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 Post subject: Assassin 251
PostPosted: Fri Dec 07, 2012 1:55 am 
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Grand Master
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Joined: Wed Apr 16, 2008 1:16 am
Posts: 1044
Location: Sydney, Australia
This Assassin fills the "must be interesting" criteria very well. I used two new variations on a technique that has become very common in Andrew's and my walk-throughs. Nothing complicated. This is why I still enjoy killers. They keep throwing up new stuff. It gets a SudokuSolver score of 1.50 so must be a couple of ways to solve it.

Assassin 251

NOTE: 1-9 cannot repeat on the diagonals

Image
Code: paste into solver:
3x3:d:k:5632:5889:5889:5889:1794:1794:2051:2051:6404:2565:5632:5889:5632:6918:2311:2311:6404:6404:2565:2565:5632:6918:6918:6918:6404:5128:6404:2565:4361:5386:4363:6918:2828:2828:5128:5128:4621:4361:5386:5386:4363:2318:2318:1807:1807:4621:4621:5386:3856:2833:4363:2322:2322:6675:6676:4621:6676:3856:2833:2833:3605:6675:6675:6676:6676:3094:3094:3094:3605:4119:3605:6675:6676:2584:2584:3865:3865:4119:4119:4119:3605:
solution:
+-------+-------+-------+
| 7 5 9 | 1 3 4 | 6 2 8 |
| 2 4 8 | 5 9 6 | 3 7 1 |
| 1 3 6 | 2 7 8 | 4 9 5 |
+-------+-------+-------+
| 4 8 7 | 3 1 2 | 9 5 6 |
| 6 9 1 | 8 5 7 | 2 4 3 |
| 3 2 5 | 6 4 9 | 8 1 7 |
+-------+-------+-------+
| 8 7 3 | 9 2 5 | 1 6 4 |
| 5 1 2 | 4 6 3 | 7 8 9 |
| 9 6 4 | 7 8 1 | 5 3 2 |
+-------+-------+-------+
Cheerio
Ed


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 Post subject: Re: Assassin 251
PostPosted: Mon Dec 17, 2012 7:22 am 
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Grand Master
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Joined: Wed Apr 16, 2008 1:16 am
Posts: 1044
Location: Sydney, Australia
Here's the way I did it. Steps 10 & 14 are the keys. Have included a couple of pics. Really enjoyed finding those.
18 steps:
1. 26(4)r6c9: no 1
1a. "45" on n9: 3 outies r6c9+r89c6 = 11 (no 9)

2. 9(2)r5c6 and 9(2)r6c7: no 9
2a. 7(2)n6: no 7,8,9
2b. 9 in n6 only in r4: locked for r4
2c. r45c2 = 17 = [89]

3. "45" on r1234: 2 remaining innies r4c34 = 10 = {37/46}(no 1,2,5) = [4/7..]

4. 11(2)r4c6: {47} blocked by h10(2)r4c34
4a. = [29]/{56}(no 1,3,4,7; no 2 in r4c7)

5. "45" on n1: 3 outies r12c4+r4c1 = 10 (no 9)

6. "45" on n12: 3 outies r2c7 + r4c15 = 8
6a. min. r4c15 = 3 -> max. r2c7 = 5
6b. -> min. r2c6 = 4 (& no 9)

7. "45" on c6789: 4 innies r1367c6 = 26 (no 1)
7a. 7(2)r1c5 (no 7,8,9; no 6 in r1c5)

8. "45" on n4: 2 outies r5c4+r7c2 - 11 = r4c1
8a. ->min. 2 outies = 12 (no 1,2,3: no 4 in r5c4)

9. "45" on n7: 2 innies r7c2+r8c3 = 9 (no 9; no 1,6,7,8 in r8c3)

