Thanks manu for a nice Assassin! As you said it requires work right until the end.
I didn't use any difficult moves but because of the length of my solving path I'll rate A159 at 1.25, even though none of my steps are at that level.
Here is my walkthrough; a few minor corrections have been made. Once I'd realised the importance of the 32(5) cage at R4C4 things seemed to flow.
Prelims
a) R12C1 = {29/38/47/56}, no 1 b) R23C8 = {16/25/34}, no 7,8,9 c) R5C56 = {15/24} d) R5C89 = {15/24} e) R78C8 = {49/58/67}, no 1,2,3 f) R89C1 = {29/38/47/56}, no 1 g) 11(3) cage in R3C7 = {128/137/146/236/245}, no 9 h) 20(3) cage at R4C5 = {389/479/569/578}, no 1,2 i) 11(3) cage in R6C6 = {128/137/146/236/245}, no 9 j) R789C9 = {126/135/234}, no 7,8,9 k) R9C678 = {389/479/569/578}, no 1,2 l) 32(5) cage at R4C4 = {26789/35789/45689}, no 1, CPE no 8,9 in R5C4 m) 33(5) cage in N6 = {36789/45789}, 7,8 locked for N6
1. Naked quad {1245} in R5C5689, locked for R5
2. 45 rule on R1234 4 innies R4C4589 = 30 = {6789}, locked for R4 2a. Max R4C23 = 9 -> min R3C2 = 3 2b. Max R4C67 = 9 -> min R3C7 = 2
3. 45 rule on N6 2 innies R46C7 = 6 = {15/24} 3a. Naked quad {1245} in R46C7 + R5C89, locked for N6
4. 45 rule on C9 3 innies R456C9 = 19 = {289/469/478/568} (cannot be {379} because R5C9 only contains 1,2,4,5), no 1,3, clean-up: no 5 in R5C8
5. 32(5) cage at R4C4 = {26789/35789} (cannot be {45689} because 4,5 only in R6C4), no 4, CPE no 7 in R5C4 5a. 2,5 only in R6C4 -> R6C4 = {25} 5b. Killer pair 2,5 in R5C56 and R6C4, locked for N5
6. 20(3) cage at R4C5 = {389} (only remaining combination, cannot be {479} because R5C4 only contains 3,6) -> R5C4 = 3, R46C5 = {89}, locked for C5 and N5
7. 32(5) cage at R4C4 (step 5) = {26789} -> R6C4 = 2, 8,9 locked in R5C123, locked for R5 and N4, clean-up: no 4 in R5C56 7a. Naked pair {15} in R5C56, locked for R5 and N5 -> R4C6 = 4 7b. R46C7 = {15} (hidden pair in N6), locked for C7 7c. R6C8 = 3 (hidden single in N6), clean-up: no 4 in R23C8
8. R4C6 = 4 -> R34C7 = 7 = [25/61], R3C7 = [26] 8a. Killer pair 2,6 in R23C7 and R3C8, locked for N3
9. 1 in N9 locked in R789C9, locked for C9 9a. R789C9 = {126/135}, no 4
10. R123C9 = {359/458}, no 7, 5 locked for C9 and N3, clean-up: no 2 in R23C8, no 3 in R789C9 (step 9a) 10a. Naked pair {16} in R23C8, locked for C8 and N3 -> R3C7 = 2, R4C7 = 5 (step 8), R6C7 = 1, clean-up: no 7 in R78C8 10b. Naked triple {126} in R789C9, locked for C9 and N9 -> R5C89 = [24], clean-up: no 8 in R123C9 (step 10) 10c. Naked triple {359} in R123C9, locked for C9 and N3
11. Naked pair {78} in R46C9, locked for N6 -> R4C8 = 9, R5C7 = 6, R46C5 = [89], R46C9 = [78], R4C4 = 6, R6C6 = 7, R7C7 = 3 (cage sum), clean-up: no 4 in R78C8 11a. Naked pair {58} in R78C8, locked for C8 and N9
12. R9C678 = {479} (only remaining combination, cannot be {389/569/578} because 3,5,6,8 only in R9C6) -> R9C6 = 9, R9C78 = {47}, locked for R9 and N9 -> R8C7 = 9, clean-up: no 2,4,7 in R8C1, no 2 in R9C1
13. R1C678 = {278/458/467} (cannot be {368} because 3,6 only in R1C6), no 1,3 13a. 2,5 of {278/458} must be in R1C6 -> no 8 in R1C6
14. R6C23 = {456} -> 15(3) cage at R6C2 = {456} (only remaining combination)
15. 45 rule on N89 2 outies R79C3 = 11 = [56/65/83/92], no 1,2,4,7 in R7C3, no 1,8 in R9C3 [I’d seen “cell cloning” R6C1 = R7C2 first but then looked for a technically simpler step.]
