Afmob has verified the previous few steps
[edit: and thanks to Andrew for some corrections]. So, continuing on.
32. r4c4 = (24) -> 45(9)n56 must have at least one of 2 or 4 in n6 -> {249} combo blocked from 15(3)r4c9
32a. 15(3)r4c9 = {168/267/456}(no 9)
Looks like it might be cracked now so will miss lots of clean-up.
33. r9c9 = 9 (hsingle c1)
33a. r8c9 = 3
33b. r89c1 = [85]
34. r5c1 = 9 (hsingle c1)
34a. r5c23 = 6 = {15} ({24} blocked by r4c3): both locked for r5 & n4
35. r4c7 = 9 (hsingle n6)
36. no 3 in the two 8(2) cages in c1
36a. 3 only in 15(3)n1 = [438] (only valid permutation) (must have been a hidden single 4 for c1 here too)
37. r4c6 = 1 (hsingle r4)
37a. r4c8 = 7 (hsingle r4)
38. 5 in n1 only in 22(3) = {589}
38a. r1c3 = 8, r12c2 = {59}: both locked for c2
39. r8c3 = 9 (hsingle n7)
39a. r5c23 = [15]
40. 11(2)n7 = {47}: both locked for n7 & r9
41. 20(4)n4 = {236}[9] -> r7c2 = 3
41a. r68c2 = {26}: locked for c2
42. r3c2 = 7 -> r3c34 = 4 = {13}: both locked for r3
43. 8(2)n1 = {26}: both locked for n1 & c1
43a. r67c1 = [71]
44. "45" n3: 1 remaining outie r1c6 = 2, r1c7 = 3
44a. r9c6 = 3
44b. r9c78 = 8 = {26}: both locked for r9 & n9
45. "45" n9: 1 remaining outie r6c8 = 3
46. "45" n7: 4 outies r6c1234 = 23 = [7]{26}[8] (only permutation)
46a. 2 & 6 both locked for n4 & r6
46b. r4c34 = [42]47. 8 in 45(9)n5 only in n6: locked for n6
47a. 5 in 45(9) only in c5: locked for c5
47b. r12c5 = 8 =
{17} only: both locked for c5 and n248. 15(3)r4c9 = {456}: all locked for c9 & n6
48a. h9(2)r17c9 = [18]
48b. r7c8 = 4 (cage sum)
48c. r1c8 = 9
48d. r12c2 = [59]
48e. r12c5 = 8 = [71]49. r23c3 = [31]
49a. r12c4 = 9 = [45]
49b. r6c6 = 950. r7c56 = 11 = [65]
Rest are singles.
Turns out that steps 28a, 29 & 30 were the keys ones. Very impressed that
manu did this one on his own.
Quite satisfied with that solution. Thanks again
manu and
Afmob.
Cheers
Ed