The first of the two crackers, this one has been available from step 2.
Image
10. 20(3)r3c8: no 1,2
10a.the two 9(2) cages at r5c6 & r6c7 must have different combinations since they are both (partly) in n6 (Anti-synchronised cages - see Mike Parker WT for A49v2 step 30 & 38 here)(no eliminations yet)
10b. 1 in n6 only in r5 or 9(2)r6c7
10c. -> 1 blocked from r5c6 since it would leave no 1 for n6 (Combined anti-synchronised cages)
10c. no 8 in r5c7

11. 1 in c6 only in n8: 1 locked for n8

12. 12(3)r8c3 = {237/246/345}(no 8,9)
12a. 11(3)r6c5 (no 9)

13. "45" on c1234: 2 outies r89c5 - 9 = 2 innies r34c4
13a. max. r89c5 = 17 -> max. r34c4 = 8 (no 6,7,8,9 in r3c4)

Same type of move as step 10.
Image
14. The two 15(2) cages at r6c4 and r9c4 = {69/78}(no 1..5)
14a. they must have different combinations since they are both (partly) in c4 (Anti-synchronised cages)
14b. -> naked quad 6,7,8,9 -> no 6,7 in r8c4 since it sees all of the two 15(2) cages (CPE)
14c. 9 in c4 only in one of the 15(2) cages at r6c3 & r9c4 ->[69] blocked from 15(2)r9c4 since it would leave no 9 for c4 (Locking-out anti-synchronised cages)[Andrew's step 15. does this a simpler way]
14d. no 9 in r9c5, no 6 in r9c4

15. 9 in n8 only in c4: locked for c4
15a. no 6 in r7c4

16. Hidden single 9 in n5 -> r6c6 = 9 (Placed for D\)

17. From step 13, r89c5 - 9 = r34c4
17a. max. r89c5 = [78] = 15 -> max. r34c4 = 6
17b. no 3,4,5 in r3c4
17c. no 6,7 in r4c4

18. r6c6 = 9 -> r4c4+r5c5 = 8 = [35] only: both placed for D\ and 5 for D/
18a. r4c3 = 7 (h10(2)r4c34)
18b. no 6 in r4c7

On from there
Merry Christmas!
Ed


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 Post subject: Re: Assassin 251
PostPosted: Tue Dec 18, 2012 9:13 pm 
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Grand Master
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Joined: Tue Jun 16, 2009 9:31 pm
Posts: 282
Location: California, out of London
Merry Christmas to you too Ed. Thanks for continuing to generate new puzzles. It's part of my morning ritual to do one or two Killers with my coffee - so really appreciate new puzzles. BTW - Thanks too to Andrew for maintaining the archive. I have no memory of solving them after a few months so it's a good source for 'new' puzzles for me.

Here's how I did it. I'll now look to see how you did it (Ed).

Typos corrected courtesy of Ed.
Hidden Text:
1. 10/4@r2c1 = {1234}
17/2@r4c2 = {89}

2. Outies n9 = +11
-> r6c9 = Max 8
-> 9 in n6 in r4
-> 17/2@r4c2 = [89]
-> 9 in n5 in r6c4 or r6c6.

3. Outies n12 = +8
-> Max r2c7 = 5
Innies n3 r2c7+r3c8 = +12
-> Min r2c7 = 3

But r2c7 = 5 would put 7 in r3c8, {26} in r1c78, and 4 in r2c6 leaving no solution for 7/2@r1c5
-> [r2c7,r3c8] = [39] or [48]

4. Innies r1234 -> r4c34 = +10 (Given that r4c2 = 8). Must be {37} or {46}
-> 1 in r4 must be in r4c1 or r4c5.
-> r4c15 = {13} or {14} (Given outies n12 = +8 and r2c7 = 3 or 4)
-> HS 2 in R4 -> r4c6 = 2
-> 11/2@r4c6 = [29]

5. 20/3@r3c8 = [8{57}] or [9{56}]. (Cannot be [9{47}] since one of (47) in r4c34).
-> 5 locked in r4,n6 in r4c89.
-> 7/2@r5c8 not {25}
Min r89c6 = +4 -> (Outies n9) Max r6c9 = 7.
-> 8 in n6 either in r5c7 or r6c78.
Either way 1 cannot be in 7/2@r5c8
-> 7/2@r5c8 = {34}

