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 Post subject: Assassin 64v2 Revisit
PostPosted: Sun Aug 01, 2021 10:24 pm 
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Assassin 64v2 Revisit.

From the archive posts, I was in another world working on the SudokuSolver scoring with Richard so wasn't doing any killers. Looking forward to it now though! It got a score of 1.28 but now at 1.85 which better matches the human WTs posted. JSudoku uses 3 chains and two 'complex intersections'. A challenge!
Triple click code:
3x3::k:2816:4353:4353:4353:5124:3845:3845:3845:3080:2816:4106:4106:5124:5124:2062:4367:4367:3080:3602:3602:4106:5124:11542:2062:4367:4121:4121:5147:3602:3602:11542:11542:11542:4121:4121:3107:5147:2341:2341:2341:11542:5673:5673:5673:3107:5147:5934:5934:11542:11542:11542:3891:3891:3107:5934:5934:2872:1593:11542:6459:4412:3891:3891:2367:2872:2872:1593:6459:6459:4412:4412:2887:2367:6217:6217:6217:6459:2637:2637:2637:2887:
Solution:
+-------+-------+-------+
| 2 1 7 | 9 6 3 | 4 8 5 |
| 9 5 3 | 4 8 1 | 2 6 7 |
| 4 6 8 | 2 5 7 | 9 3 1 |
+-------+-------+-------+
| 8 3 1 | 6 4 9 | 5 7 2 |
| 7 4 2 | 3 1 5 | 8 9 6 |
| 5 9 6 | 8 7 2 | 3 1 4 |
+-------+-------+-------+
| 1 7 4 | 5 3 8 | 6 2 9 |
| 3 2 5 | 1 9 6 | 7 4 8 |
| 6 8 9 | 7 2 4 | 1 5 3 |
+-------+-------+-------+
Cheers
Ed


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PostPosted: Wed Aug 04, 2021 2:39 am 
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Many thanks Ed! A nice puzzle. I found my key steps fairly quickly so it seemed one of the easier Revisits.

Here's My Walkthrough for Assassin 64V2 Revisited:
Prelims

a) R12C1 = {29/38/47/56}, no 1
b) R12C9 = {39/48/57}, no 1,2,6
c) R23C6 = {17/26/35}, no 4,8,9
d) R78C4 = {15/24}
e) R89C1 = {18/27/36/45}, no 9
f) R89C9 = {29/38/47/56}, no 1
g) 20(3) cage at R4C1 = {389/479/569/578}, no 1,2
h) 9(3) cage at R5C2 = {126/135/234}, no 7,8,9
i) 22(3) cage at R5C6 = {589/679}
j) 11(3) cage at R7C3 = {128/137/146/236/245}, no 9
k) 24(3) cage at R9C2 = {789}
l) 10(3) cage at R9C6 = {127/136/145/235}, no 8,9
m) 14(4) cage at R3C1 = {1238/1247/1256/1346/2345}, no 9

1a. Naked triple {789} in 24(3) cage at R9C2, locked for R9, clean-up: no 1,2 in R8C1, no 2,3,4 in R8C9
1b. 22(3) cage at R5C6 = {589/679}, 9 locked for R5
1c. 25(4) cage at R7C6 = {2689/3589/3679/4678} (cannot be {1789} which clashes with R9C4, cannot be {4579} which clashes with R78C4), no 1
1d. Killer triple 7,8,9 in 25(4) cage and R9C4, locked for N8

2a. 45 rule on C1 2 innies R37C1 = 5 = {14/23}
2b. Max R7C1 = 4 -> min R6C23 + R7C2 = 19, no 1 in R6C23 + R7C2
2c. 45 rule on N7 3(2+1) outies R6C23 + R9C4 = 22, max R9C4 = 9 -> min R6C23 = 13, no 2,3 in R6C23
2d. 45 rule on C9 2 innies R37C9 = 10 = {19/28/37/46}, no 5
2e. 45 rule on N9 3(2+1) outies R6C78 + R9C6 = 8
2f. Min R6C78 = 3 -> max R9C6 = 5
2g. Max R6C78 = 7, no 7,8,9 in R6C78
2h. 45 rule on N69 4(2+2) outies R3C89 + R59C6 = 13
2i. Min R59C6 = 6 -> max R3C89 = 7, no 7,8,9 in R3C89, clean-up: no 1,2,3 in R7C9
2j. Min R7C9 = 4 -> max R6C78 + R7C8 = 11, no 9 in R7C8

