I tried this puzzle for the first time this year. I'd found Maverick 1 very difficult, so didn't try Mav 2 when it was posted. Also I might have been put off by comments that I'd given too high a rating for my walkthrough for Mav 1.
Prelims
a) R1C67 = {39/48/57}, no 1,2,3
b) R3C23 = {29/38/47/56}, no 1
c) R34C6 = {14/23}
d) R34C8 = {79}
e) R67C2 = {14/23}
f) R67C4 = {29/38/47/56}, no 1
g) R7C78 = {29/38/47/56}, no 1
h) R9C34 = {19/28/37/46}, no 5
1) 8(3) cage at R2C5 = {125/134}
j) 20(3) cage at R3C4 = {389/479/569/578}, no 1,2
Steps resulting from Prelims
1. 8(3) cage at R2C5 = {125/134}, 1 locked for C5
1a. Naked pair {79} in R34C8, locked for C8, clean-up: no 2,4 in R7C7
2. 17(3) cage at R6C5 = {269/278/368/467} (cannot be {359/458} which clash with 8(3) cage at R2C5), no 5
3. 45 rule on C5 3 innies R159C5 = 20 = {389/479/569/578}, no 2
4. 45 rule on R1234 2 innies R4C27 = 12 = {39/48/57}, no 1,2,6
5. 45 rule on R6789 2 innies R6C38 = 7 = {16/25/34}, no 7,8,9
6. 20(3) cage at R3C4 = {389/569/578} (cannot be {479} because 4{79} clashes with R4C8 and 7{49}/9{47} clash with R4C27 + R4C8, killer ALS block), no 4
6a. 3 of {389} must be in R4C34 (R4C34 cannot be {89} which clashes with R4C278) -> no 3 in R3C4
7. 33(7) cage at R4C7 = {1234689/1235679/1245678}, CPE no 1,2,6 in R5C12
8. 45 rule on N1 1 outie R4C1 = 1 innie R2C3 + 3, no 7,8,9 in R2C3, no 1,2,3 in R4C1
9. 45 rule on N9 2 outies R6C9 = 1 innie R8C7 + 2, no 1,2 in R6C9, no 8,9 in R8C7
10. 13(3) cage at R6C6 = {139/148/157/238/247/256/346}
10a. 9 of {139} must be in R67C6 (R67C6 cannot be {13} which clashes with R34C6) -> no 9 in R6C7
11. 17(3) cage at R4C2 = {359/458}, no 7, 5 locked for N4, clean-up: no 2 in R2C3 (step 8), no 5 in R4C7 (step 4), no 2 in R6C8 (step 5)
12. 20(3) cage at R3C4 (step 6) = {389/569/578}
12a. 5 of {578} must be in R4C4 (R4C34 cannot be {78} which clashes with R4C27 + R4C8, killer ALS block) -> no 7 in R4C4
13. 45 rule on C1 2 innies R15C1 = 1 outie R9C2
13a. Min R15C1 = 4 -> min R9C2 = 4
13b. Max R15C1 = 9, no 7,8,9 in R1C1, no 9 in R5C1
14. 45 rule on C89 2 outies R79C7 = 1 innie R2C8 + 11
14a. Min R79C7 = 12, no 1,2 in R9C7
14b. Max R79C7 = 17 -> max R2C8 = 6
15. 33(7) cage at R4C7 = {1234689/1235679/1245678}, R6C38 (step 5) = {16/25/34}
15a. 14(3) cage at R5C8 = {167/257/347} (cannot be {149/158/239/248/356} which clash with 33(7) cage because R5C89 “see” all of 33(7) cage except for R6C3 and R6C38 are linked as a hidden cage; the three remaining combinations remain valid because of R6C38) , no 8,9 -> R5C9 = 7, R34C8 = [79], clean-up: no 5 in R1C6, no 6 in R2C3 (step 8), no 4 in R3C23, no 3,5 in R4C2, no 3 in R4C7 (both step 4), no 5,7 in R8C7 (step 9)
15b. 2 of {257} must be in R5C8 -> no 5 in R5C8
[Maybe there’s some direct way to prove that R6C38 must equal R6C8 plus one of R5C89? If there is, I didn’t spot it.
