Thanks Mike for a challenging variant.
Mike wrote:
outies on the corner nonets give you defined numbers straightaway then...middle third falls...after that it just seems to fall out
All of the above three assertions except one could be also be claimed to apply to the following puzzle. Guess which?
Thanks for the easy question. Now to try the puzzle.
Belated congratulations to nouggie for your first posted walkthrough.
It's surprising that this was the only walkthrough posted at the time (where was everybody?
) so here, at last, is the second one.
Here is my walkthrough for A63 V2.
Prelims
a) R4C12 = {19/28/37/46}, no 5
b) R4C89 = {12}
c) R5C12 = {17/26/35}, no 4,8,9
d) R5C89 = {17/26/35}, no 4,8,9
e) R6C12 = {49/58/67}, no 1,2,3
f) R6C89 = {29/38/47/56}, no 1
g) 20(3) cage at R1C2 = {389/479/569/578}, no 1,2
h) 11(3) cage at R1C6 = {128/137/146/236/245}, no 9
i) 14(4) cage at R2C2 = {1238/1247/1256/1346/2345}, no 9
j) 26(4) cage in N3 = {2789/3689/4589/4679/5678}, no 1
k) 26(4) cage at R4C6 = {2789/3689/4589/4679/5678}, no 1
1. Naked pair {12} in R4C89, locked for R4 and N6, clean-up: no 8,9 in R4C12, no 6,7 in R5C89, no 9 in R6C89
2. Naked pair {35} in R5C89, locked for R5 and N6, clean-up: no 6,8 in R6C89
3. Naked pair {47} in R6C89, locked for R6 and N6, clean-up: no 6,9 in R6C12
4. Naked pair {58} in R6C12, locked for R6 and N4
5. Naked triple {689} in R456C7, locked for C7
6. Killer pair 6,7 in R4C12 and R5C12, locked for N4
7. Killer pair 3,4 in R4C12 and R4C3, locked for R4 and N4
8. 9 in N4 only in R56C3, locked for C3, CPE no 9 in R6C4
9. 45 rule on N5 2 outies R5C37 = 9 = [18], clean-up: no 7 in R5C12
9a. Naked pair {26} in R5C12, locked for R5 and N4 -> R6C3 = 9, R46C7 = [96], clean-up: no 4 in R4C12
9b. Naked pair {37} in R4C12, locked for R4 -> R4C3 = 4
9c. R6C5 = 1 (hidden single in R6), R45C5 = 12 = [57/84], no 6 in R4C5, no 9 in R5C5
10. 45 rule on N1 1 remaining outie R1C4 = 3
10a. 20(3) cage at R1C2 = {389} (only remaining combination) -> R1C23 = [98]
10b. R6C4 = 2, R5C3 = 1 -> R45C4 = 12 = [57/84], no 6 in R4C4, no 9 in R5C4
10c. R6C6 = 3, R45C6 = [69] (hidden pair in N5)
11. 45 rule on N3 1 remaining outie R1C6 = 4, R1C78 = 7 = [16/25/52], no 7, no 1 in R1C8
12. 45 rule on N7 1 remaining outie R9C4 = 6, R9C23 = 7 = [25/43/52], no 1,7,8, no 3 in R9C2
13. 45 rule on N9 1 remaining outie R9C6 = 8, R9C78 = 4 = {13}, locked for R9 and N9, clean-up: no 4 in R9C2
13a. Naked pair {25} in R9C23, locked for R9 and N7
13b. R4C9 = 1 (hidden single in C9), R4C8 = 2, clean-up: no 5 in R1C7 (step 11)
14. 14(4) cage at R2C2 contains 4 = {1247/1346/2345}
14a. 1 of {1247/1346} must be in R2C2 -> no 6,7 in R2C2
14b. 3 of {2345} must be in R23C3 (R23C3 cannot be {25} which clashes with R9C3) -> no 3 in R2C2
[With hindsight I could have eliminated {1346} = 1{36}4 which clashes with R78C3, ALS block. However step 15b makes this elimination.]
15. 25(4) cage at R6C3 contains 9 = {3679} (only remaining combination because R78C3 must contain two of 3,6,7), 3,6,7 locked for N7
15a. 6 of {3679} must be in R78C3 (R78C3 cannot be {37} which clashes with 14(4) cage at R2C2) -> no 6 in R8C2
15b. 6 in N7 only in R78C3, locked for C3
15c. Naked pair {37} in R48C2, locked for C2
16. 23(4) cage at R6C7 contains 6 = {2678/4568} -> R8C8 = 8
16a. R78C7 = {27/45}
[I’ve put this step first to simplify step 17.]