3a. Killer quad 1,2,3,4 in R7C1, 11(3) cage at R7C3 and R89C1, locked for N7
3b. 1 in C1 only in R37C1 = {14} (step 2a) or R89C1 = [81] -> no 4,5 in R89C1 (locking-out cages)
3c. 11(3) cage at R7C3 = {128/146/236/245} (cannot be {137} which clashes with R89C1), no 7
3d. 11(3) cage = {128/245} (cannot be {146/236} which clash with R37C1 + R89C1), no 3,6, 2 locked for N7, clean-up: no 3 in R7C1 (step 2a), no 7 in R8C1
3e. 3 in N7 only in R789C1, locked for C1, clean-up: no 8 in R12C1
3f. 2 in C1 only in R123C1
[The first hard step]
3g. Hidden killer pair 4,5 in R7C12 and 11(3) cage for N7, both or neither in 11(3) cage -> both or neither in R7C12
3h. 23(4) cage at R6C2 cannot be {68}[45] which clashes with 20(3) cage at R4C1 -> 11(3) cage = {245}, locked for N7, clean-up: no 1 in R3C1 (step 2a)
3i. Similarly with 3,6 in R7C12 and R89C1 for N7, 23(4) cage cannot be {59}[36] which clashes with 20(3) cage -> R89C1 = {36}, locked for N7, 6 locked for C1
[The rest is fairly straightforward.]
3j. R7C1 = 1 -> R3C1 = 4 (step 2a), clean-up: no 5,7 in R12C1, no 6 in R7C9 (step 2d), no 5 in R8C4
3k. Naked pair {29} in R12C1, 9 locked for C1 and N1
3l. Naked triple {578} in 20(3) cage at R4C1, locked for N4
3m. R7C1 = 1 -> 23(4) cage at R6C2 = {1679} -> R6C23 = {69}, locked for R6, 6 locked for N4
3n. R7C2 = 7 -> R9C4 = 7 (hidden single in R9), clean-up: no 3 in R3C9 (step 2d)
3o. R3C1 = 4 -> 14(4) cage at R3C1 = {1346} (only remaining combination, cannot be {2345} = [15]{23} because 9(3) cage at R5C2 cannot be {14}4) -> R3C2 = 6, R4C23 = {13}, locked for R4 and N4
3p. Naked pair {24} in R5C23, locked for R5, R5C4 = 3 (cage sum), clean-up: no 2 in R2C6, no 4 in R7C9 (step 2d)
3q. 3 in 45(9) cage at R3C5 only in R37C5, locked for C5
3r. 45 rule on R9 3 innies R9C159 = 11 = {236} (only remaining combination, no 2,4,5 in R9C1) -> 10(3) cage at R9C6 = {145}, clean-up: no 6,7 in R8C9

4a. 45 rule on R12 4 outies R3C3467 = 26 = {2789} (only remaining combination), locked for R3 -> R3C9 = 1, R7C9 = 9 (step 2d), clean-up: no 3 in R12C9, no 3,5,7 in R2C6, no 2 in R9C9
4b. R9C5 = 2 (hidden single in R9) -> 25(4) cage at R7C6 = {2689}, 6 locked for N8, clean-up: no 4 in R78C4
4c. R78C4 = [51] -> R9C6 = 4, R37C5 = [53]
4d. Naked pair {15} in R9C78, 5 locked for N9, R8C9 = 8 -> R9C9 = 3, clean-up: no 4 in R12C9
4e. Naked pair {57} in R12C9, locked for C9 and N3 -> R5C9 = 6
4f. R5C6 = 5 (hidden single in N5) -> R5C78 = 17 = {89}, locked for N6, 8 locked for R5 -> R5C15 = [71]
[So no need to use the 45(9) interactions with R37C5 containing the same pair of digits as R5C46.]
4g. R3C89 = [31] -> R4C78 = 12 = {57}, locked for R4, 5 locked for N6 -> R4C1 = 8
4h. R6C78 = [31] (hidden pair in N6), R7C9 = 9 -> R7C8 = 2 (cage sum) -> R9C78 = [15], R4C78 = [57], R7C37 = [46], R8C78 = [74]

