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 Post subject: Assassin 181
PostPosted: Thu Nov 12, 2009 10:38 pm 
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Joined: Sat Jun 07, 2008 2:29 pm
Posts: 43
A relatively easy puzzle for this week, but you will still have to dig a little for the opening move.
I thought this was appropriate since many of us are still working through udosuk's Ray series,
Borge's girlfriends, and manu's challenging A180 (me included).

Note-read if you wish--not a spoiler:
This puzzle fits the criteria for an 'X' puzzle, no repeats on
the diagonals, so add them if you wish. It won't help you solve the puzzle or make it
any easier! :P


Enjoy!

Assassin 181
Image

3x3::k:5632:5633:5633:5633:5892:2309:2309:2309:5128:5632:5632:1547:1547:5892:4110:4110:4880:5128:1554:5632:1547:5141:4630:5892:4110:4880:5128:1554:5632:5141:2334:4630:4630:5892:4880:5128:5141:5141:2334:4647:4647:4647:1834:4651:4651:5421:5422:4399:3888:3888:1834:4651:6452:1589:5421:5422:4920:4399:3888:4651:4924:6452:1589:5421:5422:4920:4920:4399:4924:4924:6452:6452:5421:2889:2889:2889:4399:4685:4685:4685:6452:

Solution:
798563421
652194783
413287569
239846157
541729638
867351294
384675912
176932845
925418376


SS Score: 1.17


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 Post subject: Re: Assassin 181
PostPosted: Thu Nov 12, 2009 11:28 pm 
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Grand Master
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Joined: Mon Apr 21, 2008 10:32 am
Posts: 868
An Image for those of you who like to scribble and solve the Joe Casey way:
Hidden Text:
Image

_________________
Quis custodiet ipsos custodes?
Normal: [D  Y-m-d,  G:i]     PM->email: [D, d M Y H:i:s]


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 Post subject: Re: Assassin 181
PostPosted: Fri Nov 13, 2009 10:24 am 
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Expert
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Joined: Sat Jan 17, 2009 8:30 am
Posts: 118
Location: france
Ronnie G wrote:
but you will still have to dig a little for the opening move.


Right ! My more difficult moves were the first ones ! I understand what you mean.
I had fun with finding them. Thanks Ronnie G !

A181 Walkthrough

edit: some corrections :thanks Ronnie G and Andrew


Hidden Text:
Two killer triples {123} used, and the puzzle is cracked after step 2)

(prelims from Sudocue)

1)a) Cage 22(5) at r1c1 must contain at least two of {123} since 1+4+5+6+7=23 > 22.
b) r23c3=(123)
=> r1c1+r2c1+r2c2+r3c2 contains at most one of {123}
c) We deduce from a)+b) that :
(i) r1c1+r2c1+r2c2+r3c2 contains exactly one of {123}
(ii) r4c2=(123)
(iii) Killer triple {123} locked for n1 at r23c3+ r1c1+r2c1+r2c2+r3c2.
d) 6(2) at r3c1 : 6(2)=[42/51]

2)a) Outies for r1234 : r5c123=h10(3)
b) Since r4c12=(123), h10(3 :( ) contains at most one of {123}
=> h10(3)={145} locked for r5 and n4.

The puzzle is cracked


3)a) r4c1=2, r3c1=4.
b) r4c2=3.
c) Outies for n1 : r12c4=h6(2). Since min. r1c4=5, r12c4=[51].
d) r23c3={23} locked for n1 and c3
e) r1c23={89} locked for r1 and n1
f) 8 and 9 are locked for c1 at 21(4) : 21(4)={1389} locked for c1.r6c1=(89)
g) r5c1=5, r12c1={67} locked for n1. R3c2=1, r2c2=5.
h) r5c2=4, r5c3=1 => r4c4=8 (cage sum).
i) Last combo : 20(4) at r3c4 : [2954]
j) r1c23=[98], r6c1=8.
k) Hidden single for c2 : r9c2=2.
l) Combos for 11(3) at r9c2 : 11(3)=[254/263].
m) 4 locked for c3 at cage 19(3) : since 19(3)<>8, we have 19(3)={469} : r8c4=9, r78c3={46} locked for c3 and n7.
n) 11(3)r9c2=[254], r6c2=6, r6c3=7

