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 Post subject: Pinata Killer Sudoku 22
PostPosted: Mon Jan 14, 2013 10:47 am 
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Pinata Killer Sudoku 21 Solution:
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Pinata Killer Sudoku 22
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Jsudoku Code: 3x3::k:4359:4359:6408:3862:3862:791:4882:4882:4882:5636:4359:6408:6408:3093:791:4882:3603:2577:5636:6408:6408:3093:3093:2580:2580:3603:2577:5636:8963:8963:8963:8963:8963:8963:8963:2577:5636:2569:3594:6424:6424:6424:6913:2320:2320:4869:2569:3594:3594:6424:6913:6913:3599:3599:4869:4869:5387:5387:6913:6913:9486:9486:3599:3590:4869:5387:2562:3084:3084:3084:9486:3599:3590:3590:2562:2562:2829:2829:9486:9486:9486:

Sudoku Solver Score: 1.40


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PostPosted: Thu Jan 17, 2013 4:44 am 
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Thanks Pinata for another killer. It's good that you are posting weekly killers again. :D

After a fairly easy start, this one proved to be a bit harder than expected. The SS score suggests there's probably an easier way to solve it.

Here is my walkthrough for Pinata Killer #22:
Prelims

a) R1C45 = {69/78}
b) R12C6 = {12}
c) R23C8 = {59/68}
d) R3C67 = {19/28/37/46}, no 5
e) R56C2 = {19/28/37/46}, no 5
f) R5C89 = {18/27/36/45}, no 9
g) R9C56 = {29/38/47/56}, no 1
h) 10(3) cage at R2C9 = {127/136/145/235}, no 8,9
i) 21(3) cage at R7C3 = {489/579/678}, no 1,2,3
j) 10(3) cage at R8C4 = {127/136/145/235}, no 8,9
k) 14(4) cage at R6C8 = {1238/1247/1256/1346/2345}, no 9
l) 37(6) cage at R7C7 = {256789/346789}, no 1

Steps resulting from Prelims
1a. Naked pair {12} in R12C6, locked for C6 and N2, clean-up: no 8,9 in R3C7, no 9 in R9C5
1b. 37(6) cage at R7C7 = {256789/346789}, 6,7,8,9 locked for N9

2. 45 rule on R1234 1 outie R5C1 = 2, clean-up: no 8 in R56C2, no 7 in R5C89
2a. R5C1 = 2 -> R234C1 = 20 = {389/479/569/578}, no 1

3. 45 rule on R4 2 innies R4C19 = 10 = {37/46}/[82/91], no 5

4. 45 rule on C12 2 innies R34C2 = 8 = {17/35}/[26], no 4,8,9, no 6 in R3C2

5. 45 rule on N1 2(1+1) remaining outies R2C4 + R4C1 = 17 = {89}, clean-up: R4C9 = {12} (step 3)
5a. Naked pair {89} in R2C4 + R4C1, CPE no 8,9 in R2C1 + R4C4
5b. R234C1 (step 2a) = {389/479/569/578}
5c. 3 of {389} must be in R2C1 -> no 3 in R3C1

6. 45 rule on N3 1 innie R3C7 = 1 outie R4C9 + 2 -> R3C7 = {34}, clean-up: R3C6 = {67}
6a. 12(3) cage at R2C5 = {345} (hidden triple in N2)
6b. Naked triple {345} in R3C457, locked for R3, 5 also locked for N2, clean-up: no 9 in R2C8, no 3,5 in R4C2 (step 4)
6c. 3,4,5 in R234C1 (step 2a) = {389/479/569/578} only in R2C1 -> R2C1 = {345}

7. 14(4) cage at R6C8 = {1346/2345} (cannot be {1238/1247/1256} which clash with R4C9), no 7,8
7a. 14(4) cage at R6C8 = {1346/2345}, CPE no 3,4 in R5C9, clean-up: no 5,6 in R5C8
7b. Killer pair 1,2 in R4C9 and 14(4) cage, no 1 in R5C9, clean-up: no 8 in R5C8

