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PostPosted: Wed Feb 27, 2013 11:00 pm 
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Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1894
Location: Lethbridge, Alberta, Canada
Puzzle rating table, with links to archive entries; each of these has a link to the puzzle thread.

Abbreviations used in Rating Table:
Est = Estimated rating by puzzle maker
Other = Puzzle posted from another site and/or newspaper
E = Easy
H = Hard
SS Score = SudokuSolver score, rounded to nearest 0.05; there are two columns, one for v3.3.1 and the second for v3.5.7.
In the v3.3.1 column these are the scores posted by the puzzle maker in the puzzle thread and/or in the
Assassin Schedule thread, except where indicated by * when I calculated the score using SS.
Thanks Ed for calculating the v3.5.7 scores.
+-------------------------------+-----------+---------+----------+----------+
| Puzzle | Made By | Rating | SS Score | SS Score |
| | | Andrew | v3.3.1 | v3.5.7 |
+-------------------------------+-----------+---------+----------+----------+
| Assassin 203 | Ed | 1.50 | *1.60 | 1.45 |
| Paper Solvable 5 | HATMAN | 1.25 | | |
| Weekly No.256 @ KSO | Other | H1.25 | *1.45 | 1.30 |
| Assassin 204 | Ed | 1.50 | *2.00 | 1.70 |
| Assassin 205 | Ed | 1.50 | *1.55 | 1.40 |
| Assassin 206 | Ed | E1.50 | *1.60 | 1.55 |
| Assassin 207 | Ed | H1.50 | *1.70 | 1.55 |
| Assassin 208 | Ed | E1.50 | *1.85 | 1.65 |
| Assassin 209 | Ed | E1.25 | *1.30 | 1.25 |
+-------------------------------+-----------+---------+----------+----------+


Some of the selected quotes in the puzzle entries have been edited to remove "spoilers"; the full rating comments are included with the walkthroughs. In some cases the puzzle makers gave hints; these are included in tiny text in the selected quotes.


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PostPosted: Wed Feb 27, 2013 11:03 pm 
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Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1894
Location: Lethbridge, Alberta, Canada
Assassin 203 by Ed (November 2010) here
Puzzle Diagrams with "udosuk style Killer Cages":
Image     Image

Note: this is an X-killer...1-9 cannot repeat on the diagonals.
Code: Select, Copy & Paste into solver:
3x3:d:k:2817:2817:2050:4099:4868:7429:774:4615:2312:3849:3849:2050:4099:4868:7429:774:4615:2312:4618:6411:5388:4099:4868:7429:7429:4615:3865:6414:4618:6411:5388:4868:7429:7439:3865:3096:6414:6414:4618:6411:5388:7439:3865:3096:5649:6414:4618:6411:5388:7439:3098:3096:5649:5649:4618:6411:5388:3602:3603:7439:3098:2061:5649:2068:2068:3861:3602:3603:3603:7439:4118:2061:1559:1559:3861:3602:4368:4368:4368:4118:4118:
Solution:
+-------+-------+-------+
| 3 8 1 | 9 7 5 | 2 4 6 |
| 6 9 7 | 4 8 2 | 1 5 3 |
| 2 5 4 | 3 1 6 | 7 9 8 |
+-------+-------+-------+
| 7 4 2 | 6 3 9 | 8 1 5 |
| 9 1 5 | 8 2 4 | 6 3 7 |
| 8 6 3 | 1 5 7 | 4 2 9 |
+-------+-------+-------+
| 1 7 8 | 2 9 3 | 5 6 4 |
| 5 3 6 | 7 4 1 | 9 8 2 |
| 4 2 9 | 5 6 8 | 3 7 1 |
+-------+-------+-------+
Quote:
In a PM about making this pic Børge: Very difficult to colour

Ed: Assassin 203 [edit to correct number! :oops: ]
Thanks to Børge for the pics.
and those annoying diagonal cages also make for a very hard puzzle. Takes me a really unusual move (but NOT complicated) which my optimised walk-through gets on step 12...but then many more steps to get it fully cracked. This cage structure ended up quite non-symetrical to get a nice balance between progress and stuckness.

Andrew: Thanks Ed for an interesting and fun Assassin!
Yes, it was certainly difficult to colour. I managed to do it with 4 colours but then added a 5th colour for one cage, which made the cage pattern a lot clearer to work with.
I've no idea whether I found Ed's unusual step. A few of my steps were interesting and unusual.
Rating Comment. I'll rate my walkthrough for A203 at 1.5.

Ed:
Andrew wrote:
I've no idea whether I found Ed's unusual step
Your step 21 (my step 12). Thanks to Andrew for posting a really nice walk-through. Love the rating! Here's my optimised walk-through which basically follows Andrew's way but without his step 9. Unusual for Andrew and I to follow the same path so perhaps it's the only one.

Walkthrough by Andrew:
Thanks Ed for an interesting and fun Assassin!

Yes, it was certainly difficult to colour. I managed to do it with 4 colours but then added a 5th colour for one cage, which made the cage pattern a lot clearer to work with.

I've no idea whether I found Ed's unusual step. A few of my steps were interesting and unusual.

Here is my walkthrough for A203. While checking it, I found a flaw in one step but I've retained a comment about it because it would have been an interesting step. Fortunately I didn't need to do much re-work to get back to my original solving path. I've added two comments, one prompted by Ed's feedback; thanks Ed.

Prelims

a) R1C12 = {29/38/47/56}, no 1
b) R12C3 = {17/26/35}, no 4,8,9
c) R12C7 = {12}
d) R12C9 = {18/27/36/45}, no 9
e) R2C12 = {69/78}
f) 12(2) cage at R6C6 = {39/48/57}, no 1,2,6
g) 8(2) cage at R7C8 = {17/26/35}, no 4,8,9
h) R8C12 = {17/26/35}, no 4,8,9
i) R89C3 = {69/78}
j) R9C12 = {15/24}
k) 18(5) cage at R3C1 = {12348/12357/12456}, no 9

Steps resulting from Prelims
1a. Naked pair {12} in R12C7, locked for C7 and N3, clean-up: no 7,8 in R12C9
1b. 18(5) cage at R3C1 = {12348/12357/12456}, CPE no 1,2 in R456C1

2. 45 rule on N1 3 innies R3C123 = 11 = {128/137/146/236/245}, no 9

3. 45 rule on N3 2 innies R3C79 = 15 = {69/78}

4. 45 rule on N8 1 innie R7C6 = 1 outie R9C7, no 1,2 in R7C6

5. 9 in N1 only in R1C12 = {29} or R2C12 = {69} -> R1C12 = {29/38/47} (cannot be {56}, locking-out cages), no 5,6
5a. R12C3 = {17/35} (cannot be {26}, locking cages), no 2,6
5b. R3C123 (step 2) = {128/146/245} (cannot be {236}, locking cages, cannot be {137} which clashes with R12C3), no 3,7

6. R8C12 = {17/26/35}, R9C12 = {15/24} -> combined cage R89C12 = {17}{24}/{26}{15}}/{35}{24}, 2 locked for N7

7. 45 rule on C89 2 outies R56C7 = 10 = {37/46}, no 5,8,9

8. 12(3) cage in N6 cannot contain 2 (because 2+10(2) clashes with R56C7=10, CCC)
8a. 12(3) cage = {138/147/156/345}, no 9
8b. 6 of {156} must be in R6C7 -> no 6 in R4C9 + R5C8

9. 15(3) cage at R3C9 = {168/249/267/348/357/456} (cannot be {159/258} because R5C7 only contains 3,4,6,7)
9a. 1,2 of {168/249/267} must be in R4C8, 5 of {357/456} must be in R4C8, 8 of {348} must be in R3C9 -> no 6,7,8,9 in R4C8
[I first saw those eliminations as Min R3C9 + R5C7 = 9 -> max R4C8 = 5 because 15(3) cage cannot be [663], however I’ve listed the combinations because I’m now going to look at one of them.]
9b. 15(3) cage cannot be {249} = [924] because R3C79 = [69] (step 3) clashes with R56C7 = [46] (step 7)
-> 15(3) cage = {168/267/348/357/456}, no 9, clean-up: no 6 in R3C7 (step 3)
9c. 4 of {348/456} must be in R5C7 (15(3) cage = {348} cannot be [843] because R3C79 = [78] (step 3) clashes with R56C7 = [37], step 7) -> no 4 in R4C8
[I realised later that the analysis parts of steps 9b and 9c can be seen more clearly as
R3C79 = hidden 15(2) cage, R56C7 = hidden 10(2) cage -> R3C9 cannot be 5 more than R5C7. It’s a long time since I’ve used that sort of logic in a walkthrough.]

10. 45 rule on N2 3(2+1) outies R3C7 + R4C56 = 19
10a. Max R3C7 + R4C6 = 17 -> min R4C5 = 2

11. 45 rule on C1234 1 outie R5C5 = 2, placed for both diagonals, clean-up: no 9 in R1C2, no 6 in R8C1, no 4 in R9C2
[I ought to have spotted this 45 a lot sooner. I also found step 7 hard to spot.]

12. Caged X-Wing for 2 in 18(5) cage at R3C1 (2 only in R3C1 + R46C2) and combined cage R89C12 (step 6), no other 2 in C12, clean-up: no 9 in R1C1
[That’s what I saw. Much simpler, as Ed pointed out, is 2 in C3 only in R46C3, locked for 25(5) cage at R3C2, no 2 in R3C2. Then 2 in 18(5) cage at R3C1 only in R3C1.]
13. R3C1 = 2 (hidden single in N1), clean-up: no 6 in R8C2

14. 9 in N1 only in R2C12 = {69}, locked for R2 and N1, clean-up: no 3 in R1C9

15. R9C2 = 2 (hidden single in N7), R9C1 = 4, placed for D/, clean-up: no 7 in R1C2, no 5 in R2C9, no 4 in R7C6 (step 4)

16. 1 in C1 only in R78C1, locked for N7, clean-up: no 7 in R8C1

17. 1 on D/ only in R4C6 + R6C4, locked for N5

18. 45 rule on N7 3 innies R7C123 = 16 = {169/178/358} (cannot be {367} which clashes with R89C3)
18a. 1 of {169/178} must be in R7C1 -> no 6,7 in R7C1

19. 18(5) cage at R3C1 = {12348/12357/12456}
19a. 25(4) cage in N4 = {1789/3589/3679/4579} (cannot be {4678} because R456C1 are common peers of the 18(5) cage so cannot be {678}), 9 locked for N4
19b. 1,4 of {1789/4579} must be in R5C2, 6 or 9 of {3679} must be in R5C2 (R456C1 cannot be {369/679} which clash with R2C1) -> no 7 in R5C2

20. 45 rule on N4 2 remaining innies R46C3 = 1 outie R7C1 + 4 and R46C3 must contain 2
20a. Max R46C3 = 10 -> no 8 in R7C1
20b. R7C1 = {135} -> R46C3 = 5,7,9 = {23/25/27}, no 1,4,6,8

21. R12C3 = {17/35}, R46C3 (step 20b) = {23/25/27} -> variable combined cage R1246C3 = {17}{23}/{17/25}/{35}{27}, 7 locked for C3, clean-up: no 8 in R89C3

22. Naked pair {69} in R89C3, locked for C3 and N7

23. 8 in N7 only in R7C23, locked for R7, clean-up: no 4 in R6C6, clean-up: no 8 in R9C7 (step 4)

24. Variable hidden killer pair 4,8 in 18(5) cage at R3C1 and 25(4) cage in N4, 25(4) cage (step 19a) cannot contain both of 4,8 -> 18(5) cage must contain at least one of 4,8 -> 18(5) cage at R3C1 = {12348/12456}, no 7, 4 locked for N4

Original step 25 deleted. Here I thought I’d deleted 6 from the 16(3) cage in N9. I thought that I’d eliminated {169} because of clashes with R2C2 using D\ or with R9C3 but later realised that R89C8 can still be {69}; {367} clashes with the 8(2) cage.
I’ve rearranged the next few steps to get back to my original solving path.

25. 45 rule on N6 2 outies R37C9 = 1 innie R4C7 + 4
25a. Max R37C9 = 13, min R3C9 = 6 -> max R7C9 = 7

26. 17(3) cage at R9C5 = {179/359/368}
26a. Killer pair 6,9 in R9C3 and 17(3) cage, locked for R9

27. 16(3) cage in N9 = {178/358/457} (cannot be {169/349} because 4,6,9 only in R8C8, cannot be {367} which clashes with the 8(2) cage), no 6,9

28. 6 on D\ only in R2C2 + R4C4, CPE no 6 in R4C2
28a. 18(5) cage at R3C1 (step 24) = {12348/12456}
28b. 6 of {12456} must be in R6C2 -> no 5 in R6C2

[Now I’m back to my original solving path.]