4)a) Naked singles : r6c4=3, r7c4=6 and r5c4=7
b) Last combo :17(4)r6c3={1367} : r89c5={13} locked for c5 and n8
c) 18(3)r3c5 cannot contain 1, since combination {189} is blocked by r4c34=[98]
=> Hidden single for c6 : r6c6=1, r5c7=6 (cage sum)
d) 18(3)r5c4 : [7{29}], {29} locked for r5 and n5
e) r5c89={38} locked for n6 and the rest of 18(4)
f) Last combination : 18(4)r5c8={2358}
g) Hidden single for r6 : r6c8=9
h) 19(3)r2c8=8{47/56} : r5c89=[38]

5)a) Innies c9 : r89c9=h11(2) => (cage sum) r78c8=h5(2)={14} locked for c8, n9 and the rest of 25(5)
b) h11(2)r8c9 =[56]
c) 6(2)r6c9=[42]
d) 19(3)r2c8={568} locked for c8
e) Hidden single for c8 : r9c8=7 => 18(3)=[837]
f) Hidden single for c5 : r5c5=2=> r5c6=9
g) Hidden pair for r4 : r4c56={46} locked for n5
h) Cage sum : r3c5=8.
i) 19(3)r2c8=[865]
j) 15(3)r6c4=[357]
k) r23c3=[23]
l) r78c6=[52]
m) r3c6=7
n) r2c5=9 (hidden single)
o) Last combo for 23(4) at r1c5 : [6971]

The rest is naked singles


Last edited by manu on Sat Nov 14, 2009 5:13 pm, edited 1 time in total.

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 Post subject: Re: Assassin 181
PostPosted: Fri Nov 13, 2009 4:03 pm 
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Joined: Sat Jun 07, 2008 2:29 pm
Posts: 43
Well, that was entirely too easy for you people. Someone please hurry up & sign the schedule so I can post something a bit more challenging!

P.S. Thanks, Borge, for the much improved image!


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 Post subject:
PostPosted: Fri Nov 13, 2009 9:24 pm 
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Grand Master
Grand Master

Joined: Mon Apr 21, 2008 9:44 am
Posts: 310
Location: MV, Germany
Thanks for this fun Killer, Ronnie! Like manu I cracked this Killer right at the start but the moves he and I used aren't trivial, so SudokuSolver's rating sounds right.

A181 Walkthrough:

1. R123 !
a) Outies R1234 = 10(3) <> 8,9
b) ! Outies N1 = 11(2+2): R4C12 >= 5 since (12,13) are Killer pairs of Outies R1234
-> R1C4 = 5, R2C4 = 1 and R4C12 = 5(2) = [14/23/41]
c) 6(3) = {123} -> 2,3 locked for C3+N1
d) 22(3) = {589} -> 8,9 locked for R1+N1
e) 22(5) = {13567} -> R4C2 = 3; 1,5 locked for N1
f) R3C1 = 4 -> R4C1 = 2
g) 9(2) = [45/81]
h) Outies R1234 = 10(3) = {145} -> R5C2 = 4; 1,5 locked for R5+N4
i) Hidden Single: R9C2 = 2 @ C2, R3C2 = 1 @ C2

2. C123
a) Innies C1 = 18(3) = {567} -> R5C1 = 5; 6,7 locked for C1+N1
b) R5C3 = 1 -> R4C4 = 8
c) 20(4) = {2459} -> R4C3 = 9, R3C4 = 2
d) R1C3 = 8
e) 19(3) = {469} since R78C3 <> 3,9 -> R8C4 = 9; 4,6 locked for C3+N7
f) 11(3) = {245} -> R9C3 = 5, R9C4 = 4
g) 21(3) = {678} -> R6C2 = 6; 8 locked for N7
h) R6C3 = 7, R6C4 = 3, R7C4 = 6, R7C3 = 4
i) 17(4) = {1367} -> 1,3 locked for C5+N8

3. R4567
a) 18(3) @ R5 = {279} -> R5C4 = 7; 2,9 locked for R5+N5
b) 18(3) @ N2 <> 1 since R4C5 = (456)
c) Hidden Single: R6C6 = 1 @ N5 -> R5C7 = 6
d) 18(4) = {2358} since R5C89 = (38) -> 8 locked for N6; R6C7+R7C6 = (25)
e) 15(3) = 3[48/57]
f) Naked pair (78) locked in R7C25 for R7
g) 19(3) = 9{28/37} since R7C7 <> 7,8 -> R7C7 = 9