5a. 17(3) cage at R2C7 = {269} (only remaining combination), locked for N3
5b. R1C78 = [48] -> R1C6 = 3 (cage sum, also just spotted this is hidden single in C6)
5c. R5C78 = [89] -> R2C8 = 6, R2C6 = 1 -> R3C6 = 7
5d. R3C3 = 8 -> R2C23 = 8 = {35}, locked for N1, 5 locked for R2
5e. R1C23 = [17] -> R1C4 = 9 (cage sum)

and the rest is naked singles.


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PostPosted: Fri Aug 06, 2021 12:52 am 
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Assassin 64 v3
puzzle pic A64v3:
Attachment:
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Nice work Andrew. It does seem quite trivial compared to what we've been used to. Hopefully this version 3 will be more of a challenge. This version gets 1.60. Same solution.
code: triple click:
3x3::k:0000:4353:4353:4353:5122:3843:3843:3843:3076:0000:4101:4101:5122:5122:2054:4359:4359:3076:3592:3592:4101:5122:11529:2054:4359:4106:4106:5131:3592:3592:11529:11529:11529:4106:4106:3084:5131:2317:2317:2317:11529:5646:5646:5646:3084:5131:0000:0000:11529:11529:11529:3856:3856:3084:0000:0000:2833:1554:11529:6419:4372:3856:3856:2325:2833:2833:1554:6419:6419:4372:4372:2838:2325:6144:6144:6144:6419:2575:2575:2575:2838:
Cheers
Ed


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PostPosted: Fri Aug 06, 2021 3:24 am 
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Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1894
Location: Lethbridge, Alberta, Canada
Thanks Ed! :D

How can removing two cages reduce the SS Score? :scratch:

Assassin 64 V3 is actually a new puzzle which Ed has produced!

Andrew


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PostPosted: Wed Aug 11, 2021 8:28 pm 
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Welcome to the wonderful vagaries of scoring puzzles Andrew! Here are the two solving logs if you can divine an answer. [edit: thanks to Andrew for some typos]
solving logs for v2 and v3:
V2
Puzzle Completed. Step Analysis:
12 Find Hidden Cages 4
7 Find Hidden Cages 3
16 Find Hidden Cages
73 Naked Singles
3 Naked Pairs
1 Naked Triples
1 Naked Quads
2 Hidden Singles
1 Hidden Pairs
7 Locked Cages 2
9 Locked Candidates (Box/Line)
6 Cage Blockers
1 Cage Placement 5
1 Cage Placement 2
3 Cage Placement 1
3 Cage Placement
1 Hidden Killer Mutuals 1
7 Cage Combinations
18 Cage Combinations Extended
16 Cage Blockers Extended 9
1 Cage Blockers Complex 2
2 45 Rule Two Innies/Outies 2
4 45 Rule Single House 4
18 45 Rule Single House 3
1 Common Peer Elimination Extended 5
1 Common Peer Elimination Extended 4
1 Common Peer Elimination Extended 3
77 Cage Cleanup 2
2 Cage Cleanup 1
80 Cage Cleanup
5 Locked Candidates (House/Cage)
1 Forced Cage Candidates
7 Forced Cage Candidates - Extended
1 Forced Cage Candidates - Complex
1 Hidden Killer Triples
1 Hidden Killer Quads
1 Cage Combinations Complex
1 45 Rule Single House Innies&Outies 4
3 45 Rule Single House Innies&Outies 3
Total solving time (seconds): 1.08
Calculated score: 1.85