29. 9 in N9 only in R789C7, locked for C7, clean-up: no 6 in R3C9 (step 3)
29a. 9 in N3 only in R13C8, locked for C8
29b. R3C7 + R4C56 = 19 (step 10)
29c. Max R3C7 + R4C5 = 17 -> no 1 in R4C6

30. Naked pair {78} in R3C79, locked for R3 and N3, CPE no 7 in R5C7, clean-up: no 1 in R3C23 (step 5b)
30a. Naked pair {45} in R3C23, locked for R3 and N1, CPE no 5 in R46C3, clean-up: no 7 in R1C1, no 3 in R12C3
30b. Naked pair {38} in R1C12, locked for R1
30c. Naked pair {17} in R12C3, locked for C3
30d. 1 in R3 only in R3C456, locked for N2
[I added the CPE to step 30a later. That’s why I didn’t use the naked pair in R46C3 next. The next three steps, before I used the naked pair, are very powerful.]

31. 18(3) cage in N3 = {369/459}
31a. R2C8 = {35} -> no 5 in R1C8, no 3 in R3C8

32. 3 in N3 only in R2C89, locked for R2
32a. 5 in N5 only in R1C9 + R2C8, locked for D/, clean-up: no 3 in R8C1

33. Naked triple {378} in R3C7 + R7C3 + R8C2, locked for D/, 3 also locked for N7 -> R2C8 = 5, R1C9 = 6, placed for D/, R13C8 = [49], R2C9 = 3, R4C6 = 9, R6C4 = 1, clean-up: no 3 in R7C7, no 2 in R7C8, no 9 in R9C7 (step 4)

34. Naked pair {23} in R46C3, locked for C3, N4 and 25(5) cage at R3C2, no 3 in R5C4 -> R7C3 = 8, placed for D/, R3C7 = 7, placed for D/, R3C9 = 8, R8C2 = 3, R8C1 = 5, R7C12 = [17], R1C2 = 8, R1C1 = 3, placed for D\, clean-up: no 5 in R6C6, no 9 in R7C7, no 3 in R7C8, no 1,7 in R8C9

35. 8(2) cage at R7C8 = [62]

36. Naked pair {45} in R4C2 + R5C3, locked for N4 -> R6C2 = 6, R2C2 = [69], R5C2 = 1

37. R46C3 = {23} = 5, R7C2 = 7 -> R3C2 + R5C4 = 13 = [58], R3C3 = 4, placed for D\, R6C6 = 7, placed for D\, R7C7 = 5, placed for D\

and the rest is naked singles.

Rating Comment. I'll rate my walkthrough for A203 at 1.5. It was hard to know what rating to give some steps. It might be argued that steps 9b and 9c ought to be rated a bit higher but, since I'm not sure whether they are necessary for the solving path, I've done my rating on the rest of my walkthrough.
Walkthrough by Ed:
Andrew wrote:
I've no idea whether I found Ed's unusual step
Your step 21 (my step 12). Thanks to Andrew for posting a really nice walk-through. Love the rating! Here's my optimised walk-through which basically follows Andrew's way but without his step 9. Unusual for Andrew and I to follow the same path so perhaps it's the only one. Thanks Andrew for some corrections and additions.

A203 WT 25 steps

Prelims
i. 11(2)n1: no 1
ii. 8(2)n1: no 4,8,9
iii. 3(2)n3 = {12}
iv. 9(2)n3: no 9
v. 15(2)n1 = {69/78}
vi. 18(5)n1: no 9
vii. 12(2)n5: no 1,2,6
viii. 8(2)n9: no 4,8,9
ix. 8(2)n7: no 4,8,9
x. 15(2)n7 = {69/78}
xi. 6(2)n7 = {15/24}

1. "45" on c1234: 1 outie r5c5 = 2: placed for both diagonals
1a. no 9 in r1c2
1b. no 7 in r2c9
1c. no 6 in r8c1
1d. no 4 in r9c2

2. 3(2)n3 = {12}: both locked for c7 & n3
2a. no 7,8 in 9(2)n3

3. "45" on n1: 3 innies r3c123 = 11 (no 9)

4. 9 in n1 in 11(2) = {29} or 15(2) = {69} = [2/6..]
4a. -> {26} blocked from 8(2)n1 (no 2,6)
(note: Andrew pointed out this same move also blocks {56} from the 11(2) using Locking-out cages. Love those.)


5. 2 in c3 only in r46c3: locked for n4 and not elsewhere in 25(5)n1

6. 18(5)n1 = {1248/12357/12456}
6a. must have 1 and 2 -> 2 locked for c1
6b. no 1 in r456c1 since they see all 1 in 18(5)
6c. no 6 in r8c2

7. 8(2)n7 = {17/35} = [1/5..]
7a. -> {15} blocked from 6(2)n7
7b. -> 6(2) = [42]: 4 placed for D/
7c. no 9 in r1c1
7d. no 7 in r1c2
7e. no 5 in r2c9

8. r3c1 = 2 (hsingle c1)

9. 1 in c1 only in n7: locked for n7
9a. no 7 in r8c1

10. "45" on n4: 2 innies r46c3 (must have 2) - 4 = 1 remaining outie r7c1
10a. since 2 is locked at one of r46c3 -> the other innie - 2 = r71
10b. ->no 1,4,6 in r46c3; no 8 in r7c1

11. r46c3 sees all 8 & 9 in n7 -> no 8,9 (CPE)
11a. no 6,7 in r7c1 (step 10a)
11b. from step 10a, r46c3 = [2]{3/5/7} (important for next step)

The key step
12. 8(2)n1 = {17/35} and r46c3 has 3/5/7
12a. -> 7 locked for c3

13. 15(2)n7 = {69}: both locked for c3 & n7

14. 17(3)n8 = {179/359/368} = [6/9..]
14a. Killer pair 6,9 with r9c3: both locked for r9

15. "45" on n3: 2 innies r3c79 = 15 (no 3,4,5)

16. "45" on n6: 2 outies r37c9 - 4 = 1 innie r4c7
16a. max. r4c7 = 9 -> max. r37c9 = 13 (no 8,9 in r7c9)

17. 16(3)n9; {169/349} blocked since r8c8 is the only cell with (469)
17a. -> no 9 in 16(3)

18. 9 in n9 only in c7: locked for c7
18a. no 6 in r3c9 (h15(2)r3c79)

19. "45" on n2: 3 outies r3c7+r4c56 = 19
19a. max. any two outies = 17 -> no 1

20. r6c4 = 1 (hsingle D/)

21. 9 in n1 only in 15(2) = {69} only: both locked for r2 and n1
21a. no 5 in 11(2)n1
21b. no 3 in r1c9

22. r4c6 = 9 (hsingle D/)
22a. no 3 in r7c7

23. "45" on c4: 2 remaining innies r45c4 = 14 = {68} only: both locked for c4 and n5
23a. no 4 in r7c7

24. 1 in D\ only in n9 in 16(3) = {178} only: all locked for n9, no 1 in r9c8
24a. no 4,5 in r6c6

25. naked quad 1,3,7,8 in D\ in r1c1, r6c6, r8c8, r9c9: locked for D\
25a. r4c4 = 6


Much easier now.


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PostPosted: Fri Apr 26, 2013 2:51 am 
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Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1894
Location: Lethbridge, Alberta, Canada
Paper Solvable 5 Zero X Killer by HATMAN (November 2010) here
Puzzle Diagram:
Image
Diagrams with "udosuk style Killer Cages" by Børge:
Image     Image
Code: Select, Copy & Paste into solver:
3x3:d:k:1:3078:3078:5135:18:19:3333:3333:4:3078:1:5135:5135:20:21:22:4:3333:3078:23:1:1:5898:4:4:5134:3333:24:25:1:5898:4361:3852:4:5134:5134:26:27:5898:2827:4361:3852:3852:2321:2321:28:29:2:2827:4361:30:3:5389:5389:3336:31:2:2:32:3:3:5389:3079:3336:2:5136:5136:33:34:35:3:3079:2:3336:3336:5136:36:37:3079:3079:3:
Note that this code doesn't generate the zero cages
Solution:
+-------+-------+-------+
| 8 4 2 | 9 5 7 | 3 1 6 |
| 1 9 7 | 4 6 3 | 8 2 5 |
| 5 6 3 | 2 8 1 | 7 9 4 |
+-------+-------+-------+
| 7 2 1 | 6 9 4 | 5 3 8 |
| 4 8 9 | 3 1 5 | 6 7 2 |
| 3 5 6 | 8 7 2 | 1 4 9 |
+-------+-------+-------+
| 6 7 5 | 1 2 9 | 4 8 3 |
| 2 3 8 | 7 4 6 | 9 5 1 |
| 9 1 4 | 5 3 8 | 2 6 7 |
+-------+-------+-------+
Quote:
HATMAN: This has both types of zero: areas with no cages and cages with no sum.
I do not know how to enter zero cages into SudokuSolver so I am unsure of the score, but I have managed it on paper.

Andrew: Thanks HATMAN for another fun puzzle. :D Cages without totals are an interesting concept! They proved useful in the later stages of my solving path.
I solved it by elimination solving although many of the steps are essentially paper solvable ones; for example step 2 since the follow-ups from Prelims (in step 1) can be easily visualised. Also I think that steps 7 and 11 are essentially paper solvable, and also human solvable, steps.
I was going to use one 45 but then spotted the clash in step 16 and found that the 45 wasn't needed.
Rating Comment. I'll rate my walkthrough for A203 at 1.25.

HATMAN: I think cages without totals were started a couple of years ago by Mike-Japan (another lost voice).
Note that your definition of paper-solvable is higher than mine, I'm looking for around 0.75 but definitely below 1.0. Of course we all see different things in a puzzle and I know by know that my "vision" is somewhat different to others.

Apologies for not responding to your PM, I was in Nigeria and workload (for once positive) prevented me checking in regularly.
For the corner lace with Windoku r1c2=r2c4, r2c1= r4c2 and r1c5r5c1 = r2c3r3c2 with these relationships in place both of the lace practice ones rattle out.

Andrew: Thanks for those comments.
Assuming that you are referring to the same cage interactions as I did in my rating comment, I think that steps can be Paper Solvable and still rated higher than 1.0. The interactions in my steps 7 and 11 were definitely paper solvable ones. I assume that they were the key steps for this puzzle. If there was something easier which I missed, I'd be interested to know.

Thanks also for the comments about the Lace Windokus. I've also had helpful discussions about those with Ed and Simon by PM. Thanks guys.

simon_blow_snow: To me, "Paper Solvable" means you can solve it without using any pencilmarks. When I went through Andrew's walkthrough (briefly), I really could not see how a player can follow it without listing out the pencilmarks.
Below I will include a walkthrough, which I think one can follow it without listing pencilmarks. However one may need to jot down some (very few) small notes on the side to keep track of some tiny details.
I would urge the readers to try to follow this walkthrough by actually create a blank 9x9 grid on paper (you can draw it by hand if you don't want to use the printer), and try to fill in the 81 cells one by one while following this walkthrough. You can also have the image of this puzzle on the computer screen as a reference.
Please don't list any pencilmark, and if you find any particular gap in the walkthrough that needs more elaboration, please do post a comment, I will try to fill in the gap.
Note that when solving without pencilmarks it is not very often to use naked singles or subsets. In the puzzle I just used one naked single, which should be easy to spot on paper at that stage.
Also I used a lot of cage sums min-max analysis, which I believe HATMAN would consider appropriate as a Paper Solving techniques because the cage sums are all we have recorded on the grid when solving without pencilmarks.

Andrew: Well done Simon for posting a genuinely "Paper Solvable" walkthrough. I assume that steps where one combination is listed for a cage are written as notes outside the grid, what I call pencilmarks (see below), and only actual placements are written in the cells of the grid.
I liked the 3rd line of step 3. I wish I'd spotted that step; it would have simplified my solving path a bit.
Further Rating Comment. After going through Simon's walkthrough, I'll stick to my rating for this puzzle. While steps like minmax, must include and don't include are technically simpler, in my opinion the way that step 5a (for example) builds up a long chain of must include and don't include is at least a 1.25 step.
I'm inclined to think that this puzzle is easier to solve by elimination solving, but not a lot easier.
Simon wrote:
To me, "Paper Solvable" means you can solve it without using any pencilmarks. When I went through Andrew's walkthrough (briefly), I really could not see how a player can follow it without listing out the pencilmarks.
I take a broader view of "Paper Solvable". While it means that it can be solved without using pencilmarks (in your use of that term) I take it as meaning an easier puzzle which can be solved that way if one wishes. I use a sort of "paper solvable" approach on another sudoku site although not as rigorously as in Simon's walkthrough.
If HATMAN, or anyone else posting "Paper Solvable" puzzles, would prefer that they should only be solved that way then I'll limit myself to brief posts about them, without a walkthrough, unless I'm able to find a "paper solvable" solving path.

