SudokuSolver Forum

A forum for Sudoku enthusiasts to share puzzles, techniques and software
It is currently Thu Nov 21, 2019 12:26 am

All times are UTC




Post new topic Reply to topic  [ 4 posts ] 
Author Message
 Post subject: Assassin 386
PostPosted: Tue Oct 15, 2019 8:41 pm 
Offline
Grand Master
Grand Master

Joined: Wed Apr 16, 2008 1:16 am
Posts: 829
Location: Sydney, Australia
Attachment:
a386.JPG
a386.JPG [ 68.83 KiB | Viewed 215 times ]
An X puzzle so 1-9 cannot repeat on either diagonal. Note: it has 3 cells not covered by cages.

Assassin 386
I found this a very difficult puzzle, though enough satisfying steps to make it worthy of an Assassin. Found a strange step to get inroads started. SS gives it 1.45 JS uses 4 chains.
code:triple click:
3x3:d:k:2584:2584:2584:4864:4864:4353:0000:0000:3330:2563:2563:0000:4864:5380:4353:6661:6661:3330:5126:6151:4864:4864:5380:2312:2312:6661:3330:5126:6151:6151:8969:5380:2312:2314:2571:6661:5126:6151:8969:8969:5380:5380:2314:2571:6661:2572:2317:2317:8969:8969:4366:2575:2575:5648:2572:4625:4625:8969:3090:4366:3091:2575:5648:1812:4625:5653:5653:3090:4366:3091:4374:5648:1812:1812:5653:5653:2583:2583:4374:4374:5648:
solution:
Code:
+-------+-------+-------+
| 3 5 2 | 4 1 8 | 6 9 7 |
| 6 4 1 | 3 7 9 | 5 8 2 |
| 7 8 9 | 2 6 5 | 1 3 4 |
+-------+-------+-------+
| 8 9 4 | 7 5 3 | 2 6 1 |
| 5 3 6 | 8 2 1 | 7 4 9 |
| 1 2 7 | 9 4 6 | 3 5 8 |
+-------+-------+-------+
| 9 7 5 | 1 3 4 | 8 2 6 |
| 2 6 8 | 5 9 7 | 4 1 3 |
| 4 1 3 | 6 8 2 | 9 7 5 |
+-------+-------+-------+


Top
 Profile  
Reply with quote  
 Post subject: Re: Assassin 386
PostPosted: Sun Oct 20, 2019 2:59 am 
Offline
Master
Master

Joined: Tue Jun 16, 2009 9:31 pm
Posts: 199
Location: California, out of London
Thanks Ed for a very interesting puzzle. I did it twice - and the second way was much more pleasing to me. The first one was somewhat laborious and was based on the outies of n4 and slowly eliminating impossibilities. Here's how I did it the second time...
Assassin 386 WT:
1. 17(2)n2 = {89}
-> 17(3)c6 = {467}
-> Remaining cells in c6 = r3459c6 = {1235} with r9c6 from (123)

2. Of the numbers (347) in n8, one goes in the 12(2) and at least one goes in r78c6
-> 10(2)n8 cannot be [73]
-> 10(2)n8 from [82] or [91]
-> At least one of (35) in r34c6
-> 9(3)r3c6 cannot be {126}

3! Innies n69 = r45c9 = +10(2)
The values in those cells can only go in n3 in r1c78 and r3c7
Since those three cells (which are the innies n3c69) = +16(3)
-> the third innie must be 6.
-> 6 in r1c78
-> (Remaining innies from {19}, {28}, {37}) -> r3c7 cannot be 4 or 5
-> 9(3)r3c6 cannot be {234}
-> 9(3)r3c6 = {135} with 5 in r34c6

4! Innies c123456 = r2c3 + r34c6 = +9(3)
-> r2c3 = r3c7 = 1 or 3

5. 19(5) must contain a 1
-> r3c6 cannot be 1 (sees all cells in 19(5)n2)
-> r3c6 from (35)