4. C789
a) 18(3) = {378} locked for R9; 3 also locked for N9
b) 19(3) @ N9 = {289} -> 2,8 locked for R8
c) 25(5) = 169{27/45} -> R6C8 = 9; 1 locked for N9
d) 6(2) = {24} -> R7C9 = 2, R6C9 = 4
e) 19(3) @ N3 = 8{47/56} -> 8 locked for C8+N3; R23C8 <> 5,7
f) R6C5 = 5, R6C7 = 2
g) 20(4) = {1379} locked for C9; 3 also locked for N3
h) 16(3) = {457} since R23C7 = (457) -> 5 locked for C7; CPE: R2C89 <> 4,7

5. Rest is singles.

Rating:
Hard 1.0. I used two Killer pairs in combination with a fairly large Hidden Cage.


Last edited by Afmob on Sat Nov 14, 2009 7:22 pm, edited 3 times in total.

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 Post subject: Re: Assassin 181
PostPosted: Sat Nov 14, 2009 5:38 am 
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Grand Master
Grand Master

Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1895
Location: Lethbridge, Alberta, Canada
Thanks Ronnie. I enjoyed your latest Assassin!

My breakthrough was basically the same as Afmob's but it took me a few steps to find it. Some of my earlier steps seemed a bit irrelevant although one proved to be useful later; they could however be useful for a harder puzzle using the same cage structure so that's another reason why I've kept them in. I found manu's way to crack this puzzle very interesting. I'd never have thought to look at the 22(5) cage so early; maybe I ought to learn to look at such things earlier.

Rating Comment:
I'll rate my walkthrough for A181 at Easy 1.25 which is consistent with the SS score. I used 4(2+2) outies.

Here is my walkthrough for A181.

Prelims

a) R34C1 = {15/24}
b) 9(2) cage at R4C4 = {18/27/36/45}, no 9
c) 7(2) cage at R5C7 = {16/25/34}, no 7,8,9
d) R67C9 = {15/24}
e) 22(3) cage at R1C2 = {589/679}
f) 9(3) cage at R1C6 = {126/135/234}, no 7,8,9
g) 6(3) cage at R2C3 = {123}
h) 19(3) cage at R2C8 = {289/379/469/478/568}, no 1
i) 21(3) cage at R6C2 = {489/579/678}, no 1,2,3
j) 19(3) cage at R7C3 = {289/379/469/478/568}, no 1
k) 19(3) cage at R7C7 = {289/379/469/478/568}, no 1
l) 11(3) cage at R9C2 = {128/137/146/236/245}, no 9

Steps resulting from Prelims
1a. 9 locked in 22(3) cage at R1C2, locked for R1
1b. Naked triple {123} in 6(3) cage at R2C3, CPE no 1,2,3 in R2C12

2. 45 rule on C9 3 innies R589C9 = 19 = {289/379/469/478/568}, no 1

3. 45 rule on R1234 3 innies R3C4 + R4C34 (which form a hidden cage because they “see” each other) = 19 = {289/379/469/478/568}, no 1, clean-up: no 8 in R5C3
3a. 45 rule on R1234 3 outies R5C123 = 10 = {127/136/145/235}, no 8,9

4. 45 rule on R6789 3 innies R6C67 + R7C6 (which form a hidden cage because they “see” each other) = 8 = {125/134}, clean-up: no 1 in R5C7
4a. Max R6C7 + R7C6 = 7 -> min R5C89 = 11, no 1 in R5C8

5. R5C123 (step 3a) = 10
5a. 45 rule on C12 2 innies R19C2 = 1 outie R5C3 + 10
5b. Min R19C2 = 11, no 1 in R9C2

6. 45 rule on R6789 3 outies R5C789 = 17
6a. 45 rule on C89 2 innies R19C8 = 1 outie R5C7 + 3
6b. Max R5C7 = 6 -> max R19C8 = 9, no 9 in R9C8

7. 45 rule on N1 4(2+2) outies R12C4 + R4C12 = 11
7a. Min R12C4 = 6 -> max R4C12 = 5
7b. R4C12 = {14/23} (cannot be {12/13} which clash with R5C123), clean-up: no 1 in R3C1
7c. R4C12 = 5 -> R12C4 = 6 = [51], clean-up: no 4 in R5C3
7d. 22(3) cage at R1C2 = {589} (only remaining combination), 8,9 locked for R1 and N1
7e. Naked pair {23} in R23C3, locked for C3 and N1, clean-up: no 6,7 in R3C4, no 4 in R4C1
7f. R4C1 = {12} -> R4C2 = {34}

8. R5C123 (step 3a) = {145/235} (cannot be {127} which clashes with R4C1, cannot be {136} which clashes with R4C12), no 6,7, 5 locked for R5 and N4, clean-up: no 2,3 in R4C4, no 2 in R6C6
8a. Killer pair 1,2 in R4C1 and R5C123, locked for N4
8b. Killer pair 3,4 in R4C2 and R5C12, locked for N4
[Or steps 8a and 8b could be given as naked quint {12345} in R4C12 + R5C123, locked for N4.]