8. 45 rule on C9 2 innies R19C9 = 2 outies R56C8 + 12
8a. Max R19C9 = 17 -> max R56C8 = 5, no 5,6 in R6C8
8b. Min R56C8 = 4 (cannot be {12} which clashes with R4C9) -> min R19C9 = 16 -> R19C9 = {79/89}
8c. R56C8 = 4,5 = {13/14/23}
8d. Killer pair 1,2 in R4C9 and R56C8, locked for N6
8e. 2 in N6 only in R4C9 + R6C8, CPE no 2 in R78C9

9. 45 rule on N9 3 innies R78C9 + R8C7 = 8 = {134} (only remaining combination, cannot be {125} because R78C9 = {15} clashes with 10(3) cage at R2C9), locked for N9
9a. 4 must be in R78C9 (R78C9 cannot be {13} which clashes with 10(3) cage at R2C9), no 4 in R8C7
9b. 4 in N9 only in R78C9, locked for C9 and 14(4) cage at R6C8, no 4 in R6C8
[Sorry, my step numbering has got mixed up. I must have simplified some earlier steps and forgotten to adjust the step numbers. Don’t think any steps are missing.]

12. 14(4) cage at R6C8 (step 7a) = {1346/2345}
12a. 5,6 only in R6C9 -> R6C9 = {56}

13. 2 in C9 only in 10(3) cage at R2C9 (step 8) = {127} (only remaining combination, cannot be {235} because 3,5 only in R2C9), locked for C9, 7 also locked for N3
13a. Naked pair {89} in R19C9, locked for C9, clean-up: no 1 in R5C8
13b. Naked pair {56} in R56C9, locked for N6
13c. Killer pair 8,9 in R1C45 and R1C9, locked for R1
13d. Killer pair 8,9 in R1C9 and R23C8, locked for N3
13e. R4C9 + R5C8 = {12} (hidden pair in N6)
13f. R8C7 = 1 (hidden single in N9)

14. 19(4) cage at R1C7 = {1459/1468/2359/2368} (cannot be {1369/2458} which clash with R23C8)
14a. 1 of {1459/1468} must be in R1C8 -> no 4 in R1C8
14b. 4 in N3 only in R123C7, locked for C7

15. Max R1C12 = 11 (cannot be {67} which clashes with R1C45, cannot be {57} because 17(3) cage cannot be {57}5) -> min R2C2 = 6

16. R34C2 (step 4) = {17}/[26], R56C2 = {19/37/46} -> combined cage R3456C2 = {17}{46}/[26]{19}/[26]{37}, 6 locked for C2 and N4

17. R1C45 = {69/78}, R2C4 = {89} -> variable combined cage R1C45 + R2C4 = {69}8/{78}9
17a. 17(3) cage at R1C1 = {179/359/368/458/467} (cannot be {269/278} which clash with R1C45 + R2C4), no 2
17b. 7 of {179} must be in R1C1 (R12C2 cannot be [79] which clashes with combined cage R3456C2), 7 of {467} must be in R2C2 -> no 1 in R1C1, no 7 in R1C2

18. 2 in N1 only in 25(5) cage at R1C3 = {12589/12679/23479/23569/23578/24568}
18a. 1,2 in N1 only in 17(3) cage at R1C1 = {179} or 25(5) cage -> 25(5) cage = {12589/12679/24568} (cannot be {23479/23578}, locking-out cages, cannot be {23569} which clashes with 17(3) cage = {179} = {17}9), no 3
18b. Killer pair 5,6 in 17(3) cage and 25(5) cage, locked for N1
[Note. This works because 25(5) cage contains both of 5,6 when 17(3) cage = {179}. Alternatively the step can be considered to be a combined cage, since any 5,6 in the 25(5) cage must be in N1.]

19. R234C1 (step 2a) = {389/479}, 9 locked for C1

20. Naked pair {34} in R2C15, locked for R2

21. 1 in C1 only in R679C1, CPE no 1 in R7C2

22. 25(5) cage at R1C3 (step 18a) = {12589/12679/24568}
22a. 17(3) cage at R1C1 = {179/359/458/467} (cannot be {368} which clashes with 25(5) cage because 8 of {368} can only be in R2C2)
22b. Hidden triple killer 1,6,8 in 25(5) cage, 17(3) cage and R234C1 for N1, 25(5) cage contains two of 1,6,8 (not necessarily both in N1) -> 17(3) cage at R1C1 and R234C1 must contain at least one of 1,6,8
22c. R234C1 = {step 19) = {389/479} -> 17(3) cage at R1C1 (step 17a) = {179/458/467} (cannot be {359} because R234C1 = {479} doesn’t contain 8), no 3
[I suppose that’s a variant on locking-out cages using the hidden killer triple.]

