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 Post subject: Assassin 216
PostPosted: Fri Jul 08, 2011 9:44 pm 
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Time to make good on my promise in goooders' Special 1, and give Ed some relief.
I have 9 puzzles with a good SS score spread from 0.93 through 7.02, which both JSudoku and SudokuSolver can solve.
Have to do some analysis of the puzzles first to select which ones to post.

According to Ed one of the characteristics of a good Assassin is that SudokuSolver can solve it in a blink of an eye, and that JSudoku has a terrible time solving it.
The v1 at 1.40 of the upcoming Assassin has exactly this characteristic.
Here the A216 v1. A couple of other easier and/or more difficult versions may follow.


A216 v1
Images:
Image     Image
normalized PS-code:
3x3::k:3072:4097:7938:7938:7938:7938:7942:7942:7942:3072:4097:4097:7938:6413:6413:9231:7942:7942:1554:4097:11540:6413:6413:9231:9231:9231:7942:1554:4097:11540:6413:9231:9231:9231:8994:5411:3108:3108:11540:11540:11540:9231:8994:8994:5411:7213:7470:7470:7470:11540:8994:8994:5411:5411:7213:7213:7470:7470:11540:11540:11540:7485:5411:4671:7213:7213:7470:3395:7485:7485:7485:7485:4671:4671:7213:7213:3395:2381:2381:2383:2383:
Solution:
+-------+-------+-------+
| 5 2 8 | 3 9 7 | 4 1 6 |
| 7 6 3 | 4 1 2 | 5 9 8 |
| 4 1 9 | 8 5 6 | 2 7 3 |
+-------+-------+-------+
| 2 4 7 | 9 8 1 | 3 6 5 |
| 9 3 5 | 6 2 4 | 7 8 1 |
| 6 8 1 | 7 3 5 | 9 4 2 |
+-------+-------+-------+
| 3 7 6 | 5 4 8 | 1 2 9 |
| 1 5 4 | 2 6 9 | 8 3 7 |
| 8 9 2 | 1 7 3 | 6 5 4 |
+-------+-------+-------+

EDIT 2011-07-10:
After I posted A216, i tweeted that I had done so and included the hashtags #Sudoku, #Killer and #Assassin.
One result is that Slawabor Henryk'Son mentions A216 and includes a link to it in his #sudoku Daily paper from 2011-07-09.
If you open the bottom collapsible frame, you should see his #sudoku Daily paper from 2011-07-09.


Image

Image

(Archive Note): The image for the final frame has been included; the link to the right of this image no longer worked.


Last edited by Børge on Sun Jul 10, 2011 1:14 pm, edited 20 times in total.

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 Post subject: Re: Assassin 216
PostPosted: Sun Jul 10, 2011 12:11 pm 
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A216 v0.5     SS score 0.93 ◄ Select to see the SS score
Images:
Image     Image
normalized PS-code:
3x3::k:784:5899:7436:7436:7436:7436:9475:9475:9475:784:5899:5899:7436:5894:5894:9217:9475:9475:2063:5899:11522:5894:5894:9217:9217:9217:9475:2063:5899:11522:5894:9217:9217:9217:6405:6410:4113:4113:11522:11522:11522:9217:6405:6405:6410:9479:8196:8196:8196:11522:6405:6405:6410:6410:9479:9479:8196:8196:11522:11522:11522:4617:6410:5384:9479:9479:8196:2578:4617:4617:4617:4617:5384:5384:9479:9479:2578:1299:1299:3086:3086:
Solution:
+-------+-------+-------+
| 1 4 7 | 5 3 6 | 9 8 2 |
| 2 6 3 | 8 4 9 | 1 7 5 |
| 5 9 8 | 1 7 2 | 3 4 6 |
+-------+-------+-------+
| 3 1 4 | 2 6 8 | 7 5 9 |
| 9 7 2 | 3 1 5 | 8 6 4 |
| 8 5 6 | 7 9 4 | 2 3 1 |
+-------+-------+-------+
| 4 3 1 | 9 5 7 | 6 2 8 |
| 6 2 9 | 4 8 3 | 5 1 7 |
| 7 8 5 | 6 2 1 | 4 9 3 |
+-------+-------+-------+

A216 v2     SS score 2.51 ◄ Select to see the SS score
Images:
Image     Image
normalized PS-code:
3x3::k:3840:5121:5890:5890:5890:5890:6918:6918:6918:3840:5121:5121:5890:6413:6413:10511:6918:6918:1042:5121:11540:6413:6413:10511:10511:10511:6918:1042:5121:11540:6413:10511:10511:10511:7458:6947:2852:2852:11540:11540:11540:10511:7458:7458:6947:9773:8494:8494:8494:11540:7458:7458:6947:6947:9773:9773:8494:8494:11540:11540:11540:5181:6947:4927:9773:9773:8494:3139:5181:5181:5181:5181:4927:4927:9773:9773:3139:1101:1101:3151:3151:
Solution:
+-------+-------+-------+
| 7 4 1 | 3 9 8 | 2 5 6 |
| 8 5 6 | 2 7 4 | 3 9 1 |
| 3 2 9 | 1 5 6 | 7 8 4 |
+-------+-------+-------+
| 1 3 4 | 8 2 9 | 5 6 7 |
| 2 9 7 | 5 6 1 | 4 3 8 |
| 6 8 5 | 4 3 7 | 9 1 2 |
+-------+-------+-------+
| 5 7 3 | 6 1 2 | 8 4 9 |
| 9 1 8 | 7 4 5 | 6 2 3 |
| 4 6 2 | 9 8 3 | 1 7 5 |
+-------+-------+-------+

A216 v7 :rambo: for sleepless nights     SS score 7.02 ◄ Select to see the SS score
Images:
Image     Image
normalized PS-code:
3x3::k:2304:6145:6402:6402:6402:6402:9478:9478:9478:2304:6145:6145:6402:4621:4621:9231:9478:9478:4370:6145:11540:4621:4621:9231:9231:9231:9478:4370:6145:11540:4621:9231:9231:9231:6946:6179:1572:1572:11540:11540:11540:9231:6946:6946:6179:7725:7982:7982:7982:11540:6946:6946:6179:6179:7725:7725:7982:7982:11540:11540:11540:6205:6179:4671:7725:7725:7982:3907:6205:6205:6205:6205:4671:4671:7725:7725:3907:3405:3405:1615:1615:
Solution:
+-------+-------+-------+
| 4 2 1 | 9 5 6 | 3 7 8 |
| 5 7 8 | 4 3 2 | 1 9 6 |
| 9 6 3 | 1 7 8 | 2 5 4 |
+-------+-------+-------+
| 8 1 7 | 5 4 3 | 6 2 9 |
| 2 4 9 | 6 8 7 | 5 3 1 |
| 6 3 5 | 2 1 9 | 8 4 7 |
+-------+-------+-------+
| 1 9 6 | 7 2 5 | 4 8 3 |
| 3 5 4 | 8 9 1 | 7 6 2 |
| 7 8 2 | 3 6 4 | 9 1 5 |
+-------+-------+-------+

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 Post subject: Re: Assassin 216
PostPosted: Tue Jul 12, 2011 5:20 am 
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Børge wrote:
give Ed some relief
Thanks! And for taking the next one. I'm still slaving away bug-hunting the next release of SS with Richard. Way behind on catching up with posts here.
Børge wrote:
According to Ed one of the characteristics of a good Assassin is that SudokuSolver can solve it in a blink of an eye, and that JSudoku has a terrible time solving it.
The v1 at 1.40 of the upcoming Assassin has exactly this characteristic.
To be fair to JSudoku, I also look for ones that it can solve easily and SS has a lot of trouble...but it does usually end up that the SS one is the one I can solve or find the most interesting.

Thanks everyone for letting me be the first with a walkthrough! ;) I couldn't get far with this V1 but fortunately, found some advanced moves (steps 3,8,13) and one trick (step 4). Hopefully, they are all easy to follow. If they are not clear, please let me know. [edit: thanks Andrew!]I know SudokuSolver can't do some of those steps so there must be another way. Finally, thanks for a really tough puzzle Børge!