6. Remaining Innies n1 = r3c123 = +22(3) or +24(3) (No 1234)
-> 1 in 19(5)n2 in n2

7! 9(3)r3c6 from [315], [513], or [531]
But the last of those puts 3 in r2c3 and HS 1 in c5 in r1c5 which leaves no solution for 10(3)n1
-> r3c7 = r2c3 = 1

8. Continuing from that...
-> 10(3)n1 = {235}
-> 10(2)n1 = {46}
-> r3c123 = {789}
Also r1c78 = {69}
-> 17(2)n2 = [89]
Also since r3c3 is min 7 -> 7 in n2 not in 19(5)
-> (HS 7 in n2) r2c5 = 7
-> (HS 7 in r1) r1c9 = 7
-> 13(3)n3 = [724]
-> 26(5)n36 = [{358}{19}] with 8 in r2c78
Also NP r1c45 = {14}
-> (Since r3c3 is min 7) 6 cannot be in 19(5)n2
-> HS r3c5 = 6
-> (Since r3c68 = {35}) NS r3c4 = 2
-> (HS 2 in n8) -> 10(2)r9c5 = [82]
-> 12(2)n8 = {39}
Also NS r5c6 = 1
-> r45c5 = {25}
-> 9(3)r3c6 = [513]
-> (IOD c5) r16c5 = [14]
-> r12c4 = [43]
-> r2c78 = {58} and r3c8 = 3
Also Remaining cell in 19(5) = r3c3 = 9
-> r3c12 = {78}
Also Remaining Innies r6789 = r67c4 = +10(2) = [91]

9. Some more...
IOD n9 -> r6c9 = r7c8 + 6
-> r6c9 = 8 and r7c8 = 2
-> r6c78 = [35]
-> r2c78 = [58]
Also 9(2)n6 = {27} and 10(2)n6 = {46}
-> r1c78 = [69]
Also r789c9 = {356}
-> 12(2)n9 = {48}
-> r89c8 = {17} and r9c7 = 9

10. Even more...
HS 1 in r6 -> r6c1 = 1
-> r7c1 = 9
Also 7(3)n7 = [241]
Also 20(3)c1 = {578}
-> r12c1 = [36]
etc.
(Diagonals have not yet been used).


Top
 Profile  
Reply with quote  
 Post subject: Re: Assassin 386
PostPosted: Fri Oct 25, 2019 8:20 am 
Offline
Grand Master
Grand Master

Joined: Wed Apr 16, 2008 1:16 am
Posts: 829
Location: Sydney, Australia
Very pleasing way indeed wellbeback! Loved it. I changed the cage structure to close up wellbeback's step 3 but the SSscore stayed the same. Must be something else I missed. This is the way I struggled through it. Took a very long time to find my step 4 which allowed some progress. Step 12 was my key, then quite a long tail. An interesting puzzle this turned out to be!

A386 WT:
Preliminaries from Sudoku Solver
Cage 17(2) n2 - cells ={89}
Cage 12(2) n8 - cells do not use 126
Cage 12(2) n9 - cells do not use 126
Cage 9(2) n6 - cells do not use 9
Cage 9(2) n4 - cells do not use 9
Cage 10(2) n1 - cells do not use 5
Cage 10(2) n8 - cells do not use 5
Cage 10(2) n47 - cells do not use 5
Cage 10(2) n6 - cells do not use 5
Cage 7(3) n7 - cells ={124}
Cage 9(3) n235 - cells do not use 789
Cage 10(3) n1 - cells do not use 89
Cage 10(3) n69 - cells do not use 89
Cage 20(3) n14 - cells do not use 12

1. 7(3)n7 = {124}: all locked for n7
1a. no 6,8,9 in r6c1

2. 17(2)n2 = {89}: both locked for n2 and c6

3. 17(4)r6c6 = {467} only: all locked for c6
3a. r9c5 = (789)