9. 22(5) cage at R1C1 = {13567} (only remaining combination) -> R4C2 = 3, R4C1 = 2 (step 7b), R3C1 = 4
9a. R5C2 = 4 (hidden single in N4), R3C2 = 1, R9C2 = 2 (hidden singles in C2), clean-up: no 3 in R6C6
9b. Naked pair {15} in R5C13, locked for R5
9c. 5 in N1 locked in R2C12, locked for R2

10. 21(3) cage at R6C2 = {579/678}, 7 locked for C2
10a. 7 in N1 locked in R12C1, locked for C1

11. 21(4) cage at R6C1 = {1389} (only remaining combination, cannot be {1569} which clashes with R5C1), locked for C1 -> R5C12 = [51], R4C4 = 8
11a. R2C2 = 5 (hidden single in N1)
11b. 21(3) cage at R6C2 (step 10) = {678} (only remaining combination), locked for C2 -> R1C23 = [98]
11c. 8 in N4 locked in R6C12, locked for R6

12. R5C12 = [54] = 9 -> R3C4 + R4C3 = 11 = [29], R23C3 = [23], R6C1 = 8
12a. Naked pair {67} in R6C23, locked for R6

13. 18(3) cage in N5 = {279/369}, 9 locked for R5 and N5
13a. R6C8 = 9 (hidden single in R6)
13b. 19(3) cage at R2C8 = {478/568}, no 3, 8 locked for C8 and N3
13c. R5C9 = 8 (hidden single in R5)

14. 9 in C9 locked in R23C9, locked for N3
14a. 20(4) cage at R1C9 = {1379/2369} (cannot be {1469/2459} which clash with R67C9), no 4,5, 3 locked for C9 and N3
14b. Killer pair 1,2 in 20(4) cage and R67C9, locked for C9

15. 9(3) cage at R1C6 = {126/234}, 2 locked for R1
15a. 45 rule on R1 3 innies R1C159 = 14 = {167/347} = {67}1/[743], no 3 in R1C5, no 6,7 in R1C9

16. R9C2 = 2 -> R9C34 = 9 = [54/63]
16a. 4 in C3 locked in R78C3, locked for 19(3) cage at R7C3, no 4 in R8C4
16b. 19(3) cage at R7C3 = {469} (only remaining combination) -> R8C4 = 9, R78C3 = {46}, locked for C3 and N7 -> R6C23 = [67], R9C3 = 5, R9C4 = 4

17. R6C4 = 3 -> R67C5 = 12 = [48/57], R7C4 = 6, R5C4 = 7, R78C3 = [46], clean-up: no 2 in R6C9
17a. R6C7 = 2 (hidden single in R6), R1C8 = 2 (hidden single in R1), clean-up: no 5 in R6C6
17b. R6C7 = 2 -> R67C6 = [15] (step 4), R5C7 = 6, R5C8 = 3
17c. Naked pair {78} in R7C25, locked for R7
17d. Naked pair {12} in R7C89, locked for R7 and N9

18. R6C3 + R7C4 = [76] = 13 -> R89C5 = 4 = {13}, locked for C5 and N8
18a. R8C6 = 2 (hidden single in N8), locked for C6 -> R5C56 = [29]
18b. R8C6 = 2 -> R78C7 = 17 = [98]

19. 6 in R4 locked in R4C56, locked for 18(3) cage at R3C5, no 6 in R3C5
19a. 18(3) cage at R3C5 = {468/567}, no 9
19b. R2C5 = 9 (hidden single in C5)
19c. Naked pair {78} in R37C5, locked for C5
19d. R1C1 = 7 (hidden single in R1), R2C1 = 6

20. 20(4) cage at R1C9 (step 14a) = {1379} (only remaining combination), locked for C9 -> R9C9 = 6, R7C9 = 2, R6C9 = 4

and the rest is naked singles.


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