R2C3 (step 16) = {12457/13456}
17a. 7 of {12457} only in R3C123, 4 of {13456} must be in R3C123 (R3C123 cannot be {356} which clashes with 9(3) cage at R3C4) -> R3C123 must contain at least one of 4,7
17b. R12C1 = {29/38/56} (cannot be {47} which clashes with R3C123), no 4,7 in R12C1

[nd’s solving path for #10 was a bit more direct than my one because he used the following step, so I’ll use it here.]
18. 45 rule on R3 3 innies R3C789 = 1 remaining outie R4C3 + 18
18a. R4C3 = {456} -> R3C789 = 22,23,24 and must contain 8,9 (step 16c) = {589/689/789}, no 4

19. 4 in R3 only in R3C123, locked for N1 and 19(5) cage at R2C3, no 4 in R4C3
19a. R4C3 = {56} -> R3C789 (step 18a) = 23,24 = {689/789}, no 5
19b. R4C3 + R3C789 = 5+{689}/6+{789}, CPE no 6 in R3C123

20. 45 rule on N12 2 innies R12C6 = 1 outie R4C3 + 7
20a. Min R4C3 = 5 -> min R12C6 = 12, no 2 in R12C6

21. 45 rule on N12 3(2+1) outies R23C7 + R4C3 = 17
21a. R4C3 = {56} -> R23C7 = 11,12 must contain one of 2,3,4,5 -> R2C7 = {2345}

22. 45 rule on R123 2 innies R23C9 = 1 outie R4C3 + 8
22a. R4C3 = {56} -> R23C9 = 13,14 -> R2C9 = {4567}

23. 45 rule on R123 3(2+1) outies R4C3 + R45C9 = 16
23a. Max R4C3 = 6 -> min R45C9 = 10, no 1

24. 45 rule on N4578 4(3+1) outies R489C7 + R4C8 = 1 innie R4C3 + 6
24a. Max R4C3 = 6, min R489C7 = 7 (R489C7 cannot total 6, IOU) -> max R4C8 = 5
24b. Max (R4C3 – R4C8) = 5 -> max R489C7 = 10 (R489C7 cannot total 11 which would clash with R789C7, CCC) -> no 8 in R4C7

25. 35(6) cage at R4C4 must contain 8, locked for N5

26. 33(5) cage at R1C2 = {36789/45789}, 19(5) cage at R2C3 (step 16) = {12457/13456}
26a. 45 rule on N1 3(2+1) outies R12C4 + R4C3 = 18
26b. Consider placements for R4C3
R4C3 = 5 => R3C123 = {247}, locked for R3 and N1, R12C4 = 13 must contain 7 for 33(5) cage = {67}
or R4C3 = 6 => R3C123 = {345}, 2 in N1 only in R12C1 = {29}, locked for N1, R12C4 = 12 must contain 9 for 33(5) cage = {39}
-> R12C4 = {39/67}, no 4,5,8
26c. R12C4 = {39/67}, 9(3) cage at R3C4 = {126/135}, killer pair 3,6 locked for N2; clean-up: no 8 in R12C5
26d. R12C4 = {39/67}, R12C5 = {29/47}, killer pair 7,9 locked for N2
[Also, in the same way as step 19b …]
26e. R12C4 + R4C3 = {67}+5/{39}+6, CPE no 6 in R4C4

27. 33(5) cage at R1C2 = {36789} (only remaining combination), no 5, 8 locked for N1, clean-up: no 3 in R12C1
27a. Extending step 26b slightly
R4C3 = 5 => R3C123 = {247} => R12C1 = {56}
or R4C3 = 6 => R3C123 = {345} => R12C1 = {29}
-> R12C1 + R4C3 = {56}+5/{29}+6, CPE no 6 in R1C3 + R45C1

28. 8 in N2 only in R12C6, locked for C6 and 24(4) cage at R1C6, no 8 in R3C7
28a. 24(4) cage at R1C6 contains 8 = {2589/3489/4578} (cannot be {3678} because 6,7 only in R3C7), no 6

29. 9 in N7 only in R7C12
29a. 45 rule on N7 4 innies R7C123 + R9C3 = 24 = {2589/2679/3489/3579/4569}
29b. 2 of {2589/2679} must be in R7C3 -> no 2 in R9C3

30. 45 rule on R89 4 innies R8C5678 = 24 = {1689/2589/2679/3579/3678/4569/4578} (cannot be {3489} because R8C5 only contains 5,6)
30a. When R8C7 = 3 or 4, then the same number must be in R8C345, therefore from 12(4) cage at R8C3 -> R8C57 = [54/63] when R8C7 = 3 or 4
30b. R8C5678 = {1689/2589/2679/3678/4569/4578} (cannot be {3579} because of step 30a)
30c. 5,6 of R8C5678 = {1689/2589/2679/3678/4578} must be in R8C5, 5 of {4569} must be in R8C5 (because of step 30a) -> no 5 in R8C6

31. 12(4) cage at R7C3 = {1236/1245}
31a. 17(3) cage at R7C8 (step 9c) = {359/368/458/467}
31b. 7 of {467} must be in R8C8 (cannot be {47}6 which clashes with 12(4) cage), no 7 in R7C89

32. 33(7) cage at R5C2 = {1234689/1235679} contains 6
32a. Consider combinations for 35(6) cage at R4C6 = {146789/236789/245789/345689}
35(6) = {146789/236789/345689} contain 6 -> either 6 in N5 so 33(7) and 35(6) cages contain both 6s for N45 or 6 in R4C7 => R4C3 = 5, R45C9 = 11 (step 23), no 2 in R45C9
or 35(6) cage = {245789}, 2 locked for N6
-> no 2 in R45C9

33. Hidden killer pair 1,2 in 35(6) cage at R4C6 and 34(6) cage at R5C7 for N6, each cage can only contain one of 1,2 -> 35(6) cage = {146789/236789/245789}, 34(6) cage = {136789/145789/235789/245689}

34. 35(6) cage at R4C6 (step 33) = {146789/236789/245789}, 33(7) cage at R5C2 (step 32) = {1234689/1235679} contains 6
34a. Consider combinations for 9(3) cage at R4C1
9(3) cage = {126}, locked for N4 => 6 in 33(7) cage must be in N5 => 35(6) cage cannot be {236789} because 2,3,6 only in R4C78
or 9(3) cage = {135}, locked for N4 -> R4C3 = 6 => 6 in 33(7) cage must be in N5 => 35(6) cage cannot contain 6
or 9(3) cage = {234} => 35(6) cage cannot be {236789} because R4C78 = {23} clashes with 9(3) cage, ALS block
-> 35(6) cage at R4C6 = {146789/245789}, no 3

35. 8 in N8 only in R8C4 + R9C45, CPE no 8 in R9C3
35a. 8 in N8 must be in either 14(3) cage at R8C4 = {248} or in 14(3) cage at R9C5 = {158/248}
[I can see a contradiction move here but, since these days I prefer forcing chains to contradiction moves I’ll try one …]
35b. 14(3) cage at R8C4 = {239/248/257/347/356}
35c. 45 rule on N7 2 outies R6C12 = 2 innies R79C3 + 5
35d. Consider placement of 2 in R7
R7C3 = 2, min R6C12 = {57} = 12 => min R79C3 = 7 => min R9C3 = 5 => 14(3) cage at R8C4 = {257/347/356}
or 2 in R7C45 => 14(3) cage at R8C4 = {347/356}
-> 14(3) cage at R8C4 = {257/347/356}, no 8,9

36. R9C5 = 8 (hidden single in N8), R9C67 = 6 = [24/42/51]

37. R8C6 = 9 (hidden single in N8)
37a. 9 in N9 only in 17(3) cage at R8C9 = {179/269/359}, no 4,8
37b. 17(3) cage at R7C8 (step 9c) = {368/458/467}
37c. R789C7 (step 4) = {128/137/236/245} (cannot be {146} which clashes with 17(3) cage at R7C8)

38. 7 in R7 only in R7C1267
38a. R8C6 = 9 -> R67C6 + R8C7 = 10
38b. R6C6 + R7C127 (step 6c) = 1+{589}/1+{679}/2+{689}/3+{789} -> R6C6 + R7C6 + R8C7 = [172/154/271/352/361] -> R8C7 = {124}

39. R789C7 (step 37c) = {128/245}, no 6,7, 2 locked for C7 and N9, clean-up: no 6 in 17(3) cage at R8C9 (step 37a)
39a. Killer pair 1,5 in R789C7 and 17(3) cage at R8C9, locked for N9

40. Hidden killer pair 5,7 in R7C127 and R7C6 for R7, neither can contain both of 5,7 -> R7C127 (step 6c) = {589/679/789} = 22,24, R7C6 = {57}, R6C6 (step 6) = {13}
40a. R678C6 are all odd, cage sum odd -> R8C7 must be even = {24}

41. 2 in N5 only in R5C56 + R6C45, locked for 33(7) cage at R5C2, no 2 in R5C23

42. 2 in N4 only in 9(3) cage at R4C1 = {126/234}, no 5
42a. 6 of {126} must be in R4C2 -> no 1 in R4C2

43. Consider combinations for R789C7 (step 39) = {128/245}
43a. R789C7 = {128} = [821] => R9C6 = 5
or R789C7 = {245} => R7C7 = 5
-> 5 in R7C7 or R9C6, CPE no 5 in R7C6
[I think the puzzle is now almost cracked.]

44. R7C6 = 7, R8C6 = 9 -> R6C6 + R8C7 = 3 -> R6C6 = 1, R8C7 = 2, clean-up: no 4 in R9C6 (step 36)

45. 33(7) cage at R5C2 (step 32) = {1234689/1235679} -> R5C2 = 1

46. 9(3) cage at R4C1 (step 42) = {234} (only remaining combination), locked for N4

47. 29(4) cage at R6C1 = {5789}, 7 locked for R6 and N4

48. Naked triple {589} in R7C127, locked for R7

49. 6 in R7 only in R7C89, locked for N9

50. 14(3) cage at R8C4 (step 35d) = {347/356} (cannot be {257} which clashes with R9C6), no 2
50a. 7 of {347} must be in R9C3, 5 or 6 of {356} must be in R9C3 (R89C4 cannot be {56} which clashes with R8C5) -> R9C3 = {567}
50b. 14(3) cage = {347/356}, 3 locked for C4 and N8, clean-up: no 9 in R12C4 (step 26b)

51. Naked pair {67} in R12C4, locked for C4, N2 and 33(5) cage at R1C2, no 6,7 in R1C23 + R2C2, clean-up: no 4 in R12C5
51a. Naked pair {29} in R12C5, locked for C5 and N2
51b. 9(3) cage at R3C4 = {135} (only remaining combination), locked for R3 and N2
51c. Naked pair {48} in R12C6, locked for C6 and 24(4) cage at R1C6, no 4 in R2C7

52. Naked triple {247} in R3C123, locked for R3 and N1 -> R3C7 = 9, R2C7 = 3 (cage sum), clean-up: no 9 in R12C1
52a. R2C3 = 1, R3C123 = {247} = 13 -> R4C3 = 5 (cage sum), R4C6 = 6

53. Naked pair {78} in R6C12, locked for R6, N4 and 29(4) cage at R6C1, no 8 in R7C12
53a. Naked pair {69} in R56C3, locked for C3
53b. Naked pair {59} in R6C12, locked for R6 and N7 -> R7C7 = 8, R9C7 = 1 (step 39), R9C6 = 5 (step 36)

54. R8C8 = 7 -> R7C89 = 10 = {46}, locked for R7 and N9, R7C345 = [321], R8C5 = 6

55. 33(7) cage at R5C2 (step 32) = {1235679} (only remaining combination) -> R5C5 = 7, R4C5 = 4, R4C7 = 7

56. Naked pair {23} in R4C12, locked for R4 and N4 -> R5C1 = 4, R4C89 = [18]

and the rest is naked singles.

I'll rate my walkthrough for nd#10 v2 at Hard 1.75. In addition to the features used for nd#10 I also used several forcing chains.


