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 Post subject: Assassin 363
PostPosted: Thu Nov 15, 2018 6:46 am 
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Assassin 363
This one took an inordinately long time on the first solve. Finally found what I'd been missing. Pretty basic. But still have to use a couple of advanced steps to crack it. Found a couple of different ways to solve it but found a fairly short way. Not as much combo work compared to many of my other WTs. SS scores it 1.60 JSudoku must have a bug.
code:
3x3::k:4352:2305:2305:8706:8706:4611:4611:4611:4611:4352:5380:1285:1285:8706:6150:4611:5895:4104:2825:5380:1546:1546:8706:6150:5895:5895:4104:2825:5380:5380:1291:8706:6150:4108:5895:5895:2829:2829:3854:1291:8706:6150:4108:6159:6159:2320:2320:3854:8465:4882:4882:4108:6159:6159:3091:3091:3854:8465:4882:4882:4116:6159:4117:2070:3091:8465:8465:8465:4116:4116:2583:4117:2070:3608:3608:3608:3353:3353:3353:2583:4117:
solution:
Code:
+-------+-------+-------+
| 9 3 6 | 7 8 2 | 1 4 5 |
| 8 7 1 | 4 5 3 | 6 2 9 |
| 4 2 5 | 1 9 6 | 8 3 7 |
+-------+-------+-------+
| 7 9 3 | 2 1 8 | 5 6 4 |
| 6 5 2 | 3 4 7 | 9 8 1 |
| 1 8 4 | 9 6 5 | 2 7 3 |
+-------+-------+-------+
| 2 4 9 | 6 7 1 | 3 5 8 |
| 5 6 7 | 8 3 9 | 4 1 2 |
| 3 1 8 | 5 2 4 | 7 9 6 |
+-------+-------+-------+
Cheers
Ed


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 Post subject: Re: Assassin 363
PostPosted: Sat Nov 24, 2018 7:43 pm 
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Posts: 280
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You've done better than me Ed - I still haven't found a good way of solving this after hours of trying! I've found some interesting steps - but none so far have given me the breakthrough!


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 Post subject: Re: Assassin 363
PostPosted: Tue Nov 27, 2018 6:19 am 
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Joined: Wed Apr 16, 2008 1:16 am
Posts: 1040
Location: Sydney, Australia
Thanks for giving it a good crack wellbeback and letting us know. The irony is I used a couple of wellbeback-type steps to (nearly) break it (7&9)! I find these a lot quicker these days and really like when I find them. They make much less combo work.
WT for a363:
Preliminaries courtesy of SudokuSolver
Cage 16(2) n3 - cells ={79}
Cage 17(2) n1 - cells ={89}
Cage 5(2) n12 - cells only uses 1234
Cage 5(2) n5 - cells only uses 1234
Cage 6(2) n12 - cells only uses 1245
Cage 8(2) n7 - cells do not use 489
Cage 9(2) n4 - cells do not use 9
Cage 9(2) n1 - cells do not use 9
Cage 10(2) n9 - cells do not use 5
Cage 11(2) n4 - cells do not use 1
Cage 11(2) n14 - cells do not use 1
Cage 33(5) n578 - cells do not use 12
Cage 18(5) n23 - cells do not use 9

No routine clean-up done unless stated.
1. 16(2)n3 = {79}, both locked for c9 and n3

2. 16(3)r7c9 = {268/358}(no 1,4)
2a. must have 8, locked for c9 and n9
2b. no 2 in 10(2)n9

This is the basic step I missed for a long, long time. Bad
3. "45" on n36: 2 outies r1c6 + r7c8 = 7 (no 7,8,9)

4. "45" on c89: 1 outie r3c7 + 1 = 2 innies r1c89
4a. innie(s) are in the same nonet as the outie -> can't be equal -> no 1 in r1c89 (IOU)
4b. max. r3c7 = 8 -> max. r1c89 = 9 (no 8)
4c. min r1c89 = {23} = 5 -> min. r3c7 = 4

5. 17(2)n1 = {89} only: both locked for c1 and n1
5a. no 1 in 9(2)n1
5b. no 2,3 in 11(2)r3c1