BTW How did the term pencilmarks become a word meaning some/all candidates written in the cells of a sudoku grid? Candidates seems to me a much more appropriate term. When I first saw the phrase pencilmarks I assumed it referred to notes written outside the grid; I was therefore very surprised when I later discovered that many people use it to mean candidates.
Also how did the term player get introduced in the context of sudokus? In my opinion solver is far more appropriate for sudukos, crossword puzzles, etc. Player implies playing, either individually or in a team, against opponent(s). I consider myself to be a solver so I trust that nobody will ever refer to me as a player.

simon_blow_snow: I think the term "pencilmark" originated from the Sudoku Players' Forum, used to be in http://www.sudoku.com and now in http://forum.enjoysudoku.com. Obviously the term "players" also came from there. Other similar forums such as the Sudoku Programmers Forum (in http://www.setbb.com) and another one (which no longer exists) used to have a certain group of common visitors, and they helped formulate a "standard terminology" in various places.

HATMAN: Simon
I started these Paper Solvable for interesting puzzles that I can do on paper (including pencil-marks, but hopefully minimal). I am rather messy and for harder puzzles I have to do them on spreadsheet (developed on Udosuk's basis) or on JSudoku.
For stronger solvers doing them without pencilmarks (Andrew note the sale of pencils with rubbers has jumped manifold since the re-introduction of Sudoku to the English speaking world) seems eminently sensible.

Andrew
A few posts ago I talked of using dots and dashes as pencilmarks but did not make myself fully clear. The approach is to only partially mark-up and works well with non-consecutive or anti-chess. When you derive non-obvious placement possibilities: put dots. When you derive non-obvious placement eliminations: put dashes.

I'm just back in England for a few days awaiting my Nigerian visa. As you can imagine I am not enjoying the cold, however yesterday I had the pleasure of going to my grandson's second birthday. The difficulty was that I had to drive from London to Leeds and back which in snowstorms on English roads was not a pleasure. Tonight I go back to Africa; thankfully.
Maurice

Walkthrough by Andrew:
Thanks HATMAN for another fun puzzle. :D Cages without totals are an interesting concept! They proved useful in the later stages of my solving path.

I solved it by elimination solving although many of the steps are essentially paper solvable ones; for example step 2 since the follow-ups from Prelims (in step 1) can be easily visualised. Also I think that steps 7 and 11 are essentially paper solvable, and also human solvable, steps.

I was going to use one 45 but then spotted the clash in step 16 and found that the 45 wasn't needed.

Here is my walkthrough

Prelims

a) R56C4 = {29/38/47/56}, no 1
b) R5C89 = {18/27/36/45}, no 9
c) 20(3) cage at R1C4 = {389/479/569/578}, no 1,2
d) 23(3) cage at R3C5 = {689}
e) 20(3) cage at R3C8 = {389/479/569/578}, no 1,2
f) 21(3) cage at R6C8 = {489/579/678}, no 1,2,3
g) 20(3) cage at R8C3 = {389/479/569/578}, no 1,2
h) 12(4) cage in N1 = {1236/1245}, no 7,8,9
i) 13(4) cage in N3 = {1237/1246/1345}, no 8,9
j) 13(4) cage in N7 = {1237/1246/1345}, no 8,9
k) 12(4) cage in N9 = {1236/1245}, no 7,8,9

Steps resulting from Prelims
1a. 12(4) cage in N1 = {1236/1245}, 1,2 locked for N1
1b. 13(4) cage in N3 = {1237/1246/1345}, 1 locked for N3
1c. 23(3) cage at R3C5 = {689}, CPE no 6,8,9 in R3C3 (using D\) + R5C5
1d. 13(4) cage in N7 = {1237/1246/1345}, 1 locked for N7
1e. 12(4) cage in N9 = {1236/1245}, 1,2 locked for N9

2. R5C5 + R6C6 = {12} (hidden pair on D\), locked for N5, clean-up: no 9 in R56C4
2a. R5C5 = 1 (hidden single on D/), R6C6 = 2, clean-up: no 8 in R5C89

3. R5C5 = 1 -> 17(3) cage at R4C5 = {179}, locked for C5 and N5, clean-up: no 4 in R56C4
3a. Killer pair 6,8 in R4C4 and R56C4, locked for C4 and N5

4. 4 in N5 only in R45C6, locked for C6
4a. 15(3) cage at R4C6 = {348/456} -> R5C7 = {68}

5. R5C3 = 9 (hidden single in 23(3) cage at R3C5

6. R37C4 = {12} (hidden pair in C4)
6a. 1 in N6 only in R46C7, locked for C7

7. 20(3) cage at R1C4 and 20(3) cage at R8C3 can only contain one 8 in C3 and one 9 in C4 -> both 20(3) cages = {479/569/578}, no 3, 8 locked in R28C3 for C3

8. 3 in C4 only in R56C4 = {38}, locked for C4 and N5 -> R4C4 = 6, placed for D\, R3C5 = 8

9. Naked pair {45} in R45C6, locked for C6, R5C7 = 6 (step 4a), clean-up: no 3 in R5C89

10. R5C89 = {27} (cannot be {45} which clashes with R5C6), locked for R5 and N6

[Returning to the 20(3) cages at R1C4 and R8C3.]
11. One of the 20(3) cages must contain 4 for C4 and the other must contain 8 for C3 -> 20(3) cages at R1C4 and R8C3 (step 7) = {479/578}, no 6 in R28C3, CPE no 7 in R2C6, no 7 in R8C6
11a. 4 of the cage containing {479} must be in C4 -> no 4 in R28C3
11b. 8 of the cage containing {578} must be in C3 -> no 5 in R28C3
11c. Naked pair {78} in R28C3, locked for C3

12. 21(3) cage at R6C8 = {489/579} (cannot be {678} because 6,7 only in R7C8), no 6, CPE no 9 in R4C8
12a. 7 of {579} must be in R7C8 -> no 5 in R7C8

13. 6 in N9 only in 12(4) cage = {1236}, locked for N9

14. 3 on D\ only in R1C1 + R2C2 + R3C3, locked for N1
14a. 12(4) cage in N1 = {1245} (only remaining combination), locked for N1 -> R3C3 = 3

15. R3C2 = 6 (hidden single in N1)
15a. 9 in N1 only in R1C1 + R2C2, locked for D\
15b. 4,5 on D\ only in R7C7 + R8C8 + R9C9, locked for N9

16. 20(3) cage at R3C8 = {389/578} (cannot be {479} = [749] which clashes with 21(3) cage at R6C8), no 4, 8 locked for R4 and N6
16a. 9 of {389} must be in R3C8, 7 of {578} must be in R3C8 -> R3C8 = {79}

17. 21(3) cage at R6C8 (step 12) = {489/579}
17a. 7,8 only in R7C8 -> R7C8 = {78}
17b. 9 locked for R6 and N6 -> R6C5 = 7, R4C5 = 9

18. R8C7 = 9 (hidden single in N9)

19. 9 in R3 only in R3C68, CPE no 9 in R1C9 + R2C8

20. R3C8 = 9 (hidden single in N3)
20a. 20(3) cage at R3C8 (step 16) = {389} (only remaining combination), 3,8 locked for R4 and N6

21. R6C9 = 9 (hidden single in N6)
21a. R9C1 = 9 (hidden single on D/)

22. 20(3) cage at R8C3 (step 11) = {578} (only remaining combination) -> R8C3 = 8, R89C4 = {57}, locked for C4 and N8, R2C3 = 7, R1C1 = 8, placed for D\, R2C2 = 9, R2C4 = 4, R1C4 = 9

23. R7C8 = 8 (hidden single in N9), R6C8 = 4 (step 12), R4C89 = [38]

24. Naked triple {457} in R7C7 + R8C8 + R9C9, locked for cage at R6C7 -> R6C7 = 1, R4C7 = 5, R4C6 = 4, placed for D/, R5C6 = 5

25. 5 in N3 only in 13(4) cage = {1345} (only remaining combination), locked for N3

26. Naked triple {267} in R1C9 + R2C8 + R3C7, locked for D/, N3 and cage at R1C9 -> R2C7 = 8, R3C6 = 1

and the rest is naked singles, without needing to use diagonals.

Rating Comment. I'll rate Paper Solvable 5 Zero-X at 1.25. I think steps 7 and 11 deserve that rating, as does the clash in step 16.
Walkthrough by simon_blow_snow:
To me, "Paper Solvable" means you can solve it without using any pencilmarks. When I went through Andrew's walkthrough (briefly), I really could not see how a player can follow it without listing out the pencilmarks.

Below I will include a walkthrough, which I think one can follow it without listing pencilmarks. However one may need to jot down some (very few) small notes on the side to keep track of some tiny details.

I would urge the readers to try to follow this walkthrough by actually create a blank 9x9 grid on paper (you can draw it by hand if you don't want to use the printer), and try to fill in the 81 cells one by one while following this walkthrough. You can also have the image of this puzzle on the computer screen as a reference.

Please don't list any pencilmark, and if you find any particular gap in the walkthrough that needs more elaboration, please do post a comment, I will try to fill in the gap.

Here is my walkthrough (9 steps with a big step 5)

1:
{1} of N19 locked in 12(4) cages
{1} of N37 locked in 13(4) cages
--> N5 must include 1 of D\,D/ --> R5C5=1

2:
17(3): R46C5 =17-1 =16 ={79}
--> 23(3)={689} with 9 only possible in R5C3
--> R5C3=9, R3C5+R4C4={68}
{2} of N19 locked in 12(4) cages
--> Hidden single D\: R6C6=2

3:
20(3) cages cannot include {12}
Hidden pair C4: R37C4={12}
Outies C4: R28C3+R3C5 =20+23+11+20+1+2-45-9 =23 =7+8+8
--> R28C3={78}, R3C5=8 --> R4C4=6

4:
Innies N5: R45C6=9={45} --> 15(3): R5C7 =15-4-5 =6
--> 9(2)<>{18/36/45}, ={27}
--> 21(3): R7C8<>{6} (R6C89<>{78})
--> 12(4) in N9 must include {6} of N9, ={1236}
--> D\123 must include {3} of D\
--> 12(4) in N1={1245}
Hidden single N1: R3C2=6

5a:
D\12 must include {9} of N1
--> D\789, R3C134<>{9}
13(4) cages cannot include {9}
--> R3C678 must include {9} of R3
--> D/12<>{9}
--> R46C9 must include {9} of C9
--> R46C8<>{9}
--> R37C8 must include {9} of C8

5b:
20(3)+21(3) of C89: R37C8+R46C89 =20+21 =41
R46C89 must come from {134589} (R5C789={267})
max R37C8 =8+9 =17 --> min R46C89 =41-17 =24
--> R46C89<>{1} (or max =1+5+8+9 =23<24)
max R46C89 =4+5+8+9 =26 --> min R37C8 =41-26 =15
But R37C8<>{6} and must include {9}
--> R37C8<>15 --> min R37C8=16 --> max R46C89 =41-16 =25
--> R46C89 must include {3} (or min =4+5+8+9 =26>25)

5c:
But 21(3) cannot include {3} --> R4C89 must include {3}
--> R3C8 20(3)={389} --> R3C8<>{38}, =9
Hidden single C9: R6C9=9 --> 17(3)=[917]
Hidden single N9: R8C7=9
Hidden single D/: R9C1=9
Hidden single N1: R2C2=9
Hidden single N8: R7C6=9
Hidden single N2: R1C4=9

6:
11(2)={38} --> R1C4 20(3)<>{389/569}, ={479}
--> R2C34=[74] --> D\13=[83], R8C3=8
Hidden single N9: R7C8=8 --> 21(3)=[498]
--> R3C8 20(3)=[938]
Hidden single N3: R2C7=8
Hidden single D/: R6C4=8 --> 11(2)=[38]
Hidden singles N48: R5C2=R9C6=8

7:
D\789={457} --> R6C7<>{5}
Hidden singles N6: R46C7=[51] --> 15(3)=[456]
Hidden single N4: R5C1=4
Hidden single R3: R3C9=4
Hidden singles D\,R8: R7C7=R8C5=4

8:
Innies N3: D/123=15<>{14589}={267} --> D/78=[53]
--> R6C123=[356]
Innies N7: R7C2=7
Hidden single N4: R4C1=7

9:
R3C6=1 (only possibility) --> R37C4=[21]
--> R3C17=[57], R4C23=[21]
Hidden single N2: R1C6=7 --> R28C6=[36]
Hidden singles N3: R1C7=3 --> R9C7=2
--> N7 13(4)=[6214] --> N9 12(4)=[3126] --> N3 13(4)=[3154]
--> N1 12(4)=[4215], R1279C5=[5623], D/12=[62]
--> 9(2)=[72], D\89=[57] --> R8C3 20(3)=[875]

(Typos corrected thanks to Andrew)

(Revised step 5b for better min-max analysis)

Note that when solving without pencilmarks it is not very often to use naked singles or subsets. In the puzzle I just used one naked single, which should be easy to spot on paper at that stage.