Last edited by Ed on Sat Jun 14, 2008 9:06 am, edited 4 times in total.

Top
 Profile  
Reply with quote  
PostPosted: Mon Jun 09, 2008 12:50 am 
Offline
Grand Master
Grand Master

Joined: Wed Apr 16, 2008 1:16 am
Posts: 1044
Location: Sydney, Australia
Assassin 31 by Ruud (Dec 06)
Puzzle pic:
Image
Code: Select, Copy & Paste into solver:
3x3::k:4096:3841:4866:4866:5636:3333:3333:5383:2056:4096:3841:4866:1548:5636:3854:3333:5383:2056:3858:3841:5140:1548:5636:3854:3608:5383:4890:3858:3841:5140:5140:5636:3608:3608:5383:4890:3858:5413:1574:5140:7976:3608:4394:5675:4890:5413:5413:1574:7976:7976:7976:4394:5675:5675:6710:5413:1574:7976:3386:7976:4394:5675:4414:6710:6710:6710:2626:3386:3396:4414:4414:4414:3400:3400:3400:2626:3386:3396:3406:3406:3406:
Solution:
+-------+-------+-------+
| 7 5 6 | 9 3 2 | 8 4 1 |
| 9 1 4 | 5 6 8 | 3 2 7 |
| 3 2 8 | 1 4 7 | 5 9 6 |
+-------+-------+-------+
| 4 7 5 | 3 9 1 | 2 6 8 |
| 8 9 3 | 4 2 6 | 1 7 5 |
| 2 6 1 | 7 8 5 | 9 3 4 |
+-------+-------+-------+
| 5 4 2 | 6 1 3 | 7 8 9 |
| 6 8 7 | 2 5 9 | 4 1 3 |
| 1 3 9 | 8 7 4 | 6 5 2 |
+-------+-------+-------+
Quote:
Nasenbaer: This one gave me some headache
sudokuEd: I found this a really tricky Assassin - took 3 attempts to get it properly
Andrew, in A34 & A71 threads: I haven't finished Assassin 31...I'm surprised that the SS score for .. A31 (is) that low (1.00) [edit: see table above for current version of SSscore]
Andrew, Jan '09: This time I found A31 a lot easier...I'll rate A31 as Hard 1.0 .... The current SS score of 0.95 still looks a bit low to me
The way he figured it out Walkthrough by Nasenbaer:
This one gave me some headache until I realized that I had missed an elimination.

The walkthrough is the way I figured it out, no cleanups or shortcuts, unnecessary steps included. Please feel free to comment.

Edit: Ed gave me some corrections and additions, they are included in blue.

Walkthrough Assassin 31

1. r12c1 = 16(2) = {79} -> 7,9 locked in N1 and c1
2. r567c3 = 6(3) = {123} -> 1,2,3 locked in c3
3. r23c4 = 6(2) = {15|24}
4. r23c6 = 15(2) = {69|78}
5. r89c4 = 10(2) = {19|28|37|46}
6. r89c6 = 13(2) = {49|58} ({67} not possible, one is needed for step 4
7. -> 8,9 locked for c6 in 15(2) and 13(2)
8. N12 : 19(3) = {469|478|568} -> r1c4 = {456789} -> no 7 or 9 in r12c3 -> no 4 in r1c4 possible
9. 45 on c5: r56c5 = 10(2) = {19|28|37|46} -> no 5
10. 45 on N7 : r7c23 = 6(2) = [42]|[51] -> 3 locked in r56c3 for N4
11. 45 on N9 : r7c78 = 15(2) = {69|78}
12. 45 on N8 : r7c46 = 9(2) = {27|36|[81]} ({45} not possible, one is needed for 6(2) in r7) -> 6 locked in 9(2) or 15(2) for r7
13. 45 on r89 : r7c159 = 15(3) = {159|249|258|357} -> {258} blocked by r7c23 (step 10) which eliminates 8 for 15(3)
14. 45 on c12 : r89c3 = 16(2) = {79} -> 7,9 locked for c3 and N7
15. 45 on c89 : r89c7 = 10(2) = {19|28|37|46} -> no 5
16. 45 on c123 : r145c4 = 16(3)
17. 45 on c1234 : r67c4 = 13(2) = {67|[58]} -> no 6,7 in r7c6 (step 12)
18. 45 on c789 : r145c6 = 9(3) = {126|135|234}
19. 45 on c6789 : r67c6 = 8(2) = [53]|[62]|[71]
20. using steps 12, 17, 19 : r6c46 = 12{2} = {57} -> 5,7 locked for r6 and N5
21. -> no 7 in r7c4 and no 2 in r7c6 -> no 3,7 in 10(2) in c5
22. 6,8 locked in r7c478 for r7
23. N7 : 13(3) = {139|157|247} -> r9c12 = {12345}
24. N7 : 26(4) = {3689|5678} -> no 1,2,4 -> 6,8 locked in N7 and r8 -> r8c12 = {68}
25. -> no 2,4 in r9c47 and no 5 in r9c6
26. N9 : 17(4) = {1259|1349|1457|2357} = [7/9..] -> Killer pair with r7c78 for n9 -> no 7,9 in 13(3) -> no 1,3 in r8c7
27. c6 : r7c6 = {13} -> {135} not possible for 9(3) -> no 5
28. step 13 : r7c1 = {35} -> 15(3) = {159|357} -> r7c59 = {13579}
29. -> single in r7 : r7c3 = 2, r7c2 = 4
30. r9 : 1 locked in r9c12 -> no 9 in r8c47
31. N4 : 1 locked in r56c3
32. N47 : 21(4) = 4{269|278} -> 2 locked in N4 -> no 8 in r5c2
33. c1 : 15(3) : must have one but can't have both 6 and 8 -> {168} not possible -> no 1 -> r9c1 = 1 -> r6c1 = 2 -> no 8 in r5c5 -> 8 not possible in r3c1
To clarify step 33: c1 : 6,8 locked in 15(3) and r8c1 -> no 6,8 in r6c1 -> r6c1 =2
34. c2 : 6,8 locked in r568c2
35. -> c2 : 15(4) = {1239|1257} -> r4c2 = {79}
36. 8 locked in r123c3 -> no 8 in r4c3
37. N58 : 31(6) = 567{139|148|238} -> no 6 possible in r45c4 and r9c5 -> 6 locked in r79c4 -> no 6 in r1c4
38. N9 : 13(3) = {238|247|256|346} -> no 9 (now unnecessary due to addition in step 26)
39. N145 : 20(4) = {1469|1568|2459|2468|3458} -> r34c3 = {4568}, min: 9, max: 14 -> r45c4 = {123489}, min: 6, max: 11 (8 not possible) -> (step 16) r1c4 = {5679} -> r45c4 : min: 7 -> combination {68} not possible in r34c3
To clarify step 39: r45c4 = {123489}, so r45c4 = 8 not possible (5,7 removed by step 20) -> no 8 possible in r1c4
40. 45 on N2 (2 innies, 1 outie) : r1c46 - 2 = r4c5
40a. r1c46 : min: 6, max: 11
40b. r4c5 : min: 4, max: 9
41. 45 on N1 (2 innies, 2 outies) : r3c13 + 5 = r1c4 + r4c2
41a. r1c4 + r4c2 : min: 12, max: 18 (doubles possible)
41b. r3c13 : min: 7, max: 13
42. 45 on N3 (2 innies, 2 outies) : r3c79 - 3 = r1c6 + r4c9
42a. r1c6 + r4c9 : min: 2, max: 14 (doubles possible)
42b. r3c79 : min: 5, max: 17
43. N69 : 22(4) : {2578} not possible
44. 45 on r6789 : r5c1469 = 23(4)
45. N8 : 13(3) : can't have both 3 and 8 (9(2)), can't have both 4 and 8 (13(2)) -> 13(3) = {139|157|247} -> no 8 in 13(3)
46. N12 : r1c4 = {579} -> no 5 in r12c3 for 19(3)
47. (step 39) 20(4) has 5 -> 20(4) = 5{168|249|348}
48. N9 : 17(4) = 1{259|349|457} -> has 7 or 9 -> 7,9 locked in r78c789 -> no 7 in 13(3) -> no 3 in r8c7 (this is now unnecessary, it was done before in addition to step 26)
49. -> N9 : 17(4) : 2 not possible in r8c89
50. c7 : 17(3) : {368} not possible, one is needed in r9c7
51. c5 : 22(4) = {2389|2569|2578|3469|3568|4567} -> no 1 -> {2569} also blocked by 13(3)
52. c5 : 13(3) can't have both 1 and 3 -> {139} not possible -> no 3,9 -> 7 locked in 13(3) for c5 and N8 (this is the key to unlock the whole puzzle, should have gotten here earlier)
53. -> N8 : {37} not possible in 10(2) -> r7c6 = 3 -> r7c4 = 6 -> r7c1 = 5 -> r9c2 = 3 -> r9c3 = 9 -> r8c3 = 7 -> r9c4 = 8 -> r8c4 = 2 -> r9c6 = 4 -> r8c6 = 9 -> r9c5 = 7 -> r7c5 = 1 -> r8c5 = 5 -> r9c7 = 6 -> r8c7 = 4 -> r7c9 = 9
54. N58 : 31(6) : r5c5 = 2, r6c5 = 8
55. singles in c6 : r1c6 = 2, r6c6 = 5 -> r6c4 = 7
56. c6 : 15(2) = {78}
57. N356 : 14(4) : r45c6 = {16} locked in N5 -> r34c7 = {25} locked in c7
58. c4 : 6(2) = {15} -> r1c4 = 9 -> r12c3 = {46} locked in N1 and c3 -> r3c1 = 3 -> r3c3 = 8 -> r1c1 = 7 -> r2c1 = 9 -> r3c6 = 7 -> r2c6 = 8
59. combination eliminations: r4c2 = 7, r4c3 = 5 -> r4c7 = 2 -> r3c7 = 5 -> r3c4 = 1 -> r2c4 = 5 -> r3c2 = 2 -> r2c2 = 1 -> r1c2 = 5
60. r45c1 = {48} -> r8c1 = 6 -> r8c2 = 8
61. r12c7 = [83] -> r7c78 = [78]
The rest is simple cleanup.

Greetings
Condensed Nasenbaer's walkthrough by sudokuEd:
I found this a really tricky Assassin - took 3 attempts to get it properly.

Here is a condensed version of (Nasenbaer's) walk-through: with the un-necessary steps left out. The step numbers match. I've made a few little adjustments to clean up - so any mistakes are mine.