Start to Assassin 216 V1
13 steps:
note: this is an optimised solution so only the essential steps are included. Other possible eliminations have not been included. However, I do try and do the clean-ups as I go. Please let me know of any errors.
Prelims
i. 12(2)n1: no 1,2,6
ii. 16(5)r1c2: no 5,7,8,9
iii. 36(8)r2c7: no 9
iv. 6(2)r3c1: no 3,6..9
v. 35(5)r4c8: no 1..4
vi. 12(2)n6: no 1,2,6
vii. 28(7)r6c1: no 8,9
viii. 13(2)n8: no 1,2,3
ix. 9(2)r9c6 & 9(2)n9: no 9

1. 12(2)n1 = {39/48/57} = one of 7,8,9 ->Hidden killer triple 7,8,9 in n1 -> r13c3 must have two of 7,8,9
1a. r13c3 from (789)

2. 28(7)r6c1 = {1234567} only and r9c1 sees all of those -> r9c1 = (89)

3. c1 & c2 must have six of 7,8,9. The two 12(2) cages at r15c1 have two only -> the other four must be at r6789c12 with only 3 killer cages left to get them from
3a. ->28(7)r6c1 must have 7 in r6c1+r7c12+r8c2: locked for 28(7)
3b. 18(3)n9 must have at least two of 7,8,9 but can't have more than two or it will exceed the cage total = {189/279/378}(no 4,5,6)
3c. one spot left for 7,8,9 in c12 -> r6c2 from (789)

4. r6c2 sees all 7,8,9 in c3 (r7c3 is in the same cage) except r13c3 -> r6c2 is cloned in r13c3
4a. -> r6c2 can't be repeated in 12(2)n1 (Anti-clone)
4b. r5c1 in 12(2)n4 sees both cells of 12(2)n1: since they have the same cage total-> they must have different combinations of {39/48/57} = two of 7,8,9 in the two cages
4c. r6c2 and 12(2)n4 are in the same nonet so can't have repeats
4d. -> r6c2, 12(2)n1 & 12(2)n4 must all have different uses of 7,8,9
4e. -> Anti-clone killer triple 7,8,9 in 12(2)n1, 12(2)n4 and r6c2-> no 7 in common peer in r6c1

5. 7 in 28(7)r6c1 only in n7: 7 locked for n7

6. 18(3)n7 = {189} only: all locked for n7

7. 6 in c1 only in r67c1: 6 locked for 28(7)r6c1

8. Caged X-cycle on 1 in 28(7)r6c1(must have 1) and 18(3)n7(must have 1) -> 1 in r68c1 locked for c1 and 1 in r9c24 locked for r9
8a. 6(2)r3c1 = {24} only: both locked for c1
8b. no 8 in 12(2)n1
8c. no 8 in r5c2
8d. no 8 in the two 9(2) cages at r9c6 and r9c8

9. 8 in n1 only in c3: locked for c3

10. "45" on n1: 2 outies r4c12 + 11 = 2 innies r13c3 which must have 8 = {78/89} = 15/17
10a. -> r4c12 = 4/6 but r4c12 cannot sum to 4 -> sum to 6 = {24} only: both locked for r4 and n4
10b. -> r13c3 = 17 = {89} only: 9 locked for n1 and c3
10c. 12(2)n1 = {57} only: both locked for c1
10d. 12(2)n4 = {39} only: both locked for n4 and r5

11. 7 in c3 only in n4: locked for n4
11a. r6c2 = 8

12. hidden pair 5,7 in c2 in r78c2 = {57}: 5 locked for n7 & 28(6)r6c1

13. The two 9(2) cages in r9 use two of 2,3,4 -> r9c34 cannot use more than one of 2,3,4 -> must have 1
13a. r9c4 = 1

The rest are normal assassin level moves....but it took me many steps to fully crack it. Sorry I don't have time to take it any further at the moment.
Cheers
Ed


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 Post subject: Re: Assassin 216
PostPosted: Wed Jul 13, 2011 2:12 am 
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Thanks for a challenging puzzle, Børge! It may seem surprising but I found this one as hard to solve as the much higher rated goooders' Special 1.

Even though Ed and I worked in the same areas, which are clearly the key ones for this puzzle, we used some very different steps.
Comments of some of Ed's steps:
Step 3 could be called a double hidden killer triple; I've occasionally used such steps in the past but rarely think of looking for them.
Step 4. Wow! :applause: It's amazing that Ed spotted that and saw all the sub-steps through to the conclusion.
Rating Comment:
I'll rate my walkthrough for A216 at 1.5. I used a short contradiction move and a Caged X-Wing, the same step which Ed called a Generalised X-cycle.
I also used the same "trick" that I used for goooders' Special 1 but it wasn't as powerful this time.
Ed wrote:
Thanks everyone for letting me be the first with a walkthrough! ;)
You're welcome! I was hoping to post my walkthrough yesterday evening but while checking it I found that "I'd seen a hidden single which wasn't yet one" so had to re-work from around step 20. I guess having a "magic button" to show remaining positions for each value, when using a software solver, must be helpful and would have stopped me making that step, but I wouldn't want to have to work with 3x3 grids of small numbers; I really don't know how people can work that way, I'll stick with my Excel worksheet with rows of 9 candidates in each cell.

Here is my walkthrough for A216:
Prelims

a) R12C1 = {39/48/57}, no 1,2,6
b) R34C1 = {15/24}
c) R5C12 = {39/48/57}, no 1,2,6
d) R89C5 = {49/58/67}, no 1,2,3
e) R9C67 = {18/27/36/45}, no 9
f) R9C89 = {18/27/36/45}, no 9
g) 16(5) cage at R1C2 = {12346}
h) 35(5) cage at R4C8 = {56789}
i) 28(7) cage at R6C1 = {1234567}, no 8,9
j) 36(8) cage at R2C7 = {12345678}, no 9
k) and, of course, 45(9) cage at R3C3 = {123456789}

Steps resulting from Prelims
1a. 35(5) cage at R4C8 = {56789}, CPE no 5,6,7,8,9 in R6C89
1b. 28(7) cage at R6C1 = {1234567}, CPE no 1,2,3,4,5,6,7 in R9C1

2. Hidden killer triple 7,8,9 in R12C1, R1C3 and R3C3 for N1, R12C1 contains one of 7,8,9 -> R1C3 and R3C3 must each contain one of 7,8,9 -> R1C3 = {789}, R3C3 = {789}
2a. 5 in N1 only in R123C1, locked for C1, clean-up: no 1 in R3C1, no 7 in R5C2
2b. 1,6 in N1 only in R123C2 + R2C3, locked for 16(5) cage at R1C2, no 1,6 in R4C2
2c. 5 in 28(7) cage at R6C1 only in R7C2 + R8C23 + R9C34, CPE no 5 in R9C2

3. 45 rule on C12 4(3+1) outies R289C3 + R9C4 = 1 innie R6C2 + 2
3a. Min R289C3 + R9C4 = 6+1 = 7 -> min R6C2 = 5
3b. Max R289C3 + R9C4 = 11, min R89C3 + R9C4 = 6 -> no 6 in R2C3
3c. Max R289C3 + R9C4 = 11, min R289C3 = 6 -> max R9C4 = 5
3d. 6 in N1 only in R123C2, locked for C2
3e. 7 in 28(7) cage at R6C1 only in R6C1 and N7, CPE no 7 in R8C1

4. 6 in C1 only in R678C1, CPE no 6 in R89C3
4a. 6 in 28(7) cage at R6C1 only in R67C1, locked for C1
4b. 6 in N7 only in R7C13, locked for R7
4c. 6 in N4 only in R456C3 + R6C1, CPE no 6 in R6C5

5. 45 rule on N2 2(1+1) outies R1C3 + R4C4 = 1 innie R3C6 + 11
5a. Max R1C3 + R4C4 = 17 (cannot be [99] = 18 because R1C3 + R4C4 “see” all the cells in N2 which contain 9) -> max R3C6 = 6
5b. Min R1C3 + R4C4 = 12, no 1,2 in R4C4

[I initially saw the next step in the same way
45 rule on N6 2(1+1) outies R6C6 + R7C9 = 1 innie R4C7 + 11 ...
However the following way is more powerful.]
6. Hidden killer quad 1,2,3,4 in R4C7 + 21(5) cage at R4C9 for N6, 21(5) cannot contain more than three of 1,2,3,4 -> R4C7 = {1234}
6a. 21(5) cage must contain three of 1,2,3,4 in N6 -> no 1,2,3,4 in R7C9

7. 18(3) cage at R8C1 = {189/279/378}, no 4
7a. 7 of {279/378} must be in R9C2 -> no 2,3 in R9C2

8. 45 rule on N7 2 outies R6C1 + R9C4 = 1 innie R7C3 + 1
8a. Min R6C1 + R9C4 = 3 (both in same cage) -> min R7C3 = 2

9. 45 rule on N1 2 innies R13C3 = 2 outies R4C12 + 11
9a. R13C3 = {78/79/89} = 15,16,17 -> R4C12 = 4,5,6 = [13/14/23/24/42]
[Sorry, I can’t see anything better than a short contradiction move.]
9b. R13C3 cannot be {78}, here’s how
R13C3 = {78} = 15 => R4C12 = 4 = [13] => R12C1 = {39}, locked for C1 => R89C1 = [28] => 18(3) cage at R8C1 cannot be [288]
9c. -> R13C3 = {79/89}, 9 locked for C3 and N1, clean-up: no 3 in R12C1
9d. 3 in N1 only in R123C2 + R2C3, locked for 16(5) cage at R1C2, no 3 in R4C2
9e. R4C12 = [14/24/42], 4 locked for R4 and N4, clean-up: no 8 in R5C12
9f. Killer pair 4,5 in R12C1 and R34C1, locked for C1
9g. 8 in N4 only in R456C3 + R6C2, CPE no 8 in R6C5

10. 8 in C2 only in R69C2, CPE no 8 in R7C3
10a. 8,9 in N7 only in 18(3) cage at R8C1 (step 7) = {189} (only remaining combination), 1 locked for N7
10b. 1 in 28(7) cage at R6C1 only in R6C1 + R9C4, CPE no 1 in R6C4

11. Caged X-wing for 1 in 28(7) cage at R6C1 and 18(3) cage at R8C1, no other 1 in C1 and R9, clean-up: no 5 in R3C1, no 8 in R9C67, no 8 in R9C89
[Looks like the puzzle should be cracked now.]