Took a long time to find this strange "45"
4. "45" on n4578: 2 outies r3c12 - 4 = 4 innies r45c56
4a. -> max. 4 innies = 13 -> no 8,9
4b. max. 4 innies = 13 and 2+3+4+5 = 14 so must have 1: 1 locked for n5

5. 21(5)r2c5 = {12567/13467/23457}
5a. must have 7: locked for c5
5b. 12(2)n8 = {39/48}(no 5)
5c. no 3 in r9c6

6. killer pair 8,9 in r789c5: both locked for c5 and n8

7. 5 in n8 only in c4: locked for c4

8. "45" on n9: 1 outie r6c9 - 6 = 1 innie r7c8 = [71/82/93]

9. "45" on n9: 3 outies r6c789 = 16
9a. but {268} as {26}[8] only, blocked by 2 in r7c8 (step 8)
9b. {34}[9] blocked by 3 in r7c8
9c. = {169/178/259/358/367/457}

10. "45" on n78: 2 outies r6c16 - 6 = 1 innie r7c4
10a. no 6 in r6c1 -> r7c4 <> r6c6 -> no 4,6,7 in r7c4 (since 17(4)r6c6 = {467}

11. "45" on r6789: 3 outies r45c4 + r5c3 = 21 = {489/579/678}(no 1,2,3) = 5/8 or 4/7
11a. -> r6c45 + r7c4 = 14
11b. but {158/347} blocked by h21(3) since same cage
11c. h14(3) = {149/167/239/248/257/356}

Get my key elimination in this step. Not easy
12. h14(3) = {149/167/239/248/257/356}
12a. h16(3)r6c789 = {169/178/259/358/367/457}
12b. consider 5 in r6c5 in h14(3) from {257/356}
12c. from {257} -> [75] in r6c45 -> {169} in h16(3)r6c789 but this blocks all combos for 9(2)n4
12d. from {356} -> [65] in r6c45 -> 9 in r6 only in h16(3)r6c789 = {169/259} but these are both blocked
12e. -> no 5 in r6c5

13. 1 and 5 in n5 only in r45c56 which are from 10-13 total (step 4)
13a. 1+5=6 -> other two = 5,6,7 (can't be 4 since 1 already fixed
13b. = {23/24/34}
13c. -> no 6,7 in r45c5

14. 21(5)r2c5 = {12567/13467/23457}
14a. must have 7 which is only in n2: locked for n2
14b. {13467/23457} must have 3 in r5c6 to avoid {34} clashing with 12(2)n8
14c. {12567} ={67}{125} -> r4c6 = 3
14d. -> 3 must be in r45c6: locked for c6 and n5

15. 21(5)r2c5 = {12567/13467/23457}
15a. must have 4 for c5 or {12567} -> r6c5 = 4
15b. 4 locked for c5

16. 12(2)n8 = {39} only: both locked for c5 and n8
16a. r9c56 = [82]

17. r9c12 = {14}: both locked for r9 & r8c1 = 2

18. h14(3)r6c4 must have 1 or 5 for r7c4 = {149/167/257}(no 8)

19. "45" on n78: 2 outies r6c16 - 6 = r7c4 -> r6c16 = 7 or 11 = [16/34]/{47}
19a. -> {27}[5] blocked from h14(3)r6c4 (two 7 in r6)
19b. -> h14(3) = {149/167}(no 2,5)
19c. r7c4 = 1
19d. r6c45 = [94/76]
19e. no 7 in r6c9 (iodn9=-6)
19f. r6c16 = 7 = [16/34]
19g. r7c1 = (79)

20. 7 in c6 only in n8: locked for n8

21. 5 in c4 only in r89c4: locked for 22(4)

22. 5 in n7 only in 18(3) = {567} only: all locked for n7
22a. r67c1 = [19]
22b. -> r6c6 = 6 (r6c16=7), 6 placed for d\
22c. r6c45 = [94] (h14(3)), 9 placed for d/