(Nasenbaer) Walkthrough: Assassin 31, Condensed version

1. r12c1 = 16(2) = {79} -> 7,9 locked in N1 and c1

2. r567c3 = 6(3) = {123} -> 1,2,3 locked in c3

3. r23c4 = 6(2) = {15|24}

4. r23c6 = 15(2) = {69|78}

5. r89c4 = 10(2) = {19|28|37|46}

6. r89c6 = 13(2) = {49|58} ({67} not possible, one is needed for step 4

7. -> 8,9 locked for c6 in 15(2) and 13(2)

8. N12 : 19(3) = {469|478|568} -> r1c4 = {456789} -> no 7 or 9 in r12c3 -> no 4 in r1c4 possible

9. 45 on c5: r56c5 = 10(2) = {19|28|37|46} -> no 5

10. 45 on N7 : r7c23 = 6(2) = [42]|[51] -> 3 locked in r56c3 for N4

11. 45 on N9 : r7c78 = 15(2) = {69|78}

12. 45 on N8 : r7c46 = 9(2) = {27|36|[81]} ({45} not possible, one is needed for 6(2) in r7) -> 6 locked in 9(2) or 15(2) for r7

13. 45 on r89 : r7c159 = 15(3) = {159|249|357} (no 8) (since {258} blocked by r7c23 -step 10)

14. 45 on c12 : r89c3 = 16(2) = {79} -> 7,9 locked for c3 and N7

15. 45 on c89 : r89c7 = 10(2) = {19|28|37|46} -> no 5

16. 45 on c123 : r145c4 = 16(3)

17. 45 on c1234 : r67c4 = 13(2) = {67|[58]} -> no 6,7 in r7c6 (step 12)

18. 45 on c789 : r145c6 = 9(3) = {126|135|234} (no 7)

19. 45 on c6789 : r67c6 = 8(2) = [53]|[62]|[71]

20. using steps 12, 17, 19 : r6c46 = 12{2} = {57} -> 5,7 locked for r6 and N5

21. -> no 7 in r7c4 and no 2 in r7c6 -> no 3,7 in 10(2) in c5

22. 6,8 locked in r7c478 for r7

23. N7 : 13(3) = {139|157|247} -> r9c12 = {12345}

24. N7 : 26(4) = {3689|5678} ({2789/4679} blocked by 13(3),{4589} blocked by r7c2) -> no 1,2,4 -> 6,8 locked in N7 and r8 -> r8c12 = {68}

25. -> no 2,4 in r9c47 and no 5 in r9c6

26. N9 : 17(4) = {1259|1349|1457|2357} = [7/9..] -> Killer pair with r7c78 for n9 -> no 7,9 in 13(3) -> no 1,3 in r8c7

27. c6 : r7c6 = {13} -> {135} not possible for 9(3) (step 18) ={126|234} -> no 5
28. step 13 : r7c1 = {35} -> 15(3) = {159|357} -> r7c59 = {13579}

29. -> single in r7 : r7c3 = 2, r7c2 = 4

30. r9 : 1 locked in r9c12 -> no 9 in r8c47

31. N4 : 1 locked in r56c3

32. N47 : 21(4) = 4{269|278} (no 5) -> 2 locked in N4 -> no 8 in r5c2

33. c1 : 15(3) : must have one but can't have both 6 and 8 -> {168} not possible -> no 1 -> r9c1 = 1 -> r6c1 = 2 -> no 8 in r5c5 -> 8 not possible in r3c1
To clarify step 33: c1 : 6,8 locked in 15(3) and r8c1 -> no 6,8 in r6c1 -> r6c1 =2

34. c2 : 6,8 locked in r568c2


35. -> c2 : 15(4) = {1239|1257} -> r4c2 = {79}

36. 8 locked in r123c3 -> no 8 in r4c3

37. N58 : 31(6) = 567{139|148|238} -> no 6 possible in r45c4 and r9c5 -> 6 locked in r79c4 -> no 6 in r1c4

52. c5 : 13(3) can't have both 1 and 3 (blocked by 9(2), 4 and 8 (blocked by 13(2) -> {139/148} not possible -> no 3,8,9 -> =7{15/24} ->7 locked for c5 and N8 (this is the key to unlock the whole puzzle)

53. -> N8 : {37} not possible in 10(2) -> r7c6 = 3 -> r7c4 = 6 -> r7c1 = 5 -> r9c2 = 3 -> r9c3 = 9 -> r8c3 = 7 -> r9c4 = 8 -> r8c4 = 2 -> r9c6 = 4 -> r8c6 = 9 -> r9c7 = 6 -> r9c89 = {25} -> r9c5 = 7 -> r7c5 = 1 -> r8c5 = 5 -> r8c7 = 4 -> r7c9 = 9

54. N58 : 31(6) : r5c5 = 2, r6c5 = 8

55. r45c6 = {16} -> r1c6 = 2, r6c6 = 5 (single c6) -> r6c4 = 7

56. c6 : 15(2) = {78}

57. N356 : 14(4) : r45c6 = {16} locked in N5 -> r34c7 = {25} locked in c7

58. c4 : 6(2) = {15} -> r1c4 = 9 -> r12c3 = {46} locked in N1 and c3 -> r3c1 = 3 -> r3c3 = 8 -> r1c1 = 7 -> r2c1 = 9 -> r3c6 = 7 -> r2c6 = 8

59. combination eliminations: r4c2 = 7, r4c3 = 5 -> r4c7 = 2 -> r3c7 = 5 -> r3c4 = 1 -> r2c4 = 5 -> r3c2 = 2 -> r2c2 = 1 -> r1c2 = 5

60. r45c1 = {48} -> r8c1 = 6 -> r8c2 = 8

61. r12c7 = [83] -> r7c78 = [78], r4c5 = 9, r56c7 = {19}:locked for n6, r3c8 = 9, 22(4):n67 = 38{47/56} with r5c8 = {57} and 3 locked for n6 and r6 -> r56c3 = [31], r45c4 = [34], r45c1 = [48]
The rest is simple cleanup
Jan '09 Walkthrough by Andrew:
As I commented in the A34 and A71 threads on Ruud's site, I didn't manage to solve three Assassins when they first appeared. Now having caught up with my backlog of other walkthroughs I'm having another go at them.

This time I found A31 a lot easier although on checking my original partial walkthrough I found that I'd come fairly close to the breakthrough, only missing the clash in step 8 :oops: and step 12 which I felt was the key breakthrough for this puzzle.

In the introduction to A31, Ruud wrote:
A tough Assassin that stumps SumoCue. Activate grey matter to continue.
SumoCue probably missed step 12.

I'll rate A31 as Hard 1.0 because of my hardest moves step 12 and the two-directional clash in step 18; I'm not sure if that clash was necessary but it made the solution quicker. The current SS score of 0.95 still looks a bit low to me; whichever way one reaches step 12 looks like Hard 1.0.

Here is my walkthrough.

Prelims

a) R12C1 = {79}, locked for C1 and N1
b) R23C4 = {15/24}
c) R23C6 = {69/78}
d) R12C9 = {17/26/35}, no 4,8,9
e) R89C4 = {19/28/37/46}, no 5
f) R89C6 = {49/58} (cannot be {67} which clashes with R23C6)
g) 19(3) cage at R1C3 = {289/379/469/478/568}, no 1
h) R345C9 = {289/379/469/478/568}, no 1
i) R567C3 = {123}, locked for C3
j) 14(4) cage at R3C7 = {1238/1247/1256/1346/2345}, no 9

1. Killer pair 8,9 in R23C6 and R89C6, locked for C6

2. Max R12C3 = 14 -> min R1C4 = 5

3. 45 rule on C12 2 outies R89C3 = 16 = {79}, locked for C3 and N7

4. 45 rule on N7 2 innies R7C23 = 6 = [51/42]
4a. 3 in C3 locked in R56C3, locked for N6

5. 45 rule on N9 2 innies R7C78 = 15 = {69/78}

6. 45 rule on C89 2 outies R89C7 = 10 = {19/28/37/46}, no 5

7. 45 rule on C1234 2 innies R67C4 = 13 = {49/58/67}, no 1,2,3
7a. 45 rule on C5 2 innies R56C5 = 10 = {19/28/37/46}, no 5
7b. 45 rule on C6789 2 innies R67C6 (or from cage sum) = 8 = {17/26/35}, no 4

8. 45 rule on N8 2 innies R7C46 = 9 = [63/72/81] (cannot be [45] which clashes with R7C2), clean-up: no 4,8,9 in R6C4, no 1,2,3 in R6C6

9. 45 rule on C789 3 outies R145C6 = 9 = {126/135/234}, no 7

10. R9C3 = {79} -> R9C12 = 4,6 = {13/15/24}, no 6,8
10a. Killer pair 1,2 in R7C3 and R9C12, locked for N7

11. 45 rule on C1 4 innies R6789C1 = 14 = {1238/1256/1346} (cannot be {2345} which clashes with R7C2 which “sees” all of R6789C1), 1 locked for C1
[In my original start I’d eliminated 1 from R345C1 which cannot be {168} because 26(4) cage in N7 must contain at least one of 6,8 in R78C1]
11a. 1 in N1 locked in R123C2, locked for C2, clean-up: no 3,5 in R9C1 (step 10)

12. R67C4 = 13 (step 7), R67C6 = 8 (step 7b), R7C46 = 9 (step 8) -> R6C46 = 12 = {57}, locked for R6, N5 and 31(5) cage at R5C5, clean-up: no 3 in R56C5 (step 7a), no 2 in R7C6 (step 7b)
12a. R7C46 = [63/81]
12b. Killer pair 6,8 in R7C4 and R7C78, locked for R7
12c. R145C6 (step 9) = {126/234} (cannot be {135} which clashes with R7C6), no 5
[Alternatively for step 12, 45 rule on N8 4 outies R5C5 + R6C456 = 22, R56C5 = 10 (step 7a) -> R6C46 = 12 …]

13. R789C5 = {157/247/256/346} (cannot be {139} which clashes with R7C6, cannot be {148} which clashes with R89C6, cannot be {238} which clashes with R7C46), no 8,9
13a. Killer pair 4,5 in R789C5 and R89C6, locked for N8, clean-up: no 6 in R89C4

14. R8C12 = {68} (hidden pair in N7), locked for R8, clean-up: no 2 in R9C4, no 5 in R9C6, no 2,4 in R9C7 (step 6)
14a. 26(4) cage in N7 = {3689/5678}, no 4

15. R6789C1 (step 11) = {1238/1256/1346}
15a. 1,2,4 only in R69C1 -> R69C1 = {124}

16. 21(4) cage at R5C2 = {1479/1569/1578/2469/2478/2568}
16a. R7C2 = {45} -> no 4,5 in R5C2 + R6C12
16b. Naked triple {123} in R5C3 + R6C13, locked for N4
16c. Min R45C1 = 9 -> max R3C1 = 6

17. Hidden killer pair 6,8 in R7C78 and R9C789 for N9 -> R9C789 must contain one of 6,8 = {238/256/346} (cannot be {139/157/247} which don’t contain 6 or 8, cannot be {148} which clashes with R9C12), no 1,7,9, clean-up: no 1,3,9 in R8C7 (step 6)

18. 45 rule on R9 3 innies R9C456 = 19 = {289/379/478} (cannot be {469} which clashes with R89C6 = {49}, cannot be {568} because 5,6 only in R9C5), no 1,5,6 clean-up: no 9 in R8C4
[I ought to have spotted this 45 a lot earlier. Fortunately it’s only important now.]

19. R9C1 = 1 (hidden single in R9), R6C1 = 2, R7C3 = 2, R7C2 = 4 (step 4), clean-up: no 8 in R5C5 (step 7a)
19a. R7C4 = 6 (hidden single in N8), R7C6 = 3 (step 8), R6C4 = 7 (step 7), R6C6 = 5, R7C1 = 5, R8C3 = 7 (step 14a), R9C23 = [39], R9C4 = 8, R8C4 = 2, R9C6 = 4, R8C6 = 9, R9C5 = 7, R78C5 = [15], R89C7 = [46], clean-up: no 4 in R23C4, no 6 in R23C6, no 4,9 in R56C5 (step 7a), no 9 in R7C78 (step 5)
19b. R56C5 = [28]
19c. R7C9 = 9 (hidden single in R7)
19d. R3C1 = 3 (hidden single in C1)

20. Naked pair {16} in R45C6, locked for C6, N5 and 14(4) cage at R3C7 -> R1C6 = 2, clean-up: no 6 in R2C9
20a. R1C6 = 2 -> R12C7 = 11 = {38}, locked for C7 and N3 -> R7C78 = [78], clean-up: no 5 in R12C9
20b. R56C7 = {19} (hidden pair in C7), locked for N6

21. Naked pair {15} in R23C4, locked for C4 -> R1C4 = 9, R12C1 = [79], clean-up: no 1 in R2C9
21a. R4C5 = 9 (hidden single in C5)

22. 21(4) cage at R5C2 (step 16) = {2469} (only remaining combination, cannot be {2478} because 7,8 only in R5C2) -> R56C2 = {69}, locked for C2 and N4 -> R8C12 = [68]

23. R4C2 = 7 (hidden single in C2), R4C3 = 5 (hidden single in N4), R34C7 = [52], R23C4 = [51], R3C2 = 2, R12C2 = [51]

24. R4C3 = 5, R45C4 = {34} -> R3C3 = 8 (cage sum), R23C6 = [87]

25. R1C7 = 8 (hidden single in R1), R2C7 = 3, R1C5 = 3 (hidden single in R1)
25a. Naked pair {46} in R2C35, locked for R2
25b. R3C8 = 9 (hidden single in R3)
25c. R4C6 = 1 (hidden single in R4), R5C6 = 6, R56C2 = [96], R56C7 = [19], R56C3 = [31], R45C4 = [34], R45C1 = [48], R4C89 = [68]

26. R34C8 = [96] = 15 -> R12C8 = 6 = [42]

and the rest is naked singles


Last edited by Ed on Sat Feb 07, 2009 2:58 am, edited 3 times in total.