After step 11, I’d missed 7 in R5 only in R5C345679, CPE no 7 in R4C7 which Afmob and Para both used. In a way I’m glad that I missed that as then I wouldn’t have found my interesting step 15a. ]
16. Naked pair {48} in R4C27, locked for R4, clean-up: no 1,5 in R2C3 (step 8), no 1 in R3C6
17. 20(3) cage at R3C4 (step 6) = {569/578} (cannot be {389} because 8,9 only in R3C4), no 3
17a. 8,9 only in R3C4 -> R3C4 = {89}
17b. Naked pair {67} in R4C13, locked for R4 and N4 -> R4C4 = 5, clean-up: no 6 in R67C4, no 1 in R6C8 (step 5), no 6 in R5C8 (step 15a)
18. 33(7) cage at R4C7 = {1234689} (only remaining combination), no 5
19. 45 rule on C9 1 outie R1C8 = 1 remaining innie R9C9 + 4, R1C8 = {568}, R9C9 = {124}
20. 17(3) cage at R4C2 (step 11) = {458} (only remaining combination, cannot be {359} because R4C2 only contains 4,8), locked for N4, clean-up: no 3 in R6C8 (step 9), no 4 in R5C8 (step 15a), no 1 in R7C2
21. 18(3) cage at R2C1 = {279/369/378/468/567} (cannot be {189/459} because R4C1 only contains 6,7), no 1
22. 18(3) cage at R6C9 = {189/369/459/468}, no 2
23. 45 rule on N3 3(2+1) remaining outies R12C6 + R4C9 = 15
23a. Max R4C9 = 3 -> min R12C6 = 12, no 1,2 in R2C6
24. R1C8 = R9C9 + 4 (step 19)
24a. 24(5) cage at R1C8 = {13569/14568/23568} (cannot be {12489/23469} which give innie-outie difference clash with R1C8 + R9C9), 5,6 locked for N3, clean-up: no 7 in R1C6
25. R12C6 + R4C9 = 15 (step 23)
25a. R4C9 = {123} -> R12C6 = 12,13,14 cannot be {57/67} because 5,6,7 only in R2C6 -> no 7 in R2C6
26. 7 in N2 only in 18(4) cage at R1C4 = {1467/2367/2457} (cannot be {1278} because R2C3 only contains 3,4), no 8,9
26a. R2C3 = {34} -> no 3,4 in R1C45 + R2C4
27. R159C5 (step 3) = {479/569/578} (cannot be {389} because R1C5 only contains 5,6,7), no 3
27a. 8 of {578} must be in R5C5 -> no 8 in R9C5
28. 17(3) cage at R6C5 (step 2) = {269/278/368} (cannot be {467} which clashes with R159C5), no 4
29. 45 rule on C1234 3 innies R56C3 + R5C4 = 1 outie R1C5 + 3
29a. R1C5 = {567} -> R56C3 + R5C4 = 8,9,10, no 8,9 in R5C34
29b. R56C3 = {123} -> R5C4 = {46} (only way to make total greater than 6)
30. R6C1 = 9 (hidden single in N4), clean-up: no 2 in R23C1 (step 21), no 2 in R7C4
31. R15C1 = R9C2 (step 13)
31a. Min R15C1 = 5 -> min R9C2 = 5
31b. Max R9C2 = 8 -> max R15C1 = 8, no 8 in R5C1
31c. 8 in N4 only in R45C2, locked for C2, clean-up: no 3 in R3C3
31d. 5 in N4 only in R5C12
5 in R5C1 => min R15C1 = 6 or 5 in R5C2 => no 5 in R9C2
-> min R9C2 = 6
31e. R9C2 = {67}, min R5C1 = 4 -> max R1C1 = 3
32. 45 rule on N9 3 innies R78C9 + R8C7 = 16 = {169/259/268/349} (cannot be {358} = {58}3 because 18(3) cage at R6C9 cannot be 5{58})
32a. R7C78 = {38/56}/[74] (cannot be [92] which clashes with R78C9 + R8C7), no 2,9
33. 45 rule on N7 3(1+2) remaining outies R6C2 + R89C4 = 9 -> max R89C4 = 8, no 8,9 in R89C4, clean-up: no 1,2 in R9C3
34. Hidden killer pair 8,9 in R3C4 and R67C4, R3C4 = {89} -> R67C4 must contain one of 8,9 -> R67C4 = [29/38/83], no 4,7
35. 7 in N9 only in R7C78 = [74] or in 18(4) cage at R8C8 -> if 18(4) cage contains 4 it must also contain 7 (locking cages)