V3
Puzzle Completed. Step Analysis:
9 Find Hidden Cages 4
7 Find Hidden Cages 3
12 Find Hidden Cages
76 Naked Singles
9 Naked Pairs
2 Naked Triples
1 Hidden Singles
1 Hidden Pairs
4 Locked Cages 2
6 Locked Candidates (Box/Line)
6 Cage Blockers
1 Cage Placement 2
2 Cage Placement 1
3 Cage Placement
1 Hidden Killer Mutuals 1
8 Cage Combinations
13 Cage Combinations Extended
15 Cage Blockers Extended 9
1 Cage Blockers Complex 2
1 45 Rule Two Innies/Outies 2
2 45 Rule Single House 4
11 45 Rule Single House 3
1 Common Peer Elimination Extended 5
1 Common Peer Elimination Extended 4
1 Common Peer Elimination Extended 3
65 Cage Cleanup 2
3 Cage Cleanup 1
74 Cage Cleanup
1 Hidden Killer Pairs
4 Locked Candidates (House/Cage)
2 Forced Cage Candidates
6 Forced Cage Candidates - Extended
1 Hidden Killer Triples
2 45 Rule Single House Innies&Outies 3
1 45 Rule Multiple Houses Innies&Outies 4
Total solving time (seconds): 0.63
Calculated score: 1.60
This V3 was a much better puzzle. Really enjoyed it. I saw my step 4 and the start of step 7 on the first Revisit puzzle so was really disappointed when I realised they weren't needed then.
A64v3 start:
Preliminaries from SudokuSolver
Cage 6(2) n8 - cells only uses 1245
Cage 8(2) n2 - cells do not use 489
Cage 12(2) n3 - cells do not use 126
Cage 9(2) n7 - cells do not use 9
Cage 11(2) n9 - cells do not use 1
Cage 24(3) n78 - cells ={789}
Cage 22(3) n56 - cells do not use 1234
Cage 9(3) n45 - cells do not use 789
Cage 10(3) n89 - cells do not use 89
Cage 20(3) n4 - cells do not use 12
Cage 11(3) n7 - cells do not use 9
Cage 14(4) n14 - cells do not use 9

Note: highly optimised so no clean-up done unless stated
1. "45" on c9: 2 innies r37c9 = 10 (no 5)

2. "45" on n6: 5 outies r3c89 + r5c6 + r7c89 = 20
2a. h10(2)r37c9 -> r37c8 + r5c6 = 10
2b. min. r37c8 = 3 -> max. r5c6 = 7
2c. min. r5c6 = 5 -> max. r37c8 = 5 (no 5..9)

3. "45" on c789: 3 outies r159c6 = 12 and must have 5,6,7 for r5c6
3a. but {156/237} blocked by 8(2)n2 which needs one of each of them
3b. = {147/246/345}(no 8,9)
3c. must have 4, locked for c6
3d. can't have two of 5,6,7 which must go in r5c6 -> no 5,6,7 in r19c6

4. the 5,6,7 in r5c6 must repeat in one of r37c5 because the 45(9)r3c5 also needs each of them
4a. if it repeats in r7c5 -> from step 3. there will be a h12(3)r19c6 + r7c5
4b. but from "45" on n8: 3 innies r7c5 + r9c46 = 14
4c. -> r9c4 - 2 = r1c6
4d. which is impossible since they are at least 3 different
4e. -> r5c6 repeats in r3c5 and also in r789c4
4f. -> can only be 5 or 7 since no 6 in r789c4
4g. -> r3c5 = (57), r5c6 = (57)
4h. -> h12(3)r159c6 = {147/345}(no 2)

5. 22(3)r5c6 = [5]{89}/[7]{69}
5a. 9 locked for r5 and n6
5b. r5c78 from {689}

6. "45" on n3: 2 innies r3c89 - 1 = 1 outie r1c6
6a. max. r1c6 = 4 -> r3c89 = 3,4,5 (no 6,7,8,9)
6b. -> h10(2)r37c9 = [19/28/37/46]
6c. min. r3c89 = 3 -> r1c6 = (34)
6d. max. r3c89 = 5 -> min. r4c78 = 11 (cage sum)
6e. -> no 1,2 in r4c78

7. r3c9 sees all 1,2,3,4 in n6 apart from r6c78 so must repeat there
7a. -> from h10(2)r37c9 => a h10(2) in one of r6c78, + r7c9
7b. -> the other one of r6c78 + r7c8 = 5 (cage sum)
7c. -> r6c78 cannot = 5 (Combo Crossover Clash CCC)(was very slow to realise this)
7d. also 5 cannot be in either the h10(2) or h5(2) in the 15(4) cage -> no 5 in r6c78
7e. ie r6c78 from {1234}