Top
 Profile  
Reply with quote  
PostPosted: Mon Jun 09, 2008 12:52 am 
Offline
Grand Master
Grand Master

Joined: Wed Apr 16, 2008 1:16 am
Posts: 1044
Location: Sydney, Australia
Last Killer 06 by Ruud (Dec 06)
Puzzle pic:
Image
Code: Select, Copy & Paste into solver:
3x3::k:5632:5632:5378:5378:1284:3333:3333:7687:7687:5641:5632:5632:5378:1284:3333:7687:7687:3601:5641:5632:3604:3604:6166:2839:2839:7687:3601:5641:5641:3613:6166:6166:6166:3617:3601:3601:1572:1572:3613:4903:4903:4903:3617:2347:2347:6701:6701:3613:3376:3376:3376:3617:7220:7220:6701:5687:1336:1336:3376:2875:2875:4413:7220:6701:5687:5687:4418:3651:3652:4413:4413:7220:5687:5687:4418:4418:3651:3652:3652:4413:4413:
Solution:
+-------+-------+-------+
| 2 4 8 | 6 3 1 | 7 9 5 |
| 3 9 1 | 7 2 5 | 6 8 4 |
| 7 6 5 | 9 4 8 | 3 2 1 |
+-------+-------+-------+
| 4 8 3 | 5 6 9 | 1 7 2 |
| 1 5 2 | 4 8 7 | 9 6 3 |
| 6 7 9 | 2 1 3 | 4 5 8 |
+-------+-------+-------+
| 8 2 4 | 1 7 6 | 5 3 9 |
| 5 3 7 | 8 9 4 | 2 1 6 |
| 9 1 6 | 3 5 2 | 8 4 7 |
+-------+-------+-------+
Quote:
sudokuEd: what a bomb!..this is as far as I can get this one
Nasenbaer: now I'm stuck. Has anybody a new idea?
Para: this is a really crude step, not pretty but effective
Para: On A32 thread: not getting any progress in the "Last Killer 2006"
tag solution: by sudokuEd, Nasenbaer, rcbroughton & Para
Many thanks Andrew for corrections/clarifications
Andrew in 2011: This puzzle probably had a fairly narrow solving path; my breakthrough was in the same area is in the "tag" solution. I'll rate my walkthrough.... at Hard 1.25; I only had a couple of heavier steps
Condensed Walkthrough by sudokuEd:
Wow - nice work guys. Very jealous that I missed all the action though.

Here is a condensed walkthrough. These are just the essential steps. Have left the numbering essentially the same and added a few mop-up steps. Please let me know if anything is not accurate or clear.

Well done once again. Now it's my turn for dinner - Italian style sausages. YUM!

Condensed Walk-through for Ruud's Last Killer of 06

1a. 11(2) n23, 11(2) n89, 19(3)n5 & 26(4)n47 cannot have 1
1b. 13(4)n58 cannot have 8 or 9 and must have 1 -> no 1 in r4c5
1c. 14(4) n36 & 9(2)n6: no 9
1d. 28(4)n69 = 89(47/56} -> no 8 in r45c9 -> no 1 in r5c8
1e. 17(5)n9 = 123{47/56} -> 123 locked for n9, -> no 8,9 r7c6

2. "45" r1234:r4c37 = 4 = {13} locked for r4

3. "45" r6789:r6c37 = 13 = {49/58/67} (no 123)

4. "45" r5: r5c37 = 11 (no 1)

5. 6(2)n4 = {15/24} = [1/4, 4/5..]

6. 14(3)n4 must have 1 or 3 (r4c3) = {158/167/239/347/356} ({149} blocked by 6(2)n4)
6a. -> 14(3) = [1/3] not both -> no 3 r5c3 -> no 8 r5c7 (step 4)

7. 9(2)n6 = {18/27/36} ({45} blocked by 6(2)r5)

8. 19(3) r5 = {289/379/469/478} (no 5) ({568} blocked since this means 9(2) r5 = {27} but this leaves no 2 or 5 for 6(2)r5)
[Andrew notes simpler as
r4c7 = {13} -> no 3 in r5c7
Hidden killer pair 1,3 in r4c7 and 9(2)n6 -> 9(2)n6 must contain one of 1,3 = {18/36} [This was eventually done in step 30.]
19(3) r5 = {289/379/469/478} (no 5) ({568} blocked by 9(2)n6)]


9. "45" c12 -> r28c3 = 8 = {17/26/35} (no 4,8,9)

11. "45" c89 -> r28c7 = 8 = {17/26/35} no 4,8.9

12. 14(3) c7 must have 1 or 3 (r4c7) = {149/158/239/347/356} ({167} blocked by 9(2)n6)
12a. 14(3)= [1/3] not both -> no 3 r5c7 -> no 8 r5c3 (step 4)

16. 5(2) c5 = {14/23}

17. 14(2) c5 = {59/68}

18. "45" on n5: 2 outies r37c5 = 11 => from "45" on c5, three remaining innies r456c5 = 15 = {159/168/267/357} (no 4) = [5/6..]
18a. {249} blocked by 5(2)c5 (step 16)
18b. {258} blocked by 14(2) (step 17)
18c. {348} blocked by 5(2) (step 16)
18d. {456} blocked by 14(2) (step 17)

19. "45"n5:r37c5 = 11 = {29/38/47} ({56} blocked by 14(2)c5 (step 17))
19a. -> no 1,5,6 r37c5
19a. max. r7c5 = 7 -> min r3c5 = 4

22. "45"c1234: r456c4 = 11(3) = {128/146/236/245} (no 7,9) ({137}blocked by 15(3)c5 step 18)

23. "45"c6789: r456c6 = 19(3) = {289/379/469/478} (no 1,5)({568} blocked by 11(3) step 22)
23a. {289} combination is the only one with 2 -> no 2 in r45c6

24. from step 18. r456c5 = 15(3) = {159/168/357} (no 2) ({267} blocked by 11(3) (step 22))

29. r3 : 11(2) = {29|38|47} -> {56} not possible, one is needed in 14(2) r3

30. N6 : 14(3) = [1/3] not both. The only other place for 1 or 3 in n6 is in 9(2) -> 9(2) must have [1/3] = [81]/{36}(no 2,7)

33. r5 : 3 only in 19(3) or 9(2) -> no 6 in 19(3)
33a. 3 in 19(3)= {379} only (step 8) ->(no 6)
33b. 3 in 9(2) = {36} only -> no 6 in 19(3)
33c. ->19(3) = {289/379/478} (no 6)

41. R5C3 can't be a 9
41a. 14(3)n4: only allowable combination with a 9 is {239}(step 6)
41b. -> no 9 r5c3 (since no 2 in r6c3)

43. no 9 in r5c3 (step 41b) -> no 2 in r5c7 (step 4) -> 2 only in r4c89 for n6: locked for r4 and 14(4)

44. N25 : 24(4) = 45{69|78} -> 5 locked in r4c45 for r4 and N5

50. N36 : 14(4) : no 5 in r4c89 -> {1256} not possible (because 1 in r23c9 -> 9(2) n6 = {36})-> no {156} available in r4c89)
50a. 14(4) must have 2 (step 43) = 2{138/147/345} (no 6)

51. N6 : when 14(3) = {347} -> r4c89 = [82] -> no 3 or 8 left for 9(2)
51a. -> {347} not possible,
51b. -> no 7 in 14(3) -> no 4 in r5c3 (step 4)

52. R4C8 can't be 8. Here's how:
52a.R4C8 = 8 --> R4C9 = 2 and R5C89 = {36} --->> 14(3) = {149} -> R6C89 = {75}, but no combination with {57} is possible in 28(4) N69. -> no 8 in r4c8
52b. 14(4)N36 cannot have {1238} since no {138} available in r4c89
52c. 14(4) N36 = {1247|2345} (no 8) = 24{17/35} -> no 4 in R6C9.

53. 14(3)n6 = {149/158/356} = [1/6..]
53a. 9(2)n6 = {36}/[81] = [1/6..]
53b. -> Killer pair on {16}: locked for n6

54. "45" on n3 -> 4 innies = 15
54a. 14(4) N36 = 24{17|35} (step 52c) with r4c89 = {24/27} = 6 or 9
54b. -> r23c9 = 5 or 8
54c. r23c9 = 5 = {14}-> r13c7 = (15 - 5) = 10 = {28|37} ([19/64] blocked by r23c9 in this hypothetical)
54d. r23c9 = 8 = {17} -> r13c7 = (15 - 8) = 7 {34}|[52]
54e. r23c9 = 8 = {35} -> r13c7 = (15 - 8) = 7: all combinations blocked (no 1 or 6 in r3c7, 3 and 5 in r23c9)
54f. -> r1c7 = {234578} (no 1,6,9),
54g. r3c7 = {23478} (no 9) -> no 2 r3c6
54h. r23c9 = {14/17} (no 3 or 5) = 1{4/7} -> 1 locked for n3, c9
54i. -> no 8 in r5c8
54j. -> no 7 in r8c7
54k. 14(4)n56 = {1247} -> no 7 in r6c9

57. 9(2)n6 = {36} only -> 3,6 locked for N6 and r5 -> r4c7 = 1 -> r4c3 = 3

58. r5c37 = 11 = [29/74]
58a. -> 6(2)r5 = {15} (hidden pair r5) -> 1,5 locked for N4 and r5

59. r5 : 19(3) = 8{29|47} -> 8 locked for N5

63. N6 : 14(3) = {[1]49} -> 4,9 locked for N6 and c6 -> no 2 or 7 in r7c6 -> no 7 r3c6

64. r4c89 = {27} -> 2,7 locked for N6, r4 and 14(4) -> r23c9 = {14} -> 1,4 locked for c9 and N3

65. r6c89 = {58} -> 5,8 locked for r6 and 28(4) -> r78c9 = {69} -> locked for N9 and c9 -> r5c9 = 3, r5c8 = 6 and
65a. no 5 in r7c6

66. hidden single in N3 : r2c7 = 6 -> r8c7 = 2 (step 23)

67. from step 54c : r13c7 = 10 = {37} -> 3,7 locked for N3 and c7 -> r3c6 = {48}

68. -> r79c7 = {58} -> locked for N9 -> r9c9 = 7 -> r4c9 = 2 -> r4c8 = 7

69. r6c3 = {49} -> naked pair with r6c7 for r6

70. 13(3)n23 must have 3 or 7 (r1c7) -> no 3, 7 possible in r12c6 ({733} not good)-> 5(2)n2 = {23} (only place for 3 in n2):locked for n2, c5

71. deleted

72. 13(4)n58 = {1237/1246} = 12{37/46} with 1,2 only in r6 -> 1,2 locked for r6,n5

73. 19 (3) n5 now {478} only: locked for n5, r5

74. 9 in n5 only in 24(4)n25 = {4569} -> r3c5 = 4
74a. r4c456 = {569}:locked for r4, n5

75. r4c12 = {48} locked for 22(4), n4
75a. r23c1 = {19/37} (no 2,5,6)

76. r6c12 = {67} pair: locked for 26(4)
76a. r78c1 = {49/58} (no 2,3)

the rest is pretty simple
2011 walkthrough by Andrew:
Another puzzle from Ruud's site which I didn't try at the time. We were staying with our daughters in Lethbridge for Christmas 2006 and I had limited computer access at that time.

It was good that Ed, Peter, Richard and Para were able to take part in a "tag" solution then.

Just one comment about their solution. Step 8 of the "condensed tag" would have been simpler as
r4c7 = {13} -> no 3 in r5c7
Hidden killer pair 1,3 in r4c7 and 9(2)n6 -> 9(2)n6 must contain one of 1,3 = {18/36} [This was eventually done in step 30.]
19(3) r5 = {289/379/469/478} (no 5) ({568} blocked by 9(2)n6)

This puzzle probably had a fairly narrow solving path; my breakthrough was in the same area is in the "tag" solution.