6. Min r6c9 = 2 (Not = 1)
-> (18) in n6 both in 9/2@r6c7 or neither in there which would put both in r5c7 :)
-> 9/2@r6c7 = {18}
-> 9/2@r5c6 = [72]

7. Max r456c3 = (765) = +18 -> Min r5c4 = 3.
7 in r5c6 prevents 1 from being in 17/3@r4c4
-> HS 1 in n5 r4c5 = 1.
-> r4c1 from (43)

8. r6c9 = 6 or 7
-> (Outies n9 = +11) r89c6 = {14} or {13}
-> 11/2@r6c5 does not contain a 1 -> Must contain a 2.
-> r7c5 = 2.

9. Outies D\ = +8.
(A)r8c6 from {134} -> r2c4 from (754).
-> HS 1 in n2 -> r1c4 = 1.
(B)-> (Outies n1 = +10) -> r2c4 from (56)
Only candidate that works for both (A) and (B) r2c4 = 5.
-> r4c1 = 4 and r8c6 = 3.
-> r4 = [4873129{56}]
Also r2c7 = 3
-> r3c8 = 9 and r2c6 = 6.
Also r6c9 = 7
Also r2c5 = 9
-> r3c456 = [278]

etc. etc.


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 Post subject: Re: Assassin 251
PostPosted: Sat Dec 22, 2012 12:29 am 
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Grand Master
Grand Master

Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1895
Location: Lethbridge, Alberta, Canada
Thanks Ed for a challenging Assassin. I got stuck, then had to take a break for a few days for urgent, non-sudoku stuff. I thought that Ed had managed to “Assassinate” me, then I came back to this puzzle a couple of days ago and managed to find a breakthrough step.

Thanks wellbeback for your appreciation of the archives which were, of course, started by Ed. :) If you want to add any walkthroughs for puzzles in Archive parts A, B or C, please send them to Ed, I've added almost 50 that way; any walkthroughs for more recent puzzles can be posted in this forum and I'll add them to the archives.

Here is my walkthrough for Assassin 251:
Prelims

a) R1C56 = {16/25/34}, no 7,8,9
b) R1C78 = {17/26/35}, no 4,8,9
c) R2C67 = {18/27/36/45}, no 9
d) R45C2 = {89}
e) R4C67 = {29/38/47/56}, no 1
f) R5C67 = {18/27/36/45}, no 9
g) R5C89 = {16/25/34}, no 7,8,9
h) R67C4 = {69/78}
i) R6C78 = {18/27/36/45}, no 9
j) R9C23 = {19/28/37/46}, no 5
k) R9C45 = {69/78}
l) 20(3) cage at R3C8 = {389/479/569/578}, no 1,2
m) 11(3) cage at R6C5 = {128/137/146/236/245}, no 9
n) 10(4) cage at R2C1 = {1234}
o) 26(4) cage at R6C9 = {2789/3689/4589/4679/5678}, no 1
p) 14(4) cage at R7C7 = {1238/1247/1256/1346/2345}, no 9

Steps resulting from Prelims
1a. Naked pair {89} in R45C2, locked for C2 and N4, clean-up: no 1,2 in R9C3
1b. Naked quad {1234} in 10(4) cage at R2C1, no 1,2,3,4 in R1C1

[Ed wanted interesting steps, so here’s one …]
2. 45 rule on N14 4(3+1) outies R125C4 + R7C2 = 21
2a. Max R7C2 = 7 -> min R125C4 = 14
2b. All 3-cell combinations from 13 upward must contain at least one of 6,7,8,9
2c. Killer quad 6,7,8,9 in R125C4, R67C4 and R9C4, locked for C4
2d. Hidden killer quad 6,7,8,9 in R125C4, R67C4 and R9C4 for C4, R67C4 and R9C4 contain three of 6,7,8,9 -> R125C4 must contain one of 6,7,8,9
2e. Max R125C4 = 18 (all 3-cell combinations from 19 upward contain more than one of 6,7,8,9) -> min R7C2 = 3
2f. Max R4C4 = 5 -> min R5C5 + R6C6 = 12, no 1,2 in R5C5 + R6C6