23. r45c4 = {78} = 15 -> r5c3 = 6 (h21(3))

24. "45" on c5: 1 remaining innie r1c5 = 1 outie r5c6 = (15)
24a. hsingle 3 in n5 -> r4c6 = 3, placed for d/

25. r45c56 = {1235} = 11 -> r3c12 = 15 (from iodn4578)(no 1,2,3,4,5)
25a. -> 2 remaining innies n1 r23c3 = 10 (no 5)

26. "45" on c1234: 1 remaining outie r1c5 = 1 innie r2c3 = 1 only -> both = [1]
26a. -> r3c3 = 9 (h10(2)r23c3), 9 placed for d\
26b. r5c6 = 1 (1 outie c5)
26c. r3c67= [51] (cage sum)
26d. 19(5)r1c4 must have 1 & 9 -> r123c4 = {234} only: 2 locked for n2 and 4 for c4

27. r3c12 = h15(2) = {78} only: both locked for n1 and r3

etc
Cheers
Ed


Top
 Profile  
Reply with quote  
 Post subject: Re: Assassin 386
PostPosted: Wed Nov 06, 2019 9:16 pm 
Online
Grand Master
Grand Master

Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1679
Location: Lethbridge, Alberta, Canada
I also loved the way wellbeback broke open this Assassin! I missed his step 2 and the key point of step 3. I would also give step 2 a !

My solving path was a lot longer but still used interesting steps!

Here is my walkthrough for Assassin 386:
This is a Killer-X.

Prelims

a) R12C6 = {89}
b) R2C12 = {19/28/37/46}, no 5
c) R45C7 = {18/27/36/45}, no 9
d) R45C8 = {19/28/37/46}, no 5
e) R67C1 = {19/28/37/46}, no 5
f) R6C23 = {18/27/36/45}, no 9
g) R78C5 = {39/48/57}, no 1,2,6
h) R78C7 = {39/48/57}, no 1,2,6
i) R9C56 = {19/28/37/46}, no 5
j) 10(3) cage at R1C1 = {127/136/145/235}, no 8,9
k) 20(3) cage at R3C1 = {389/479/569/578}, no 1,2
l) 9(3) cage at R3C6 = {126/135/234}, no 7,8,9
m) 10(3) cage at R6C7 = {127/136/145/235}, no 8,9
n) 7(3) cage at R8C1 = {124}

Steps resulting from Prelims
1a. Naked pair {89} in R12C6, locked for C6, clean-up: no 1,2 in R9C5
1b. Naked triple {124} in 7(3) cage at R8C1, locked for N7, clean-up: no 6,8,9 in R6C1

2. 45 rule on C6 4 innies R3459C6 = 11 = {1235}, locked for C6, clean-up: no 3,4,6 in R9C5
2a. 9(3) cage at R3C6 = {126/135/234}
2b. 4,6 of {126/235} must be in R3C7 -> no 2 in R3C7

3a. 45 rule on R6789 3 outies R4C4 + R5C34 = 21 = {489/579/678}, no 1,2,3
3b. 45 rule on R6789 3 innies R6C45 + R7C4 = 14 = {149/167/239/248/257/356} (cannot be {158/347} which clash with R4C4 + R5C34)

4. 45 rule on C1 4(3+1) outies R1C23 + R29C2 = 12
4a. Min R129C2 = 6 -> max R1C3 = 6
4b. Min R1C23 + R9C2 = 3+1 = 4 -> max R2C2 = 8, clean-up: no 1 in R2C1

5a. 45 rule on C9 2 innies R45C9 = 10 = {19/28/37/46}, no 5
5b. 45 rule on C9 3 outies R2C78 + R3C8 = 16
5c. 45 rule on C789 3 innies R1C78 + R3C7 = 16
5d. 45 rule on whole grid R1C78 + R2C3 = 16
5e. R1C78 + R3C7 = 16, R1C78 + R2C3 = 16 -> R2C3 = R3C7 = {13456}
[This can also be obtained from 45 rule on C123456, which I spotted later.
Note that whichever value is in R2C3 and R3C7 must be in R1C45 for N2.]