Prelims

a) R12C5 = {14/23}
b) R3C34 = {59/68}
c) R3C67 = {29/38/47/56}, no 1
d) R5C12 = {15/24}
e) R5C89 = {18/27/36/45}, no 9
f) R7C34 = {14/23}
g) R7C67 = {29/38/47/56}, no 1
h) R89C5 = {59/68}
i) 21(3) cage at R1C3 = {489/579/678}, no 1,2,3
j) 19(3) cage in N5 = {289/379/469/478/568}, no 1
k) 14(4) cage at R2C9 = {1238/1247/1256/1346/2345}, no 9
l) 26(4) cage at R6C1 = {2789/3689/4589/4679/5678}, no 1
m) 13(4) cage at R6C4 = {1237/1246/1345}, no 8,9
n) 28(4) cage at R6C8 = {4789/5689}, no 1,2,3
o) 17(5) cage in N9 = {12347/12356}, no 8,9

Steps resulting from Prelims

1a. R3C67 = {29/38/47} (cannot be {56} which clashes with R3C34), no 5,6
1b. R5C89 = {18/27/36} (cannot be {45} which clashes with R5C12), no 4,5
1c. 13(4) cage at R6C4 = {1237/1246/1345}, CPE no 1 in R4C5
1d. 28(4) cage at R6C8 = {4789/5689}, CPE no 8 in R45C9, clean-up: no 1 in R5C8
1e. 17(5) cage in N9 = {12347/12356}, 1,2,3 locked for N9, clean-up: no 8,9 in R7C6

2. 45 rule on C12 2 outies R28C3 = 8 = {17/26/35}, no 4,8,9

3. 45 rule on C89 2 outies R28C7 = 8 = {17/26/35}, no 4,8,9

4. 45 rule on R1234 2 innies R4C37 = 4 = {13}, locked for R4

5. 45 rule on R5 2 innies R5C37 = 11 = {29/38/47/56}, no 1

6. 45 rule on R6789 2 innies R6C37 = 13 = {49/58/67}, no 1,2,3

7. 45 rule on N5 2 outies R37C5 = 11 = {47}/[83/92] (cannot be {56} which clashes with R89C5), no 1,5,6, no 2,3 in R3C5

8. 45 rule on C1234 3 innies R456C4 = 11 = {128/137/146/236/245}, no 9
8a. 7 of {137} must be in R4C4 -> no 7 in R56C4

9. 45 rule on C6789 3 innies R456C6 = 19 = {289/379/469/478/568}, no 1
9a. 2 of {289} must be in R6C6 -> no 2 in R45C6

10. 45 rule on N5 R456C4 = 11, R456C6 = 19 -> R456C5 = 15 = {159/168/357} (cannot be {249/348} which clash with R12C5, cannot be {258/456} which clash with R89C5, cannot be {267} which clashes with R456C4), no 2,4
10a. 1 of {168} must be in R6C5 -> no 6 in R6C5
10b. R456C4 (step 8) = {128/146/236/245} (cannot be {137} which clashes with R456C5), no 7
10c. R456C6 (step 9) = {289/379/469/478} (cannot be {568} which clashes with R456C5), no 5

11. Hidden killer pair 2,4 in R12C5 and R37C5, R12C5 contains one of 2,4 -> R37C5 (step 7) must contain one of 2,4 = [47/74/92], no 3,8

12. 14(3) cage in N4 = {158/167/239/347/356} (cannot be {149/257} which clash with R5C12, cannot be {248} because R4C3 only contains 1,3)
12a. R4C3 = {13} -> no 3 in R5C3, clean-up: no 8 in R5C7 (step 5)
12b. 2 of {239} must be in R5C3 -> no 9 in R5C3, clean-up: no 2 in R5C7 (step 5)

13. 14(3) cage in N6 = {149/158/167/347/356}
13a. R4C7 = {13} -> no 3 in R5C7, clean-up: no 8 in R5C3 (step 5)

14. Hidden killer pair 1,3 in R4C7 and R5C89, R4C7 = {13} -> R5C89 must contain one of 1,3 -> R5C89 = [36/63/81], no 2,7

15. 2 in N6 only in R4C89, locked for R4 and 14(4) cage at R2C9, no 2 in R23C9
15a. 14(4) cage at R2C9 = {1238/1247/1256/2345} (only combinations containing 2)
15b. 1,3 of {1238} must be in R23C9 -> no 8 in R23C9

16. R456C4 (step 10b) = {128/146/236/245}
16a. 8 of {128} must be in R4C4 -> no 8 in R5C4
16b. 1 of {146} must be in R6C4, 6 of {236} must be in R4C4 -> no 6 in R6C4

17. 19(3) cage in N5 = {289/379/469/478} (cannot be {568} which clashes with R5C89), no 5
17a. 3 of {379} must be in R5C4 -> no 3 in R5C56

18. Hidden killer pair 1,3 in R12C5 and R6C5 for C5, R12C5 contains one of 1,3 -> R6C5 = {13}
18a. R456C5 (step 10) = {159/168/357}
18b. 5 of {159/357} must be in R4C5 -> no 7,9 in R4C5

19. 24(4) cage at R3C5 = {4569/4578}, 5 locked for R4 and N5

20. 13(4) cage at R6C4 = {1237/1246}
20a. 6 of {1246} must be in R6C6 -> no 4 in R6C6
20b. R456C6 (step 10c) = {289/379/469/478}
20c. 6 of {469} must be in R6C6 -> no 6 in R45C6

21. 14(4) cage at R2C9 (step 15a) = {1238/1247/2345} (cannot be {1256} = {15}{26} which clashes with R5C89), no 6
21a. 14(4) cage at R2C9 = {1238/1247/2345} -> R23C9 = {13/14/17/35}
[R23C9 for analysis in next step]

[I first saw the key breakthrough in the next step by the more human approach of
45 rule on N3 4 innies R13C7 + R23C9 = 15
14(4) cage at R2C9 at R2C9 cannot be {2345} = {35}{24} because R23C9 = {35} = 8 => R13C7 = 7 cannot be {25/34} which clash with R23C9 and there are no 1,6 in R3C7.
However that’s also a contradiction move so I then looked for another way.]

22. 30(5) cage in N3 = {24789/25689/34689/35679/45678} (cannot be {15789} which clashes with R23C9), no 1, clean-up: no 7 in R8C7 (step 3)
22a. 45 rule on N3 4 innies R13C7 + R23C9 = 15 and must contain 1 = {1239/1248/1257/1347} (cannot be {1356} = [63]{15} because R23C9 cannot be {15}, step 21a), no 6
22b. R23C9 (step 21a) = {13/14/17} (cannot be {35} because R13C7 + R23C9 doesn’t contain both of 3,5), no 5, 1 locked for C9 and N3, clean-up: no 8 in R5C8

23. Naked pair {36} in R5C89, locked for R5 and N6 -> R4C7 = 1, R4C3 = 3, clean-up: no 5 in R28C3 (step 2), no 7 in R2C7 (step 3), no 5 in R5C37 (step 5), no 7 in R6C3 (step 6), no 2 in R7C4

24. 14(3) cage in N6 (step 13) = {149} (only remaining combination, cannot be {158} because 5,8 only in R6C7), locked for C7 and N6, clean-up: no 2,7 in R3C6, no 4 in R5C3 (step 5), no 5,6,8 in R6C3 (step 6), no 2,7 in R7C6

25. Naked pair {49} in R6C37, locked for R6

26. R5C12 = {15} (hidden pair in R5), locked for N4

27. Killer pair 2,7 in R28C3 and R5C3, locked for C3, clean-up: no 3 in R7C4

28. Naked pair {14} in R7C34, locked for R7, clean-up: no 7 in R3C5 (step 7), no 7 in R7C7
28a. 4 in C5 only in R123C5, locked for N2, clean-up: no 7 in R3C7

29. 8 in R5 only in R5C56, locked for N5
29a. 24(4) cage at R3C5 (step 19) = {4569} (only remaining combination), no 7, 6 locked for N5
29b. Naked pair {49} in R3C5 + R4C6, locked for 24(4) cage -> R4C45 = {56}, locked for R4
29c. Naked pair {49} in R3C5 + R4C6, CPE no 9 in R3C6 + R5C5, clean-up: no 2 in R3C7

30. Naked pair {38} in R3C67, locked for R3, clean-up: no 6 in R3C34
30a. Naked pair {59} in R3C34, locked for R3 -> R3C5 = 4, R4C6 = 9, R7C5 = 7 (step 7), R5C5 = 8, R5C46 = [47] (hidden pair in N5), R56C7 = [94], R56C3 = [29], R7C34 = [41], R6C5 = 1 (hidden single in N5), clean-up: no 6 in R28C3 (step 2), no 6 in R89C5

31. Naked pair {23} in R12C5, locked for N2 -> R3C67 = [83], clean-up: no 5 in R28C7 (step 3)

32. Naked pair {59} in R89C5, locked for C5 and N8 -> R4C45 = [56], R3C34 = [59], clean-up: no 6 in R7C7

33. Naked pair {67} in R12C4, locked for C4, N2 and 21(3) cage at R1C3 -> R1C3 = 8

34. R12C6 = {15} = 6 -> R1C7 = 7 (cage sum), R12C4 = [67], R28C3 = [17], R9C3 = 6

35. R9C3 = 6 -> R89C4 = 11 = {38}, locked for C4 and N8 -> R6C46 = [23], R7C7 = 6, R7C7 = 5, R9C7 = 8, R7C9 = 9

36. R23C9 = [41] -> 14(4) cage at R2C9 (step 21) = {1247} (only remaining combination) -> R4C89 = {27}, locked for R4 and N6, R8C9 = 6, R5C89 = [63], R3C8 = 2, R1C9 = 5, R6C9 = 8

37. R6C12 = {67} = 13 -> R78C1 = 13 = [85]

38. R4C12 = [48] = 12 -> R23C1 = 10 = [37]

and the rest is naked singles.

Rating comment. I'll rate my walkthrough for Last Killer of 2006 at Hard 1.25; I only had a couple of heavier steps involving analysis.


Last edited by Ed on Sat Jun 14, 2008 9:09 am, edited 1 time in total.

Top
 Profile  
Reply with quote  
PostPosted: Mon Jun 09, 2008 12:59 am 
Offline
Grand Master
Grand Master

Joined: Wed Apr 16, 2008 1:16 am
Posts: 1044
Location: Sydney, Australia
Assassin 32 by Ruud (Jan 07)
Puzzle pic:
Image
Code: Select, Copy & Paste into solver:
3x3::k:6912:6912:6912:6912:2308:5893:5893:5893:5893:3849:2058:2827:6912:2308:5893:1807:3088:2321:3849:2058:2827:4373:2308:3607:1807:3088:2321:3355:3355:4373:4373:3871:3607:3607:2850:2850:3355:3621:2086:2086:3871:3113:3113:4651:2850:3621:3621:4143:4143:3871:4146:4146:4651:4651:3894:2615:1592:4143:5434:4146:2876:2365:2878:3894:2615:1592:5186:5434:6980:2876:2365:2878:5186:5186:5186:5186:5434:6980:6980:6980:6980:
Solution:
+-------+-------+-------+
| 2 1 8 | 9 3 5 | 4 6 7 |
| 6 3 4 | 7 2 1 | 5 9 8 |
| 9 5 7 | 8 4 6 | 2 3 1 |
+-------+-------+-------+
| 4 8 3 | 6 9 7 | 1 2 5 |
| 1 7 6 | 2 5 3 | 9 8 4 |
| 5 2 9 | 4 1 8 | 6 7 3 |
+-------+-------+-------+
| 7 4 1 | 3 6 2 | 8 5 9 |
| 8 6 5 | 1 7 9 | 3 4 2 |
| 3 9 2 | 5 8 4 | 7 1 6 |
+-------+-------+-------+
Quote:
Nasenbaer: After a hard days work on Ruud's "Last Killer 2006" with sudokued, rcbroughton and Para (I had a lot of fun there) Assassin 32 was almost relaxing
Para: Did 32 to relax after not getting any progress in the "Last Killer 2006"
Andrew: (found) a couple of interesting moves which I wouldn't have found if I had followed a more direct solving path..(the) variants on Assassin 32 (were) Both definitely harder than Ruud's original
Walk-through by Nasenbaer:
After a hard days work on Ruud's "Last Killer 2006" with sudokued, rcbroughton and Para (I had a lot of fun there) Assassin 32 was almost relaxing. :wink:

I could have been faster, step 33 should have come a lot earlier. Oh well. The walkthrough is the way I solved it, so it's the long(er) way. Want a condensed version? Feel free to do it! :wink:

One other thing: for multiple solved cells I used square brackets because I'm sometimes lazy. (example: r34c2 = [28] would mean r3c2 = 2, r4c2 = 8)

Edit: Corrections included, thanks to Andrew.