Also I used a lot of cage sums min-max analysis, which I believe HATMAN would consider appropriate as a Paper Solving techniques because the cage sums are all we have recorded on the grid when solving without pencilmarks.


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PostPosted: Fri Apr 26, 2013 2:54 am 
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Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1894
Location: Lethbridge, Alberta, Canada
Weekly No.256 @ KSO posted by herschko (December 2010) here
Puzzle Diagrams with "udosuk style Killer Cages" by Børge:
Image     Image
Code: Select, Copy & Paste into solver:
3x3::k:4609:4609:4609:3074:2563:7172:7172:7172:5381:8710:3074:3074:3074:2563:7172:7172:5381:5381:8710:8710:8967:1800:1800:7172:3593:5381:8714:8710:8710:8967:1803:1803:7948:3593:8714:8714:8710:8967:8967:7948:7948:7948:8714:8714:8461:8967:8967:4110:7948:1807:1807:8714:8461:8461:8967:4368:4110:7441:2066:2066:8714:8461:8461:4368:4368:7441:7441:3091:4372:4372:4372:8461:4368:7441:7441:7441:3091:4372:3861:3861:3861:
Solution:
+-------+-------+-------+
| 4 6 8 | 5 7 9 | 1 3 2 |
| 7 1 2 | 4 3 8 | 5 6 9 |
| 5 9 3 | 6 1 2 | 8 4 7 |
+-------+-------+-------+
| 3 4 1 | 2 5 7 | 6 9 8 |
| 6 7 5 | 8 9 4 | 2 1 3 |
| 2 8 9 | 3 6 1 | 4 7 5 |
+-------+-------+-------+
| 9 5 7 | 1 2 6 | 3 8 4 |
| 1 3 4 | 9 8 5 | 7 2 6 |
| 8 2 6 | 7 4 3 | 9 5 1 |
+-------+-------+-------+
Quote:
herschko: I highly recommend Weekly Killer No. 265 (11/29/2010) over at [url]killersudokuonline.com[/url]. Very challenging, with several large cages. I had to extend some techniques in ways I don't think I have done before.

simon_blow_snow: Actually, this one is not particular difficult compared to some former toughies. I think perhaps you missed a few critical moves from the very start.
In another forum which no longer exists I wrote a few walkthroughs for some KSO weeklies which were definitely much trickier than this. Real shame all those were lost forever. :rambo:

Joe Casey: I agree with both of you, more or less: it was quite a stinker; my way into it was similar to Simon's. Then I had partial solutions on opposite sides of the board, and only a few combinations were compatible.
Hidden Text:
It was a big help that R3C9 copied into R6C8 and R8/9 C7.
Harder than the recent average, I thought, and I bungled it and had to restart, but on looking back after solving, it doesn't seem so hard (as often happens).

Andrew (in 2011): It was only yesterday, when I was setting up the outline for Archive Part H, that I realised that I hadn't looked at this puzzle at the time, possibly because there wasn't a diagram when this thread was started; it was only months later that I downloaded SudokuSolver, and then only to calculate SS scores for the archive.
Thanks Børge for posting the diagrams. Thanks also to whoever created the puzzle on the KSO website; I've never tried a puzzle from that site before.
As Simon said, it's not a particularly difficult puzzle if one finds a few critical moves from the very start. It took me until step 11 to spot one of them; if I'd spotted that one earlier it would have simplified things and shortened my solving path. I started with what seemed to me at the time to be other critical moves.
A nice observation by Joe Casey, making use of the fact that R3C79 must have a different total than R34C7; as a "clone" step it leads to a shorter solving path but puts up the technical difficulty.
Rating Comment. I'll rate my walkthrough at Hard 1.25.

Post by simon_blow_snow including spoilers:
Actually, this one is not particular difficult compared to some former toughies. I think perhaps you missed a few critical moves from the very start.

Spoilers

16(2)={79} [C3]
Innie/outies N14: R7C13-R2C23=13 --> R7C13=16/17, R2C23=3/4
--> R7C13={79/89} [{9} R7 N7], R2C23={12/13} [{1} R2 N1 12(4)]
--> 12(4): R12C4=8/9
--> R12C4+R3C45=15/16 coming from {123456}, must include 6 [N2]
Outies N2: R2C23+R1C78+R2C7=12 --> R1C78+R2C7=8/9={1??/234}
--> 28(6): R123C6=19/20 <>{1}
--> R1C78 must include {1} (or min =2+3+4+5+7+8 =29 >28) [R1 N3]
--> 10(2)<>[19], ={28/37}
--> N2 7(2) must include {1} of N2, ={16}

cracked...

In another forum which no longer exists I wrote a few walkthroughs for some KSO weeklies which were definitely much trickier than this. Real shame all those were lost forever. :rambo:
Walkthrough by Andrew:
It was only yesterday, when I was setting up the outline for Archive Part H, that I realised that I hadn't looked at this puzzle at the time, possibly because there wasn't a diagram when this thread was started; it was only months later that I downloaded SudokuSolver, and then only to calculate SS scores for the archive.

Thanks Børge for posting the diagrams. Thanks also to whoever created the puzzle on the KSO website; I've never tried a puzzle from that site before.

As Simon said, it's not a particularly difficult puzzle if one finds a few critical moves from the very start. It took me until step 11 to spot one of them; if I'd spotted that one earlier it would have simplified things and shortened my solving path. I started with what seemed to me at the time to be other critical moves.

A nice observation by Joe Casey, making use of the fact that R3C79 must have a different total than R34C7; as a "clone" step it leads to a shorter solving path but puts up the technical difficulty.

Here is my walkthrough for Weekly no.256 @ KSO

Prelims

a) R12C5 = {19/28/37/46}, no 5
b) R3C45 = {16/25/34}, no 7,8,9
c) R34C7 = {59/68}
d) R4C45 = {16/25/34}, no 7,8,9
e) R67C3 = {79}
f) R6C56 = {16/25/34}, no 7,8,9
g) R7C56 = {17/26/35}, no 4,8,9
h) R89C5 = {39/48/57}, no 1,2,6
i) 12(4) cage at R1C4 = {1236/1245}, no 7,8,9

Steps resulting from Prelims
1a. Naked pair {79} in R67C3, locked for C3
1b. 12(4) cage at R1C4 = {1236/1245}, CPE no 1,2 in R2C56, clean-up: no 8,9 in R1C5

2. 28(6) cage at R1C6 cannot contain more than two of 7,8,9
2a. Hidden killer triple 7,8,9 in R12C5 and 28(6) cage for N2 -> R12C5 must contain one of 7,8,9 and 28(6) cage must contain two of 7,8,9 in N2
-> R12C5 = [19/28/37/73], no 4,6
-> 28(6) cage contains two of 7,8,9 in N2, no 7,8,9 in R1C78 + R2C7

3. 45 rule on N23 2 innies R3C79 = 2 outies R2C23 + 12
3a. Min R2C23 = 3 -> min R3C79 = 15, no 1,2,3,4,5, clean-up: no 9 in R4C7
3b. Max R3C79 = 17 -> max R2C23 = 5, no 5,6

4. 45 rule on N2 3 innies R123C6 = 2 outies R2C23 + 16
4a. Min R2C23 = 3 -> min R123C6 = 19, no 1

5. 45 rule on N2369 4(2+2) outies R2C23 + R89C6 = 11
5a. Min R2C23 = 3 -> max R89C6 = 8, no 8,9

6. 45 rule on R12 1 innie R2C1 = 2 outies R3C68 + 1
6a. Min R3C68 = 3 -> min R2C1 = 4
6b. Max R3C68 = 8, no 8,9 in R3C6, no 7,8,9 in R3C8

7. 45 rule on R89 2 outies R7C24 = 1 innie R8C9
7a. Min R7C24 = 3 -> min R8C9 = 3
7b. Max R7C24 = 9, no 9 in R7C24

8. 28(6) cage at R1C6 = {123589/123679/124579/124678/134578} (cannot be {134569/234568} which only contain one of 7,8,9), 1 locked for N3
8b. Max R3C68 = 8 (step 6b) -> no 7 in R3C6
8b. 7,8,9 of 28(6) cage only in R12C6 -> R12C6 = {789}

9. X-wing for 1 in 12(4) cage at R1C4 and 28(6) cage at R1C6 for R12, no other 1 in R12, clean-up: no 9 in R2C5
9a. 9 in N2 only in R12C6, locked for C6

10. 28(6) cage at R1C6 (step 8) contains 9 = {123589/123679/124579}, CPE no 2 in R3C8
10a. Max R3C68 = 8 (step 6b) -> no 6 in R3C6
10b. Min R3C68 = 5 -> min R2C1 = 6 (step 6)

11. 45 rule on N14 2 outies R7C13 = 2 innies R2C23 + 13
11a. Min R2C23 = 3 -> min R7C13 = 16, R7C13 = {79/89}, 9 locked for R7 and N7
11b. R7C13 = 16,17 -> R2C23 = 2,3 = {12/13}, locked for R2, N1 and 12(4) cage at R1C4, no 1 in R12C4

12. 1 in N2 only in R3C45 = {16}, locked for R3 and N2, clean-up: no 8 in R4C7

13. 12(4) cage at R1C4 = {1245} (only remaining combination) -> R12C4 = {45}, locked for C4 and N2, R2C23 = {12}, locked for R2 and N1, clean-up: no 2,3 in R4C5

14. R2C23 + R89C6 = 11 (step 5)
14a. R2C23 = {12} = 3 -> R89C6 = 8 = {17/26/35}, no 4

15. 4 in N8 only in R89C5 = {48}, locked for C5 and N8, clean-up: no 2 in R1C5, no 3 in R4C4, no 3 in R6C6
15a. Naked pair {37} in R12C5, locked for C5 and N2 -> R3C6 = 2, clean-up: no 5 in R6C5, no 4 in R6C6, no 6 in R7C5, no 1,5 in R7C6, no 6 in R89C6 (step 14a)
15b. Naked quad {1256} in R4C45 + R6C56, locked for N5 -> R5C5 = 9

16. R2C1 = R3C68 + 1 (step 6)
16a. Max R3C68 = 7 -> max R2C1 = 8

17. R3C79 = R2C23 + 12 (step 3)
17a. R2C23 = {12} = 3 -> R3C79 = 15 = [87]

18. 9 in N1 only in R3C12, locked for R3 -> R3C7 = 8, R3C9 = 7, R4C7 = 6, clean-up: no 1 in R4C45

19. R4C45 = [25]
19a. Naked pair {16} in R6C56, locked for R6

20. R123C6 = {89}2 -> 28(6) cage at R1C6 (step 10) = {123589} (only remaining combination), 1,3,5 locked for N3 -> R3C8 = 4

21. Naked pair {69} in R2C89, locked for R2 and N3 -> R1C9 = 2, R12C6 = [98], R2C1 = 7, R12C5 = [73], R2C7 = 5, R12C4 = [54]

22. 18(3) cage at R1C1 = {468} (hidden triple in N1)

23. R7C5 = 2 (hidden single in C5), R7C6 = 6, R6C56 = [61], R3C45 = [61], clean-up: no 7 in R89C6 (step 14a)

24. Naked pair {35} in R89C6, locked for C6, N8 and 17(4) cage at R8C6, no 3,5 in R8C78
24a. Naked pair {47} in R45C6, locked for N5

25. R89C6 = {35} = 8 -> R8C78 = 9 = [18/27/72], no 4,6,9, no 1 in R8C8

26. R7C13 = R2C23 + 13 (step 11)
26a. R2C23 = {12} = 3 -> R7C13 = 16 = [97], R6C3 = 9, R7C4 = 1

27. R789C4 = 1{79} = 17 -> R8C3 + R9C23 = 12 = {246/345}, no 8, 4 locked for N7

28. R89C7 = [79] (hidden pair in C7), R8C8 = 2 (step 25), R89C4 = [97]
28a. R9C7 = 9 -> R9C89 = 6 = {15}, locked for R9 and N9 -> R89C6 = [53]

29. Naked triple {348} in R7C789, locked for R7 and N9, 8 also locked for 33(6) cage at R5C9 (no 8 in R5C9 + R6C89) -> R7C2 = 5, R8C9 = 6, R2C89 = [69]

30. R8C3 + R9C23 (step 27) = {246} (only remaining combination) -> R8C3 = 4, R9C23 = {26}, locked for N7 -> R9C1 = 8, R89C5 = [84]

31. R4C6 = 7 (hidden single in R4), R5C6 = 4

32. 5 in R6 only in R6C89, locked for N6
32a. 33(6) cage at R5C9 = {345678} (only remaining combination), no 1,2 -> R5C9 = 3, R7C89 = [84], R6C89 = [75], R6C7 = 4, R56C4 = [83], R9C89 = [51], R4C9 = 8, R5C78 = [21], R6C12 = [28]

33. R5C2 = 7 (hidden single in R5)
33a. R5C2 + R6C12 + R7C1 = 26 -> R345C3 = 9 = {135} -> R5C3 = 5

and the rest is naked singles.