6. "45" on r1: 1 outie r2c7 + 18 = 3 innies r1c145
6a. max. 3 innies = 24 -> max. r2c7 = 6
6b. min. 3 innies = 19 (no 1)
6c. 1 in r1 only in 18(5) -> no 1 in r2c7
6d. min. r2c7 = 2 -> min. 3 innies r1 = 20 (no 2)

Key step
7. r3c7 + r7c8 see all of c9 -> can't have a repeat (anti-clone)
7a. 18(5)r1c6 = {12348/12456}
7b. {12348} as [18]{234} only (note: no 6)
7c. -> r7c8 = 6 (outies n36=7)
7d. but this forces 6 in n3 into r3c7 which means no 6 for c9
7e. -> 18(5) = {12456} only (no 3,8)
7f. no 4 in r7c8 (outies n36=7)

8. 18(5)r1c6 = {12456}, must have at least one of 4,5 in r1
8a. -> {45} blocked from 9(2)n1
8b. = {27/36}(no 4,5)

9. "45" on r1: 1 outie r2c7 + 18 = 3 innies r1c145
9a. -> r2c7 cannot repeat in any of those innie s since the remaining two innies can't reach 18 (anti-clone)-> r2c7 repeats in r1 only in 9(2)n1
9b. no 4,5 in r2c7

10. "45" on c89: 1 outie r3c7 + 1 = 2 innies r1c89
10a. innies can't total 5 -> no 4 in r3c7
10b. can't be {25}+[6] since r2c7 = (26) -> no 6 in r3c7
10c. = {24}[5]/{45}[8](no 6)
10d. must have 4 in r1c89: 4 locked for r1 and n3
10e. must have 5 in r1c89 or r3c7: 5 locked for n3
10f. no 3 in r7c8 (outiesn36=7)

11. 3 in n3 in in r23c8: 3 locked for c8 and no 3 in r4c9
11a. no 7 in 10(2)n9

Another tricky one.
12. "45" on n6: 4 outies r3c7 + r237c8 = 18
12a. those outies must have 3 & 8 for n3 = 11 -> one of outies in n3 and r7c8 = 7
12b. but {16} blocked by 10(2)n9 = {19/46} = 1/6
12c. -> r7c8 = (25), r23c8 = {238}(no 1,6)
12d. 2 locked for c8 in one of r237c8
12e. no 1,6 in r1c6 (outies n36=7)

13. outies n36 = 7 = {25} only
13a. -> no 5 in r1c8, no 2,5 in r7c6
13b. r1c8 = 4

Pretty much cracked now.
14. naked pair {25} in r1c69: both locked for r1 and no 2 in r2c7
14a. r12c7 = [16]

15. 4 in c9 only in n6: locked for n6

16. 16(3)n6: {358} blocked by r3c7
16a. = {259} only: all locked for c7 and n6
16b. r3c7 = 8

17. r23c8 = {23}: locked for c8, n3
17a. r23c8 + r3c7 = {238} = 13 -> r4c89 = 10 = [64] only permutation

18. r1c69 = [25], r7c8 = 5, 16(3)n9 = {268}(no 3)

19. 5(2)r2c3: {23} blocked by r2c8
19a. = {14} only: both locked for r2

20. 9(2)n1 = {36} only: both locked for r1 and n1

21. 11(2)r3c1 = [47] only permutation
21a. r2c34 = [14]
21b. r3c34 = [51] only permutation
21c. naked pair {27} in r23c2: both locked for c2 and no 2 in r4c3
21d. r23c2 = 9 -> r4c23 = 12 = {39} only combination

22. "45" on n14: 1 remaining outie r7c3 = 9
22a. r4c23 = [93], r1c23 = [36], r45c4 = [23]
22b. r7c3 = 9 -> r56c3 = 6 = {24} only: both locked for c3 and n4
22c. 9(2)r6c12 = [18] only permutation

23. r89c3 = {78} = 15 -> 1 remaining innie n7 -> r9c2 = 1
23a. r89c8 = [19]