16. 45 rule on N23 2 outies R13C3 = 5 = [14/23/41] 16a. 45 rule on N1 1 remaining innie R3C2 = 1 outie R4C1 + 6 -> R3C2 = {789}
17. 19(4) cage at R8C4 = {1378/1468/1567/2458} (cannot be {2368} because 2,3,6 only in R9C35, cannot be {2467/3457} because 4,7 only in R8C4) 17a. 4,7 only in R8C4 -> R8C4 = {47} 17b. 3 of {1378} must be in R9C3 -> no 3 in R9C5
18. 3 in N8 locked in R8C56, locked for R8, clean-up: no 8 in R9C1 18a. 19(4) cage at R7C6 must contain 3 and 9 = {1369/2359}, no 4,7,8
19. 8 in C6 locked in R23C6, locked for N2 and 22(4) cage at R2C5 19a. 22(4) cage at R2C5 = {1678/2578/3478} (cannot be {3568} because R2C7 only contains 4,7) 19b. 4,7 of {3478} must be in R2C57 -> no 3 in R2C5
20. R1C7 = 8 (hidden single in C7), clean-up: no 3 in R2C1 20a. R1C678 (step 13) = {278/458}, no 6
21. R3C345 = {149/347/356} (cannot be {167} which clashes with R3C8) 21a. 9 of {149} must be in R3C4 -> no 1 in R3C4 21b. 6 of {356} must be in R3C5 -> no 5 in R3C5
22. Hidden killer pair 4,7 in R7C45 and R8C4 for N8 -> R7C45 must contain one of 4,7 22a. R7C345 = {279/459/468/567} (cannot be {189} which doesn’t contain one of 4,7), no 1
23. 22(4) cage at R2C5 (step 19a) = {1678/3478} (cannot be {2578} which clashes with R1C6), no 2,5 23a. 2 in N2 locked in R1C56, locked for R1, clean-up: no 9 in R2C1, no 3 in R3C3 (step 16)
24. Naked pair {14} in R13C3, locked for C3 and N1, clean-up: no 7 in R12C1 24a. 4 in 15(3) cage at R6C2 locked in R67C2, locked for C2 24b. 4 in N7 locked in R7C12, locked for R7
25. R8C4 = 4 (hidden single in N8)
26. R7C345 (step 22a) = {279/567}, no 8, 7 locked for R7, clean-up: no 3 in R9C3 (step 15) 26a. R9C4 = 8 (hidden single in C4) 26b. 1 in C4 locked in R12C4, locked for N2 and 16(4) cage at R1C3 -> R1C3 = 4, R3C3 = 1 (step 16), R23C8 = [16], R1C8 = 7, R1C6 = 2 (step 20a), R2C7 = 4, R9C78 = [74]
27. 22(4) cage at R2C5 (step 23) = {3478} -> R2C5 = 7, R23C6 = {38}, locked for C6 and N2 -> R3C5 = 4, R3C4 = 9 (step 21), R12C4 = [15], R1C5 = 6, R7C4 = 7, clean-up: no 3 in R4C1 (step 16a)
28. R7C345 (step 26) = {279/567} 28a. 6,9 only in R7C3 -> R7C3 = {69}, clean-up: no 6 in R9C3 (step 15)
29. R8C5 = 3 (hidden single in C5), R78C6 (step 18a) = {16}, locked for C6 and N8 -> R5C56 = [15]
30. R79C3 (step 15) = [92] (cannot be [65] which clashes with R6C3), R79C5 = [25], R4C3 = 3, clean-up: no 6 in R8C1
31. Naked pair {16} in R7C69, locked for R7 31a. 6 in 15(3) cage at R6C2 locked in R6C23, locked for R6
32. R8C9 = 2 (hidden single in C9)
33. Naked pair {58} in R8C18, locked for R8
34. R6C3 = 5 (hidden single in C3), R6C12 = [46], R7C2 = 4
35. R4C3 = 3 -> R34C2 = 9 = [72/81] 35a. Killer pair 1,7 in R34C2 and R8C2, locked for C2 -> R9C2 = 3, R9C1 = 6, R8C1 = 5
and the rest is naked singles
Last edited by Andrew on Sat Jun 20, 2009 4:02 am, edited 2 times in total.
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