I'm still struggling with those "continental" 1s in A111 so after doing SOK1 Variant yesterday I did A112 today.
I'll rate it at 0.75. I note Gary's slightly lower rating and agree that after the simple opening steps it's straightforward but there's still a reasonable amount of work which I feel is probably better done using elimination solving which is why I haven't rated this puzzle lower.
Here is my walkthrough. My solution path is fairly similar to Nasenbaer's but I'll post it anyway.
Prelims
a) R56C4 = {16/25/34}, no 7,8,9 b) R56C6 = {18/27/36/45}, no 9 c) R7C34 = {17/26/35}, no 4,8,9 d) R7C67 = {29/38/47/56}, no 1 e) 10(3) cage in N1 = {127/136/145/235}, no 8,9 f) 21(3) cage at R1C3 = {489/579/678}, no 1,2,3 g) R1C456 = {127/136/145/235}, no 8,9 h) 9(3) cage at R1C7 = {126/135/234}, no 7,8,9 i) 21(3) cage in N3 = {489/579/678}, no 1,2,3 j) R3C234 = {789}, locked for R3 k) R678C5 = {389/479/569/578}, no 1,2 l) 19(3) cage in N7 = {289/379/469/478/568}, no 1 m) 10(3) cage at R8C3 = {127/136/145/235}, no 8,9 n) 21(3) cage at R8C7 = {489/579/678}, no 1,2,3 o) 13(4) cage at R6C8 = {1237/1246/1345}, no 8,9
1. 45 rule on C5 3 innies R159C5 = 7 = {124}, locked for C5
2. R3C678 = {256/346}, no 1, 6 locked for R3 2a. Killer pair 3,5 in R3C5 and R3C678, locked for R3
3. 45 rule on N5 2 innies R46C5 = 16 = {79}, locked for C5 and N5, clean-up: no 2 in R56C6
4. R234C5 = {369/378/567} 4a. 6,8 only in R2C5 -> R2C5 = {68}
5. 45 rule on R1289 2 innies R28C5 = 9 = [63], R3C5 = 5, R4C5 = 7 (step 4), R67C5 = [98], clean-up: no 2 in R3C678 (step 2), no 5 in R7C3, no 3 in R7C7 5a. Naked triple {346} in R3C678, locked for R3
6. R1C456 = {127} (only remaining combination), locked for R1 and N2 6a. Naked pair {34} in R23C6, locked for C6 and N2, clean-up: no 5,6 in R56C6, no 7 in R7C7 6b. Naked pair {89} in R23C4, locked for C4 6c. Naked pair {18} in R56C6, locked for C6 and N5, clean-up: no 6 in R56C4 6d. 7 in R3 locked in R3C23, locked for N1 6e. 6 in N5 locked in R4C46, locked for R4
7. Killer pair 2,4 in R56C4 and R5C5, locked for N5
8. 21(3) cage at R1C3 = {489} (only remaining combination), 4 locked in R12C3, locked for C3 and N1 8a. 10(3) cage in N1 = {136/235}, 3 locked for N1 8b. Naked quad {4789} in R12C3 + R3C23, locked for N1
9. 45 rule on R12 2 remaining innies R1C19 = 13 = [58], no 5,8 in R9C19, clean-up: no 2 in 10(3) cage in N1 (step 8a) 9a. R1C19 = 13 -> R9C19 = 9 = {27/36}, no 1,4,9 9b. 10(3) cage in N1 = {136} -> R1C2 = 6, R2C12 = {13}, locked for R2 and N1 -> R3C1 = 2, R3C9 = 1, R2C6 = 4, R1C7 = 3, R2C7 = 2 (cage sum), R3C6 = 3, clean-up: no 9 in R7C6, no 7 in R9C9 (step 9a) 9c. Naked pair {46} in R3C78, locked for N3 -> R1C8 = 9, R1C3 = 4 [I then spotted that R3C2 cannot be 7 because that would force UR in R23C34 for 8,9 but I don’t use UR]
10. 13(4) cage at R6C8 = {1237/1246/1345} 10a. 1 locked in R67C8, locked for C8 10b. R7C8 = 1 (hidden single in N9), clean-up: no 7 in R7C34
11. 45 rule on N6 1 remaining outie R7C9 = 5, R2C89 = [57], clean-up: no 3 in R7C3, no 6 in R7C67 11a. 13(4) cage at R6C8 = {1345} (only remaining combination) -> R6C89 = {34}, locked for R6 and N6, clean-up: no 3,4 in R5C4
12. Naked pair {25} in R56C4, locked for C4 and N5 -> R7C34 = [26], R4C46 = [36], R5C5 = 4, R7C6 = 7, R7C7 = 4, R1C456 = [712], R3C78 = [64] , R6C89 = [34], R9C5 = 2, clean-up: no 7 in R9C1 (step 9a)
13. Naked pair {39} in R7C12, locked for N7 -> R9C1 = 6, R9C9 = 3
14. 12(3) cage in N8 = {129} (only remaining combination) -> R8C46 = [19], R9C46 = [45]
15. 21(3) cage at R8C7 = {579} (only remaining combination) -> R89C7 = [79], R9C8 = 8, R4C89 = [29], R5C89 = [76], R8C89 = [62], R8C3 = 5, R9C23 = [71], R4C3 = 8, R23C3 = [97], R2C4 = 8, R3C24 = [89], R56C3 = [36], R8C12 = [84],
16. R7C12 = {39} = 12 -> R6C12 = 8 = [71]
and the rest is naked singles
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