24. "45" on r9: 2 remaining innies r9c19 = 9 = [36] only permutation

25. r9c2 = 1 -> r9c34 = 13 = [85] only permutation
etc
Cheers
Ed


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 Post subject: Re: Assassin 363
PostPosted: Tue Nov 27, 2018 8:06 pm 
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Thanks Ed and well done! I wrote my WT before looking at yours and they are almost identical in their key steps. That might be a first! :)

Assassin 363 WT:
1. 17(2)n1 = {89}
-> 11(2)r3c1 from {47} or {56}

2. Innies n14 = r2356c3 = +12(4) = {12(36|45)}
-> Min r7c3 = 6

3. 33(5)r6c4 = {789(36|45)}
Innies - Outies c1234 -> r1c4 = r8c5 + 4
Since Min r8c5 = 3 -> Min r1c4 = 7
Since (789) all in 33(5) -> [r1c4,r8c3,r8c5] from [773], [884], [995]
(If either of the latter two -> HS r9c4 = 6)

4. 16(2)n3 = {79}
-> 16(3)n9 = {8{26|35)}

5. Outies n36 = r1c6 + r7c8 = +7(2)
-> 7 not in 18(5)r1c6
-> 18(5)r1c6 from {124{38|56)}
-> One of the pairs (38) and (56) in 23(5) in n3

6. Outies c89 = r1c67 + r23c7 = +17(4)
Innies - Outies c89 -> r1c89 = r3c7 + 1
-> 1 not in r1c89 -> 1 in r1c67 or r2c7
Since Max r3c7 = 8 -> 8 not in r1c89
Also Max r1c89 = +9(2) -> Min r1c67+r2c7 = +9(3)

7. Whatever goes in r7c8 (6 or less) goes in c9 in r1c9 or r4c9
If the latter also goes in r12c7
-> 18(5)r1c6 consists of a H+7(2) + H+11(3)
and one of the H+7(2) must be in r1c6

8. Max r1c12345 = +33(5) -> Min r1c6789 = +12(4)
-> Max r2c7 = 6

9. Can 18(5)r1c6 be {12348}?
8 could only go in r1c7
One of (234) must be in 9(2)r1 -> One of (234) in r2c7
Last line in Step 7 -> r1c6, r7c8 = {34}
-> Leaves no place for 1 in 18(5)
-> 18(5)r1c6 = {12456}
-> (38) in 23(5) in n3

10. Min r1c89 = {24} -> Min r3c7 = 5
-> 3 in r23c8
-> 7 in n9 in r789c7
-> 7 in n6 in r456c8

11. At least one of (45) in r1c6789
-> 9(2)n1 from [27] or {36}
Since both (26) in 18(5) -> r2c7 from (26)
-> 1 in r1c67

12. 4 cannot go in r1c67 since that would put r2c7 + r3c7 = +12(2)
-> 4 in r1c89
-> [r1c89,r3c7] from [{24},5] or [{45},8]
But the former puts r123c7 = [165] and 8 in r456c7 which leaves no solution for 16(3)n6
-> r1c89 = {45}
-> r1c67,r2c7 = {126}
Also r3c7 = 8

13. Since 8 already in c7 -> 3 and 5 cannot both go in 16(3)n6
-> At least one of (35) in c7 in n9
-> 16(3)n9 = {268}
-> 10(2)n9 = {19}
-> Outies n36 -> [r1c6,r7c8] = [25]
-> r12c7 = [16]
-> Also r23c8 = {23}
-> r4c89 = [64]
-> r1c89 = [45]
-> r56c9 = {13}
-> r56c8 = {78}
-> 16(3)n6 = {259}
-> r789c7 = {347}

14. 9(2)n1 = {36}
-> 11(2)r3c1 = [47]
-> (Since r23c8 = {23}) -> 5(2)r2c3 = [14]
-> 6(2)r3c3 = [51]
-> r56c3 = {24}
-> r7c3 = 9
-> Remaining Innies n4 = r4c23 = +12(2) = [93]
-> 9(2)n1 = [36]
Also r23c2 = {27}
Also 9(2)n4 = [18]
-> 11(2)n4 = {56}