Edit 2: Finally got around to do the rest of the corrections, sorry for the delay. Thanks again to Andrew for the input.

Walkthrough Assassin 32

1. N1 : 15(2) = {69|78}, N7 : 15(2) = {69|78} -> 6,7,8,9 locked in c1
2. N1 : 8(2) = {17|26|35} -> no 4,8,9
3. N1 : 11(2) = {29|38|47|56} -> no 1
4. N3 : 7(2) = {16|25|34} -> no 7,8,9
5. N3 : 12(2) = {39|48|57} -> no 1,2,6
6. N3 : 9(2) = {18|27|36|45} -> no 9
7. N7 : 10(2) = {19|28|37|46} -> no 5
8. N7 : 6(2) = {15|24} -> no 3,6,7,8,9
9. N9 : c7 : 11(2) = {29|38|47|56} -> no 1
10. N9 : c9 : 11(2) = {29|38|47|56} -> no 1
11. N9 : 9(2) = {18|27|36|45} -> no 9
12. r5 : 8(2) = {17|26|35} -> no 4,8,9
13. r5 : 12(2) = {39|48|57} -> no 1,2,6
14. N6 : 11(3) : no 9
15. 45 on N1 : r12c4 = 16(2) = {79} -> 7,9 locked for 27(5), N2 and c4
16. -> r1c123 11(3) = {128|146|236|245}
17. 45 on N3 : r12c6 = 6(2) = {15|24} -> no 3,6,8 -> r1c789 = 17(3)
18. 45 on N2 : r3c46 = 14(2) = {68} -> 6,8 locked for N2 and r3
19. Clean-up -> no 7,9 in r2c1, no 2 in in r2c2, no 3,5 in r2c3, no 1 in r2c7, no 4 in r2c8, no 1,3 in r2c9, no 1 in r5c3
20. N2 : 9(3) = 3{15|24} -> 3 locked for N2 and c5
21. N4 : 13(3) : r45c1 = {12345} -> r4c2 = {6789}
22. 45 on N7 : r89c4 = 6(2) = {15|24}
23. 45 on N9 : r89c6 = 13(2) = {49|58|67} -> r9c789 = 14(3)
24. 45 on N8 : r7c46 = 5(2) = {23} ({14} blocked by 6(2) in r78c4) -> 2,3 locked for N8 and r7
25. -> N8 : 6(2) = {15} -> 1,5 locked for 20(5), N8 and c4
25a. -> r9c123 = 14(3) = 15{239|248|347} -> N7 : 6(2) = {15} -> 1,5 locked for N7 and c3
26. Clean-up -> no 8 in r89c6, no 7,8,9 in r8c2, no 9 in r7c2, no 8,9 in r8c7, no 6,7 in r8c8, no 8,9 in r8c9, no 3,7 in r5c3, no 3 in r5c4
27. r5 : 8(2) = {26} -> 2,6 locked for r5
28. N8 : 21(3) = 8{49|67} -> 8 locked for N8 and c5
29. 4 locked in r46c4 for c4 and N5 -> no 8 in r5c7
30. N5 : 15(3) = {159|267}
31. N245 : 17(4) = {269|278|368|467} -> 2,4 not possible in r4c3
32. N256 : 14(3) = {158|167|248|356} -> no 6,8,9 in r4c67, no 2 in r4c7
33. 45 on r1 : r1c456 = 17(3) = [935] -> r2c46 = [71] -> r23c5 = {24} -> 2,4 locked for c5
34. N8 : 21(3) = {678} -> 6,7,8 locked for N8 and c5
35. N8 : 13(2) = {49} -> 4,9 locked for 27(5), N8 and c6 -> r9c789 = 14(3) = {158|167|257|356}
36. Clean-üp -> no 1,7 in r3c2, no 6 in r2c3, no 4 in r3c3, no 5 in r3c8, no 2 in r3c9, no 3,7 in r5c7
37. N256 : 14(3) : {158} not possible
37a. not connected: no 3,7 in r4c7 possible
38. 5 locked in r23c2 for for N1 and c2 -> 8(2) = {35} -> 3,5 locked for N1 and c2 -> no 8 in r2c3, no 7 in r7c2
new 39. N7 : 14(3) : 3 locked in r9c13 for N7 and r9, 14(3) = 3{29|47}, no 6,8 (same result as old version but clearer)
(old 39. N7 : 14(3) : {248} not possible, blocked by 10(2) -> no 6, 8 in 14(3) -> 14(3) = 3{29|47} -> 3 locked for N7 and r9)
40. 45 on r9 : r9c456 = 17(3) = [179]|[584] -> no 6 in r9c5
41. 6 locked in r9c789 for N9, r9 and 27(5) -> r9c789 = {167}, locked for r9 and N9
42. r9c456 = [584] -> r8c46 = [19] -> r78c3 = [15]
43. N9 : 14(3) = {239} -> 10(2) = {46} -> 4,6 locked for c2 -> 15(2) = {78} -> r23c1 = [69] -> r23c3 = [47] -> r23c5 = [24] -> r23c8 = [93] -> r23c7 = [52] -> r23c9 = [81] -> r23c2 = [35]
44. Clean-Up -> no 7 in r5c6, no 3 in r4c6, no 9 in r7c7, no 6 in r8c7, no 8 in r8c8, no 4,8 in r7c8, no 3 in r8c9, no 5 in r7c9
45. 9 single in N9 -> r78c9 = [92] -> r78c8 = [54] -> r78c2 = [46] -> r78c5 = [67] -> r78c7 = [83] -> r78c1 = [78]
46. N568 : 16(3) = 6{28|37} ({349} not possible) -> 6 locked for r6 -> r6c6 = {678}, r6c7 = {67}
47. N458 : 16(3) = [943] -> N568 : 16(3) = [862] -> N256 : 14(3) = [671] -> N245 : 17(3) = [836]

The rest is simple clean-up

Have fun
Walkthrough by Andrew using clean-up steps (like Nasenbaer's):
Not my best walkthrough but I decided to post it anyway. It has a couple of interesting moves which I wouldn't have found if I had followed a more direct solving path. I've included some comments on moves that I missed first time.

I liked the way that (Nasenbaer) used clean-up steps so I've done something similar in my walkthrough.

Thanks Ed for a couple of comments, which I have added, and the correction of a typo; I also found another typo while going through Ed's comments.

Clean-up is used in various steps, using the combinations in steps 1 to 14 for further eliminations from these two cell cages; it is also used for the two cell sub-cages that are produced by applying the 45 rule to N1, N3, N7 and N9. In some of the later steps, clean-up is followed by further moves and sometimes more clean-up.

1. R23C1 = {69/78}

2. R23C2 = {17/26/35}, no 4,8,9

3. R23C3 = {29/38/47/56}, no 1 [Ed has pointed out that {56} is blocked. It would make R23C1 = {78} and then 5,6,7 would all be blocked from R23C2 which is impossible. Nice one Ed! I must admit that I was making the first 17 steps fairly mechanically, not looking for any interactions at that stage, before I started thinking.]

4. R23C7 = {16/25/34}, no 7,8,9

5. R23C8 = {39/48/57}, no 1,2,6

6. R23C9 = {18/27/36/45}, no 9

7. R5C34 = {17/26/35}, no 4,8,9

8. R5C67 = {39/48/57}, no 1,2,6

9 R78C1 = {69/78}, 6,7,8,9 locked in R2378C1 for C1

10. R78C2 = {19/28/37/46}, no 5

11. R78C3 = {15/24}

12. R78C7 = {29/38/47/56}, no 1

13. R78C8 = {18/27/36/45}, no 9

14. R78C9 = {29/38/47/56}, no 1

15. R123C5 = {126/135/234}, no 7,8,9

16. 11(3) cage in N6, no 9

17. R789C5 = {489/579/678}, no 1,2,3

18. 13(3) cage in N4, max R45C1 = {45} = 9, min R4C2 = 6 (4,5 already being used)

19. 45 rule on N1 3 innies R1C123 = 11 -> R12C4 = 16 = {79}, locked for C4 and N2, no 7,9 in R123C1, clean-up: no 1 in R5C3

20. 17(3) cage in N254, max R34C4 = 14 -> min R4C3 = 3

21. 45 rule on N3 3 innies R1C789 = 17 -> R12C6 = 6 = {15/24} (when I was checking this walkthrough before posting it, I noticed that this eliminates {126} from R123C5 but haven’t changed the walkthrough; that combination is eliminated in step 23)

22. 45 rule on N2 2 remaining innies R3C46 = {68}, locked for R3 and N2, clean-up: no 7,9 in R2C1, no 2 in R2C2, no 3,5 in R2C3, no 1 in R2C7, no 4 in R2C8, no 1,3 in R2C9

23. R123C5 = 3{15/24}, 3 locked for C5 [Ed has pointed out that this eliminates {258/456} from R456C5]

24. 17(3) cage in N254, R3C4 = {68}, no 1 in R4C4 (cannot have {188})

25. 14(3) cage in N256, R3C6 = {68}, min R34C6 = 7, max R4C7 = 7, similarly min R3C6 + R4C7 = 7, max R4C6 = 7

26. 45 rule on N7 3 innies R9C123 = 14 -> R89C4 = 6 = {15/24}

27. 45 rule on N9 3 innies R9C789 = 14 -> R89C6 = 13 = {49/58/67}, no 1,2,3

28. 45 rule on N8 2 remaining innies R7C46 = 5 = {23} (the only remaining 3s in N8), locked for R7 and N8, clean-up: no 7,8 in R8C2, no 4 in R8C3, no 8,9 in R8C7 and R8C9, no 6,7 in R8C8, no 4 in R89C4

29. R89C4 = {15}, locked for C4 and N8, no 1,5 in R9C123, clean-up: no 3,7 in R5C3, no 8 in R89C6

30. 8 in N8 locked in R789C5 = 8{49/67}, 8 locked for C5 [Corrected]

31. 16(3) cage in N458, R7C4 = {23}, valid combinations {268/349/358/367} ({259} not possible because 5,9 are in same cell), no other 2,3 in this cage, no 1,4 in R6C3 -> R6C3 = {56789}, R6C4 = {468}

32. 4 in C4 locked in R46C4, locked for N5, clean-up: no 8 in R5C7

33. 16(3) cage in N658, R7C6 = {23}, valid combinations {259/268/349/358/367}, no other 2,3 in this cage, no 1 in R6C67 -> R6C6 = {56789}, R6C7 = {456789}

34. 17(3) cage in N254, R3C4 = {68}, valid combinations {269/278/368/458/467}, no 4 in R4C3 -> R4C3 = {356789}, R4C4 = {23468}

35. 14(3) cage in N256, R3C6 = {68}, valid combinations {158/167/248/356}, no 6 in R4C6, no 2,6 in R4C7 -> R4C6 = {12357}, R4C7 = {13457}

36. 14(3) sub-cage R9C123 in N9, valid combinations {239/248/347}, no 6

37. R78C3 = {15} (the only remaining 5s in N7 - I should have spotted this earlier), locked for C3 and N9, clean-up: no 6 in R2C3, no 9 in R78C2, no 3 in R5C4 -> R5C34 = {26}, locked for R5