Rating Comment. I'll rate my walkthrough for Weekly no.256 @ KSO at Hard 1.25, rather than a bit lower, because of the large cages and because some of the 45s aren't easy to spot.


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PostPosted: Thu Oct 23, 2014 3:42 am 
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Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1894
Location: Lethbridge, Alberta, Canada
Assassin 204 by Ed (December 2010) here
Puzzle Diagram:
Image
Note: 1-9 cannot repeat on the diagonals
Puzzle Diagrams with "udosuk style Killer Cages":
Image     Image
Code: Select, Copy & Paste into solver:
3x3:d:k:4608:4608:2561:8706:8706:771:771:2308:2308:4608:2561:2561:8706:5125:5125:2310:4103:4103:6152:6152:8706:8706:5125:5125:2310:4103:5385:6152:6152:4106:4106:4106:5125:7691:7691:5385:2316:2316:6413:4106:2830:7691:7691:783:5385:2320:6929:6413:6413:2830:7698:7691:783:3859:2320:6929:6413:6413:7698:7698:5908:3859:3859:2325:6929:6929:7698:7698:5908:5908:5908:3859:2325:2325:7698:7698:3862:3862:4887:4887:4887:
Solution:
+-------+-------+-------+
| 9 7 3 | 6 8 1 | 2 4 5 |
| 2 1 6 | 9 5 4 | 8 7 3 |
| 5 8 4 | 7 3 2 | 1 6 9 |
+-------+-------+-------+
| 7 4 2 | 5 1 6 | 9 3 8 |
| 6 3 9 | 8 2 7 | 5 1 4 |
| 8 5 1 | 4 9 3 | 6 2 7 |
+-------+-------+-------+
| 1 6 8 | 3 4 9 | 7 5 2 |
| 4 9 7 | 2 6 5 | 3 8 1 |
| 3 2 5 | 1 7 8 | 4 9 6 |
+-------+-------+-------+
Quote:
Ed: Merry Christmas! Found a really nice way to crack this one which might have to go into the techniques forum. Love the way hard killers keep surprising with the variety of ways to attack them.

Joe Casey: Nice one, Ed. Found a nice logical way into it. Don't know if it's the same as yours, but very satisfying anyway.
Have a Happy Christmas.

Andrew: Thanks Ed for a fun Assassin!
I don't know whether I found the same way as Ed did to crack this puzzle; my key breakthrough was in step 12 (with hindsight it was possible earlier than that) and I used another interesting move in step 19 to get a quick finish.
Rating Comment. I'll rate A204 at 1.5. I think step 12 probably deserves this rating, as does the combination blocker in step 19.
Happy Christmas to all forum members! :santa:

HATMAN: Joe
Very neat but let me check out that jump

Joe Casey: Thanks. I gather that my post was a bit too elliptical.
I still don't do walk-throughs. But sometimes I want to substantiate my claim to have solved the puzzle; or to let other solvers compare their route; or to offer a hint and encouragement to anyone who hasn't solved it. That, and my natural indolence, is why I'm a bit elliptical.

HATMAN: I have similar views on walkthroughs, perhaps the phase skip-through instead?

Ed: Very interesting! Andrew got my way with his step 12 but his is better because it locks four candidates whereas I just saw the two highest ones. It looks like the Blocking Cages technique (see several posts starting at the bottom of this post). Great walkthrough Andrew and love the rating!
I still can't work out how Joe Casey and HATMAN get their way to work but know it is correct. [edit: got it now - thanks to Andrew and Joe for helpful PMs] Checked a number of puzzles with this same pattern (generated by JSudoku) and they all have the same feature with that sum of 45. Well done! :applause:

Joe Casey's solving outline:
R1C7 & R3C9 must be 2,9; then R3C1-3 makes 17, so no 1; so the left 9-cage in N3 is 8 over 1; 1,2,3&5 in R9 are on the left; so in N9 the 1,2 are in R78C9; then R9C3=R8C6=R7C8=5; etc.
Walkthrough by Andrew:
Here is my walkthrough for A204. I forgot until the final stages that this is a Killer-X so if you work through my steps using a software solver in editor mode please switch off the Killer-X option.

Here is my walkthrough for A204

Prelims

a) R1C67 = {12}
b) R1C89 = {18/27/36/45}, no 9
c) R23C7 = {18/27/36/45}, no 9
d) R5C12 = {18/27/36/45}, no 9
e) R56C5 = {29/38/47/56}, no 1
f) R56C8 = {12}
g) R67C1 = {18/27/36/45}, no 9
h) R9C56 = {69/78}
i) 10(3) cage in N1 = {127/136/145/235}, no 8,9
j) 21(3) cage at R3C9 = {489/579/678}, no 1,2,3
k) 9(3) cage in N7 = {126/135/234}, no 7,8,9
l) 19(3) cage in N9 = {289/379/469/478/568}, no 1
m) 27(4) cage at R6C2 = {3789/4689/5679}, no 1,2
n) 34(5) cage at R1C4 = {46789}, no 1,2,3,5

Steps resulting from Prelims
1a. Naked pair {12} in R1C67, locked for R1, clean-up: no 7,8 in R1C89
1b. Naked pair {12} in R56C8, locked for C8 and N6
1c. 34(5) cage at R1C4 = {46789}, CPE no 4,6,7,8,9 in R3C56

2. 45 rule on N3 2 innies R1C7 + R3C9 = 11 = [29], R1C6 = 1, clean-up: no 7 in R23C7
2a. 21(3) cage at R3C9 = {489/579}, no 6
2b. 10(3) cage in N1 = {127/136/145/235}
2c. 7 of {127} must be in R1C3 -> no 7 in R2C23

3. 20(5) cage at R2C5 = {23456} (only remaining combination), no 7,8,9

4. 45 rule on R9 4 innies R9C1234 = 11 = {1235}, locked for R9
4a. 4 in R9 only in 19(3) cage, locked for N9
4b. 19(3) cage = {469/478}
4c. 9(3) cage in N7 = {126/135/234}
4d. 4,6 of {126/234} must be in R8C1 -> no 2 in R8C1

5. 7,8 in N2 only in R1C45 + R23C4, locked for 34(5) cage at R1C4, no 7,8 in R3C3
5a. 45 rule on N2 2(1+1) outies R3C3 + R4C6 = 10 = [46/64], CPE no 4,6 in R4C3

6. 45 rule on N1 3 innies R3C123 = 17 = {368/458/467} (cannot be {278} because R3C3 only contains 4,6), no 1,2
6a. 45 rule on N1 2 outies R4C12 = 1 innie R3C3 + 7
6b. Min R3C3 = 4 -> min R4C12 = 11, no 1 in R4C12

7. R3C7 = 1 (hidden single in R3), R2C7 = 8
7a. 2 in R3 only in R3C56, locked for N2

8. R78C9 = {12} (hidden pair in C9)
8a. R6C9 + R7C8 = 12 = [39/48/57/75], no 6,8 in R6C9, no 3,6 in R7C8

9. 45 rule on N9 2(1+1) outies R6C9 + R8C6 = 12 = [39/48/57/75], no 2,3,4,6 in R8C6

10. 45 rule on C12 1 outie R8C3 = 1 innie R2C2 + 6 -> R2C2 = {123}, R8C3 = {789}

11. 45 rule on N6 1 remaining outie R5C6 = 1 innie R6C9, no 2,6,8,9 in R5C6
11a. 9 in N6 only in 30(5) cage at R4C7 = {34689/35679}
11b. 8 of {34689} must be in R4C8 -> no 4 in R4C8

12. 30(7) cage at R6C6 = {1234569/1234578}, R9C56 = {69/78}, CPE no 7,8,9 in R8C6 (R8C6 “sees” all 6,7,8,9 in the 30(7) cage and R9C56, which cannot both contain 6,9 and cannot both contain 7,8)
12a. R8C6 = 5
12b. R9C3 = 5 (only remaining place for 5 in 30(7) cage), clean-up: no 4 in R6C1
12c. R7C8 = 5 (hidden single in N9), R6C9 = 7 (step 8a), R5C6 = 7 (step 11), clean-up: no 4 in R1C9, no 5 in R45C9, no 2 in R5C12, no 4 in R56C5, no 2 in R7C1, no 8 in R9C5

13. Naked pair {48} in R45C9, locked for C9 and N6 -> R9C9 = 6, clean-up: no 3 in R1C8, no 9 in R9C56

14. R9C56 = [78]
14a. R9C7 = 4 (hidden single in C7), R9C8 = 9
14b. Naked pair {37} in R78C7, locked for C7 and N9 -> R8C8 = 8, clean-up: no 2 in R2C2 (step 10)
14c. R4C8 = 3 (hidden single in N6)

15. 9 in C6 only in R67C6, locked for 30(7) cage at R6C6, no 9 in R7C5 + R8C45
15a. 1 in 30(7) cage at R6C6 only in R7C5 + R8C45 + R9C4, locked for N8

16. 5 in N2 only in R23C5, locked for C5, clean-up: no 6 in R56C5

17. 10(3) cage in N1 = {127/136}, no 4, 1 locked for N1
17a. R3C123 (step 6) = {368/458} (cannot be {467} which clashes with 10(3) cage), no 7, 8 locked for R3, N1 and 24(4) cage at R3C1, no 8 in R4C12

18. Naked pair {467} in R3C348, locked for R3

19. 10(3) cage in N1 (step 17) = {136} (only remaining combination, cannot be {127} = [712] which clashes with R2C2 + R8C3 = [17], step 10), locked for N1, 6 locked for C3 -> R3C3 = 4

20. R2C1 = 2 (hidden single in N1), clean-up: no 7 in R7C1
20a. Naked pair {58} in R3C12, locked for R3, N1 and 24(4) cage at R3C1, no 5 in R4C12

21. Naked pair {79} in R1C12, locked for R1
21a. Naked pair {68} in R1C45, locked for R1 and N2 -> R1C3 = 3, R2C23 = [16], R8C3 = 7 (step 10), R1C89 = [45], R2C89 = [73], R3C8 = 6, R2C56 = [54], R4C6 = 6, R23C4 = [97], R78C7 = [73], clean-up: no 8 in R5C1
21b. Killer pair 2,3 in R3C5 and R56C5, locked for C5

22. R8C2 = 9 (hidden single in R8), R1C12 = [97]

23. R3C12 = {58} = 13 -> R4C12 = 11 = [74], R45C9 = [84], clean-up: no 5 in R5C12

24. 1,2 in R4 only in 16(4) cage = {1258} (only remaining combination) -> R5C4 = 8, R4C4 = 5, R5C7 = 9, R5C5 = 1, R5C3 = 2, R1C45 = [68], clean-up: no 1 in R5C1, no 3 in R56C5
24a. Naked pair {36} in R5C12, locked for R5 and N4 -> R56C7 = [56], clean-up: no 3,6 in R7C1
24b. Naked pair {29} in R56C5, locked for C5 and N5 -> R3C56 = [32], R6C6 = 3, R7C6 = 9

25. R6C4 = 4, R567C3 = {189} = 18 -> R7C4 = 3 (cage sum)

26. 27(4) cage at R6C2 = {5679} (only remaining combination) -> R6C2 = 5, R7C2 = 6

It was only at this stage, when I started checking whether I’d reached naked singles, that I saw at the top of my worksheet the note that this puzzle is a Killer-X. Up to this stage I haven’t made any eliminations resulting from placements on the diagonals.

So close to being a unique puzzle without using the diagonals!