15. Innies r9 -> r9c189 = +18(3)
Given existing placements can only be [396]
-> r8c1 = 5 and r8c8 = 1

16. HP r89c3 = {78}
-> Remaining Innie n7 -> r9c2 = 1
-> 14(3)r9c2 = [185]
etc.


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 Post subject: Re: Assassin 363
PostPosted: Wed Jan 30, 2019 6:05 am 
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Joined: Wed Apr 23, 2008 6:04 pm
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Location: Lethbridge, Alberta, Canada
This was one of the Assassins which I skipped over at the time and only recently tried it. I found it slow going until I belatedly spotted the 45 in my step 14, after which I started to make serious progress; step 14 and the start of step 15 were my key steps. My solving path was very different to those of Ed and wellbeback.

Thanks Ed for pointing out that my step 14d had been incomplete. I've also moved my note about when the puzzle was cracked.
Here is my walkthrough for Assassin 363:
Prelims

a) R12C1 = {89}
b) R1C23 = {18/27/36/45}, no 9
c) R2C34 = {14/23}
d) R23C9 = {79}
e) R34C1 = {29/38/47/56}, no 1
f) R3C34 = {15/24}
g) R45C4 = {14/23}
h) R5C12 = {29/38/47/56}, no 1
i) R6C12 = {18/27/36/45}, no 9
j) R89C1 = {17/26/35}, no 4,8,9
k) R89C8 = {19/28/37/46}, no 5
l) 18(5) cage at R1C6 = {12348/12357/12456}, no 9
m) 33(5) cage at R6C4 = {36789/45789}, no 1,2

Steps Resulting From Prelims
1a. Naked pair {89} in R12C1, locked for C1 and N1, clean-up: no 1 in R1C23, no 2,3 in R34C1, no 2,3 in R5C2, no 1 in R6C2
1b. 1 in N1 only in R23C23, CPE no 1 in R4C4
1c. Naked pair {79} in R23C9, locked for C9 and N3
1d. 16(3) cage at R7C9 = {268/358}, no 1,4, 8 locked for C9 and N9, clean-up: no 2 in R89C8

2. 45 rule on C1 3 innies R567C1 = 9 = {126/135/234}, no 7, clean-up: no 4 in R5C2, no 2 in R6C2

3. 45 rule on N14 1 outie R7C3 = 2 innies R23C3 + 3, min R23C3 = 3 -> min R7C3 = 6
3a. Min R7C3 = 6 -> max R56C3 = 9, no 9 in R56C3

4. 45 rule on N7 2 innies R78C3 = 1 outie R9C4 + 11
4a. Max R78C3 = 17 -> max R9C4 = 6

5. 45 rule on R9 2 outies R8C18 = 1 outie R9C9
5a. Min R8C18 = 3 -> min R9C9 = 3
5b. Max R9C9 = 8 -> max R8C18 = 8, no 9 in R8C8, clean-up: no 1 in R9C8
5c. 45 rule on R9 3 innies R9C189 = 18 = {189/369/378/468/567} (cannot be {279} because R9C9 only contains 3,5,6,8, cannot be {459} because 4,9 only in R9C8), no 2, clean-up: no 6 in R8C1

6. 45 rule on C1234 1 innie R1C4 = 1 outie R8C5 + 4 -> R1C4 = {789}, R8C5 = {345}
6a. Hidden killer triple 7,8,9 in R1C4 and R678C4 for C4, R1C4 = {789} -> R678C4 must contain two of 7,8,9
6b. 33(5) cage at R6C4 = {36789/45789}, R678C4 contains two of 7,8,9 -> R8C3 = {789}
6c. 3 of {36789} must be in R8C5 -> no 3 in R678C4
6d. Min R78C3 = 13 -> min R9C4 = 2 (step 4)

7. 45 rule on N6 2 innies R4C89 = 1 outie R7C8 + 5, IOU no 5 in R4C9

8. 18(5) cage at R1C6 = {12348/12357/12456}
8a. 8 of {12348} must be in R1C678 (R1C6789 cannot be {1234} which clashes with R1C23), no 8 in R2C7