12. Naked pair {24} in R4C12, locked for R4 and N4
12a. Naked pair {24} in R34C1, locked for C1, clean-up: no 8 in R12C1
12b. Naked pair {57} in R12C1, locked for C1 and N1, clean-up: no 5 in R5C2
12c. Naked pair {89} in R13C3, locked for C3
12d. Naked pair {39} in R5C12, locked for R5 and N5
12e. 7 in 28(7) cage at R6C1 only in R78C2 + R89C3, locked for N7
12f. R6C2 = 8 (hidden single in N4)
12g. Naked quad {1567} in R456C3 + R6C1, CPE no 1,5,7 in R6C5
12h. 8 in 35(5) cage at R4C8 only in R4C8 + R5C78, locked for N6

13. R78C2 = {57} (hidden pair in C2), locked for N7 and 28(7) cage at R6C1, no 5 in R9C4
13a. 2,4 in N7 only in R789C3, locked for C3

14. 1,8,9 in R9 only in R9C12345
14a. 45 rule on R9 5 innies R9C12345 = 27 = {12789/13689/14589}
14b. 5,6,7 only in R9C5 -> R9C5 = {567}, clean-up: no 4,5,9 in R8C5
14c. 8,9 only in R9C12 -> R9C1 = 8, R9C2 = 9, R8C1 = 1, R5C12 = [93], R6C1 = 6, R7C1 = 3
14d. Naked pair {24} in R89C3, locked for C3 and 28(7) cage at R6C1 -> R7C3 = 6, R9C4 = 1
14e. R2C3 = 3 (hidden single in C3)
14f. R9C3 = {24} -> R9C12345 = {12789/14589}, no 6, clean-up: no 7 in R8C5
14g. 6 in 35(5) cage at R4C8 only in R4C8 + R5C78, locked for N6

15. 2,4 in N6 only in 21(5) cage at R4C9 = {12459/23457}, no 8, 5 locked in C9, clean-up: no 4 in R9C8

16. R6C5 = 3 (hidden single in 45(9) cage at R3C3)

17. R6C2 = 8, R7C3 = 6 -> 29(6) cage at R6C2 = {123689/125678/134678} -> R6C3 = 1
17a. 3 of {123689} must be in R8C4 -> no 9 in R8C4
17b. Naked pair {24} in R6C89, locked for R6 and N6

18. Naked pair {57} in R45C3, locked for 45(9) cage at R3C3, no 5,7 in R5C45 + R7C567

19. 2,4 in N5 only in R5C456, CPE no 2,4 in R7C6
19a. Naked pair {89} in R3C3 + R7C6, locked for 45(9) cage at R3C3, no 8,9 in R5C45 + R7C57
19b. 6 in 45(9) cage at R3C3 only in R5C45, locked for R5 and N5

20. R4C8 = 6 (hidden single in R4), clean-up: no 3 in R9C9
20a. 9 in 35(5) cage at R4C8 only in R6C67, locked for R6

21. Naked triple {578} in R5C378, locked for R5 -> R5C9 = 1, R4C7 = 3, clean-up: no 6 in R9C6
21a. 6 in R9 only in R9C79, locked for N9

22. 21(5) cage at R4C9 (step 15) = {12459} (only remaining combination), no 7, 9 locked for C9
22a. 7 in N6 only in R5C78 + R6C7, locked for 35(5) cage at R4C8, no 7 in R6C6

23. 45 rule on N6 2 outies R6C6 + R7C9 = 14 = {59}, CPE no 9 in R7C6
23a. R7C6 = 8, R3C3 = 9, R1C3 = 8, R8C5 = 6, R9C5 = 7, clean-up: no 2 in R9C67, no 2 in R9C89
23b. R9C3 = 2 (hidden single in R9), R8C3 = 4

24. Naked pair {24} in R57C5, locked for C5 and 45(9) cage at R3C3 -> R5C4 = 6, R7C7 = 1
24a. 9 in C5 only in R12C5, locked for N2
24b. 8 in N2 only in R2C5 + R3C45, locked for 25(5) cage at R2C5, no 8 in R4C4

25. Naked triple {579} in R4C349, locked for R4 -> R4C56 = [81]
25a. R3C4 = 8 (hidden single in N2)
25b. 7 in N5 only in R46C4, locked for C4

26. 45 rule on N3 3 innies R2C7 + R3C78 = 14 = {257} (only remaining combination), locked for N3 and 36(8) cage at R2C8 -> R5C6 = 4, R3C6 = 6, R57C5 = [24], clean-up: no 5 in R9C7

27. 7 in R3 only in R3C78, locked for N3
27a. Naked triple {257} in R2C167, locked for R2 -> R2C4 = 4

28. R3C9 = 3 (hidden single in R3)
28a. Naked pair {46} in R19C9, locked for C9 -> R2C9 = 8, R6C89 = [42], R8C9 = 7, R78C2 = [75]

29. Naked pair {19} in R12C8, locked for C8 and N3
29a. Naked pair {46} in R1C79, locked for R1
29b. R2C2 = 6 (hidden single in N1)

30. 7,8,9 in R8 only in 29(5) cage at R7C8 = {23789} (only remaining combination), no 5 -> R7C8 = 2

31. R8C4 = 2 (hidden single in R8)

32. 29(6) cage at R6C2 (step 17) = {125678} (only remaining combination) -> R67C4 = [75], R9C6 = 3, R9C7 = 6

and the rest is naked singles.
Thanks Ed for correcting my typos.


Last edited by Andrew on Fri Jul 15, 2011 10:45 pm, edited 1 time in total.

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 Post subject: Re: Assassin 216
PostPosted: Thu Jul 14, 2011 3:19 am 
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Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1895
Location: Lethbridge, Alberta, Canada
I found A216 V0.5 much harder than would be expected from calling it a V0.5 and from the SS score. While it started much more easily than the V1, I then had to think hard to make progress.

Rating Comment:
I'll rate my walkthrough for A216 V0.5 at 1.25. It felt as hard as many of Ruud's Assassins. Maybe if I'd spotted step 18 earlier I could have gone for a lower rating. Perhaps the low SS score is because software is better than I am at spotting "only remaining combination" in large cages. ;)
Here is my walkthrough for A216 V0.5:
Prelims

a) R12C1 = {12}
b) R34C1 = {17/26/35}, no 4,8,9
c) R5C12 = {79}
d) R89C5 = {19/28/37/46}, no 5
e) R9C67 = {14/23}
f) R9C89 = {39/48/57}, no 1,2,6
g) 21(3) cage at R8C1 = {489/579/678}, no 1,2,3
h) 18(5) cage at R7C8 = {12348/12357/12456}, no 9
i) 37(6) cage at R1C7 = {256789/346789}, no 1
j) 36(8) cage at R2C7 = {12345678}, no 9
k) and, of course, 45(9) cage at R3C3 = {123456789}

Steps resulting from Prelims
1a. Naked pair {12} in R12C1, locked for C1 and N1, clean-up: no 6,7 in R34C1
1b. Naked pair {35} in R34C1, locked for C1
1c. Naked pair {79} in R5C12, locked for R5 and N4

2. 37(6) cage at R1C7 = {256789/346789}, 6,7,8 locked for N3
2a. 1 in N3 only in R2C7 + R3C78, locked for 36(8) cage at R2C7, no 1 in R3C6 + R4C567 + R5C6

3. 37(7) cage at R6C1 = {1246789/1345789/2345689}, CPE no 4,8,9 in R9C1

4. 21(3) cage at R8C1 = {678} (only remaining combination, cannot be {489} because R9C1 only contains 6,7, cannot be {579} because [975] clashes with R5C1), locked for N7

5. 45 rule on N7 2 outies R6C1 + R9C4 = 1 innie R7C3 + 13
5a. Min R6C1 + R9C4 = 14, no 4 in R6C1, no 1,2,3,4,5 in R9C4
5b. R7C1 = 4 (hidden single in C1)
5c. Max R6C1 + R9C4 = 17 -> no 5,9 in R7C3
5d. 9 in N7 only in R78C2 + R89C3, locked for 37(7) cage at R6C1, no 9 in R9C4
5e. Max R6C1 + R9C4 = 15 -> max R7C3 = 2

6. R5C1 = 9 (hidden single in C1), R5C2 = 7

7. Naked triple {678} in R9C124, locked for R9, clean-up: no 2,3,4 in R8C5, no 4,5 in R9C89
7a. Naked pair {39} in R9C89, locked for R9 and N9, clean-up: no 1,7 in R8C5, no 2 in R9C67
7b. Naked pair {14} in R9C67, locked for R9 -> R9C5 = 2, R8C5 = 8, R9C3 = 5

8. Naked pair {67} in R89C1, locked for C1 and N7 -> R6C1 = 8, R9C2 = 8

9. 23(5) cage at R1C2 must contain at least one of 1,2 -> R4C2 = {12}

10. 45 rule on N1 2 innies R13C3 = 2 outies R4C12 + 11
10a. Min R4C12 = 4 -> min R13C3 = 15, no 3,4 in R13C3

11. 45 rule on N9 2 innies R7C79 = 2 outies R89C6 + 10
11a. Min R89C6 = 4 -> min R7C79 = 14 -> R7C79 = {68/78}, 8 locked for R7
11b. Max R7C79 = 15 -> max R89C6 = 5 -> R89C6 = 4,5 = {13/14}, 1 locked for C6 and N8

12. 45 rule on N6 2(1+1) outies R6C6 + R7C9 = 1 innie R4C7 + 5
12a. Min R6C6 + R7C9 = 8 -> min R4C7 = 3
12b. Max R6C6 + R7C9 = 13, max R6C6 = 7