27. R5C5 = 2 (hidden single on D\), R7C3 = 8 (hidden single on D/)

and the rest is naked singles.
HATMAN's query:
Very neat but let me check out that jump to 555
Outies and innies on N9 r8c6 = r7c8 = 5/7/8/9 and r9c3 already = 1/2/3/5
R9c6 sees all of 30(7) so r9c56 contains the missing 15 hence they form a 45 cage
LOL with N8 -> r6c6 = r7c4 & r9c3=r8c6 hence 555
Joe Casey's explanation, after HATMAN's query:
Why are these three cells equal? The 30-cage in N8 is seen by R9C6; so the 30-cage lacks whatever that 15-cage is. Its outies must be copied in, so R6C6=R7C4, so R9C3=R8C6.
Ed's alternative way to look at Joe Casey's cracker:
Another way to get the same result: First, I can't see why r9c5 can't be repeated in r6c6 with those two cages that total 45 [edit: Got it now. The 30(7) is missing a 15(2) which can only be {69/78} missing: since all the 30(7) sees one of the cells in the 15(2) at r9c56 -> it must have the missing combination -> r9c5 cannot repeat in r6c6]

But here is another way to prove that r9c3 = r8c6.
a. "45" on n8: 2 outies r6c6 + r9c3 = 2 innies r7c4 + r8c6
b. since one of the outies (r6c6) sees one of the innies (r8c6) they cannot be equal -> the other outie and innie cannot be equal or the IOD of 0 will never be achieved.
c. -> r9c3 cannot equal r7c4
d. -> r9c3 sees all of n8 indirectly except r8c6 -> r9c3 and r8c6 must be equal


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PostPosted: Sun Oct 26, 2014 3:06 am 
Offline
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Grand Master

Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1894
Location: Lethbridge, Alberta, Canada
Assassin 205 by Ed (February 2011) here
Puzzle Diagram:
Image
note: it has a remote 6(2) cage at r5c46
Puzzle Diagrams with "udosuk style Killer Cages":
Image     Image
Code: Select, Copy & Paste into solver:
3x3::k:5121:2562:2562:2562:2563:11524:11524:11524:11524:5121:3845:3845:9990:2563:2563:2563:11524:11524:5121:5121:9990:9990:3079:3079:4616:11524:11524:2313:2313:9990:9990:5898:3079:4616:4616:11524:3851:3851:9990:1548:5898:1548:2061:2830:2830:4111:7184:7184:7184:5898:5898:2061:3857:3857:4111:4111:7184:7184:7184:5650:2061:5139:5139:2324:4117:5142:5142:5142:5650:5650:5650:5139:2324:4117:4117:4117:5142:4631:4631:4631:5139:
Solution:
+-------+-------+-------+
| 2 4 1 | 5 3 6 | 8 9 7 |
| 7 9 6 | 8 4 1 | 2 3 5 |
| 8 3 5 | 9 2 7 | 6 4 1 |
+-------+-------+-------+
| 1 8 4 | 6 9 3 | 5 7 2 |
| 9 6 7 | 4 5 2 | 1 8 3 |
| 5 2 3 | 7 1 8 | 4 6 9 |
+-------+-------+-------+
| 4 7 9 | 1 6 5 | 3 2 8 |
| 6 5 2 | 3 8 9 | 7 1 4 |
| 3 1 8 | 2 7 4 | 9 5 6 |
+-------+-------+-------+
Quote:
Ed: Found a really neat way to make big inroads near the beginning. Unfortunately, the end is a bit tedious but hopefully I just missed something.

Frank: Tough one Ed. I liked the fact it was asymmetric.
My 2 key moves were:
Thanx for the puzzle :)

Andrew: Thanks Ed for a fun puzzle.
I found my first important step fairly quickly but it took me some time to find my other key moves; with hindsight ...

Ed:
Frank wrote:
Tough one Ed. I liked the fact it was asymmetric.
Thanks. Nice to know some of us are asymmetrics - it's not everyone's taste. The next couple I'm working on are also. Been aiming for simpler cage structures and using asymmetry to give that extra bit of a twist.
I used a variation on Andrew's "Killer pairs" move in his step 4 to make big inroads elsewhere (my step 5). Andrew's is a blocking move whereas mine is a locking move....perhaps Alternating Killer pairs (or AK blocks in Andrew's)???? If anyone can remember seeing it used before please let me know. It may be a good one for the techniques forum.
Thank you to Andrew for his walk-through, very easy to read. Appears that Frank used a similiar approach. Andrew's step 34 makes a huge difference to the ending of the puzzle compared to how I found it.

Andrew: Thanks for the kind comments, Ed, but your clever step 5 is a lot more powerful than my step 4. You were helped a lot by your step 2; I don't think I seriously looked at that "45". As a result you got one of your key results in your step 8; I didn't reach the same naked pair until my step 19a.
Thanks for commenting about my step 34. Yes, it was very useful.
Maybe you missed the fact that:
the outies from N9 at that stage had to contain 9.
Ed wrote:
Nice to know some of us are asymmetrics - it's not everyone's taste.
I'm also happy with asymmetrics. I never assume that because I've found a "45" there must be a corresponding one on the opposite side of the grid.
I think if there's a feature of cage patterns that I'm not particularly keen about it's disjoint/remote cages. The one in A205 wasn't a problem, since it was completely enclosed in both R5 and N5; for this puzzle it didn't affect "45s" involving multiple columns. More generally disjoint/remote cages do tend to reduce the number of available "45s", often significantly.

Frank's key moves:
Tough one Ed. I liked the fact it was asymmetric.

My 2 key moves were:

to show that the {234} in r2c7 copied over to r4c9, and the 11/2 cage in N6 was {38}

Thanx for the puzzle :)
Walkthrough by Andrew:
Thanks Ed for a fun puzzle.

I found my first important step fairly quickly but it took me some time to find my other key moves; with hindsight steps 13, 14 and 17 could have been done a lot earlier.

Here is my walkthrough for A205

Prelims

a) R2C23 = {69/78}
b) R4C12 = {18/27/36/45}, no 9
c) R5C12 = {69/78}
d) R5C46 = {15/24}
e) R5C89 = {29/38/47/56}, no 1
f) R6C89 = {69/78}
g) R89C1 = {18/27/36/45}, no 9
h) 10(3) cage at R1C2 = {127/136/145/235}, no 8,9
i) 8(3) cage at R5C7 = {125/134}
j) 10(4) cage at R1C5 = {1234}
k) 39(6) cage at R2C4 = {456789}, no 1,2,3
l) and of course 45(9) cage at R1C6 = {123456789}

Steps resulting from Prelims
1a. 8(3) cage at R5C7 = {125/134}, 1 locked for C7
1b. 10(4) cage at R1C5 = {1234}, 1 locked for N2, CPE no 4 in R2C4
1c. 1 in N3 only in 45(9) cage -> no 1 in R4C9

[There must be interactions between R2C23 and 39(6) cage at R2C4 but I can’t yet see how to use them.]

2. R2C7 = {234} -> R2C7 + 8(3) cage at R5C7 = 10,11,12 = {1234/1235/1245}, 2 locked for C7

3. 45 rule on R1234 1 innie R4C5 = 1 outie R5C3 + 2 -> R4C5 = {6789}, R5C3 = {4567}

4. R5C3 = {4567} -> either R5C3 = {45}, killer pair 4,5 in R5C3 and R5C46, locked for R5 or R5C3 = {67}, killer pair 6,7 in R5C12 and R5C3, locked for R5 -> R5C89 = {29/38}, no 4,5,6,7
[I later realised that this step is better written as
Hidden killer quad 4,5,6,7 in R5C12, R5C3, R5C46 and R5C89 for R5, R5C12 contains one of 6,7, R5C3 contains one of 4,5,6,7, R5C46 contains one of 4,5 -> R5C89 cannot contain more than one of 4,5,6,7 -> R5C89 = {29/38}, no 4,5,6,7]

5. Killer pair 8,9 in R5C12 and R5C89, locked for R5
5a. Killer pair 8,9 in R5C89 and R6C89, locked for N6

6. 18(3) cage at R3C7 = {279/369/378/459/468/567} (cannot be {189} because 8,9 only in R3C7), no 1
6a. 8,9 of {369/378/459/468} must be in R3C7 -> no 3,4 in R3C7
6b. 5 of {459/567} must be in R4C78 (R4C78 cannot be {67} which clashes with R6C89) -> no 5 in R3C7

7. 1 in N6 only in R56C7, locked for 8(3) cage at R5C7 -> no 1 in R7C7

8. 12(3) cage at R3C5 = {129/138/147/156/237/246/345}
8a. 1 of {129/138/147/156} must be in R4C6, 5,6,7 of {237/246/345} must be in R3C56 (R3C56 cannot be {23/24/34} which clash with 10(4) cage at R1C5, ALS block) -> no 5,6,7,8,9 in R4C6

9. 45 rule on N5 3 innies R4C46 + R6C4 = 16 = {169/178/268/349/358/367} (cannot be {259/457} which clash with R5C46)
9a. 1,2 of {169/179/268} must be in R4C6 -> no 1,2 in R6C4

10. Law of Leftovers for N3, R1C6 + R4C9 must contain exactly the same pair of candidates as R23C7, no 5 in R23C7 -> no 5 in R1C6 + R4C9

11. 45 rule on N1 1 outie R1C4 = 1 innie R3C3, no 2,3 in R1C4, no 8,9 in R3C3

12. 10(3) cage at R1C2 = {127/136/145/235}
12a. 6,7 of {127/136} must be in R1C4 -> no 6,7 in R1C23

13. Hidden killer triple 1,2,3 in R4C12, R4C6 and R4C789 for R4, R4C789 can only contain one of 2,3 (cannot contain both of 2,3 which would clash with R5C89) -> R4C12 and R4C6 must each contain one of 1,2,3 -> R4C6 = {123}, R4C12 = {18/27/36}, no 4,5
13a. Killer pair 2,3 in R4C789 and R5C89, locked for N6

14. 8(3) cage at R5C7 = {125/134}
14a. 2,3 only in R7C7 -> R7C7 = {23}

15. 45 rule on N6 2 outies R37C7 = 1 innie R4C9 + 7
15a. Max R37C7 = 12 -> no 6,7 in R4C9

16. Law of Leftovers for N3, R1C6 + R4C9 must contain exactly the same pair of candidates as R23C7
16a. R2C7 = R4C9 = {234} -> R1C6 = R3C7 = {6789}

17. Consider placements for 3 in N6
3 in R4C789 => R4C12 = {18/27} => R5C12 = {69} (cannot be {78} which clashes with R4C12
3 in R5C89 = {38}, locked for R5 => R5C12 = {69}
17a. -> R5C12 = {69}, locked for R5 and N4, clean-up: no 3 in R4C12, no 8 in R4C5 (step 3), no 2 in R5C89

18. Naked pair {38} in R5C89, locked for R5 and N6, clean-up: no 3 in R2C7 (step 16), no 7 in R6C89
18a. Naked pair {69} in R6C89, locked for R6 and N6

19. 7 in N6 only in R4C78, locked for R4 and 18(3) cage at R3C7, no 7 in R3C7, clean-up: no 7 in R1C6 (step 16), no 2 in R4C12, no 5 in R5C3 (step 3)
19a. Naked pair {18} in R4C12, locked for R4 and N4
19b. R89C1 = {27/36/45} (cannot be {18} which clashes with R4C1), no 1,8

20. R4C6 = 3 (hidden single in R4), R3C56 = 9 = {27/45}, no 6,8,9
20a. Killer pair 2,4 in 10(4) cage at R1C5 and R3C56, locked for N2, clean-up: no 4 in R3C3 (step 11)
20b. 3 in N2 only in R12C5, locked for C5

21. R4C45 = {69} (hidden pair in R4)

22. Killer pair 2,4 in R2C7 and 8(3) cage at R5C7, locked for C7

23. 18(3) cage at R3C7 (step 6) must contain 7 in R4C78 = {279/567}, no 4,8, clean-up: no 8 in R1C6 (step 16)

24. 4 in 39(6) cage at R2C4 only in R45C3, locked for C3 and N4
24a. 8,9 in 39(6) cage at R2C4 only in R234C4, locked for C4
24b. 2 in N6 only in R6C123, locked for R6

25. 10(3) cage at R1C2 = {127/136/145/235}
25a. R1C4 = {567} -> no 5 in R1C23

26. 2 in R4 only in R4C89, CPE no 2 in R123C8
26a. 2 in 45(9) cage at R1C6 only in R1234C9, locked for C9

27. 8 in N5 only in 23(4) cage = {1589/2489/2678} (cannot be {4568} which clashes with R5C46)
27a. 2 of {2489/2678} must be in R5C5 -> no 4,7 in R5C5

28. R5C3 = 7 (hidden single in R5), R4C3 = 4 (hidden single in N4), R4C9 = 2, R2C7 = 2 (hidden single in N3), R7C7 = 3, clean-up: no 8 in R2C2

29. Naked pair {57} in R4C78, locked for N6, R3C7 = 6 (step 23), R1C6 = 6 (step 16), R3C3 = 5, R1C4 = 5 (hidden single in N2), R4C4 = 6 (hidden single in 39(6) cage at R2C4), R4C5 = 9, clean-up: no 4 in R3C56 (step 20), no 1 in R5C6
29a. Killer pair 8,9 in R2C23 and R2C4, locked for R2

30. Naked pair {27} in R3C56, locked for R3
30a. Naked triple {235} in R6C123, locked for R6

31. 23(4) cage in N5 = {1589/2489}, no 7
31a. 2,5 only in R5C5 -> R5C5 = {25}
31b. R6C4 = 7 (hidden single in N5)

32. 28(6) cage at R6C2 must contain 7 = {123679/124579/134578} (cannot be {124678} because R6C23 must contain two of 2,3,5), 1 locked for R7
32a. R6C23 must contain two of 2,3,5 -> no 2,5 in R7C345
32b. 9 of {123679} must be in R7C3 -> no 6 in R7C3

33. 20(4) cage in N1 = {1469/1478/2369/2378} (cannot be {1289/1379/2468/3467} which clash with R2C23
33a. 2 of {2369/2378} must be in R1C1 -> no 3 in R1C1
33b. 6,7 of {2369/2378} must be in R2C1 -> no 3 in R2C1
33c. 9 of {1469/2369} must be in R3C2 (R123C1 cannot contain both of 6,9 which would clash with R5C1) -> no 9 in R13C1