8. "45" on n9: 3 outies r6c78 + r9c6 = 8
8a. r6c78 cannot be 5 (step 7c) -> no 3 in r9c6
8b. r9c6 = (14) -> r6c78 = 4 or 7
8c. = {13}/{34}(no 2)
8d. 3 locked for r6, n6 and no 3 in r7c8

9. 2 in n6 only in 12(3) = {246} only
9a. all locked for c9, 4 and 6 for n6
9b. deleted

10. 11(2)n9 = {38} only: both locked for c9 and n9
10a. r37c9 = [19]

11. r6c78 = {13} = 4 -> r7c8 = 2 (cage sum)

12. 3 outies n9 = 8 (step 8) = {13}[4] only
12a. 1 locked for r6
12b. r15c6 = [35] (h12(3)r159c6 sum)
12c. -> r3c5 = 5 (since r3c5 = r5c6)

13. 2 which must be in 45(9) only in n5: locked for n5

14. "45" on n2: 1 innie r1c4 = 9

15. "45" on c3..9: 2 remaining innies r59c4 = 10 = [37] only

Much easier now.
Cheers
Ed


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PostPosted: Sat Aug 14, 2021 4:58 am 
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Nice solving path Ed! I missed one of your key steps so found it hard going and not a particularly interesting puzzle.

Which of these puzzles is better and more enjoyable depends, of course, on how one solved it so that's V2 for me and V3 for Ed. However I must disagree with Ed, neither of these puzzles can be considered to be much better than the other.

Here's how I solved Assassin 64 V3:
Prelims

a) R12C9 = {39/48/57}, no 1,2,6
b) R23C6 = {17/26/35}, no 4,8,9
c) R78C4 = {15/24}
d) R89C1 = {18/27/36/45}, no 9
e) R89C9 = {29/38/47/56}, no 1
f) 20(3) cage at R4C1 = {389/479/569/578}, no 1,2
g) 9(3) cage at R5C2 = {126/135/234}, no 7,8,9
h) 22(3) cage at R5C6 = {589/679}
i) 11(3) cage at R7C3 = {128/137/146/236/245}, no 9
j) 24(3) cage at R9C2 = {789}
k) 10(3) cage at R9C6 = {127/136/145/235}, no 8,9
l) 14(4) cage at R3C1 = {1238/1247/1256/1346/2345}, no 9

1a. Naked triple {789} in 24(3) cage at R9C2, locked for R9, clean-up: no 1,2 in R8C1, no 2,3,4 in R8C9
1b. 22(3) cage at R5C6 = {589/679}, 9 locked for R5
1c. 25(4) cage at R7C6 = {2689/3589/3679/4678} (cannot be {1789} which clashes with R9C4, cannot be {4579} which clashes with R78C4), no 1
1d. Killer triple 7,8,9 in 25(4) cage and R9C4, locked for N8
1e. 45 rule on C9 2 innies R37C9 = 10 = {19/28/37/46}, no 5

2a. 45 rule on C456789 3 innies R159C4 = 19 = {289/379/469/478/568}, no 1
2b. Max R5C4 = 6 -> min R19C4 = 13, no 2,3 in R1C4
2c. 1 in N5 only in R4C456 + R5C5 + R6C456, locked for 45(9) cage at R3C5
2d. 45 rule on C789 3 outies R159C6 = 12
2e. Min R59C6 = 6 -> max R1C6 = 6

3a. 45 rule on N9 3(2+1) outies R6C78 + R9C6 = 8
3b. Min R6C78 = 3 -> max R9C6 = 5
3c. Max R6C78 = 7, no 7,8,9 in R6C78
3d. 45 rule on N69 4(2+2) outies R3C89 + R59C6 = 13
3e. Min R59C6 = 6 -> max R3C89 = 7, no 7,8,9 in R3C89, clean-up: no 1,2,3 in R7C9 (step 1e)
3f. Min R7C9 = 4 -> max R6C78 + R7C8 = 11, no 9 in R7C8