13. 32(6) cage at R6C2 = {145679/235679}, 7,9 locked for C4 -> R9C4 = 6, R89C1 = [67]
13a. 6 in 32(6) cage only in R6C23, locked for R6 and N4
13b. R7C3 = {12} -> no 1,2 in R6C234

14. 37(7) cage at R6C1 (step 3) = {2345689} (only remaining combination), no 1
14a. R7C3 = 1 (hidden single in N7)
14b. R4C2 = 1 (hidden single in N4)

15. 32(6) cage at R6C2 (step 13) = {145679} (only remaining combination), no 3

16. 2 in N4 only in R45C3, locked for C3 and 45(9) cage at R3C3, no 2 in R5C4

17. 18(5) cage at R7C8 = {12357/12456}
17a. 2 of {12357} must be in R7C8 (R8C6789 cannot contain both of 2,3 which would clash with R8C23, ALS block), 6 of {12456} must be in R7C8 -> R7C8 = {26}
17b. 5 in N9 only in R8C789, locked for R8

18. 45 rule on C12 2 remaining outies R28C3 = 1 innie R6C2 + 7
18a. R6C2 = {456} -> R28C3 = 11,12,13 = [83/39/93/49], no 6,7 in R2C3

19. 7 in N1 only in R13C3
19a. 45 rule on N1 2 innies R13C3 = 1 remaining outie R4C1 + 12
19b. R4C1 = {35} -> R13C3 = 15,17 can only be 15 -> R13C3 = {78}, 8 locked for N1
19c. R13C3 = {78} = 15 -> R4C1 = 3, R3C1 = 5

20. Naked pair {24} in R45C3, locked for C3, N4 and 45(9) cage at R3C3, no 4 in R5C45 + R6C5
20a. R6C23 = [56]
20b. Naked triple {479} in R678C4, 4 locked for C4
20c. 9 in N5 only in R6C45, locked for R6
20d. 5 in N8 only in R7C56, locked for 45(9) cage at R3C3, no 5 in R5C45
20e. 2,5 in C4 only in R1234C4, CPE no 2,5 in R2C56
20f. R1C7 = 9 (hidden single in C7)

21. 45 rule on N2 2(1+1) outies R1C3 + R4C4 = 1 innie R3C6 + 7
21a. R1C3 = {78} + R4C4 = {258} cannot total 11,14 -> no 4,7 in R3C6
21b. 7 in 36(8) cage at R2C7 only in R4C567, locked for R4

22. 5 in N2 only in 29(5) cage at R1C3
22a. 29(5) cage = {35678} (only remaining combination), no 1,2,4, 6,7 locked for R1, 3,6 locked for N2
22b. R1C1 = 1 (hidden single in R1), R2C1 = 2

23. 1,9 in N2 only in 23(5) cage at R2C5 = {12479} (only remaining combination), no 5,8 -> R4C4 = 2, R3C4 = 1, R45C3 = [42]
23a. R3C6 = 2 (hidden single in N2), R2C7 = 1 (hidden single in N3), R9C67 = [14], R3C78 = [34]

24. 45 rule on N2 1 remaining outie R1C3 = 7, R3C3 = 8, R5C4 = 3
24a. Naked pair {58} in R12C4, locked for N2
24b. Naked pair {36} in R1C56, locked for R1 -> R1C2 = 4

25. R8C6 = 3 (hidden single in N8), R8C23 = [29], R7C2 = 3, R2C3 = 3
25a. Naked triple {157} in R8C789, locked for R8 and N9 -> R8C4 = 4, R7C789 = [628], R5C5 = 1
25b. Naked pair {79} in R6C45, locked for R6 and N5 -> R6C67 = [42]

26. R5C9 = 4 (hidden single in R5), R4C9 = 9 (cage sum), R9C89 = [93], R6C89 = [31]

27. R4C7 = 7 (hidden single in R4)

and the rest is naked singles.

Maybe I'll try the V2 and even the V7. It's interesting that the V7 has exactly the same SS score 7.02 ◄ Select to see the SS score as goooder's Special 1; however it may well be a lot harder for human solvers.


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 Post subject: Re: Assassin 216
PostPosted: Wed Dec 21, 2011 3:33 am 
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Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1895
Location: Lethbridge, Alberta, Canada
Having done a few other variants, I decided that it was time to have a go at A216 V2.

I actually finished it just over a week ago but then got tempted into trying the V7. I've only now checked my walkthrough and simplified some of the later stages, removing the only step with fairly heavy combination analysis.

Thanks Børge for this variant. It's an interesting cage pattern and was fun to work on; that's not something one can say too often about a V2 puzzle.

Rating Comment:
I'll rate my walkthrough for A216 V2 at Hard 1.5. I used a contradiction move, some forcing chains and locking-out cages. Hard was added because I used several steps in the 1.5 range.

Here is my simplified walkthrough for A216 V2:
Prelims

a) R12C1 = {69/78}
b) R34C1 = {13}
c) R5C12 = {29/38/47/56}, no 1
d) R89C5 = {39/48/57}, no 1,2,6
e) R9C67 = {13}
f) R9C89 = {39/48/57}, no 1,2,6
g) 19(3) cage at R8C1 = {289/379/469/478/568}, no 1
h) 41(8) cage at R2C7 = {12356789}, no 4
i) and, of course, 45(9) cage at R3C3 = {123456789}

Steps resulting from Prelims
1a. Naked pair {13} in R34C1, locked for C1, clean-up: no 8 in R5C2
1b. Naked pair {13} in R9C67, clean-up: no 9 in R8C5, no 9 in R9C89

2. 45 rule on N7 2 outies R6C1 + R9C4 = 1 innie R7C3 + 12
2a. Max R6C1 + R9C4 = 17 -> max R7C3 = 5
2b. Min R6C1 + R9C4 = 13, no 2 in R6C1 + R9C4
2c. 2 in R9 only in R9C123, locked for N7

3. 19(3) cage at R8C1 = {289/469/478/568}
3a. 2,5 of {289/568} must be in R89C1 (R89C1 cannot be {68/89} which clash with R12C1), no 2,5 in R9C2
3b. 7 of {478} must be in R8C1 (R9C12 cannot be [47]/{78} which clash with R9C89), no 7 in R9C12

4. 38(7) cage at R6C1 = {1256789/1346789/2345789}, CPE no 8,9 in R9C1

5. R6C1 + R9C4 = R7C7 + 12 (step 2)
5a. 19(3) cage at R8C1 (step 3) = {289/469/478/568} contains two even numbers, 38(7) cage at R6C1 = {1256789/1346789/2345789} contains three even numbers -> R6C1 + R9C4 must contain one odd and one even number (cannot contain two even numbers = {68} because no 2 in R7C3)
5b. 19(3) cage and 38(7) cage contain four even numbers in N7 -> R7C3 must be odd -> R7C3 = {135}

6. 45 rule on N6 2(1+1) outies R6C6 + R7C9 = 1 innie R4C7 + 11
6a. Min R6C6 + R7C9 = 12, no 1,2 in R6C6 + R7C9
6b. Max R6C6 + R7C9 = 18 -> max R4C7 = 7
6c. One of 29(5) cage at R4C8 and 27(5) cage at R4C9 must contain 9 in N6 -> Max R6C6 + R7C9 = 17 -> max R4C6 = 6

7. 45 rule on N9 2 innies R7C79 = 2 outies R89C6 + 9
7a. Max R7C79 = 17 -> max R89C6 = 8, no 8,9 in R8C6
7b. Min R89C6 = 3 -> min R7C79 = 12, no 1,2 in R7C7
7c. 2 in N9 only in R7C8 + R8C789, locked for 20(5) cage at R7C8, no 2 in R8C6
7d. Min R89C6 = 4 -> min R7C79 = 13, no 3 in R7C79

8. 45 rule on R1234 4(1+3) innies R3C3 + R4C389 = 1 outie R5C6 + 25
8a. Max R3C3 + R4C389 = 9 + 24 = 33 -> max R5C6 = 8
8b. Min R3C3 + R4C389 = 26, max R4C389 = 24 -> min R3C3 = 2

9. 45 rule on C1 3 innies R567C1 = 1 outie R9C2 + 7
9a. Max R567C1 = 16, min R67C1 = 9 -> max R5C1 = 7, clean-up: no 2,3 in R5C2
9b. R9C2 = {4689} -> R567C1 = 11,13,15,16
9c. There is only one combination for R567C1 containing 8 = {258} (cannot be {268} which clashes with R12C1)
9d. R567C1 + R9C2 = {258} + 8 can only be [285] + 8 -> no 8 in R7C1

10. 2 in C1 only in R59C1 -> R5C12 = [29] or 19(3) cage at R8C1 = {289}, CPE no 9 in R78C2
10a. 6 in R9 only in R9C1234, CPE no 6 in R7C12 + R8C23

11. 19(3) cage at R8C1 (step 3) = {289/469/478/568} cannot be {478}, here’s how
11a. 19(3) cage = {478} = [748] => R12C1 = {69}, R6C1 = 8 (hidden single in C1), R9C34 = [26] (hidden singles in R9) but R6C1 + R9C4 cannot both be even (step 5a)
-> 19(3) cage at R8C1 = {289/469/568}, no 7
11b. 7 in N7 only in 38(7) cage at R6C1, no 7 in R6C1 + R9C4
[I later found a way to eliminate the {478} combination using a forcing chain for the combinations in R6C1 + R9C4, using interactions with R12C1 or R9C89 for some of the combinations. However in this case I prefer the contradiction move, which is neater.]