35a. 18(4) cage = {1278/1359/1368/1467/2358/2457} (cannot be {1458/2349/3456} which contain 4 but not 7, cannot be {2367} which clashes with R7C78, cannot be {1269} which clashes with R78C9 + R8C7)
35b. R1C8 = R9C9 + 4 (step 19)
35c. 18(4) cage = {1278/1368/1467/2358/2457} (cannot be {1359} which gives innie-outie difference clash with R1C8 + R9C9), no 9
35d. 7 of {1467/2457} must be in R9C7 -> no 4 in R9C7
36. 9 in N9 only in R78C9, locked for C9
36a. R78C9 + R8C7 (step 32) contains 9 = {169/259/349}, no 8
37. 24(5) cage at R1C8 (step 24a) = {14568/23568}, 8 locked for N3, clean-up: no 4 in R1C6
38. 17(4) cage at R2C6 = {1259/1349/2348} (cannot be {1268/1358/2456} because 5,6,8 only in R2C6), no 6
39. 6 in N2 only in 18(4) cage at R1C4 (step 26) = {1467/2367}, no 5
40. R159C5 (step 27) = {479/569/578}
40a. R1C5 = {67} -> no 6,7 in R59C5
41. R12C6 + R4C9 = 15 (step 23)
41a. R4C9 = {123} -> R12C6 = 12,13,14 = {39/48/49/58/59}
41b. 4,5 of {48/58} must be in R2C6 -> no 8 in R2C6
42. 17(4) cage at R2C6 (step 38) = {1259/1349}, 1 locked for N3
43. 13(3) cage at R6C6 = {148/157/238/247/256/346} (cannot be {139} which clashes with R6C23, ALS block), no 9
44. 27(5) cage at R6C1 contains 9 = {12789/13689/14679/23679} (cannot be {14589/23589} because R9C2 only contains 6,7, cannot be {24579/34569} which clash with R5C1), no 5
45. R5C3 + R6C23 = {123} = 6
45a. 45 rule on N14 using R5C3 + R6C23 = 6, 2 remaining innies R24C3 = 10 = [37/46]
45b. Consider permutations for R24C3
R24C3 = [37] => 18(4) cage at R1C4 (step 39) = {2367}, 2 locked for C4 => R67C4 = {38}
or R24C4 = [46] => R3C4 = 9 (step 17) => R67C4 = {38}
-> R67C4 = {38}
[One of these options could be taken as far as a contradiction; I’ve avoided doing this because it’s not necessary.]
46. Naked pair {38} in R67C4, locked for C4 -> R3C4 = 9, R4C3 = 6 (step 17), R2C3 = 4 (step 45a), R4C1 = 7, clean-up: no 3 in R1C7, no 2,5 in R3C2, no 2 in R3C3, no 7 in R9C3, no 4,6 in R9C4
47. 17(4) cage at R2C6 (step 42) = {1259/1349} -> R2C7 = 9, R1C7 = 4, R1C6 = 8, R4C7 = 8, R4C2 = 4, R5C12 = [58], clean-up: no 1 in R6C2, no 6 in R6C9, no 6 in R8C7 (both step 9), no 3 in R7C8
48. Naked pair {23} in R67C2, locked for C2 -> R3C2 = 6, R3C3 = 5, R9C2 = 7, R12C2 = [91], R8C2 = 5, clean-up: no 3 in R9C3
49. Naked pair {38} in R23C1, locked for C1 and N1 -> R1C13 = [27], R1C5 = 6, R1C4 = 1, R9C4 = 2, R9C3 = 8, R2C4 = 7, R1C89 = [53], R9C9 = 1 (step 19), R4C9 = 2, R23C9 = [68], R2C8 = 2, R3C7 = 1, R2C6 = 5 (step 42), R2C5 = 3, R4C5 = 1, R4C6 = 3, R3C6 = 2, R3C5 = 4, R5C5 = 9, R9C5 = 5, clean-up: no 6 in R7C7
50. Naked pair {78} in R78C5, locked for C5 and N8 -> R6C5 = 2, R67C2 = [32], R6C3 = 1, R67C4 = [83], R78C3 = [93], R8C4 = 4 (cage sum), R8C7 = 2, R6C9 = 4 (step 9), R6C8 = 6, R6C67 = [75], R7C6 = 1 (cage sum)
and the rest is naked singles.
I'll rate my walkthrough for Maverick 2 at 1.75 because of step 15a which uses the interaction of a "sees all except" step with a hidden cage. I also used a couple of short forcing chains later.