3. 45 rule on D\ 2(1+1) outies R2C4 + R8C6 = 8 = {17/26/35}/[44], no 8,9

4. 45 rule on N1 3(2+1) outies R12C4 + R4C1 = 10
4a. Max R12C4 = 9, no 9 in R1C4

5. 45 rule on N9 3(1+2) outies R6C9 + R89C6 = 11
5a. Min R89C6 = 3 -> max R6C9 = 8
5b. Min R6C9 = 2 -> max R89C6 = 9, no 9 in R9C6

6. 9 in N6 only in R4C789, locked for R4 -> R45C2 = [89], clean-up: no 3 in R4C6, no 2,3 in R4C7

7. 45 rule on N3 2 innies R2C7 + R3C8 = 12 = [39]/{48/57}, no 1,2,6, no 3 in R3C8, clean-up: no 3,7,8 in R2C6

8. 45 rule on N7 2 innies R7C2 + R8C3 = 9 = {36/45}/[72], no 1,7,8,9 in R8C3

9. 45 rule on R1234 2 remaining innies R4C34 = 10 = [64/73]
9a. 17(3) cage at R4C4 = {359/368/458/467}
9b. R4C4 = {34} -> no 3,4 in R5C5 + R6C6
9c. R4C67 = [29/56/65] (cannot be {47} which clashes with R4C34), no 4,7

10. 45 rule on N4 2(1+1) outies R5C4 + R7C2 = 1 innie R4C1 + 11
10a. Min R5C4 + R7C2 = 12 -> min R5C4 = 5

11. 45 rule on N12 3(1+2) outies R2C7 + R4C15 = 8
11a. Min R4C15 = 3 -> max R2C7 = 5, clean-up: no 1,2 in R2C6, no 4,5 in R3C8 (step 7)
11b. Min R2C7 = 3 -> max R4C15 = 5, no 5,6,7 in R4C5

12. 45 rule on C1234 2 outies R89C5 = 2 innies R34C4 + 9
12a. Min R34C4 = 4 -> min R89C5 = 13, no 1,2,3 in R8C5

13. 45 rule on R1 2 innies R1C19 = 1 outie R2C3 + 7, IOU no 7 in R1C9

14. 9 in C6 only in R36C6
14a. 45 rule on C6789 4 innies R1367C6 = 26 = {2789/3689/4589/4679}, no 1, clean-up: no 6 in R1C5
14b. 2 of {2789} must be in R1C6 -> no 2 in R37C6
14c. 11(3) cage at R6C5 = {128/137/146/236/245}
14d. 8 of {128} must be in R7C6 -> no 8 in R67C5

15. 9 in C4 only in R67C4 = {69} or R9C45 = [96] (locking cages) -> no 6 in R9C4, clean-up: no 9 in R9C5
15a. Min R89C5 = 13 (step 12a) -> min R8C5 = 5
15b. Min R8C5 = 5 -> max R8C34 = 7 -> max R8C4 = 4 (12(3) cage at R8C3 cannot be [255])

16. Hidden killer pair 5,9 in R4C67 and 20(3) cage at R3C8 for R4, R4C67 contains one of 5,9 -> 20(3) cage must contain one of 5,9 in R4C89
16a. 20(3) cage at R3C8 = {479/569/578} (cannot be {389} because 8{39} plus R4C67 = {56} clashes with R4C34, blocking cages), no 3

17. R125C4 + R7C2 = 21 (step 2)
17a. Max R125C4 containing one of 6,7,8 (step 2d) = 17 -> min R7C2 = 4, clean-up: no 6 in R8C3 (step 8)