12. 7 in C1 only in R12C1 = {78} or in R57C1 => R567C1 = {247/457} (cannot be {267} which clashes with R12C1) -> no 8 in R567C1 (locking-out cages)

13. 8 in 38(7) cage at R6C1 only in R7C2 + R8C23 + R9C34, CPE no 8 in R9C2
13a. 19(3) cage at R8C1 (step 11a) = {289/469/568}
13b. 8 of {568} must be in R8C1 -> no 5 in R8C1

14. R9C2 = {469} -> R567C1 = 11,13,16 (step 9b) = {245/247/256/259/457}
14a. 2 of {256} must be in R5C1 -> no 6 in R5C1, clean-up: no 5 in R5C2
14b. R567C1 + R9C2 = {259} + 9 can only be [295] + 9 -> no 9 in R7C1

15. R6C1 + R9C4 = R7C7 + 12 (step 2)
15a. R7C7 = {135} -> R6C1 + R9C4 = 13,15,17 = {49/58/69/89}
15b. 8 of {58} must be in R9C4 -> no 5 in R9C4

16. R6C1 + R9C4 (step 15a) = {49/58/69/89}
16a. Consider the combinations for R6C1 + R9C4
R6C1 + R9C4 = {49/69/89}, 9 locked for 38(7) cage at R6C1 => 9 in N7 only in 19(3) cage at R8C1 (step 11a) = {289/469}
or R6C1 + R9C4 = {58}, no 5 in R9C1
-> no 5 in R9C1

17. 19(3) cage at R8C1 (step 11a) = {289/469}, 9 locked for N7
17a. 9 in 38(7) cage only in R6C1 + R9C4 (step 15a) = {49/69/89}, no 5
17b. R6C1 + R9C4 = {49/69/89}, CPE no 9 in R6C4

18. R567C1 = 11,13,16 (step 9b) = {245/247/256/259/457}
18a. 2 of {245/247/256/259} must be in R5C1, 4 of {457} must be in R6C1 -> no 4 in R5C1, clean-up: no 7 in R5C2
18b. 4 of {245/247/457} must be in R6C1 -> no 4 in R7C1

19. 4 in C1 only in R689C1, CPE no 4 in R7C2 + R8C23 + R9C3

20. 4 in N7 only in 19(3) cage at R8C1 (step 17) = {469}, locked for N7

21. R9C3 = 2 (hidden single in N7)
21a. 38(7) cage at R6C1 = {1256789/2345789}, 5 locked for N7
21b. 8 in N7 only in 38(7) cage, no 8 in R9C4

22. R5C1 = 2 (hidden single in C1), R5C2 = 9

23. Naked pair {46} in R9C12, locked for R9 and N7 -> R8C1 = 9, R9C4 = 9, clean-up: no 6 in R12C1, no 3,8 in R8C5, no 8 in R9C89
23a. Naked pair {57} in R9C89, locked for R9 and N9 -> R9C5 = 8, R8C5 = 4

24. Naked pair {78} in R12C1, locked for C1 and N1 -> R7C1 = 5

25. 20(5) cage at R7C8 contains 2 = {12368/12458/12467/23456} (cannot be {12359} = 95{123} which clashes with R9C7), no 9

26. 9 in N9 only in R7C79
26a. R7C79 = R89C6 + 9 (step 7)
26b. R7C79 = {49/69/89} -> R89C6 = 4,6,8 -> {13/15/17/35}, no 6 in R8C6

27. 33(6) cage at R6C2 = {345678} (only remaining combination), no 1,2 -> R7C3 = 3, 4,8 locked for R6 -> R6C1 = 6, R9C12 = [46]
27a. 33(6) cage = {345678}, 6 locked for C4 and N8
27b. 2 in N8 only in R7C56, locked for R7 and 45(9) cage at R3C3, no 2 in R6C5
27c. 2 in R6 only in R6C789, locked for N6
27d. 4 in N5 only in R456C4, locked for C4

28. 3 in N4 only in R4C12, locked for R4
28a. 45 rule on N1 2 innies R13C3 = 2 outies R4C12 + 6
28b. Max R13C3 = 15 -> max R4C12 = 9, no 7,8 in R4C2

29. 3 in 45(9) cage at R3C3 only in R5C45 + R6C5, locked for N5

30. R6C6 + R7C9 = R4C7 + 11 (step 6)
30a. R6C6 + R7C9 cannot total 12 -> no 1 in R4C7
30b. R4C7 = {56} -> R6C6 + R7C9 = 16,17 = [79/98], CPE no 9 in R6C89

31. 3 in N8 only in R89C6, locked for C6
31a. R7C79 = R89C6 + 9 (step 7)
31b. Max R7C79 = 17 -> max R89C6 = 8 = [53], no 7 in R8C6
31c. R89C6 = [13/31/35] = 4,8 -> R7C79 = 13,17, no 6 in R7C7

32. 3 in 41(8) cage at R2C7 only in R2C7 + R3C78, locked for N3
32a. 45 rule on N3 3 innies R2C7 + R3C78 = 18 = {369/378}, no 1,2,5

33. 45 rule on C12 2 remaining outies R28C3 = 1 innie R6C2 + 6
33a. Min R6C2 = 4 -> min R28C3 = 10, no 1 in R2C3

34. 45 rule on N2 2(1+1) outies R1C3 + R4C4 = 1 innie R3C6 + 3
34a. R1C3 + R4C4 cannot total 4 -> no 1 in R3C6
[Note that, since there is now no 3 in R1C3 + R4C4, they cannot contain the same number.]

35. 1 in 41(8) cage at R2C7 only in R4C56 + R5C6, locked for N5
35a. 1 in C4 only in R123C4, locked for N2
35b. 1 in R6 only in R6C789, locked for N6

36. 2 in R4 only in R4C456
36a. R1C3 + R4C4 = R3C6 + 3 (step 34)
36b. Consider placements for 2 in R4C456
R4C4 = 2 => R1C3 + R4C4 cannot total 5 (no 3 in R1C3) => no 2 in R3C6
or 2 in R4C56, locked for 41(8) cage at R2C7, no 2 in R3C6
-> no 2 in R3C6
36c. 2 in 41(8) only in R4C56, locked for R4
36d. 2 in C4 only in R123C4, locked for N2
36e. Max R1C3 + R4C4 = 12, min R4C4 = 4 -> no 9 in R1C3

37. 20(5) cage at R7C8 (step 25) contains 2,3 = {12368/23456}
37a. 6 of {12368} must be in R8C789 (R8C6789 cannot be {1238} which clashes with R8C23, ALS block), 4 of {23456} must be in R7C8 -> no 6 in R7C8
37b. 6 in N9 only in R8C789, locked for R8
37c. R7C4 = 6 (only remaining place for 6 in 33(6) cage at R6C2, step 27)

38. 20(5) cage at R1C2 contains 2 = {12359/23456}
38a. 6,9 only in R2C3 -> R2C3 = {69}
38b. 20(5) cage = {12359/23456}, 5 locked for C2

39. Omitted. At this stage I originally did combination analysis on 29(5) cage at R4C8 and 27(5) cage at R4C9. After finding step 41, I realised this analysis wasn’t necessary.

40. 7 in N48 only in 45(3) cage at R3C3 and 33(6) cage at R6C2, no other 7 in 45(3) cage and 33(6) cage (Caged X-Wing), no 7 in R56C45

[I originally did step 41 using the cages in N6. Later I realised that there’s a simpler way.]
41. R2C7 + R3C78 (step 32a) = {369/378} -> R3C6 + R4C567 + R5C6 = {12569/12578}
41a. Consider the candidates in R4C7
R4C7 = 5 => R6C6 + R7C9 (step 6) = 16 = [79]
or R4C7 = 6 => R3C6 + R4C56 + R5C6 = {1259}, CPE no 9 in R6C6 => R6C6 = 7
-> R6C6 = 7, R7C9 = 9 (step 30b)
41b. R6C6 + R7C9 = 16 -> R4C7 = 5
[Cracked!]

[Both ways to do step 41 made step 40 unnecessary, so I’m glad that I spotted that step first; it’s an unusual Caged X-Wing.]

42. Naked triple {458} in R6C234, locked for R6 and 33(6) cage at R6C2 -> R8C4 = 7
42a. Naked pair {12} in R7C56, locked for R7, N8 -> R9C67 = [31], R8C6 = 5
42b. Naked pair {12} in R7C56, locked for 45(9) cage at R3C3, no 1 in R45C3
42c. R5C6 = 1 (hidden single in R5), R7C56 = [12]
42d. R7C2 = 7 (hidden single in N7)

43. R4C12 = {13} (hidden pair in R4)
43a. R13C3 = R4C12 + 6 (step 28a)
43b. R4C12 = {13} = 4 -> R13C3 = 10 = [19/46/64], no 5

44. R3C6 + R4C567 + R5C6 (step 41) = {12569} (only remaining combination) -> R4C5 = 2, R34C6 = {69}, locked for C6 and 41(8) cage at R2C7, no 6,9 in R2C7 + R3C78
44a. Naked triple {378} in R2C7 + R3C78, locked for N3

45. Naked pair {48} in R7C78, locked for N9
45a. 8 in C9 only in R45C9, locked for N6

46. R45C9 = {78} (hidden pair in N6), locked for C9 -> R9C89 = [75]
46a. R45C9 = {78} = 15, R7C9 = 9 -> R6C89 = 3 = {12}, locked for R6

47. R8C9 = 3 (hidden single in C9)
47a. R8C69 = [53] = 8, R8C78 = {26} = 8 -> R7C8 = 4 (cage sum), R7C7 = 8

48. Naked pair {37} in R23C7, locked for C7 and N3 -> R3C8 = 8

and the rest is naked singles.