4a. 45 rule on N3 3(2+1) outies R1C6 + R4C78 = 15
4b. Max R4C78 = 13 -> min R1C6 = 2
4c. R159C6 = 12 (step 2d) = {129/138/147/246/345} (cannot be {156/237} which clash with R23C6)
4d. R5C6 = {56789} -> no 5,6 in R19C6
4e. Max R1C6 = 4 -> min R1C78 = 11, no 1 in R1C78
4f. 45 rule on N3 2 innies R3C89 = 1 outie R1C6 + 1
4g. Max R1C6 = 4 -> max R3C89 = 5, no 5,6 in R3C89, clean-up: no 4 in R7C9 (step 1e)
4h. Max R3C89 = 5 -> min R4C78 = 11, no 1 in R4C78
4i. 10(3) cage at R9C6 = {136/145/235}
4j. 15(4) cage at R6C7 = {1239/1248/1257/1347/1356/2346}
4k. R7C9 = {6789} -> no 6,7,8 in R6C78 + R7C8

5a. 45 rule on N2 3 innies R1C46 + R3C5 = 17 = {269/278/359/368/458/467}
5b. R1C6 = {234} -> no 2,3,4 in R1C4 + R3C5

6a. R89C9 = {29/38/47} (cannot be {56} which clashes with 10(3) cage), no 5,6
6b. 12(3) cage at R4C9 = {129/138/147/156/246} (cannot be {237} which clashes with R89C9, cannot be {345} which clashes with R12C9)
6e. 6 in C9 only in R37C9 = [46] (step 1e) or 12(3) cage = {156/246} -> 12(3) cage = {129/138/156/246} (cannot be {147}, locking-out cages), no 7
[This result can also be reached using 5 in C9.]

7a. 45 rule on N9 2 innies R7C89 = 1 outie R9C6 + 7
7b. Max R9C6 = 4 -> max R7C89 = 11 but cannot be [56] which clashes with 10(3) cage at R9C6 -> no 5 in R7C8

8a. 12(3) cage at R4C9 (step 6e) = {129/138/156/246}
8b. Consider combinations for 17(3) cage at R7C7 = {179/269/359/368/458/467} (cannot be {278} which clashes with R89C9)
17(3) cage = {179/269/359/467} => 8 in R78C9, locked for C9
or 17(3) cage = {368/458} => R78C9 = {79} (hidden pair in N9), locked for C9 => R12C9 = {48}, locked for C9
-> 12(3) cage = {129/156/246}, no 3,8

9a. Consider permutations for R89C9 = [74/83/92]
R89C9 = [74], no 8 in R12C9 => R7C9 = 8 (hidden single in C9), R3C9 = 2 (step 1e), naked triple {156} in 12(3) cage at R4C9, 1 locked for N6, R6C78 + R7C8 = 7 = {124} => R7C8 = 1, 1 in N3 only in 17(3) cage at R2C7 = {179}, 9 locked for N3
or R89C9 = [83/92] => R12C9 = {48/57} (cannot be {39} which clash with R89C9
-> R12C9 = {48/57}
9b. R89C9 = [83/92] (cannot be [74] which clashes with R12C9), no 4,7
9c. 45 rule on R9 3 innies R9C159 = 11 = {236/245} (cannot be {146} because R9C9 only contains 2,3), no 1, 2 locked for R9, clean-up: no 8 in R8C1
9d. 17(3) cage at R2C7 = {179/269/359/368} (cannot be {278/458/467} which clash with R12C9), no 4
9e. R6C78 + R9C6 = 8 (step 3a)
9f. R9C6 = {134} -> R6C78 = 4,5,7 = {13/23/34} (cannot be {14/25} which clash with 12(3) cage at R4C9), no 5, 3 locked for R6, N6 and 15(4) cage at R6C7
9g. 15(4) cage at R6C7 contains 3 = {1239/1347/2346}, no 8, clean-up: no 2 in R3C9 (step 1e)
9h. Consider placement for 3 in C9
R3C9 = 3 => R7C9 = 7 (step 1e) => 15(4) cage = {1347}, no 2 => R6C78 cannot total 5 => no 3 in R9C6
or R9C9 = 3
-> R9C6 = {14}, R6C78 = {13/34}, no 2
9i. Killer pair 1,4 in 12(3) cage and R6C78, locked for N6
9j. Killer pair 1,4 in R78C4 and R9C6, locked for N8
9k. R6C78 + R9C6 = {13}4/{34}1, CPE no 1,4 in R6C6
9l. R9C159 = {236/245}
9m. 4 of {245} must be in R9C1 -> no 5 in R9C1, clean-up: no 4 in R8C1
9n. 4 in 45(9) cage at R3C5 only in R4C456 + R5C5 + R6C45, locked for N5