9. 45 rule on C89 2 innies R1C89 = 1 outie R3C7 + 1, IOU no 1 in R1C89
9a. Min R1C89 = 5 -> min R3C7 = 4
9b. Max R3C7 = 8 -> max R1C89 = 9, no 8 in R1C8
9c. 1 in C9 only in R456C9, locked for N6

10. 45 rule on C12 2 outies R14C3 = 1 innie R9C2 + 8, max R14C3 = 16 -> max R9C2 = 8

11. 45 rule on C6789 2 innies R67C6 = 1 outie R9C5 + 4, IOU no 4 in R6C6

12. 45 rule on R1 3 innies R1C145 = 1 outie R2C7 + 18
12a. Min R1C145 = 19, no 1 in R1C5
12b. 1 in R1 only in R1C67, locked for 18(5) cage at R1C6
12c. Min R2C7 = 2 -> min R1C456 = 20, no 2 in R1C5
[It’s a while since I’ve done an iterative step like this, although this time only one iteration.]

13. 34(6) cage at R1C4 = {136789/145789/235789/245689} (cannot be {345679} which clashes with R8C5)
13a. 34(6) cage = {136789/235789}, 3 locked for C5
or 34(6) cage = {145789/245689}, killer triple 3,4,5 in 34(6) cage and R8C5, locked for C5
-> no 3 in R679C5

[This 45 looks important; I ought to have spotted it earlier.]
14. 45 rule on N36 2(1+1) outies R1C6 + R7C8 = 7, no 7,8 in R1C6, no 7,9 in R7C8
14a. 18(5) cage at R1C6 = {12348/12456}
14b. 1,8 of {12348} must be in R1C67 -> no 3 in R1C67, clean-up: no 4 in R7C8
14c. R1C89 = R3C7 + 1 (step 9)
14d. 3 of {12348} must be in R2C7 (18(5) cage cannot be 18{23}4 because R1C89 + R2C7 = {23}4 clashes with R1C89 + R3C7 = {23}4, 18(5) cage cannot be 18{34}2 because R1C23 = {27} (then only place for 2 in R1) clashes with R1C14 = [97]) -> no 3 in R1C89
[Thanks Ed for pointing out that I’d overlooked R1C789 = 8{34}.]
14e. Min R1C89 = {24} = 6 -> min R3C7 = 5
14f. 3 of {12348} must be in R2C7, 2,6 of {12456} must be in R2C7 (R1C6789 cannot be {1246/1256} which clash with R1C23), no 4,5 in R2C7
14g. 4 of 18(5) cage must be in R1C6789, locked for R1, clean-up: no 5 in R1C23
14h. R3C7 = {568} -> R1C89 = 6,7,9 = {24/45} (cannot be {25} because R1C89 + R2C7 of {12456} = {25}6 clashes with R1C89 + R3C7 = {25}6), no 6, 4 locked for R1 and N3, clean-up: no 3 in R7C8
14i. R1C89 = {24/45} = 6,9 -> R3C7 = {58}