18. 45 rule on R6789 2 innies R6C36 = 1 outie R5C1 + 8, IOU no 8 in R6C6

19. 45 rule on R89 3 outies R7C137 = 1 innie R8C9 + 3
19a. Min R7C137 = 6 -> min R8C9 = 3

20. 45 rule on R9 2 innies R9C19 = 1 outie R8C7 + 4, IOU no 4 in R9C1

[I thought that Ed had managed to “Assassinate” me until I found this step which cracks the puzzle.]
21. Min R34C4 = [13] = 4 -> min R89C5 = 13 = {67} (cannot be [58] which clashes with 17(3) cage at R4C4 = [359/386]) -> no 5 in R8C5
21a. Naked quad {6789} in R7C4 + R8C5 + R9C45, locked for N8, clean-up: no 1,2 in R2C4 (step 3)
21b. Max R7C56 = 9 -> min R6C5 = 2

22. R1367C6 (step 14a) = {3689/4589/4679} (cannot be {2789} because R7C6 only contains 3,4,5), no 2, clean-up: no 5 in R1C5
22a. 7,8,9 only in R36C6 -> R3C6 = {789}, R6C6 = {79}
22b. 3 of {3689} must be in R7C6 -> no 3 in R1C6, clean-up: no 4 in R1C5

23. 17(3) cage at R4C4 (step 9a) = {359/467} (cannot be {368/458} because R6C6 only contains 7,9)
23a. 5,6 only in R5C5 -> R5C5 = {56}

24. R356C6 = {789} (hidden triple in C6) -> R5C6 = {78}, R5C7 = {12}

25. 1 in C6 only in R89C6, locked for N8
25a. 1 in C6 only in R89C6, CPE no 1 in R8C7 + R9C9

26. 11(3) cage at R6C5 = {236/245}, no 7, 2 locked for C5, clean-up: no 5 in R1C6
26a. 2 in N2 only in R13C4, locked for C4
26b. Naked pair {34} in R48C4, locked for C4, clean-up: no 4,5 in R8C6 (step 3)

27. 12(3) cage at R8C3 = {237/246} (cannot be {345} because 3,4,5 only in R8C34), no 5,8,9 -> R8C3 = 2, R7C2 = 7 (step 8)
27a. Killer pair 6,7 in R8C5 and R9C45, locked for N8
27b. Clean-up: no 6 in R2C4 (step 3), no 8,9 in R6C4, no 3 in R9C2, no 3,8 in R9C3

28. 17(3) cage at R4C4 (step 23) = {359} (only remaining combination, cannot be {467} which clashes with R6C4) -> R4C4 = 3, R5C5 = 5, R6C6 = 9, all placed for D\, 5 also placed for D/, R8C4 = 4, R8C5 = 6 (step 27), clean-up: no 6 in R4C7, no 2 in R5C89, no 9 in R9C4

29. Naked pair {78} in R9C45, locked for R9 and N8 -> R7C4 = 9, R6C4 = 6, R4C6 = 2, both placed for D/, R4C7 = 9, R6C5 = 4, R4C5 = 1 (hidden single in N5), R1C5 = 3, R1C6 = 4, R7C5 = 2, R7C6 = 5 (step 26), R2C6 = 6, R2C7 = 3, R3C8 = 9 (step 7), R4C1 = 4, clean-up: no 5 in R1C78, no 5 in R6C7, no 3,5 in R6C8

30. Naked pair {78} in R3C56, locked for R3 and N2 -> R2C45 = [59], R13C4 = [12], R8C6 = 3 (step 3), R9C6 = 1, R1C9 = 8, R8C2 = 1, both placed for D/, R3C7 = 4, placed for D/, R2C8 = 7, R3C12 = [13], R2C1 = 2, R2C2 = 4, R3C3 = 6, both placed for D\

and the rest is naked singles, without using the diagonals.

Rating Comment:
I'll rate my walkthrough for A251 at 1.5.


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