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 Post subject: Re: Assassin 216
PostPosted: Thu Dec 22, 2011 2:43 am 
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Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1895
Location: Lethbridge, Alberta, Canada
When I posted my walkthrough for the V0.5, I wrote:
It's interesting that the V7 has exactly the same SS score 7.02 ◄ Select to see the SS score as goooder's Special 1; however it may well be a lot harder for human solvers.

It certainly was. The "trick" I used for goooder's Special 1 still works for this puzzle, but it's not so useful this time.

I thought that A216 V7 was possibly the hardest puzzle that I've managed to solve (so far? ;) ), although in one respect it wasn't. There have been several very hard puzzles where I got stuck and only came back to them much later. For this puzzle each time that I stopped I managed to make further progress next time I came back to it. However after I managed to simplify my walkthrough, more than I've simplified any previous walkthrough, it probably wasn't quite as hard as I originally thought that it was.

There were several times when, after making breakthrough steps, I omitted some fairly heavy combination analysis steps which I'd originally used. I did quite a lot of analysis on the 24(5) cage at R1C2 and then on the 24(5) cage at R7C8, which I think was necessary so that I could reach the later breakthrough steps. However I've managed to omit the much harder analysis on the pairs of 5 cell cages in N2 and N6.

The 45(9) cage at R3C3 proved to be more important for this puzzle than for the other ones using this cage pattern.

Thanks Børge for a really challenging variant! However that's not an invitation for more very high score puzzles; there are still a lot of those from Ruud's site (available here through the Archive, parts A, B and C) which I haven't yet solved and in many cases haven't yet tried. Maybe next year?!

Rating Comment.:
I'll rate my walkthrough for A216 V7 at 2.5, based on the ratings I've previously given for very hard puzzles. I used a lot of contradiction moves and forcing chains. It's possible that, with a bit more effort, some of the contradiction moves could have been replaced by forcing chains, which are more satisfactory unless they are more complicated. My rating is possibly a bit high after simplifying my walkthrough; it's more representative of my feeling for this puzzle as I originally finished it.
Here is my simplified walkthrough for A216 V7:
Prelims

a) R12C1 = {18/27/36/45}, no 9
b) R34C1 = {89}
c) R5C12 = {15/24}
d) R89C5 = {69/78}
e) R9C67 = {49/58/67}, no 1,2,3
f) R9C89 = {15/24}
g) 37(6) cage at R1C7 = {256789/346789}, no 1
h) 18(5) cage at R2C5 = {12348/12357/12456}, no 9
i) 36(8) cage at R2C7 = {12345678}, no 9
j) and, of course, 45(9) cage at R3C3 = {123456789}

Steps resulting from Prelims
1a. Naked pair {89} in R34C1, locked for C1, clean-up: no 1 in R12C1
1b. 18(5) cage at R2C5 = {12348/12357/12456}, CPE no 1,2 in R12C4

2. 45 rule on N3 3 innies R2C7 + R3C78 = 8 = {125/134}, 1 locked for 36(8) cage at R2C7, no 1 in R3C6 + R4C567 + R5C6

3. 45 rule on N2 1 innie R3C6 = 2(1+1) outies R1C3 + R4C4 + 2
3a. Max R3C6 = 8 -> max R1C3 + R4C4 = 6, no 6,7,8,9 in R1C3 + R4C4
3b. Cannot have repeats in R1C3 + R4C4 because there would be no place for that number in N2, since R3C6 must be greater than either of R1C3 and R4C4.
3c. Min R1C3 + R4C4 = 3 -> min R3C6 = 5

4. 18(3) cage at R8C1 = {279/369/378/459/468/567} (cannot be {189} because 8,9 only in R9C2), no 1

5. 45 rule on C1 3 innies R567C1 = 1 outie R9C2 + 1
5a. Min R567C1 = 6 -> min R9C2 = 5

6. 30(7) cage at R6C1 = {1234569/1234578}, CPE no 2,3,4,5 in R9C1

7. 3 in R9 only in R9C34, locked for 30(7) cage at R6C1, no 3 in R6C1 + R7C12 + R8C23
7a. R567C1 = R9C2 + 1 (step 5)
7b. Min R567C1 = 7 -> min R9C2 = 6
7c. Min R9C12 = 13 -> max R8C1 = 5

8. R9C67 = {49/58} (cannot be {67} which clashes with R9C1)
8a. Killer pair 4,5 in R9C67 and R9C89, locked for R9

9. Hidden killer pair 1,2 in R9C34 + R9C89, R9C89 contains one of 1,2 -> R9C34 must contain one of 1,2 -> R9C34 = {123}
[Alternatively killer quad 6,7,8,9 in R9C12, R9C5 and R9C67, locked for R9.]

10. 45 rule on N7 2 outies R6C1 + R9C4 = 1 innie R7C3 + 3
10a. Max R6C1 + R9C4 = 10 -> max R7C3 = 7

11. Hidden killer pair 8,9 in 30(7) cage at R6C1 and R9C2 for N7, 30(7) cage contains one of 8,9 -> R9C2 = {89}
11a. Killer pair 8,9 in R9C2 and R9C67, locked for R9, clean-up: no 6,7 in R8C5
11b. Min R9C12 = 14 -> max R8C1 = 4

12. R567C1 = R9C2 + 1 (step 5)
12a. R9C2 = {89} -> R567C1 = 9,10 = {126/127/145}
12b. R56C1 cannot total 6 which clashes with R5C12, CCC -> no 4 in R7C1

13. 30(7) cage at R6C1 = {1234569/1234578}
13a. 18(3) cage at R8C1 (step 4) = {369/378} (cannot be {279/468} which clash with 30(7) cage) -> R8C1 = 3, clean-up: no 6 in R12C1
13b. 6 in C1 only in R679C1, CPE no 6 in R7C2 + R8C23

14. R9C4 = 3 (hidden single in R9)

15. R8C1 = 3 -> R9C12 = 15
15a. R89C5 = 15, R9C12 = 15, R9C15 are naked pair {67} -> R8C5 + R9C2 must be naked pair {89}, CPE no 8,9 in R8C23 + R9C6, clean-up: no 4,5 in R9C7
15b. R79C2 = {89} (hidden pair in N7), locked for C2
15c. 4 in N7 only in R7C3 + R8C23, CPE no 4 in R8C4

16. 24(5) cage at R1C2 = {12678/13479/13569/13578/14568/23469/23478/23568} (cannot be {12489} because 8,9 only in R2C3, cannot be {12579} which clashes with R58C2, ALS block, cannot be {24567} which clashes with R12C1)
16a. 8,9 only in R2C3 -> R2C3 = {89}
16b. Killer pair 8,9 in R2C3 + R3C1, locked for N1

17. Consider placements for R9C3
17a. R9C3 = 1 => R5C1 = 1 (hidden single in C1)
or R9C3 = 2 => R9C89 = {15} => R9C67 = [49] => R9C2 = 8 => R567C1 (step 12a) = 9 = {126} => R5C1 = 2, R67C1 = {16}
-> R5C1 = R9C3 -> R5C1 = {12}, clean-up: no 1,2 in R5C2
17b. R9C3 = 1 or R67C1 = {16}, CPE no 1 in R8C23
17c. R567C1 (step 12a) = {126/127/145}
17d. 4 of {145} must be in R6C1 -> no 5 in R6C1
17e. 5 in 30(7) cage at R6C1 only in R7C1 + R8C23, locked for N7

18. 24(5) cage at R1C2 (step 16) = {12678/13479/13569/13578/23469/23568} (cannot be {14568} which clashes with R5C2, cannot be {23478} which clashes with R58C2, ALS block)
18a. 24(5) cage = {12678} => R6C2 = 3 (hidden single in C2)
or for all other combinations, killer pair 4,5 in 24(5) cage at R5C2, locked for C2
-> no 4,5 in R6C2

19. 24(5) cage at R1C2 (step 18) = {12678/13479/13569/13578/23469/23568} cannot be {23469}, here’s how
24(5) cage = {23469} => R568C2 = [517] clashes with R5C12 = [15], CCC
-> 24(5) cage at R1C2 = {12678/13479/13569/13578/23568}

20. 24(5) cage at R1C2 (step 19) = {12678/13479/13569/13578/23568} cannot be {23568}, here’s how
24(5) cage = {23568} => R5C2 = 4, R5C1 = 2, R68C2 = [17] => 7 in C1 only in R12C1 = {27} clashes with R5C1
-> 24(5) cage at R1C2 = {12678/13479/13569/13578}, 1 locked for C2

21. 24(5) cage at R1C2 (step 20) = {12678/13479/13569/13578} cannot be {13569}, here’s how
24(5) cage = {13569} => R5C2 = 4, R5C1 = 2, R9C3 = 2 (step 17a) => cannot place 2 in C2
-> 24(5) cage at R1C2 = {12678/13479/13578}, 7 locked for C2
21a. Hidden killer pair 3,6 in 24(5) cage and R6C2 for C2, 24(5) cage contains one of 3,6 -> R6C2 = {36}