10a. 45 rule on N8 3 innies R7C5 + R9C46 = 14 = {158/167/248/347} (cannot be {149} because 1,4 only in R9C6, cannot be {239/257/356} because R9C6 only contains 1,4), no 9
10b. 9 in R9 only in R9C23, locked for N7
10c. R159C4 (step 2a) = {289/379/568}, R9C4 = {78} -> no 7,8 in R1C4

11a. R3C89 = R1C6 + 1 (step 4f), max R1C6 = 4 -> max R3C89 = 5
11b. Consider placement 2 in N6
2 in R4C78 => 16(4) cage at R3C8 can only be {14}{29} (with max R3C89 = 5), no 3
or 2 in 12(3) cage at R4C9, locked for C9 => R9C9 = 3
-> no 3 in R3C9, clean-up: no 7 in R7C9 (step 1e)
[It gets easier from here]
11c. 7 in C9 only in R12C9 = {57}, locked for N3, 5 locked for C9
11d. 12(3) cage at R4C9 (step 8b) = {129/246}, 2 locked for C9 and N6, R9C9 = 3 -> R8C9 = 8, clean-up: no 6 in R8C1
11e. 10(3) cage at R9C6 = {145} (only remaining combination), no 6, 4,5 locked for R9, 5 locked for N9, clean-up: no 5 in R8C1
11f. 15(4) cage at R6C7 (step 9g) = {1239/2346} -> R7C8 = 2, clean-up: no 4 in R8C4
11g. 2 in 45(9) cage at R3C5 only in R4C456 + R5C5 + R6C456, locked for N5
11h. 16(4) cage at R3C8 = {1357/1456} (cannot be {1348} because 1,3,4 only in R3C89), no 8,9, 5 locked for R4 and N6
11i. 8 in N6 only in 22(3) cage at R5C6 = {589} -> R5C6 = 5, R5C78 = {89}, 8 locked for R5, 9 locked for N6
11j. R159C6 (step 2d) = 12, R5C6 = 5 -> R19C6 = 7 = [34], clean-up: no 2 in R8C4
11k. Naked pair {15} in R78C4, locked for C4, 5 locked for N8
11l. 17(3) cage at R7C7 contains 4,7 for N9 = {467}, no 1,9
11m. R7C9 = 9 (hidden single in N9) -> R3C9 = 1 (step 1e), clean-up: no 7 in R2C6
11n. Naked triple {246} in 12(3) cage at R4C9, 4,6 locked for N6
11o. R4C78 = {57}, R3C9 = 1 -> R3C8 = 3, R6C78 = [31], R9C78 = [15], R4C78 [57]
11p. R1C6 = 3 -> R1C78 = 12 = {48}, locked for R1, 8 locked for N3
11q. R159C4 (step 10c) = {379} = [937]
11r. R1C46 + R3C5 = 17 (step 5a), R1C46 = [93] -> R3C5 = 5
11s. R7C5 + R9C46 = 14 (step 10a), R9C46 = [74] -> R7C5 = 3
11t. R7C6 = 8 (hidden single in N8)

12a. 45 rule on N7 2 innies R7C12 = R9C4 + 1
12b. R9C4 = 7 -> R7C12 = 8 = {17}, locked for R7 and N7 -> R78C4 = [51], R7C3 = 4
12c. R8C1 = 3 -> R9C1 = 6, R9C5 = 2
12d. 2 in C1 only in R123C1, locked for N1
12e. R1C4 = 9 -> R1C23 = 8 = {17}, locked for R1 and N1 -> R1C159 = [265], clean-up: no 2 in R23C6
12f. R7C1 = 1 (hidden single in C1) -> R7C2 = 7, R1C23 = [17]
12g. 3 in N4 only in R4C23 -> 14(4) cage at R3C1 = {1346} (only remaining combination, cannot be {1238} because 1,2,3 only in R4C23) -> R3C12 = [46], R4C23 = [31]
12h. R5C4 = 3 -> R5C23 = 6 = [42]
12i. 20(3) cage at R4C1 = {578} = [875]

and the rest is naked singles.


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