17. 21(4) cage at R2C7 contains 9 = {1479/2379/3459} (cannot be {1569/2469} which clash with 11(3) cage at R1C6), no 6
17a. 1 of {1479} must be in R23C7 (R23C7 cannot be {47} which clashes with R78C7) -> no 1 in R2C8
18. 1 in N3 only in R123C7, locked for C7 -> R9C78 = [31]
18a. 21(4) cage at R2C7 (step 17) = {1479/2379/3459}
18b. 3 of {3459} must be in R2C8 -> no 5 in R2C8
19. 14(3) cage in N2 = {158/167/257}, no 9
19a. 9 in N2 only in R2C45, locked for N2
20. 14(3) cage in N8 = {239/257/347} (cannot be {149} which clashes with R7C12, ALS block), no 1
20a. 3 of {239/347} must be in R7C5 -> no 4,9 in R7C5
20b. 1 in N8 only in R8C46, locked for R8
21. Naked pair {49} in R89C1, locked for C1 and N7
22. R3C2 = 4 (hidden single in N1)
22a. R5C2 = 6 (hidden single in C2), R5C1 = 2
23. 45 rule on C89 2 remaining innies R12C8 = 9 = [54/63] -> R2C8 = {34}
23a. 21(4) cage at R2C7 (step 17) = {1479/2379/3459}
23b. 5 of {3459} must be in R3C7 -> no 5 in R2C7
23c. Killer pair 3,5 in R12C8 and R5C8, locked for C8
24. 17(4) cage in N8 must contain 1 = {1259/1349/1457}
24a. 3 of {1349} must be in R8C5, 9 of {1259} must be in R9C5 -> no 9 in R8C5
25. 26(4) cage in N3 must contain 8,9 = {2789/3689/4589}
25a. 5,6 on {3689/4589} must be in R1C9 -> no 5,6 in R2C9 + R3C89
25b. 6 in N3 only in R1C89, locked for R1
26. 14(3) cage in N2 (step 19) = {158/167} (cannot be {257} which clashes with R1C5), no 2, 1 locked for R3 and N2
26a. 6 of {167} must be in R3C5 -> no 7 in R3C5
27. 24(4) cage in N2 must contain 9 = {2589/2679}
27a. 6,8,9 only in R2C45 -> R2C4 = {89}, R2C5 = {689}
28. 18(4) cage in N1 contains 4,6 = {1467/3456}
28a. 5 of {3456} must be in R1C1 -> no 5 in R23C1
29. 45 rule on C1234 4 innies R2378C4 = 22 must contain 1,9 = {1489/1579}
29a. 1 of {1579} must be in R8C4 (R78C4 cannot be {57} which clashes with 14(3) cage in N8 (step 20) = {257}, CCC; note that 14(3) cage = {347} must have 4 in R7C4 so is not relevant to this clash) -> no 5,7 in R8C4
30. 14(3) cage in N8 (step 20) = {239/257/347}
30a. Consider combinations for 17(4) cage in N8 (step 24) = {1259/1349/1457}
17(4) cage = {1259/1457}, 5 locked for N8
17(4) cage = {1349} => R8C56 = [31], R8C4 + R9C5 = {49} => R2378C4 (step 29) = {1489} (cannot be {1579} because no 1,5,7 in R28C4) => no 5,7 in R7C4
30b. -> 14(3) cage in N8 = {239/347}, no 5 -> R7C5 = 3, R7C6 = {27}, R7C4 = {49}
30c. 5 in N8 only in R8C56, locked for R8, clean-up: no 4 in R7C7 (step 16a)
31. R2378C4 (step 29) = {1489} (cannot be {1579} because 5,7 only in R3C4), locked for C4 -> R45C4 = [57], R45C5 = [84]
32. Killer pair 7,9 in 14(3) cage and R9C5, locked for N8
33. 14(3) cage in N2 (step 26) = {158/167}
33a. R3C5 = {56} -> no 5 in R3C6
34. 14(3) cage in N8 (step 30b) = {239/347}, 17(4) cage in N8 (step 33) = {1259/1457}, R78C7 (step 16a) = {27/45}
34a. Consider combinations for 14(3) cage
14(3) cage = {239} => R9C5 = 7, R8C456 = [451] => R78C7 = [72] => R7C3 = 6
14(3) cage = {347} = [437] => R7C3 = 6
34b. -> R7C3 = 6, R8C23 = {37}, locked for R8, clean-up: no 2 in R7C7 (step 16a)
35. Naked quad {1245} in R8C4567, locked for R8 -> R89C1 = [94], R8C9 = 6
35a. 24(4) cage in N9 must contain 6,9 = {2679/4569}
35b. 2,5 only in R7C9 -> R7C9 = {25}
35c. Naked triple {257} in R7C679, locked for R7
36. Naked triple {479} in R367C8, locked for C8 -> R2C8 = 3, R5C89 = [53], R1C8 = 6, R1C7 = 1 (step 11)
37. 18(4) cage in N1 (step 28) = {1467/3456}
37a. R1C1 = {57} -> no 7 in R23C1
38. 14(4) cage at R2C2 (step 14) = {1247/2345}
38a. 3 of {2345} must be in R3C3 -> no 5 in R3C3
39. 24(4) cage in N9 (step 35a) = {2679/4569} = [9267/4569]
39a. R6C89 = [74] (cannot be [47] which clashes with 24(4) cage in N9, combo blocker)
and the rest is naked singles.
Rating comment. I'll rate my walkthrough at Hard 1.5 because of the analysis in some of my later steps.