[Even though this seems to be a key breakthrough, there’s still a lot of work to do.]

23. R2C1 = 3 (hidden single in N1), R34C1 (step 19) = {89}, locked for C1, R2C5 = 4, clean-up: no 7 in R9C6
23a. Deleted

24. R3C7 = 4 (hidden single in R3), R3C6 = 6, R4C9 = 2 (step 6), R4C1 = 8 (step 3), R3C1 = 9, R3C8 = 8, R2C8 = 6, R1C9 = 9, R9C9 = 8, clean-up: no 3,5 in R9C5, no 3 in R9C6
24a. Naked pair {17} in R23C9, locked for N3

25. Naked pair {78} in R1C45, locked for R1 and N2 -> R2C4 = 9

26. R6C8 = 1, R78C9 = {34} = 7 -> R6C9 = 6, R5C9 = 5, R5C8 = 4, clean-up: no 9 in R5C2

27. 17(3) cage at R1C1 (step 22a) = {458/467}, no 1, 4 locked for N1

28. 2 in R3 only in R3C23, locked for N1

29. 25(5) cage at R1C3 (step 18a) = {12589/12679}
29a. 8 of {12589} must be in R2C3 -> no 5 in R2C3
29b. 5,6 only in R1C3 -> R1C3 = {56}

30. R1C6 = 1 (hidden single in R1), R2C6 = 2, R2C7 = 5

31. 8 in N6 only in R56C7, locked for 27(5) cage at R5C7, no 8 in R6C6 + R7C56
31a. 27(5) cage = {13689/14589/15678/23589/24678/34578} (cannot be {12789} because 1,2 only in R7C5)
31b. 3,5,7 of {34578} must be in R7C5, 1,2 of other combinations must be in R7C5 -> no 6,9 in R7C5
31c. 27(5) cage = {14589/23589/34578}

32. 25(4) cage at R5C4 = {1789/2689/3589/3679}, 9 locked for N5

33. 27(5) cage at R5C7 (step 31c) = {14589/23589/34578}
33a. 45 rule on N78 2 remaining innies R7C56 = 1 outie R6C1 + 4
33b. R6C1 = {457} -> R7C56 = 8,9,11 -> {45/29/38/47} (cannot be [17/27] because 27(5) cage only contains one of 1,2,7, cannot be {35} because R6C1 + R7C56 = 4{35} clashes with 27(5) cage = {34578}, combo blocker), no 1 -> R7C56 = 9,11 -> R6C1 = {57}
[The extra combo blocker elimination proves to be useful. Now the puzzle is cracked.]

34. R9C4 = 1 (hidden single in N8)

35. R7C1 = 1 (hidden single in N7) -> 19(4) cage at R6C1 = {1279/1378/1459}
35a. 5 of {1459} must be in R6C1 -> no 5 in R78C2

36. 14(3) cage at R8C1 = {347/356} (cannot be {239} because 2,3,9 only in R9C2, cannot be {257} which clashes with R6C1) -> R9C2 = 3, clean-up: no 7 in R56C2

37. 19(4) cage at R6C1 (step 35) = {1279/1459}, no 8, 9 locked for C2 and N7, clean-up: no 1 in R5C2

38. R56C2 = [64], R1C2 = 5, R1C3 = 6, R1C1 = 4, R2C2 = 8 (cage sum), clean-up: no 2 in R3C2 (step 4)

39. R3C3 = 2 (hidden single in N1)

40. 14(3) cage at R8C1 (step 36) = {356} (only remaining combination), 5,6 locked for C1 and N7 -> R6C1 = 7, R4C2 = 1