38. 45 rule on N4 3 innies R456C3 = 18, R5C3 = {26} (step 37), valid combinations {279/369} = 9{27/36}, no 6,8 in R46C3, R4C3 = {379}, R6C3 = {79}, 9 locked for C3 and N4, 8 in N4 in R456C2, locked for C2, clean-up: no 2 in R23C3, no 2 in R8C2 [Some of this was added when I was checking my walkthrough]

39. 2 in N7 locked in R9C123, locked for R9, R9C123 = 2{39/48}, no 7

40. 15(3) cage in N5 = {159} ({267} would clash with R5C4), locked for C5 and N5 -> R123C5 = {234}, locked for C5 and N2, R789C5 = {678}, locked for N8, R12C6 = {15}, no 1,5 in R1C789, R89C6 = {49}, no 4,9 in R9C789, clean-up: no 3,7 in R5C7

41. 1 in N3 locked in R3C79, clean-up: no 7 in R2C2
41a. 1 in R3C7 -> R2C7 = 6
41b. 1 in R3C9 -> R2C9 = 8
41c. {68} in R2C79, {68} in R2C1, killer pair 6/8, no other 6,8 in R2 including no 6 in R2C9, clean-up: no 2 in R3C2, no 3 in R3C3, no 4 in R3C8, no 3 in R3C9
[At this stage the obvious move is to use R23C3 = {47} to fix R23C1 but I didn’t see that first time through because I hadn’t seen that 9 could be fixed in R46C3 (step 38) when I first solved this puzzle]
41d. {368} not valid in R1C789 (it would clash with R23C7 if that was {16/34} or would clash with R23C8 if R23C7 = {25}), no 3 in R1C789

42. 9 in N9 locked in R7C79, locked for R7, clean-up: no 6 in R8C1, 2 in N9 locked in R8C79 (one of the 11(2) cages must be {29}), no 7 in R7C8

43. R23C3 = {47}, locked for C3 and N1, R3C1 = 9 (naked single), R2C1 = 6, clean-up: no 1 in R2C2 -> R23C2 = {35}, locked for C2 and N1, no 7 in R7C2 -> R78C2 = {46}, locked for C2 and N7, R78C1 = {78}, locked for N7, R9C2 = 9 (hidden single), R9C13 = {23}, locked for R9, more clean-up: no 1 in R3C7, no 3 in R2C8

44. R3C9 = 1 (hidden single in N3), R2C9 = 8, clean-up: no 3 in R8C9 [Corrected]

45. R6C3 = 9 (naked single), R4C3 = 3 (naked single), R9C123 = [392], R9C6 = 4, R8C6 = 9

46. R1C3 = 8, R1C12 = {12}, locked for R1, R1C6 = 5, R2C6 = 1

47. R1C789 = {467} (subtraction combo), locked for R1 and N3, R1C5 = 3 (naked single in R1), clean-up: no 3 in R23C7 -> R23C7 = {25}, locked for C7 and N3, more clean-up: no 7 in R5C6, no 6 in R78C7, no 9 in R7C7, R23C8 = [93], R2C4 = 7, R1C4 = 9, R3C2 = 5, R2C2 = 3, R3C7 = 2, R2C7 = 5, R3C5 = 4, R2C5 = 2, R2C3 = 4, R3C3 = 7, clean-up: no 6 in R7C8

48. R5C3 = 6, R5C4 = 2, R7C4 = 3, R6C4 = 4, R34C4 = {68}, R7C6 = 2, no 7 in R6C67 (16(3) cage cannot be {277}) -> R6C67 = {68}, locked for R6

49. 4 in N4 locked in 13(3) cage = 4{18/27}, no 5 -> R6C1 = 5 (hidden single in N4), rest of 14(3) cage = {18/27}, R6C5 = 1 (naked single), no 8 in R5C2 -> R56C2 = [72]

50. R4C2 = 8, R45C1 = {14}, R1C12 = [21]

51. R6C89 = [73], R5C8 = 8, clean-up: no 1 in R78C8, R6C7 = 6, R6C6 = 8, R3C6 = 6, R3C4 = 8, R4C4 = 6, R5C6 = 3, R5C7 = 9

and the rest is naked and hidden singles, simple elimination and cage sums

Assassin 32 V2 by frank (Jan 07)
Puzzle pic:
Image
Code: Select, Copy & Paste into solver:
3x3::k:7424:2309:2309:4876:4876:2061:2307:3846:5922:7424:1796:1796:4876:2061:2061:2307:3846:5922:7424:3091:3091:4373:3350:3607:1304:1304:5922:7424:7424:4373:4373:3350:3607:3607:5922:5922:3620:3620:3620:2599:2599:2599:5418:5418:5418:6446:6446:4153:4153:1841:4155:4155:6992:6992:6446:1335:1335:4153:1841:4155:3388:3388:6992:6446:3842:1856:3650:5187:5187:1799:1799:6992:6446:3842:1856:3650:3650:5187:2117:2117:6992:
Solution:
+-------+-------+-------+
| 2 1 8 | 9 3 5 | 4 6 7 |
| 6 3 4 | 7 2 1 | 5 9 8 |
| 9 5 7 | 8 4 6 | 2 3 1 |
+-------+-------+-------+
| 4 8 3 | 6 9 7 | 1 2 5 |
| 1 7 6 | 2 5 3 | 9 8 4 |
| 5 2 9 | 4 1 8 | 6 7 3 |
+-------+-------+-------+
| 7 4 1 | 3 6 2 | 8 5 9 |
| 8 6 5 | 1 7 9 | 3 4 2 |
| 3 9 2 | 5 8 4 | 7 1 6 |
+-------+-------+-------+
Quote:
frank, lead-in: I found it a very slow start, and then once I got the first few numbers the rest were easy
sudokuEd: does finish surprisingly quick, but did take a while to get to there
Andrew: definitely harder than Ruud's original puzzle...I found it the harder of the two variants
Walk-through by Andrew:
Frank’s Version

Clean-up is used in various steps, using the combinations in steps 1 to 14 for further eliminations from these two cell cages; it is also used for the two cell sub-cages that are produced by applying the 45 rule. In some of the later steps, clean-up is followed by further moves and sometimes more clean-up.

1. R1C23 = {18/27/36/45}, no 9

2. R12C7 = {18/27/36/45}, no 9

3. R12C8 = {69/78}

4. R2C23 = {16/25/34}, no 7,8,9

5. R3C23 = {39/48/57}, no 1,2,6

6. R3C78 = {14/23}

7. R34C5 = {49/58/67}, no 1,2,3

8. R67C5 = {16/25/34}, no 7,8,9

9. R7C23 = {14/23}

10. R7C78 = {49/58/67}, no 1,2,3

11. R89C2 = {69/78}

12. R89C3 = {16/25/34}, no 7,8,9

13. R8C78 = {16/25/34}, no 7,8,9

14. R9C78 = {17/26/35}, no 4,8,9

15. 8(3) cage in N2 = 1{25/34}, 1 locked for N2

16. 10(3) cage in N5 = {127/136/145/235}, no 8,9

17. 21(3) cage in N6 = {489/579/678}, no 1,2,3

18. 20(3) cage in N8 = {389/479/569/578}, no 1,2

19. 45 rule on N1 3 innies R123C1 = 17 -> R4C12 = 12 = {39/48/57}, no 1,2,6

20. 45 rule on N3 3 innies R123C9 = 16 -> R4C89 = 7 = {16/25/34}, no 7,8,9

21. 45 rule on N7 3 innies R789C1 = 18-> R6C12 = 7 = {16/25/34}, no 7,8,9

22. 45 rule on N9 3 innies R789C9 = 17 -> R6C89 = 10, no 5

23. 45 rule on N4 2 innies R46C3 = 12 = {39/48/57}, no 1,2,6

24. 45 rule on N6 2 innies R46C7 = 7 = {16/25/34}, no 7,8,9

25. 45 rule on C1 3 innies R456C1 = 10 = {127/136/145/235}, no 8,9, clean-up: no 3,4 in R4C2

26. 45 rule on N8 3 innies R7C456 = 11 = {146/236} (cannot be {128/137/245} which would clash with R7C23) = 6{14/23}, no 5,7,8,9, 6 locked for R7 and N8, 1,2,3,4 locked for R7C23456, clean-up: no 2 in R6C5, no 7,9 in R7C78 -> R7C78 = {58}, locked for R7 and N9, R7C19 = {79}, 9 locked in R789C9 for C9, clean-up: no 1 in R6C8, no 2 in R8C78, no 3 in R9C78

27. R12C8 = {69} (only remaining 9s in N3), locked for C8 and N3, clean-up: no 3 in R12C7, no 1 in R4C9, no 1,4 in R6C9, no 1 in R8C7, no 2 in R9C7

28. R5C7 = 9 (hidden single in N6), R5C89 = 12 = {48/57}, no 6

29. R12C7 must contain one of 5,7,8 -> 16(3) sub-cage R123C9 must contain two of 5,7,8 = {178/358/457}, no 2

30. 16(3) cage in N658, R6C7 = {123456}, R7C6 = {12346}, only valid combinations {169/259/268/349/358/367/457} -> R6C6 = {789}

31. Only valid combinations for 17(3) sub-cage R789C9 are 9{17/26} (9 was locked in step 26), no 3,4 -> R8C78 = {34}, locked for R8, clean-up: no 3,4 in R9C3
31a. R46C7 (step 24) cannot be {34} -> R46C7 {16/25}
31b. No {349} combination in 16(3) cage in N658

32. Only cells with 3,4 in N7 are R7C23 and R9C1. R7C23 = {14/23} -> R9C1 = {34} -> no 3,4 in R6C12

33. Only valid combinations for 18(3) sub-cage R789C1 with R7C1 = {79} and R9C1 = {34} are [783/963/954] -> R8C1 = {568}

Note. After step 31 could have used killer pair 1,2 in R7C23 and R89C3 but steps 32 and 33 are more powerful and eliminate 1,2 from the remaining cells in N7.

34. R6C12 must contain 1 or 2 -> R5C123 must contain 1 or 2, valid combinations are {158/167/248/257}, no 3 [must contain one of 4,5,6 and either 7 or 8]
34a. Either R4C12 or R46C3 must be {39}

35. 3 in R5 locked in R5C456, locked for N5, R5C456 = 3{16/25}, no 4,7, clean-up: no 4 in R7C5
35a. R5C89 = {48/57} [4/7] -> R5C123 = {167/248/257} (cannot be {158})

36. 1 in N6 must be either in the R46C7 7(2) sub-cage or in the R6C89 7(2) sub-cage so one of these sub-cages must be {16}, no other 6 in N6, clean-up: no 4 in R6C8 [this elimination could alternatively have been made because both R5C89 and R6C89 require 7 or 8 so must be {48/57} and {28/37} respectively]

37. 45 rule on N2 3 innies R3C456 = 18

38. 45 rule on R3 2 innies R3C19 = 10 = {19/28/37/46}, no 5, clean-up: no 1,4,8 in R3C1

39. 1 in R3 locked in R3C789, locked for N3, clean-up: no 8 in R12C7

40. R7C7 = 8 (hidden single in C7), R7C8 = 5, clean-up: no 2 in R4C9, no 7 in R5C9

41. 8 in N3 locked in R123C9, locked for C9, clean-up: no 4 in R5C8, no 2 in R6C8, R123C9 = 8{17/35}, no 4, no 7 in R3C9, clean-up: no 3,6 in R1C9

42. 4 in C9 locked in R45C9, locked for N6, clean-up: no 3 in R4C9

43. 1 in C9 only in R389C9 so either R123C9 or R789C9 must contain {17} -> no 7 in R6C9, clean-up: no 3 in R6C8, R56C8 = {78}, locked for C8, clean-up: no 1 in R9C7

44. 20(3) cage in N8 min R8C56 = 12 -> max R9C6 = 8

Looks like it now needs a contradiction move to break it open!