34. 9 in C6 only in R789C6
34a. 45 rule on N9 3 outies R789C6 = 18 = {189/459} (cannot be {279} which clashes with R3C6), no 2,7
34b. Killer pair 1,4 in R2C6 and R789C6, locked for C6 -> R6C6 = 8, clean-up: no 1 in R89C6

35. Naked triple {459} in R789C6, locked for C6 and N8 -> R2C6 = 1, R5C6 = 2, R5C4 = 4, R56C5 = [51], R3C56 = [27], R7C4 = 1

36. 28(6) cage at R6C2 (step 32) = {123679} (only remaining combination) -> R7C3 = 9, R7C5 = 6, R6C23 = {23}, locked for R6 -> R6C1 = 5, clean-up: no 6 in R2C2, no 4 in R89C1

37. R6C1 = 5 -> R7C12 = 11 = {47} (only remaining combination), locked for R7 and N7, R7C6 = 5, R7C9 = 8, R7C8 = 2, R5C89 = [83], clean-up: no 2 in R89C1
37a. R7C89 = [28] = 10 -> R89C9 = 10 = {19/46}, no 5,7
37b. Killer pair 6,9 in R5C9 and R89C9, locked for C9
37c. Killer pair 1,4 in R3C9 and R89C9, locked for C9 -> R1C9 = 7, R2C9 = 5
37d. R1C7 = 8 (hidden single in N3)

38. Naked pair {36} in R89C1, locked for C1 and N7 -> R5C12 = [96]

39. 9 in N3 only in R13C8, locked for C8 -> R6C89 = [69], clean-up: no 1 in R89C9 (step 37a)
39a. Naked pair {46} in R89C9, locked for C9 and N9 -> R3C9 = 1

40. R89C5 = {78} = 15 -> R8C34 = 5 = [23], R6C23 = [23], R1C3 = 1, R1C2 = 4 (step 25)

and the rest is naked singles.

Rating Comment. I'll rate my walkthrough for A205 at 1.5. I used a couple of short forcing chains, the first of which used killer pairs (which is why I didn't say Easy 1.5), law of leftovers and a hidden killer triple. Edit. I've now shown that the first forcing chain is better written as a hidden killer quad.
Ed's start:
Frank wrote:
Tough one Ed. I liked the fact it was asymmetric.
Thanks. Nice to know some of us are asymmetrics - it's not everyone's taste. The next couple I'm working on are also. Been aiming for simpler cage structures and using asymmetry to give that extra bit of a twist.

I used a variation on Andrew's "Killer pairs" move in his step 4 to make big inroads elsewhere (my step 5). Andrew's is a blocking move whereas mine is a locking move....perhaps Alternating Killer pairs (or AK blocks in Andrew's)???? If anyone can remember seeing it used before please let me know. It may be a good one for the techniques forum.

Thank you to Andrew for his walk-through, very easy to read. Appears that Frank used a similiar approach. Andrew's step 34 makes a huge difference to the ending of the puzzle compared to how I found it.

A205 Alt start
10 steps](Optimised walk-through so some obvious eliminations are not done. However, I try and do clean-up as I go. Please tell me about any mistakes or things that could be clearer)

Prelims courtesy of SudokuSolver
i. Cage 6(2) n5 - cells only use 1,2,4,5
ii. Cage 15(2) n1 - cells only use 6,7,8,9
iii. Cage 15(2) n4 - cells only use 6,7,8,9
iv. Cage 15(2) n6 - cells only use 6,7,8,9
v. Cage 9(2) n7 - cells do not use 9
vi. Cage 9(2) n4 - cells do not use 9
vii. Cage 11(2) n6 - cells do not use 1
viii. Cage 8(3) n69 - cells do not use 6,7,8,9
ix. Cage 10(3) n12 - cells do not use 8,9
x. Cage 10(4) n23 - cells ={1234}
xi. Cage 39(6) n1245 - cells ={456789}

1. "45" on r1234: 1 innie r4c5 - 2 = 1 outie r5c3 = [64/75/86/97] = [6/7..](last bit important for later)
1a. r4c5 = (6..9), r5c3 = (4..7)

2. "45" on r5: 3 innies r5c357 = 13
2a. {139/238} in that h13(3) don't work with r5c3 from (4..7)
2b. {148/256} blocked by 6(2) at r5c46 = [1/4, 2/5..]
2c. h13(3) = {157/247/346}(no 8,9)

3. 15(2)n4 can only have one of 8/9 -> Hidden Killer pair 8,9 in r5
3a. -> 11(2)n6 must have 8/9 = {29/38}(no 4,5,6,7)

4. 15(2)n6 can only have one of 6/7 -> Hidden killer pair 6,7 in n6
4a. -> r4c789 must have 6/7 for n6 (no eliminations yet)

5. from step 1, either r4c5 is from (67) -> Killer pair 6,7 in r4 with r4c789 (step 4a)
5a. or r5c3 is from (67) -> Killer pair 6,7 in n4 with 15(2)
5b. -> no 6,7 in r4c123 (Alternating Killer pair..???)
5c. 9(2)n4 = {18/45} (no 2,3)

6. r4c789 can't have more than one of 2 or 3 since 11(2)n6 must have one
6a. -> hidden killer pair 2,3 in r4 -> r4c6 = (23)
6b. and r4c789 must have one of 2/3 for r4
6c.-> Killer pair 2,3 with 11(2)n6: both locked for n6

7. 8(3)r5c7 = {125/134}: must have 2/3 -> r7c7 = (23)
7a. must have 1 -> 1 locked for n6 and c7

8. 1 in r4 only in 9(2)n4 = {18} only: both locked for n4 and 8 for r4
8a. 15(2)n4 = {69} only: both locked for n4 & r5
8b. 11(2)n6 = {38} only: both locked for n6 & 3 for r5
8c. 15(2)n6 = {69} only: both locked for n6 & r6

9. r4c6 = 3 (hsingle r4)

10. "45" on n6: 2 outies r37c7 - 7 = 1 innie r4c9
10a. max. 2 outies = 12 -> max. r4c9 = 5
10b. 7 in n6 only in r4c78: locked for r4 and for 18(3) at r3c7
10c. 18(3) can't have {378} since no 3,8 in r4c78
10d. 18(3) = {279/567}(no 3,4,8)
10e. must have 6/9 -> r3c7 = (69)

Keep on from there. If your finding it hard going at the end, see Andrew's powerful step 34. Missed that.


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PostPosted: Sun Oct 26, 2014 3:26 am 
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Grand Master

Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1894
Location: Lethbridge, Alberta, Canada
Assassin 206 by Ed (February 2011) here
Puzzle Diagram:
Image
Puzzle Diagrams with "udosuk style Killer Cages":
Image     Image
Andrew's Coloured Diagram:
Image
Code: Select, Copy & Paste into solver:
3x3::k:7169:7169:7169:4610:3587:3587:4100:4100:2309:1798:7169:4610:3335:3335:3587:3587:4100:2309:1798:4610:2056:3849:3849:5386:5386:2315:2315:4610:3084:2056:3853:3853:5386:5386:3598:3598:3343:3084:2056:3853:4880:4880:2065:2065:3598:3343:3343:6162:6162:4880:6675:6675:6675:3604:2069:2069:6162:6162:2070:6675:3604:3604:2839:3096:2585:3354:3354:2070:6675:3611:4380:2839:3096:2585:2585:2333:2333:3611:3611:4380:2839:
Solution:
+-------+-------+-------+
| 4 7 9 | 2 1 5 | 3 6 8 |
| 5 8 3 | 9 4 6 | 2 7 1 |
| 2 6 1 | 8 7 3 | 9 4 5 |
+-------+-------+-------+
| 7 9 2 | 5 6 1 | 8 3 4 |
| 1 3 5 | 4 9 8 | 6 2 7 |
| 8 4 6 | 3 2 7 | 1 5 9 |
+-------+-------+-------+
| 6 2 8 | 7 5 9 | 4 1 3 |
| 9 1 7 | 6 3 4 | 5 8 2 |
| 3 5 4 | 1 8 2 | 7 9 6 |
+-------+-------+-------+
Quote:
Ed: This one is technically easier than the last couple. No tricks or really advanced moves needed. But....I found it harder and took longer to solve! Love killers like this. Takes me about 15 steps to crack it. All traditional Assassin moves, some of which took a long time to find. Savour.

Andrew: Here is the coloured image for A206 which I made while setting up my Excel worksheets.

Andrew: Thanks Ed! I enjoyed A206. As you said it's hard to find some steps. I'll guess from your introductory comment that my breakthrough step probably wasn't the way you intended it to be solved. However it led to a straightforward and fairly quick finish and, more important for me, it avoided messy combination analysis ...

Ed: Glad you enjoyed this puzzle Andrew. You interpreted my intro perfectly with the exception of your step 12. I avoid that type of combo analysis (which must sound pretty silly since this is killer sudoku!!) when there are so many combinations involved. I missed that nice chain you found...though we worked in the same areas. You'll kick yourself about a couple of "45"s you missed!! They took me a long time to find.

This is an alternative way to crack A206

Walkthrough by Andrew:
Thanks Ed! I enjoyed A206. As you said it's hard to find some steps. I'll guess from your introductory comment that my breakthrough step probably wasn't the way you intended it to be solved. However it led to a straightforward and fairly quick finish and, more important for me, it avoided messy combination analysis for the 18(4) cage at R1C4 interacting with Innies for N1, which I'd started looking at.

Here is my walkthrough for A206; I've fixed some typos and simplified the ending

Prelims

a) R12C9 = {18/27/36/45}, no 9
b) R23C1 = {16/25/34}, no 7,8,9
c) R2C45 = {49/58/67}, no 1,2,3
d) R3C45 = {69/78}
e) R3C89 = {18/27/36/45}, no 9
f) R45C2 = {39/48/57}, no 1,2,6
g) R5C78 = {17/26/35}, no 4,8,9
h) R7C12 = {17/26/35}, no 4,8,9
i) R78C5 = {17/26/35}, no 4,8,9
j) R89C1 = {39/48/57}, no 1,2,6
k) R8C34 = {49/58/67}, no 1,2,3
l) R89C8 = {89}
m) R9C45 = {18/27/36/45}, no 9
n) 8(3) cage at R3C3 = {125/134}
o) 19(3) cage in N5 = {289/379/469/478/568}, no 1
p) 10(3) cage in N7 = {127/136/145/235}, no 8,9
q) 11(3) cage in N9 = {128/137/146/236/245}, no 9
r) 28(4) cage in N1 = {4789/5689}, no 1,2,3
s) 14(4) cage at R1C5 = {1238/1247/1256/1346/2345}, no 9

Steps resulting from Prelims
1a. Naked pair {89} in R89C8, locked for C8 and N9, clean-up: no 1 in R3C9
1b. 8(3) cage at R3C3 = {125/134}, 1 locked for C3
1c. 28(4) cage in N1 = {4789/5689}, 8,9 locked for N1
1d. 9 in C9 only in R456C9, locked for N6

2. R2C45 = {49/58} (cannot be {67} which clashes with R3C45), no 6,7
2a. Killer pair 8,9 in R2C45 and R3C45, locked for N2
2b. 14(4) cage at R1C5 = {1238/1247/1256/1346} (cannot be {2345} which clashes with R2C45)

3. 45 rule on N3 2 innies R23C7 = 11 = [29]/{38/47/56}, no 1, no 2 in R3C7
3a. 14(4) cage at R1C5 (step 2b) = {1238/1247/1256/1346}, 1 locked for N2

4. 45 rule on N7 2 innies R78C3 = 15 = {69/78}, clean-up: no 8,9 in R8C4
4a. Hidden killer pair 8,9 in R78C3 and R89C1 for N7, R78C3 contains one of 8,9 -> R89C1 must contain one of 8,9 -> R89C1 = {39/48} (cannot be {57} which doesn’t contain one of 8,9), no 5,7
4b. R23C1 = {16/25} (cannot be {34} which clashes with R89C1), no 3,4

5. 45 rule on N1 3 innies R2C3 + R3C23 = 10 = {136/235} (cannot be {127/145} which clash with R23C1), no 4,7

6. 4,7 in N1 only in 28(4) cage = {4789} (only remaining combination), no 5,6

7. 45 rule on N4 2 innies R4C1 + R6C3 = 1 outies R3C3 + 12
7a. Min R4C1 + R6C3 = 13, no 1,2,3

8. 10(3) cage in N7 = {127/145/235} (cannot be {136} which clashes with R7C12), no 6

9. 45 rule on N9 2(1+1) outies R6C9 + R9C6 = 11 = {29/38/47/56}, no 1 in R6C9 + R9C6

10. 45 rule on R6789 1 innie R6C5 = 1 outie R5C1 + 1, no 9 in R5C1

11. 45 rule on N5 3 innies R4C6 + R6C46 = 11 = {128/137/146/236/245}, no 9

12. 45 rule on N4 4 innies R4C1 + R456C3 = 20 = {1289/1469/1478/1568/2567} (cannot be {1379} because no 4 in R3C3, cannot be {2369/2378/2468} because 8(3) cage at R3C3 cannot contain both of 2,3 or both of 2,4, cannot be {2459/3458/3467} which clash with R45C2), no 3 in R45C3
12a. 6,7,8,9 only in R4C1 + R6C3 -> no 4,5 in R4C1 + R6C3

13. 6 in N1 only in R2C13 + R3C23, CPE no 6 in R4C1

14. 45 rule on N1 2 outies R1C4 + R4C1 = 1 innie R3C3 + 8
14a. Max R3C3 = 5 -> max R1C4 + R4C1 = 13, min R4C1 = 7 -> max R1C4 = 6

[Ed wrote “This one is technically easier than the last couple. No tricks or really advanced moves needed.” Even so I’ve used a short forcing chain which cracks the puzzle; after that it’s straightforward.]