41. 21(3) cage at R7C3 = {678} (only remaining combination) -> R7C4 = 6

42. R9C3 = 4 (hidden single in N7), R8C4 = 5 (cage sum), R9C6 = 9, R9C5 = 2

43. 8 in N8 only in 12(3) cage at R8C5 = {138} (only remaining combination), 3,8 locked for R8 and N8

44. 27(5) cage at R5C7 (step 31c) = {34578} (only remaining combination) -> R6C6 = 5, R56C7 = {38}, locked for C7 and N6

45. R5C5 = 1 (hidden single in N5) -> 25(5) cage at R5C4 (step 32) = {1789} (only remaining combination) -> R6C5 = 9, R5C46 = {78}, locked for R5 and N5

and the rest is naked singles.
Thanks Ed for pointing out that step 23a was incorrect; I’ve now deleted it and edited another step.

Rating Comment:
I'll rate my walkthrough for Pinata #22 at Hard 1.5. Several steps were hard, so I've gone for the top of the 1.5 range.


Last edited by Andrew on Tue Jan 22, 2013 3:32 am, edited 3 times in total.

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PostPosted: Sun Jan 20, 2013 8:05 am 
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Andrew wrote:
there's probably an easier way to solve it.
Think I found one but certainly a really challenging puzzle. As Andrew found, it has two spots where it is very resistant. Found a neat way through the first one (steps 15&16), but the second was not fun (steps 27 & 28). Just grunt and careful picking - the sort of thing that SudokuSolver does very well. SS has a spot on the solving window called 'Mutual Excludes' which after a puzzle like this, makes me wonder about my habit to never look at it. I started the same way as Andrew so have piggy-backed on his start again. Thanks Andrew! And thanks to Pinata for posting weekly again - this puzzle gave me a lot of satisfaction :)

Pinata Killer Sudoku 22
24 more steps:
copy the "marks" diagram, open A253 in SS, File>Import>Candidates>Okay. Alternatively, you can download the attached SS file which will include all the combo eliminations and hidden cages etc already at the correct spot.
.-------------------------------.-------------------------------.-------------------------------.
| 134567 1234567 1234567 | 6789 6789 12 | 23456 12356 89 |
| 345 123456789 123456789 | 89 34 12 | 23456 568 127 |
| 6789 127 126789 | 345 345 67 | 34 689 127 |
:-------------------------------+-------------------------------+-------------------------------:
| 89 167 13456789 | 1234567 123456789 3456789 | 3789 34789 12 |
| 2 134679 13456789 | 13456789 13456789 3456789 | 3789 34 56 |
| 13456789 134679 13456789 | 123456789 123456789 3456789 | 3789 12 56 |
:-------------------------------+-------------------------------+-------------------------------:
| 13456789 123456789 456789 | 456789 123456789 3456789 | 256789 256789 34 |
| 3456789 23456789 456789 | 234567 23456789 3456789 | 1 256789 34 |
| 13456789 123456789 1234567 | 1234567 2345678 3456789 | 256789 256789 89 |
'-------------------------------.-------------------------------.-------------------------------'


End of Andrew's step 14 above

15. 6 in n2 in 15(2) = {69} or in 10(2)r3c67 = [64]; = ([9]/[4]) -> {1459} blocked from 19(4)n3 (Blocking cages)
15a. 7 in n2 in 15(2) = {78} or in 10(2)r3c67 = [73]; = ([8]/[3]) -> {2368} blocked from 19(4)n3 (Blocking cages)
15b. 19(4)n3 = {1468/2359} = [4->6..]

16. 4 in n3 in 19(4) -> must also have 6 (step 15b) or 4 in r3c7 -> 6 in r3c6: both must have 6 -> no 6 in r3c8 since it sees both cages (Locking cages)
16a. no 8 in r2c8

17. 8 & 9 in r2 only in r2c234: r3c3 sees all of those -> no 8 or 9 in r3c3 (Common Peer Elimination CPE)

18. Hidden pair {89} in r3 -> r3c1 = (89)

19. Naked pair {89} in r34c1: both locked for c1

20. r34c1 = 17 -> r2c1 = 3 (cage sum)
20a. r2c5 = 4
20b. no 7 in r89c6 (h11(2)r8c56 & 11(2)r9c5)

