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Well, the next 3 Assassins are booked, so it's time for a new Messy One!

Messy One #3
SScore(3.2.0): 0.97



Code:
3x3::k:2560:2560:5634:5634:5634:5634:5382:5382:5382:2560:6410:6410:6410:3853:3342:1807:1807:5382:6418:6410:3860:3853:3853:3342:4376:4376:3098:6418:6410:3860:5150:5150:4128:4128:4376:3098:6418:6418:2086:5150:5150:5150:4128:3115:3115:5421:5421:2095:2086:5681:2866:3635:3115:4405:4918:5421:2095:5681:5681:2866:3635:3635:4405:4918:5421:2369:2369:4675:7236:7236:3635:4405:4918:4918:2369:4675:4675:4675:7236:7236:4405:

Solution:

Have fun!

Cheers,
Nasenbaer

Thanks Nasenbaer for providing a fun killer! I think of all Messies posted so far, this one was the easiest.

Messy One #3 Walkthrough:

1. R456
a) Outies R6789 = 7(3) = {124} locked for R4; 4 also locked for N6
b) 8(2) @ R5C3 = [17/26]
c) Innies R6789 = 13(2) = {67} locked for R6

2. R123
a) Outies R1 = 8(2) <> 4,8,9
b) Outies N3 = 12(2) = {39/57}
c) 12(2) <> 4,8
d) Innies+Outies N2: 5 = R1C3 - R2C4 -> R1C3 = (6789), R2C4 = (1234)

3. C123
a) Outies C12 = 10(2) = [64/73/82/91]
b) Naked quad (6789) locked in R1234C3 for C3
c) 8(2) @ R6C3 = {35} locked for C3
d) 4 locked in 9(3) @ C3 = {234} -> R8C4 = 3, {24} locked for C3+N7
e) R5C3 = 1 -> R6C4 = 7, R6C8 = 6
f) Outies N7 = 9(3) = {234} -> R6C3 = 3, {24} locked for R6+N4
g) 21(4) = 24{69/78} because R6C12 = {24}

4. R456
a) Hidden triple (124) in R4C456 @ N5 locked for R4
b) R7C3 = 5
c) 11(2) = [56/92]
d) 3,6 locked in 20(5) @ N5 = 236{18/45} -> 2 locked for N5; 3,6 locked for R5

5. R6789
a) Outies N9 = 14(2+1): R8C6 <> 9 because R6C79 >= 6
b) 18(4) <> 9 because R7C6 = (26) blocks {1269}
c) 9 locked in R7C45 @ N8 for R7+22(3)
d) Hidden Single: R6C6 = 9 @ N5 -> R7C6 = 2
e) Outies N9: 1 locked in R6C79 @ N6 -> R6C79 = 1{5/8} -> R8C6 = (58)
f) 4 locked in R7C789 @ R7 for N9
g) 28(4) = {5689} -> 6,9 locked for N9; 6 also locked for C7
h) 14(4) = 2{138/147/345} -> R8C8 = 2
i) 17(4) = 15{38/47} -> 1,5 locked for C9

6. C789
a) 12(2) = {39} locked for C9
b) 17(4) = {1457} locked for C9, {47} locked for N9
c) R5C8 = 4, R5C9 = 2, R2C9 = 6, R1C9 = 8
d) 21(4) = 68{25/34} -> R1C7 = (24)
e) 7(2) = [25/43]
f) Naked pair (35) locked in R12C8 for N3+C8
g) R3C9 = 9, R4C9 = 3
h) 17(3) = {179} -> R4C8 = 9, {17} locked for R3
i) R9C8 = 8, R7C8 = 1 -> R67C7 = 11(2) = [83] -> R6C7 = 8, R7C7 = 3

7. R123+N5
a) R6C5 = 5 -> R7C45 = 17(2) = {89} locked for R7+N8
b) 20(5) = {12368} locked for N5, 8 locked for R5
c) R8C6 = 5
d) 13(2) = {67} -> R2C6 = 7, R3C6 = 6
e) R3C3 = 8 -> R4C3 = 7
f) 7 locked in 10(3) @ N1 = {127} locked for N1

8. Rest is singles.

Rating: 1.0

Not messy at all !!



r2c34=10 and r1c3=r2c4+5 so if r2c4=x -> r1c3=x+5 and r2c3=10-x ->r12c3=15
so r12c3 and r34c3 naked quad 6789
so in c3 4 at r89 so in c3 naked single r5c3=1 so r6c4=7 -> r6c8=6 and r67c3={35}
r89c3={24} so r8c4=3




Still some work to do but it's cracked now.

Agree with Afmob.1.0 at most.

Regards

Gary

I disagree. See Ed's Messy-rules:

The score is right, and there's no symmetry.

Cheers,
Nasenbaer

After doing A108 I moved on to Messy One #3, two puzzles in a row by Nasenbaer.

I think I found this one a bit harder than Messy One #1, possibly because I took some time to find the key step, the innie-outie on N2 which leads directly to the naked quad in C3. My methodical approach must have been upset by this being a Messy One! Maybe 45s on rows, columns and corner nonets are easier to spot. Just a thought!

The key step is part of a narrow path to start this puzzle. Maybe I'm going a bit high but I'll rate it as High 1.0.

I won't post a full walkthrough. My one was fairly similar to Afmob's apart from the order of some steps.