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Assassin 353 http://www.rcbroughton.co.uk/sudoku/forum/viewtopic.php?f=3&t=1440 |
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Author: | Ed [ Sat Jun 30, 2018 7:05 pm ] |
Post subject: | Assassin 353 |
Attachment: a353.JPG [ 64.29 KiB | Viewed 6150 times ] A very easy start but then.....tricky to get into the middle. Nothing really advanced but have to be thoughful. This one started out as an easier one to remember 12 years since Ruud started making Assassins but couldn't help myself and had to toughen it up. You can guess what the easier puzzle cage was if you want to make it a bit easier. The one shown here gets a score of 1.40 JSudoku has no trouble. code: solution: Ed |
Author: | Andrew [ Sat Jul 07, 2018 3:21 am ] |
Post subject: | Re: Assassin 353 |
Thanks Ed for your latest Assassin. Mostly fairly routine, but it took me a while to spot my breakthrough step. Here is my walkthrough for Assassin 353: Rating Comment: |
Author: | wellbeback [ Sun Jul 08, 2018 8:46 pm ] |
Post subject: | Re: Assassin 353 |
Thanks Ed. I found my breakthrough step quite quickly after the easy stuff. A small follow on from Andrew's Step 8. Assassin 353 WT: |
Author: | Ed [ Mon Jul 09, 2018 9:05 pm ] |
Post subject: | Re: Assassin 353 |
As often happens, sounds like you guys found this puzzle easier than I did. I worked in similar areas to Andrew but saw it differently (as usual!). But first, loved wellbeback's step 7. Attachment: a353Wstep7.JPG [ 56.98 KiB | Viewed 6112 times ] Quote: 5. ....-> 2 and 5 in 21(5) in n6 (Important for step 7!) Often see the first part of this in puzzles but never thought of combining this with locked numbers. Very obvious once you see it!7! The breakthrough step Innies - Outies r1234 -> r4c3 + 3 = r5c1 + r5c8 Since r5c1 cannot be 3 -> r4c3 cannot be the same as r5c8 -> r4c3 cannot be the same as any of the values in the 21(5) in n6 -> r4c3 cannot be 2 or 5 Better post my WT. Thanks to Andrew for some typos. A353 25 steps: Ed |
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