6. 45 rule on N1 4 innies R2C3 + R3C123 = 25 = {1789/2689/3589/3679/4579/4678}
6a. 1 of {1789} must be in R2C3 -> no 1 in R3C23
6b. 19(5) cage at R1C4 = {12349/12367/12457/13456} (cannot be {12358} which clashes with R3C6), no 8, 1 locked for N2

7. 45 rule on N9 1 outie R6C9 = 1 innie R7C8 + 6 -> R6C9 = {789}, R7C8 = {123}

8. 45 rule on N78 2 outies R6C16 = 1 innie R7C4 + 6
8a. Max R6C16 = 13 -> max R7C4 = 7
8b. Max R6C16 = 11 (cannot be [76] because R7C4 = 7 clashes with R78C6 = {47}) -> max R7C4 = 5
8c. 35(6) cage at R4C4 must contain 8,9 in R4C4 + R5C34 + R6C45, CPE no 8,9 in R5C5

9. 20(3) cage at R3C1 = {389/569/578} (cannot be {479} which clashes with R67C1 + R89C1), no 4

10. R45C9 = 10 (step 5a)
10a. Consider placement for 5 in N6
5 in R45C7 = {45}, 4 locked for N6 => no 6 in R56C89 => 6 in N6 only in 10(3) cage at R6C7 = {136}
or 5 in 10(3) cage = {145/235}
-> 10(3) cage = {136/145/235}, no 7

[Just spotted. Not sure how or if this can be used.]
11. 45 rule on N2 3 innies R23C5 + R3C6 = 1 outie R3C3 + 9 -> R23C5 cannot total 9 (IOU) -> R4C5 + R5C56 cannot total 12
[At this stage I can’t see how to use this to eliminate any of the combinations of 19(5) cage at R1C4 (step 6b) since R3C3 doesn’t ‘see’ R2C5 so, for three of the combinations, whichever value is in R3C3 must be in R2C5.]

12. Consider permutations for R6C9 + R7C8 (step 7) = [71/82/93]
R6C9 + R7C8 = [71]
or R6C9 + R7C8 = [82] => R6C78 = 8 = {35}, locked for R6 => R6C23 = {27}, locked for R6
or R6C9 + R7C8 = [93] => no 7 in R6C1
-> R6C1 = {1234}, clean-up: no 3 in R7C1

13. 9(3) cage at R3C6 = {126/135/234}, note that {126} can only be [261]
13a. Consider combinations for 19(5) cage at R1C4 (step 6b) = {12349/12367/12457/13456}
19(5) cage = {12349/12367/12457}, CPE no 2 in R3C6 => 9(3) cage = {135}/[342]
or 19(5) cage = {13456} => 7 in N2 must be in R23C5, locked for C5 => R9C56 = [82/91] => 9(3) cage = {135/234} (cannot be [261] which clashes with R9C6)
-> 9(3) cage = {135/234}, no 6
13b. R3C7 = {1345} -> R2C3 = {1345} (step 5e)
13c. R1C78 + R3C7 = 16 (step 5c), max R3C7 = 5 -> min R1C78 = 11, no 1 in R1C78
13d. R2C3 + R3C123 (step 6) = {1789/3589/3679/4579/4678} (cannot be {2689} because no 2,6 in R2C3), no 2
13e. R2C12 = {28/46}/[91] (cannot be {37} which clashes with R2C3 + R3C123), no 3,7
13f. R2C3 + R3C123 = {1789/3679/4579/4678} (cannot be {3589} which clashes with 9(3) cage = {35}1 using R2C3 = R3C7), 7 locked for R3 and N1
13g. 3 of {3679} must be in R2C3 -> no 3 in R3C123
13h. Consider again combinations for 19(5) cage = {12349/12367/12457/13456}
19(5) cage = {12349/12367}, 2,3 locked for N2
or 19(5) cage = {12457}, 2 locked for N2, CPE no 5 in R3C6 => R3C6 = 3 => no 2,3 in R23C5
or 19(5) cage = {13456}, 3 locked for N2, CPE no 5 in R3C6 => R3C6 = 2 => no 2,3 in R23C5
-> no 2,3 in R23C5
13i. 19(5) cage = {12349/12367/12457} (cannot be {13456} which clashes with R3C5), 2 locked for N2
13j. 3 in N1 only in R1C123 + R2C3 -> 3 in R1C123 + R3C7 (using R2C3 = R3C7), CPE no 3 in R1C789