45. If R12C7 = {27} => R46C7 = {16} clashes with R9C7 = {67} -> R12C7 not {27}
45a. R12C7 = {45}, locked for C7 and N3, R8C78 = [34], R3C78 = [23], R46C7 = {16}, locked for C7 and N6, R9C7 = 7 (naked single), R9C8 = 1, clean-up: no 9 in R3C23, no 8 in R8C2, no 6 in R8C3
45b. R12C9 = {78}, R3C9 = 1
45c. R7C9 = 9 (naked single), R89C9 = {26}, locked for C9
45d. R6C9 = 3, R6C8 = 7, R5C8 = 8, R5C9 = 4, R4C9 = 5, R4C8 = 2 (naked singles), clean-up: no 7 in R4C12

Wow! That was an effective key.

46. R7C1 = 7 (naked single), R89C1 = [83] (step 33), clean-up: no 9 in R4C2, no 2 in R7C23
46a. R7C23 = {14}, locked for R7 and N7, R89C2 = {69}, locked for C2 and N7, R89C3 = {25}, locked for C3, clean-up: no 4,7 in R1C2, no 3 in R1C3, no 2,5 in R2C2, no 1 in R2C3, no 7 in R3C2, no 6 in R6C5

47. R4C12 = [48], R3C1 = 9 (naked singles), R12C1 = {26} (only valid combination), locked for C1 and N1, clean-up: no 3 in R1C2, no 7 in R1C3, no 1 in R2C2, no 1,5 in R6C2
47a. R2C23 = {34}, locked for R2 and N1, clean-up: no 5 in R1C2, no 5 in R1C7, no 8 in R3C23
47b. R12C7 = [45], R3C23 = [57] (naked singles)
47c. R2C56 = {12}, locked for R2 and N2, R1C6 = 5
47d. R3C456 = {468}, 19(3) cage in N2 = {379}

and the rest is naked and hidden singles, simple elimination and cage sums
Assassin 32 v3 by sudokuEd (Jan 07)
Puzzle pic:
Image
Code: Select, Copy & Paste into solver:
3x3::k:6661:1553:1553:3618:3618:3883:2878:2878:6980:6661:3088:3088:3618:3883:3883:3133:3133:6980:6661:2575:2575:3607:3113:3378:2108:2108:6980:6661:6661:3607:3607:3113:3378:3378:6980:6980:1284:1284:3329:3329:6943:6943:6943:6943:6943:6144:6144:3605:3605:2086:4143:4143:5954:5954:6144:2827:2827:3605:2086:4143:2360:2360:5954:6144:2826:2826:2587:4389:4389:2615:2615:5954:6144:3849:3849:2587:2587:4389:3126:3126:5954:
Solution:
+-------+-------+-------+
| 7 5 1 | 8 4 3 | 9 2 6 |
| 6 9 3 | 2 5 7 | 8 4 1 |
| 4 8 2 | 1 9 6 | 5 3 7 |
+-------+-------+-------+
| 8 1 6 | 7 3 5 | 2 9 4 |
| 3 2 4 | 9 8 1 | 6 7 5 |
| 9 7 5 | 6 2 4 | 3 1 8 |
+-------+-------+-------+
| 5 4 7 | 3 6 9 | 1 8 2 |
| 1 3 8 | 5 7 2 | 4 6 9 |
| 2 6 9 | 4 1 8 | 7 5 3 |
+-------+-------+-------+
Quote:
sudokuEd, lead-in: Faster start than Frank's, but then makes you work a bit harder in the middle
frank: got off to a fast start.... but then had to work hard as you predicted. Eventully I found a key to unlock the brute, and then sailed through the rest
Andrew: definitely harder than Ruud's original puzzle
Walkthrough by Andrew:
Ed’s Version

Clean-up is used in various steps, using the combinations in steps 1 to 16 for further eliminations from these two cell cages; it is also used for the two cell sub-cages that are produced by applying the 45 rule. In some of the later steps, clean-up is followed by further moves and sometimes more clean-up.

1. R1C23 = {15/24}

2. R1C78 = {29/38/47/56}, no 1

3. R2C23 = {39/48/57}, no 1,2,6

4. R2C78 = {39/48/57}, no 1,2,6

5. R3C23 = 10(2), no 5

6. R34C5 = {39/48/57}, no 1,2,6

7. R3C78 = {17/26/35}, no 4,8,9

8. R5C12 = {14/23}

9. R5C34 = {49/58/67}, no 1,2,3

10. R67C5 = {17/26/35}, no 4,8,9

11. R7C23 = {29/38/47/56}, no 1

12. R7C78 = {18/27/36/45}, no 9

13. R8C23 = {29/38/47/56}, no 1

14. R8C78 = 10(2), no 5

15. R9C23 = {69/78}

16. R9C78 = {39/48/57}, no 1,2,6

17. 10(3) cage in N8 = {127/136/145/235}, no 8,9

18. 45 rule on N1 3 innies R123C1 = 17 -> R4C12 = 9 = {18/27/36/45}, no 9

19. 45 rule on N3 3 innies R123C9 = 14 -> R4C89 = 13 = {49/58/67}

20. 45 rule on N7 3 innies R789C1 = 8 = 1{25/34}, 1 locked for C1, clean-up: no 8 in R4C2, no 4 in R5C2, R6C12 = 16 = {79}, locked for R6 and N4, clean-up: no 2 in R4C12, no 4,6 in R5C4, no 1 in R7C5

21. 45 rule on N9 3 innies R789C9 = 14 -> R6C89 = 9 = {18/36/45}, no 2

22. 45 rule on C1 3 innies R456C1 = 20, only valid combination = [839] -> R456C2 = [127], R456C3 = {456}, locked for C3, clean-up: no 8 in R2C2, no 4,6 in R3C2, no 3,8,9 in R3C3, no 4 in R3C5, no 5 in R4C89, no 5 in R5C4, no 5,6 in R7C2 and R8C2, no 9 in R7C3 and R8C3, no 9 in R9C2, no 8 in R9C3

23. R789C1 = {125}, locked for C1 and N7, clean-up: no 9 in R7C2 and R8C2

24. R9C2 = 6, R9C3 = 9 (hidden singles in N7), clean-up: no 3 in R2C2, no 3 in R9C78
24a. R9C78 = {48/57} -> no {45} in R7C78

25. R123C1 = {467}, locked for N1, clean-up: R1C2 = 5, R1C3 = 1, no 6 in R1C67, no 8 in R2C3, R2C23 = [93], R3C23 = [82], clean-up: no 6 in R3C78, no 4 in R4C5

26. 6 in N3 locked in R123C9, locked for C9, no 6 in R4C8, clean-up: no 7 in R4C89, no 3 in R6C8, R123C9 = 6{17/35}, no 2,4,8,9, R4C89 = {49}, locked for R4 and N6, clean-up: no 3 in R3C5, no 5 in R6C89

27. R123C9 = 6{17/35} (step 26) and R3C78 = {17/35}, 3,5,7 locked for N3 -> R2C78 = {48}, locked for R2 and N3 -> R1C78 = {29}, locked for R1

28. 45 rule on N2 3 innies R3C456 = 16, 9 locked in R3C456 = 9{16/34}, no 5,7 -> R3C5 = 9, R4C5 = 3, clean-up: no 5 in R67C5
28a. 5 in R3 locked in R3C789, locked for N3

29. R3C46 = {16/34}, R3C78 = {17/35}, killer pair 1,3 for R3
29a. Only 1 in R123C9 is in R2C9, no 7 in R2C9

30. 45 rule on N8 3 innies R7C456 = 18, valid combinations with R7C5 = {267} are {279/369/378/468/567}, no 1 (note that {279} can use either the 2 or the 7 in R7C5)

31. 2 in N6 locked in R46C7, locked for C7 -> R1C7 = 9, R1C8 = 2, clean-up: no 7 in R7C78, no 8 in R8C78, no 1 in R8C8

32. 2 in C9 locked in R789C9 = 2{39/48/57}, no 1

33. 45 rule on C9 3 innies R456C9 = 17, valid combinations are [458/953/971] -> R5C9 = {57}

34. R123C9 = 6{17/35} (step 26), if R123C9 is not {167} then R456C9 must be [971] -> no 7 in R789C9, clean-up: no 5 in R789C9

35. R9C78 = {57} (only remaining 5s in N9), locked for R9 and N9, clean-up: no 3 in R8C78

36. 10(3) cage in N8 = {136/145/235} (step 17), ({127} now not valid because it would clash with R9C1), no 7, 1,2,3,4 are locked in R9C45 for the 10(3) cage -> R8C4 = {56}
36a. R9C45 contain 1 or 2, R9C1 = {12}, killer pair 1,2 for R9

37. 17(3) cage in N8 valid combinations with R9C6 = {348} are {278/359/368/458/467}, no 1

38. 1 in N8 locked in R9C45, locked for R9, 10(3) cage = 1{36/45}, no 2

39. R9C1 = 2 (naked single in R9)

40. 14(3) cage in N254 valid combinations are {167/356} (cannot have {257} because 2,7 both in same cell) = 6{17/35}, no 2,4, clean-up: no 3 in R3C6

41. 2 in R4 locked in 13(3) cage in N256 = 2{47/56}, no 1, R3C6 = {46} -> R4C67 = {257}, clean-up: no 6 in R3C4

42. 6 in R4 locked in 14(3) cage in N254, R3C4 = {13} -> R4C34 = {567}

43. 14(3) and 15(3) cages in N2 must each have 7 or 8

44. Valid combinations for 14(3) cage in N2 {167/248/347/356} (cannot have {158} because 1,5 in the same cell, cannot have {257} because 2,5 in the same cell), no 6 in R2C4
44a. 14(3) cage must have 4 or 6, R3C6 = {46}, killer pair 4,6 for N2

45. Valid combinations for 15(3) cage in N2 {258/357} = 5{28/37}, no 7 in R1C6, no 1 in R2C56, 5 locked in R2C56, locked for R2
45a. {356} not now valid for 14(3) cage in N2

46. 1 in N2 locked in R23C4, locked for C4 -> R9C5 = 1 (hidden single in N8), clean-up: no 7 in R7C5, R67C5 = {26}, locked for C5
46a. From combinations for 14(3) cage in N2 (step 44), no 7 in R1C4
46b. From combinations for 17(3) cage in N8 (step 37), no 3,7 in R8C6

47. Combinations for 16(3) cage in N658 {169/178/259/268/349/358/367/457} -> no 4 in R7C6

48. Valid combinations for 14(3) cage in N458 with R6C3 = {456} are {248/257/356} (cannot be {347} because 3,7 in the same cell), no 9, no 4 in R6C4, no 4,5,6 in R7C4
48a. R5C4 = 9 (hidden single in C4), R4C4 = 4
48b. Valid combinations for 14(3) cage in N458 with R6C3 = {56} are {257/356} = 5{27/36}, no 8, no 2 in R7C4, 5 locked in R6C34, locked for R6

49. R1C4 = 8 (hidden single in C4) -> only valid combination for 14(3) cage in N2 = [842]

50. R1C6 = 3 (naked single), R2C56 = {57}, locked for R2, R3C4 = 1, R3C6 = 6, clean-up: no 7 in R3C78 = {35}, locked for R3

51. R2C1 = 6, R1C1 = 7, R3C1 = 4

52. R123C9 = [617], clean-up: no 8 in R6C8

53. R5C9 = 5, 6 in R5 locked in R5C78, locked for N6 -> R6C89 = [18], R5C78 = {67}, locked for R5 and N6 -> R5C56 = [81], clean-up: no 8 in R7C7, R4C7 = 2, R4C6 = 5, R6C7 = 3

and the rest is naked and hidden singles, simple elimination and cage sums


Top
 Profile  
Reply with quote  
Display posts from previous:  Sort by  
Post new topic Reply to topic  [ 75 posts ]  Go to page Previous  1, 2, 3, 4, 5, 6 ... 8  Next

All times are UTC


Who is online

Users browsing this forum: No registered users and 61 guests


You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot post attachments in this forum

Search for:
Jump to:  
Powered by phpBB® Forum Software © phpBB Group