21. r3c45 = {35}: 3 locked for r3
21a. r3c67 = [64]
21b. 15(2)n2 = {78} only: locked for r1 & n2
21c. no 5 in r89c5 (h11(2)r8c56 & 11(2)r9c5)

22. r19c9 = [98]
22a. r23c8 = [68]
22b. r34c1 = [98]
22c. r4c9 = 2 (h10(2)r4c19)
22d. r78c9 = {34} = 7 -> r6c89 = 7 = [16]
22e. r5c89 = [45]
22f. r2c4 = 9
22g. no 3 in 11(2)n8
22h. no 9 in r5c2

23. 10(2)n4 = {19/37/46} = [1/7/6] and h8(2)r34c2 = {17/26}: -> combined cage must have 6: 6 locked for c2 and n4

24. 17(3)n1: {278} blocked since 7 & 8 are both in r2c2
24a. = {458/467}(no 1,2)
24b. must have 4: 4 locked for n1
24c. must have 7 or 8 -> r2c2 = (78)

25. 1 in c1 only in n7: 1 locked for n7

26. 7 in c1 only in r6789c1: r78c2 sees all those -> no 7 in r78c2 (CPE)

The second breakthrough: this one is not fun, just grunt and concentration.
27. 19(4)r6c1: {1369/1468/1567} blocked by 1 & 6 both only in r7c1
27a. {2368} blocked by no 4,5,7 for r6c1
27b. {2359} blocked by 2,3,9 only in r78c2
27b. = {1279/1378/1459/2458/2467/3457} = [1/4;4/7;5/7..](no eliminations yet)

28. 14(3)n7: {149} can only be [419]: but blocked by 19(4)r6c1 = [1/4]
28a. {239} blocked by 2 & 3 only in r9c2
28b. {257} can only be {57}[2]; but blocked by 19(4)r6c1 = [5/7]
28c. {347} must be {47}[3]; but blocked by 19(4)r6c1 = [4/7]
28d. = {167/356}(no 2,4,9)
28e. must have 6: 6 locked for n7 and c1
28f. 3 in {356} must be in r9c2 -> no 5 in r9c2

29. r1c12 = {45} = 9 -> r2c2 = 8
29a. 5 locked for n1 and r1

30. 8 in n7 only in 21(3)r7c3: no 8 in r7c4
30a. 21(3) must have 8 = {489/678}(no 5)

31. 8 in n6 only in 27(5)r5c7: 8 locked for 27(5)
31a. no 8 in r6c6, r7c56

32. 8 in n8 only in h11(2)r8c56 = {38} only: both locked for r8 and n8

33. r78c9 = [34]

34. 10(2)r5c2: {37} blocked by r9c2 = (37)
34a. = [19/64](no 3,7)

35. Hidden single 3 in c2: r9c2 = 3
35a. r89c1 = 11 = {56} only: 5 locked for c1 and n7

36. 19(4)r6c1 = {1279} (last combo): r67c1 = [71]
36a. r78c2 = {29}: locked for c2 and n7

37. r789c3 = [874]
37a. r78c3 = 15 -> r7c4 = 6

39. "45" on n8: 2 remaining innies r7c56 = 11: but {29} blocked by r7c2
39a. -> r7c56 = [74] (last permutation)

on from there.
Cheerio
Ed


Attachments:
P22 Andrew WT Alt ending from end step 14.ssv [83.25 KiB]
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PostPosted: Tue Jan 22, 2013 3:25 am 
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Thanks Ed for posting the easier way for the first key breakthrough. Loved your steps 15 and 16! :D

Ed wrote:
SS has a spot on the solving window called 'Mutual Excludes' which after a puzzle like this, makes me wonder about my habit to never look at it.
Good for you not using it! Surely finding interactions between cages is a thing which solvers should do for themselves, just like finding 45s is. Is there any way to switch off the 'Mutual Excludes' feature?

My only artificial aids are to use the Excel Sum feature when calculating differences for 45s, with mental arithmetic to compare the Sum with the multiple of 45, and a table of combinations, although I usually only use it for larger cages; I can list combinations for 3-cell cages from memory.


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