14. Consider combinations for 9(3) cage at R3C6 (step 13a) = {135/234}
9(3) cage = {135}, 1 in R3C7 + R4C6, locked for D/
or 9(3) cage = {234} = [342], 2,4 locked for D/ => R9C1 = 1, placed for D/
-> 1 in R3C7 + R4C6 + R9C1, locked for D/

15. 45 rule on C1 2 outies R29C2 = 1 innie R1C1 + 2 -> no 2 in R9C2 (IOU)
15a. 2 in N7 only in R89C1, locked for C1, clean-up: no 8 in R2C2, no 8 in R7C1
15b. 45 rule on N7 3 innies R7C1 + R89C3 = 20 = {389/569/578}
15c. 7 of {578} must be in R7C1 -> no 7 in R89C3

16. R2C3 + R3C123 (step 13f) = {1789/3679/4579/4678}, 10(3) cage at R1C1 = {136/145/235}, R2C3 = R3C7 (step 5e), R1C78 + R2C3 = 16 (step 5d)
16a. Consider placement for 8 in N1
8 in R3C12 => R2C3 + R3C123 = {1789/4678} => R2C3 = {14}
or R2C12 = [82] => 10(3) cage = {136}, 3 locked for N1
or R2C12 = [82] => 10(3) cage = {145}, R12C6 = [89] => 9 in R1 in R1C789 so looking at those possibilities
9 in R1C78 => R1C78 + R2C3 = {29}5/{69}1 (cannot be {49}3 which clashes with 10(3) cage = {145}), no 3 in R3C7 => no 3 in R2C3
or 9 in R1C9 => 13(3) cage at R1C9 = 9{13}, locked for N3, no 3 in R3C7 => no 3 in R2C3
-> no 3 in R2C3, no 3 in R3C7
16b. 3 in N1 only in 10(3) cage = {136/235}, no 4, 3 locked for R1
16c. 9(3) cage at R3C6 (step 13a) = {135/234}, 3 locked for C6, clean-up: no 7 in R9C5
16d. Naked triple {124} in R9C126, locked for R9, 4 also locked for N7
16e. 2 in R9 only in R9C19, CPE no 2 in R4C6
16f. 9(3) cage at R3C6 (step 13a) = {135} (only remaining combination), no 4, 1 locked for D/, clean-up: no 4 in R2C3
16g. R2C3 + R3C123 = {1789/4579} (cannot be {4678} since R2C3 only contains 1,5), no 6, 9 locked for R3 and N1, clean-up: no 1 in R2C2