15. 45 rule on N9 4 innies R7C78 + R89C7 = 19 = {1279/1459/2467/3457} (cannot be {1369/1567/2359} which clash with R789C9)
15a. Hidden killer triple 4,7,9 in 16(3) cage at R4C7 and R789C7 for C7, R789C7 must contain two of 4,7,9 (because no 4,7,9 in R7C8) -> 16(3) cage must contain one of 4,7,9
15b. 16(3) cage = {259/367} (cannot be {268/358} which don’t contain any of 4,7,9, cannot be {349/457} which contain two of 4,7,9), no 4,8
15c. 4 in C7 only in R789C7, locked for N9, clean-up: no 6 in R89C8
15d. Hidden killer pair 3,6 in R456C9 and 16(3) cage at R7C9 for C9, 16(3) cage contains one of 3,6 -> R456C9 must contain one of 3,6
15e. 16(3) cage = {259} (only remaining combination, cannot be {367} which clashes with R456C9), locked for C7 and N6
[The eliminations of 4 from R123C7 led to steps 15a-15e which crack the puzzle; the rest is fairly straightforward.]
15f. R7C78 + R89C7 = {2467/3457} no 1, 7 locked for N9, clean-up: no 6 in R1C6 (step 14), no 3 in R89C8
15g. R89C8 = [19], clean-up: no 7 in R9C1
15h. R1C7 = 1 (hidden single in C7), clean-up: no 6 in R7C8 (step 14)
15i. Naked pair {25} in R1C6 + R7C8 (step 14), CPE no 2,5 in R1C8 + R7C6 -> R1C8 = 4
15j. Naked pair {25} in R1C69, locked for R1, R1C78 = [14] -> R2C7 = 6 (cage sum), clean-up: no 7 in R1C23
15k. Naked pair {36} in R1C23, locked for R1 and N1, clean-up: no 2 in R2C4, no 5 in R4C1
15l. R789C7 = {347} -> R7C8 = 5, R1C6 = 2 (step 14), clean-up: no 4 in R3C3
15l. 16(3) cage at R7C8 = {268} (only remaining combination), 6 locked for C9
15m. R3C7 = 8, R23C8 = {23}, 3 locked for C8 and 23(5) cage at R2C8 -> R4C89 = 10 = [64], R4C1 = 7 -> R3C1 = 4, clean-up: no 1 in R2C4, no 2 in R3C3, no 1 in R5C4, no 2 in R6C1, no 5 in R6C2, no 1 in R9C1
15n. Naked pair {15} in R3C34, locked for R3
15o. 7 in N1 only in R23C2, locked for C2
15p. R9C189 = 18 (step 5c), R9C8 = 9 -> R9C19 = 9 = [36] -> R8C1 = 5, clean-up: no 9 in R1C4 (step 6), no 6,8 in R5C2, no 4,6 in R6C2
15q. Killer pair 1,3 in R6C12 and R6C9, locked for R6
15r. 3 in N9 only in R78C7, R78C7 = {34/37} = 7,10 -> R8C6 = {69}
15s. 34(6) cage at R1C4 (step 13) must contain 9, locked for C5
15t. 9 in C4 only in R678C4, locked for 33(6) cage at R6C4, no 9 in R8C3

16. 12(3) cage at R7C1 = {129/246}, no 8, 2 locked for N7
16a. R2C34 = [14] (cannot be {23} which clashes with R2C8) -> R3C34 = [51]
16b. Naked pair {23} in R45C4, locked for C4 and N5
16c. R9C4 = 5 -> R9C23 = 9 = [18]
16d. 12(3) cage at R7C1 = {246} (only remaining combination), 6 locked for N7
16e. Naked pair {27} in R23C2, 2 locked for C2 and 21(4) cage at R2C2 -> R47C3 = [39], R4C2 = 9 (cage sum)
16f. R5C2 = 5 -> R5C1 = 6
16g. R7C1 = 2, R78C9 = [82]
16h. R7C4 + R8C3 = [67], R8C6 = 9, R68C4 = [98], R8C3 = 3 (cage sum), R78C2 = [46]
16i. R6C12 = [18], R56C8 = [87]
16j. R7C56 = {17}, locked for N8 -> R6C56 = 11 = {56}, locked for R6 and N5
16k. R45C4 = [23], R89C7 = [47], R9C6 = 4
16l. Naked pair {18} in R4C56, locked for N5 -> R5C6 = 7, R7C6 = 1, R45C6 = [87] -> R23C6 = 9 = [36]

and the rest is naked singles.

Rating Comment:
I'll rate my WT for A363 at Easy 1.5. For a change no forcing chains; my hardest steps were combination interactions in N3.


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 Post subject: Re: Assassin 363
PostPosted: Wed Jan 30, 2019 7:11 pm 
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Posts: 40
Location: Canberra, Australia
May I be briefly "off topic" and just ask whether Andrew, or any Killer people, have looked at my Psycho Killer puzzle in the variants area yet?


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