22. Consider the combinations for 24(5) cage at R1C2 (step 21) = {12678/13479/13578}
24(5) cage = {12678/13479} => no 5 in 24(5) cage
or 24(5) cage = {13578} => R5C2 = 4, R5C1 = 2, R12C1 = {45}, locked for N1 => R1234C2 = {137}5
-> no 5 in R123C2

23. Consider the combinations for 24(5) cage at R1C2 (step 21) = {12678/13479/13578}
24(5) cage = {12678/13578} => no 4 in 24(5) cage
or 24(5) cage = {13479} => R5C2 = 5, R5C1 = 1, R8C2 = 2 (hidden single in C2), 2 in C1 only in R12C1 = {27} => R1234C2 = {134}7
-> no 4 in R4C2

24. Consider the combinations for 24(5) cage at R1C2 (step 21) = {12678/13479/13578}
24a. 24(5) cage = {12678} => R12C1 = {45} => no 4,5 in R13C3, no 3 in R4C2
or 24(5) cage = {13479} => R1234C2 = {134}7 (step 23) => R12C1 = {27} => R13C3 = [56]
or 24(5) cage = {13578} => R1234C2 = {137}5 (step 22) => R12C1 = {45} => R13C3 = [26]
-> no 4 in R1C3, no 4,5 in R3C3, no 3 in R4C2

25. 3,7 in N9 only in R7C79 or in 24(5) cage at R7C8
25a. 45 rule on N9 2 innies R7C79 = 2 outies R89C6 + 2
25b. R89C6 cannot total 8 (because no 3 in R8C6) -> R7C79 cannot total 10 -> cannot be {37} -> 24(5) cage at R7C8 must contain at least one of 3,7
25c. 24(5) cage at R7C8 = {12579/12678/13479/13569/13578/23469/23568} (cannot be {12489/14568} which don’t contain 3 or 7, cannot be {23478/24567} which clash with R8C23, ALS block)
25d. {12579/12678} don’t contain 4, 3 in the other combinations must be in R7C8 -> no 4 in R7C8
25e. 9 of {12579} must be in R8C6789 (R8C6789 cannot be {1257} which clashes with R8C23, ALS block), {12678} doesn’t contain 9, 3 in all other combinations must be in R7C8 -> no 9 in R7C8

26. R9C67 = [49/58], R9C89 = {15/24} -> combined cage R9C6789 = [49]{15}/[58]{24} -> R9C789 = 8{24}/9{15}, all three even or all three odd
26a. Consider the combinations for 24(5) cage at R7C8 (step 25c) = {12579/12678/13479/13569/13578/23469/23568}
26b. 24(5) cage = {12579} must have 2 in R8C6 (otherwise clash with R9C789) and one of 5,7 in R7C8 (R8C6789 cannot contain all of 2,5,7 which clashes with R8C23, ALS block)
or 24(5) cage = {12678} must have 1 in R8C6 (otherwise clash with R9C789)
or 3 of the other combinations must be in R7C8
-> no 1 in R7C8
26c. 2 of {12579} must be in R8C6, 1 of {12678} must be in R8C6, 4,8 of {13479/13578} must be in R8C6 (otherwise clash with R9C789) -> no 7 in R8C6

27. Consider the combinations for R9C789 (step 26) = 8{24}/9{15}
27a. R9C789 = 8{24}, locked for N9
or R9C789 = 9{15} => R9C3 = 2, R9C2 = 8, R9C1 = 7 (cage sum) => R8C23 = {45}
CPE no 4 in R8C789
27b. 24(5) cage at R7C8 (step 25c) = {12579/12678/13479/13569/13578/23568} (cannot be {23469} = 34{269} which clashes with R9C789)

28. Similarly
R9C789 = 8{24}, R9C6 = 5
or R9C789 = 9{15} => R9C3 = 2, R9C2 = 8, R9C1 = 7 (cage sum) => R8C23 = {45}
CPE no 5 in R8C46

29. 24(5) cage at R7C8 (step 27b) = {12579/12678/13479/13569/13578} (cannot be {23568} = 3{2568} which clashes with R9C789), 1 locked for R8

30. Consider the combinations for 24(5) cage at R7C8 (step 29) = {12579/12678/13479/13569/13578}
24(5) cage = {12579/13479/13569/13578}, killer pair 8,9 in R8C5 and R8C789 (because 3 of {13479/13569/13578} must be in R7C8), locked for R8
or 24(5) cage = {12678} => R9C789 = 9{15} => R9C2 = 8, R9C1 = 7 (cage sum), R9C5 = 6, R8C5 = 9
-> no 9 in R8C4

31. 24(5) cage at R7C8 (step 29) = {12579/12678/13479/13569/13578} (cannot be {13479}, here’s how
24(5) cage = 34{179}, 4,7 locked for R8 => R8C23 = {25}, locked for N7 and 30(7) cage at R6C1, R9C3 = 1, R6C1 = 4 (only remaining place for 4 in 30(7) cage at R6C1), R79C1 = {67} clashes with R12C1 = {27}
-> 24(5) cage = {12579/12678/13569/13578}, no 4

32. 4 in R8 only in R8C23, locked for N7 and 30(7) cage at R6C1, no 4 in R6C1
32a. 4 in C1 only in R12C1 = {45}, locked for C1 and N1
32b. 7 in C1 only in R679C1, CPE no 7 in R8C3

33. 24(5) cage at R1C2 (step 21) = {12678/13578} -> R2C3 = 8, R34C1 = [98]
33a. 8 in 36(8) cage at R2C7 only in R35C6, locked for C6

34. R8C23 = {45} (hidden pair in N7), locked for R8

35. 2 in C2 only in 24(5) cage at R1C2 (step 33) = {12678} (only remaining combination), no 3,5

36. R6C2 = 3 (hidden single in C2)

37. 24(5) cage at R7C8 (step 31) = {12579/12678} (cannot be {13569/13578} because 3,5 only in R7C8), no 3, 7 locked for N9
37a. 1,2 cannot both be in N9 (because of clash with R9C89) -> R8C6 = {12}
37b. Killer pair 1,2 in 24(5) cage and R9C89, locked for N9
37c. Killer pair 8,9 in 24(5) cage and R9C7, locked for N9
37d. 8 in C6 only in R35C6, R3C6 = 8 or R5C6 = 8 => R7C5 = 8 (hidden single in 45(9) cage at R3C3), CPE no 8 in R13C5

38. Consider the combinations for 24(5) cage at R7C8 (step 37) = {12579/12678}
24(5) cage = {12579} => R8C3 = 6 (hidden single in R8)
or 24(5) cage = {12678} => R8C5 = 9 (hidden single in R8), R9C5 = 6
CPE no 6 in R7C456
38a. 24(5) cage = {12579}, no 6
or 24(5) cage = {12678} => R8C5 = 9 (hidden single in R8), R9C5 = 6, 6 in R8 only in R8C789, locked for N9
-> no 6 in R7C8

39. Consider the combinations for 24(5) cage at R7C8 (step 37) = {12579/12678}
24(5) cage = {12579} => R7C79 = {36} (hidden pair in N9)
or 24(5) cage = {12678} => R8C6 = 1 (R7C8 + R8C789 cannot be {1678} which clashes with R9C789) => R7C8 + R8C789 = {2678} => R9C89 = {15} => R7C79 = {34} (hidden pair in N9)
-> R7C79 = {34/36}, no 5

40. 45 rule on N6 2(1+1) outies R6C6 + R7C9 = 1 innie R4C7 + 6
40a. Min R4C7 = 2 -> min R6C6 + R7C9 = 8, max R7C9 = 6 -> min R6C6 = 2

41. 45 rule on N69 3 outies R689C6 = 2 innies R47C7 + 4
41a. Min R47C7 = 6 (cannot be 5 because R689C6 cannot total 9)
41b. Min R689C6 = 10, max R89C6 = 7 -> no 2 in R6C6
41c. Max R689C6 = 16 -> max R47C7 = 12

42. R4C7 cannot be 2, here’s how
42a. R4C7 = 2 => R2C7 + R3C78 = {134} (step 2), R7C7 = {46} (because min R47C7 = 6, step 41a), R7C9 = 3 (hidden single in R7), R6C6 = 5 (step 40) “sees” all 5s in 36(8) cage at R2C7
-> no 2 in R4C7

43. Similarly R4C7 cannot be 3, here’s how
43a. R4C7 = 3 => R7C9 = 3 (hidden single in R7), R6C6 = 6 (step 40) “sees” all 6s in 36(8) cage at R2C7
-> no 3 in R4C7

44. R7C79 = R89C6 + 2 (step 25a)
44a. R7C79 = {34/36} = 7,9 -> R89C6 = 5,7 = [14/25]
44b. R4C7 cannot be 5, here’s how
R4C7 = 5, R7C7 = 3, R7C9 = 4, R6C6 = 7 (step 40) “sees” all 7s in 36(8) cage at R2C7
or R4C7 = 5, R7C7 = 3, R7C9 = 6, R89C6 = [25], R6C6 (step 40) = 5 clashes with R9C6
or R4C7 = 5, R7C7 = {46} => R7C9 = 3 (hidden single in R7), R6C6 + R7C9 = 11 but there’s no 8 in R6C6
-> no 5 in R4C7

45. R7C7 cannot be 6, here’s how
R4C7 = 4, R7C7 = 6, R7C9 = 3 (hidden single in R7), R6C6 = 7 (step 40) “sees” all 7s in 36(8) cage at R2C7
or R4C7 = 6 -> no 6 in R7C7
or R47C7 cannot be [76] because max R47C7 = 10 (step 41c)
-> no 6 in R7C7

[Continuing analysis in this area, using the 45s in steps 40 and 41.]
46. R7C79 = {34/36} = 7,9 -> R89C6 = 5,7 = [14/25] (step 44a)
46a. R47C7 = [43] => R689C6 = [425] (cannot be [614] because R6C6 “sees” all 6s in 36(8) cage at R2C7)
or R47C7 = [63] = 9 => R6C6 + R7C9 (step 40) = 12 = [66] => R689C6 = 13 = [625]
or R47C7 = [64] = 10 => R7C9 = 3 => R689C6 = 14 = [914]
or R47C7 = [73] = 10 => R689C6 = 14 = [725/914]
or R47C7 cannot be [74] = 11 because R689C6 (step 41) cannot total 15 with R89C6 = 5,7
-> R47C7 = [43/63/64/73], R689C6 = [425/625/725/914], no 5 in R6C6
46b. R4C7 + R6C6 + R7C9 = [446/666/693/776/794]

[At this stage I originally did detailed combination interactive analysis of the 27(5) and 24(5) cages in N6, followed by detailed innie-outie analysis for N5. After doing the latter I found some better steps which I’ve moved forward to here, in the hope that the detailed analysis can be avoided, or at least simplified.]