17. 19(5) cage at R1C4 (step 13i) = {12349/12367/12457} contains both of 1,2 in R123C4 + R1C5
17a. Hidden killer pair 1,2 in R789C4 and R9C6 for N8, R9C6 = {12} -> R789C4 contains one of 1,2
17b. Hidden killer pair 1,2 in R123C4 and R789C4 for C4, R789C4 contains one of 1,2 -> R123C4 cannot contain both of 1,2 -> R123C4 contains one of 1,2 -> R1C5 = {12}
17c. Killer pair 1,2 in R123C4 and R789C4, locked for C4
17d. 45 rule on C1234 2 outies R16C5 = 1 innie R2C3 + 4, R2C3 = {15} -> R16C5 = 5,9 = [14/18/23/27], R6C5 -> {3478}
17e. R6C45 + R7C4 (step 3b) = {149/167/239/248/257/356}
17f. 1,2 of {149/248} must be in R7C4 -> no 4 in R7C4
17g. 3 of {239/356} must be in R6C5 -> no 3 in R67C4
17h. 7 of {167/257} must be in R6C5 -> no 7 in R6C4

18. Min R23C5 = 10 (cannot total 9, step 11) -> max R4C5 + R5C56 = 11, no 9 in R4C5
18a. 9 in N5 only in R456C4, locked for C4 and 35(6) cage at R4C4

[I ought to have seen this step a bit earlier; it became available after step 15 but I was focussed on 19(5) cage whenever I could use it.]
19. 20(3) cage at R3C1 (step 9) = {569/578} (cannot be {389} which clashes with R2C1 + R67C1), no 3, 5 locked for C1
19a. Hidden killer pair 7,9 in 20(3) cage and R7C1 for C1, 20(3) cage contains one of 7,9 -> R7C1 = {79}, clean-up: no 4 in R6C1
19b. R1…9C1 = [18]{569}[3724]/[36]{578}[1924] -> R1C1 = {13}, R2C1 = {68}, R8C1 = 2, R9C1 = 4, placed for D/, R9C2 = 1, R9C6 = 2 -> R9C5 = 8, clean-up: no 8 in R6C3, no 4 in R78C5
19c. R6C16 = R7C4 + 6 (step 8)
19d. Max R6C16 = 10 -> no 5 in R7C4 -> R7C4 = 1, R6C16 = 7 = [16/34]
19e. 7 in C6 only in R78C6, locked for N8, clean-up: no 5 in R78C5
19f. R1C5 = 1 (hidden single in N2)
19g. R1C1 = 3, placed for D\, R6C1 = 1 -> R7C1 = 9, R78C5 = [39]
19h. 20(3) cage = {578} -> R2C1 = 6, R2C2 = 4, placed for D\
19i. R6C6 = 6, placed for D\, R78C6 = {47}, 4 locked for N8, R89C4 = {56}, locked for C4 and 22(4) cage at R8C3 -> R89C3 = [83]
19j. Naked pair {25} in R1C23, locked for R1, 5 locked for N1
19k. R2C3 = 1 -> R3C7 = 1 (step 5e)
19l R7C8 = 2 -> R6C78 = 8 = {35}, locked for R6 and N6, R6C9 = 8 (step 7)
190m. R6C23 = {27} (only remaining combination), locked for R6 and N4 -> R6C4 = 9, placed for D/, R6C5 = 4
19n. Naked pair {58} in R45C1, locked for N4, 8 locked for C1 -> R3C1 = 7, R3C3 = 9, placed for D\, R3C2 = 8
19o. R45C7 = {27} (only remaining combination), locked for C7 and N6
19p. R78C7 = [84] (only remaining permutation), 8 placed for D\, R4C4 = 7, placed for D\
19q. R9C4789 = [6975], R8C8 = 1, R78C9 = [63]
19r. R1C9 = 7, placed for D/, R23C9 = 6 = [24]

and the rest is naked singles, without using the diagonals.

Rating Comment:
I'll rate my WT for A386 at 1.5. I used several forcing chains and the 'clone' R2C3=R3C7, including together.


Top
 Profile  
Reply with quote  
Display posts from previous:  Sort by  
Post new topic Reply to topic  [ 4 posts ] 

All times are UTC


Who is online

Users browsing this forum: Andrew and 11 guests


You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot post attachments in this forum

Search for:
Jump to:  
Powered by phpBB® Forum Software © phpBB Group