47. R7C79 = [34/36] => R1C3 = 3 (hidden single in C3)
or R7C79 = [43] => R89C6 = [14] (step 44a), R9C89 = {15}, locked for R9 => R9C3 = 2 => R1C3 = {13}
-> R1C3 = {13}, no 2

[Step 47 made some use of the snake-like 45(9) cage; this makes more use of it.]
48. Consider the placements for 3 in C3 and R7
R3C3 = 3 => no 3 in R5C5
or R7C7 = 3 => no 3 in R5C5
or R1C3 + R7C9 = [33] (only other places for 3 in C3 and R7) => R7C7 = 4, R4C7 + R6C6 = [69] (step 46b), R4C4 = 2 (step 3, because there’s no 6 in R3C6) => 1,2,5 of 36(8) cage at R2C7 must be in R2C7 + R3C78 (step 2) => R4C56 + R5C6 must contain 3,4 for 36(8) cage at R2C7, locked for N5 => no 3 in R5C5
-> no 3 in R5C5
[Possibly the most important step so far, apart from the placements.]

49. 3 in N5 only in R4C56 + R5C6, locked for 36(8) cage at R2C7, no 3 in R2C7 + R3C78, clean-up: no 4 in R2C7 + R3C78 (step 2)
49a. Naked triple {125} in R2C7 + R3C78, locked for N3 and 36(8) cage, no 2,5 in R3C6 + R4C567 + R5C6
49b. 4 in 36(8) cage only in R4C567 + R5C6, if R4C7 = 4 => R689C6 = [425] (step 46b) -> 4 must be in R4C56 + R56C6, locked for N5

50. Consider the placements for 3 in 45(9) cage at R3C3
R3C3 = 3 => R7C9 = 3 (hidden single in R7)
or R7C7 = 3 => R1C3 = 3 (hidden single in C3)
-> 3 must be in R1C3 or R7C9, CPE no 3 in R1C9
[Not quite a generalised X-Wing or XY-Wing, possibly some sort of “fish”.]

51. 45 rule on N2356 4 innies R56C45 = 2(1+1) outies R1C3 + R7C9 + 13
51a. Consider permutations for R7C79 and their effect on N5
R7C79 = [34], R4C7 + R6C6 = [79] (step 46b), R1C3 = 3 (hidden single in C3), R1C3 + R7C9 = [34] = 7 => R56C45 = 20 must contain 7 but not 9 = {2567} => R4C4 = 1, R5C6 = 8 (hidden singles in N5)
or R7C79 = [36], R89C6 = [25] (step 44a), R9C7 = 8, R4C7 + R6C6 = [44/66/77] (step 46b), R1C3 = 3 (hidden single in C3), R1C3 + R7C9 = [36] = 9 => R56C45 = 22 must contain 9 = {1579/2569} => R4C4 = {12}, R5C6 = 8 (hidden single in N5)
or R7C79 = [43] , R89C6 = [14] (step 44a), R3C3 = 3 (only place for 3 in 45(9) cage at R3C3), R1C3 = 1, R4C4 = 5 (because min R3C6 = 6 => min R1C3 + R4C4 = 4, step 3), R3C6 = 8 (step 3), R4C7 + R6C6 = [69] (step 46b), R1C3 + R7C9 = [13] = 4 => R56C45 = 17 must contain 6 and 8 = {1268} => R5C6 = {37}
-> R5C6 = {37} or R5C6 = 8, no 4,6 in R5C6
51b. 4 in 36(8) cage at R2C7 only in R4C567, locked for R4

[Steps 52 to 59 have been omitted. They were detailed combination interactive analysis of the 25(5) and 18(5) cages in N2, then of the 27(5) and 24(5) cages in N6.]

[It was only after doing detailed combination analysis on the cages in N6 (now omitted) that I realised that, as well as examining R7C79 = [34/36/43], I can get something more from R7C79 = {34} but only because I’ve eliminated 4 from R56C45.]
60. Consider R7C79 = {34} => R89C6 = [14] (step 44a), R9C89 = {15}, locked for R9, R9C3 = 2, R5C1 = 2 (step 17a), R5C2 = 4 => R7C7 = 4 (only remaining place for 4 in 45(9) cage at R3C3), R7C9 = 3
-> R7C79 = [36/43], no 4 in R7C9

[Steps 61 to 64 have been omitted. They were further detailed combination interactive analysis of the 27(5) and 24(5) cages in N6.]

[I first saw the next step as a contradiction move, see note after this step. I’ve tried reworking it as a forcing chain and almost managed it; one branch still ended in a contradiction. I’m writing it this way because it doesn’t necessarily follow that the chains in step 51a work in reverse; some chains aren’t reversible.]
65. R1C3 + R7C9 = [13/36] (because 3 must be in R1C3 or R7C9, step 50) = 4,9 -> R56C45 (step 51) = 17,22
65a. Consider placements for 8 in 45(9) cage at R3C3
8 in R5C45 + R6C5 => only combinations for R56C45 totalling 17,22 and containing 8 are {1268/2578} (cannot be {1678} which clashes with R4C56 + R5C6, ALS block)
then R56C45 = {1268} = 17 => R1C3 + R7C9 = 4 = [13] => R7C79 = [43]
or then R56C45 = {2578} => R5C6 = 3, R4C56 = {46}, R4C7 = 7, R6C6 = 9 but R4C7 + R6C6 cannot be [79] because there’s no 4 in R7C9 (step 46b)
or 8 in R7C5 => R89C5 = [96], R9C1 = 7, R9C2 = 8 (cage sum), R9C7 = 9, R9C6 = 4, R8C6 = 1 (step 44a) => R7C79 = [43] (step 44a)
-> R7C79 = [43]
[This result is obtained more simply as a contradiction. R7C79 = [36] => R5C6 = 8 (step 51a), R7C5 = 8 (only remaining place for 8 in 45(9) cage at R3C3); R7C79 = [36], R89C6 = [25] (step 44a), R9C7 = 8, R9C2 = 9, R9C1 = 6 (cage sum), R9C5 = 7, R8C5 = 8 clashes with R7C6 -> R7C79 cannot be [36] -> R7C79 = [43].]

[Now the puzzle is cracked, although there are still several cages to be sorted out.]

66. R7C79 = [43], R89C6 = [14] (step 44a), R4C5 = 4 (hidden single in N5), R9C7 = 9, R9C2 = 8, R9C1 = 7 (cage sum), R9C5 = 6, R8C5 = 9, R7C2 = 9, clean-up: no 2 in R9C89

67. R9C89 = {15}, locked for R9 and N9, R9C3 = 2, R5C1 = 2 (hidden single in C1), R5C2 = 4, R8C23 = [54]

68. R3C3 = 3 (only remaining place for 3 in 45(9) cage at R3C3), R1C3 = 1, R7C3 = 6, R67C1 = [61]
68a. R4C2 = 1 (hidden single in C2)

69. Min R3C6 = 6 -> min R1C3 + R4C4 = 4 (step 3) -> R4C4 = 5, R3C6 = 8 (step 3)

70. R7C9 = 3 -> R4C7 + R6C6 = [69] (step 46b)
70a. Naked pair {37} in R45C6, locked for C6 and N5
70b. R5C4 = 6 (hidden single in N5)

[The remaining steps have been re-worked; the original steps used some results from the omitted combination analysis.]

71. 5 in N8 only in R7C56, locked for 45(9) cage at R3C3, no 5 in R5C3
71a. R6C3 = 5 (hidden single in C3)

72. 31(6) cage at R6C2 = {235678} (only remaining combination) -> R678C4 = {278}, locked for C4, 7 also locked for N8

73. R3C4 = 1 (hidden single in C4)

74. Naked pair {25} in R3C78, locked for R3 and N3 -> R2C7 = 1, R3C5 = 7, R3C2 = 6, R3C9 = 4

75. 18(5) cage at R2C5 = {12357} (only remaining combination) -> R2C56 = [32]

76. R7C9 = 3, 4 and 9 in N6 only in 24(5) cage at R4C9 = {13479} (only remaining combination) -> R6C8 = 4, R456C9 = {179}, locked for C9 and N6

77. R4C8 = 2 (hidden single in R4)

and the rest is naked singles.


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