15. Consider placement for 1 in N1
R2C1 = 1 => R3C1 = 6 => R3C45 = {78}, locked for R3
or 1 in R3C123 => no 1 in R3C8 => no 8 in R3C9
-> no 8 in R3C9, clean-up: no 1 in R3C8

16. Hidden killer pair 8,9 in R3C45 and R3C7 for R3, R3C45 must contain one of 8,9 -> R3C7 = {89}, clean-up: R2C7 = {23} (step 3)

17. Combined cage R23C45 = 13(2) + 15(2) = 28(4) = {4789/5689}
17a. 14(4) cage at R1C5 (step 2b) = {1247/1256} (cannot be {1346} which clashes with R23C45), no 3 -> R2C7 = 2, R1C56 + R2C6 = {147/156}, R3C7 = 9 (step 3), clean-up: no 7 in R12C9, no 5 in R3C1, no 6 in R3C45, no 7 in R3C89, no 6 in R5C8

18. Naked pair {78} in R3C45, locked for R3 and N2, clean-up: no 5 in R2C45
18a. Naked pair {49} in R2C45, locked for R2 and N2, clean-up: no 5 in R1C9
18b. R1C4 + R3C6 = {23} (hidden pair in N2)

19. 4 in R3 only in R3C89 = {45}, locked for R3 and N3
19a. 6 in R3 only in R3C12, locked for N1, clean-up: no 1 in R3C1
19b. Killer pair 3,5 in R2C3 and 8(3) cage at R3C3, locked for C3

20. 11(3) cage in N9 = {146/236} (cannot be {137} which clashes with R12C9, cannot be {245} which clashes with R3C9), no 5,7, 6 locked for C9 and N9, clean-up: no 3 in R12C9, no 5 in R9C6 (step 9)
20a. Naked pair {18} in R12C9, locked for C9 and N3, clean-up: no 4 in 11(3) cage in N9, no 3 in R9C6 (step 9)
20b. Naked triple {236} in 11(3) cage, locked for C9 and N9, clean-up: no 8,9 in R9C6 (step 9)

21. 14(3) cage at R6C9 = {149} (only remaining combination) -> R6C9 = 9, R7C78 = {14}, locked for R7 and N9, R9C6 = 2 (step 9), R3C6 = 3, R1C4 = 2, clean-up: no 7 in R7C12, no 6 in R7C5, no 6,7 in R8C5, no 7 in R9C45
21a. Naked pair {57} in R89C7, locked for C7, clean-up: no 1,3 in R5C8
21b. 7 in N3 only in R12C8, locked for C8, clean-up: no 1 in R5C7

22. R2C3 + R3C23 (step 5) = {136} (only remaining combination, cannot be {235} because 3,5 only in R2C3) -> R2C3 = 3, R3C23 = [61], R23C1 = [52], R4C1 = 7 (cage sum), clean-up: no 5 in R45C2, no 3 in R7C2
22a. R5C9 = 7 (hidden single in C9)
22b. R45C3 = {25} (hidden pair in C3), locked for N4

23. R3C67 = [39] = 12 -> R4C67 = 9 = {18} (cannot be {45} which clashes with R4C9), locked for R4, clean-up: no 4 in R5C2

24. 9 in N4 only in R45C2 = {39}, locked for C2 and N4

25. 13(3) cage in N4 = {148} (only remaining combination), locked for N4 -> R6C3 = 6, clean-up: no 9 in R78C3 (step 4), no 4,7 in R8C4
25a. Naked pair {78} in R78C3, locked for C3 and N7 -> R9C3 = 4, R1C3 = 9, clean-up: no 5 in R9C45
25b. R7C1 = 6 (hidden single in C1), R7C2 = 2, R7C9 = 3, R9C9 = 6, R8C9 = 2, clean-up: no 5 in R8C5, no 3 in R9C45
25c. 1 in C1 only in R56C1, locked for N4

26. Naked pair {18} in R9C45, locked for R9 and N8 -> R8C5 = 3, R7C5 = 5, R8C4 = 6, R8C3 = 7, R89C1 = [93], R8C6 = 4
26a. 4 in N6 only in 14(3) cage = {347} (only remaining combination) -> R4C89 = [34], R3C89 = [45], R45C2 = [93], R5C7 = 6, R5C8 = 2, R7C78 = [41], R6C8 = 5, R45C3 = [25]

27. R4C45 = [56] -> R5C4 = 4 (cage sum), R2C45 = [94]
27a. Naked pair {89} in R5C56, locked for R5 and N5 -> R4C6 = 1

and the rest is naked singles.

Rating Comment. I'll rate my walkthrough for A206 at Easy 1.5 because I used a very short forcing chain. From Ed's introductory comment it's likely that the rating for this puzzle should be a bit lower although possibly using a longer solving path.
Ed's start:
Andrew wrote:
I'll guess from your introductory comment that my breakthrough step probably wasn't the way you intended it to be solved....However.... it avoided messy combination analysis
Glad you enjoyed this puzzle Andrew. You interpreted my intro perfectly with the exception of your step 12. I avoid that type of combo analysis (which must sound pretty silly since this is killer sudoku!!) when there are so many combinations involved. I missed that nice chain you found...though we worked in the same areas. You'll kick yourself about a couple of "45"s you missed!! They took me a long time to find.

This is an alternative way to crack A206. Starting after Andrew's step 6.
6 steps End of Andrew's step 6 here
.-------------------------------.-------------------------------.-------------------------------.
| 4789 4789 4789 | 234567 1234567 1234567 | 123456789 1234567 12345678 |
| 1256 4789 2356 | 4589 4589 1234567 | 2345678 1234567 12345678 |
| 1256 12356 1235 | 6789 6789 234567 | 3456789 1234567 2345678 |
:-------------------------------+-------------------------------+-------------------------------:
| 123456789 345789 12345 | 123456789 123456789 123456789 | 12345678 1234567 123456789 |
| 123456789 345789 12345 | 123456789 23456789 23456789 | 123567 123567 123456789 |
| 123456789 123456789 23456789 | 123456789 23456789 123456789 | 12345678 1234567 123456789 |
:-------------------------------+-------------------------------+-------------------------------:
| 123567 123567 6789 | 123456789 123567 123456789 | 1234567 1234567 1234567 |
| 3489 1234567 6789 | 4567 123567 123456789 | 1234567 89 1234567 |
| 3489 1234567 234567 | 12345678 12345678 123456789 | 1234567 89 1234567 |
'-------------------------------.-------------------------------.-------------------------------'


7. "45" on r12: 1 outie r3c1 + 3 = 2 innies r1c4 + r2c3
7a. -> no 3 in r1c4 (IOU)

8. 3 in r1 only in r1c56789 -> no 3 in r2c7 (CPE)
8a. no 8 in r3c7 (h11(2)r23c7)

9. "45" on n14: 1 outie r1c4 + 4 = 1 innie r6c3
9a. r1c4 = (245), r6c3 = (689)

Now the hardest one
10. "45" on r12: 3 innies r1c4 + r2c13 = 10
10a. the only way for r1c4 + r2c3 to sum to 9 (and -> have 1 in r2c1) is [45]: however, this is blocked by 13(2)n2 which must have 4/5
10b. -> no 1 in r2c1
10c. no 6 in r3c1

11. 1 in n1 only in r3: locked for r3
11a. no 8 in r3c9

12. 8 in r3 only in 15(2)n2 = {78} only: both locked for r3 and n2

Cracked.


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PostPosted: Sun Oct 26, 2014 9:38 pm 
Offline
Grand Master
Grand Master

Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1894
Location: Lethbridge, Alberta, Canada
Assassin 207 by Ed (March 2011) here
Puzzle Diagram:
Image
Puzzle Diagrams with "udosuk style Killer Cages":
Image     Image
Code: Select, Copy & Paste into solver:
3x3::k:3585:3585:3585:5634:5634:5634:3843:3076:3076:1029:1029:2566:2566:5634:7175:3843:3076:3336:4105:9738:9738:2566:7175:7175:7175:4363:3336:4105:4105:9738:2828:2828:7175:4363:4363:11533:2830:2830:9738:9738:2063:2063:4363:11533:11533:5136:5136:9738:2833:2833:5906:11533:11533:11533:5136:9738:9738:4627:5906:5906:5906:11533:11533:3860:3860:4627:4627:3349:5906:3350:3863:11533:3352:3352:3352:3349:3349:3349:3350:3863:3863:
Solution:
+-------+-------+-------+
| 8 2 4 | 3 6 9 | 7 1 5 |
| 3 1 7 | 2 4 5 | 8 6 9 |
| 6 5 9 | 1 8 7 | 2 3 4 |
+-------+-------+-------+
| 1 9 2 | 4 7 6 | 5 8 3 |
| 4 7 6 | 8 5 3 | 1 9 2 |
| 5 8 3 | 9 2 1 | 6 4 7 |
+-------+-------+-------+
| 7 4 1 | 6 9 2 | 3 5 8 |
| 9 6 5 | 7 3 8 | 4 2 1 |
| 2 3 8 | 5 1 4 | 9 7 6 |
+-------+-------+-------+
Quote:
Ed: Hard to believe it's now three years since Ruud posted his last Assassin. This one is worthy of his legacy except it is not symmetrical. Found a fun way through this one with two key moves. Not complicated but both are a twist on the simplest version of that type of move. Presumably that means there are other ways to solve this. Good luck!

Andrew: Thanks Ed for a challenging Assassin! I've no idea whether the steps I used are the ones you referred to but my first key move is certainly a twist on a known technique. I found it harder than your recent Assassins so maybe I missed something.
My walkthrough would have been shorter if I hadn't missed one important step when it first became available; however I didn't feel that it was an obvious step (some may disagree with that) so I haven't re-worked my steps but only made comments about it.
Many thanks to Ed for the comments and one correction, all given in blue in my walkthrough; I've also added a general comment at the end.
Ed told me that his solving method was very different. I'll be interested to see how you did it.

Ed:
At the end of his WT Andrew wrote:
[R..C.. and R..C.. were very important in my solving path, with some of the steps involving them being hard to spot.]
Got another step to add to those cells! Plus, a very different way to get to Andrew's first placement. Thanks very much Andrew for finding another way through this one. It shows how long and difficult a puzzle it is without my two key steps (8 & 15), especially the second. I managed to find those two fairly quickly so didn't realise how resistant this puzzle could be.

I've used Andrew's steps up to the end of 7.

Andrew: Congratulations Ed for spotting your two steps fairly quickly. :applause: Neither of them are obvious so I don't feel that I missed something that I ought to have seen. Your steps should lead to a shorter solving path than mine. Not a "clone" in sight for you! ;)

Ed:
Andrew wrote:
Congratulations Ed for spotting your two steps fairly quickly...Neither of them are obvious so I don't feel that I missed something that I ought to have seen.
Thanks! I routinely look for direct-link candidates (if X -> Y) in a cage whenever I look at a list of combinations....perhaps in the way you routinely do cage-placement clean-up in your walk-throughs. In contrast, I don't look for those clean-ups except if I'm stuck. I also look for killer halves routinely in case an easy block/pair is available. I rarely look for killer thirds as a block but do look for a third for if it may lead to a killer triple.
Another way to see my step 15 is using CCC but you have to see the direct linked candidate first.

Walkthrough by Andrew:
Thanks Ed for a challenging Assassin! I've no idea whether the steps I used are the ones you referred to but my first key move is certainly a twist on a known technique. I found it harder than your recent Assassins so maybe I missed something.

My walkthrough would have been shorter if I hadn't missed one important step when it first became available; however I didn't feel that it was an obvious step (some may disagree with that) so I haven't re-worked my steps but only made comments about it.

Many thanks to Ed for the comments and one correction, all given in blue in my walkthrough; I've also added a general comment at the end.

Ed told me that his solving method was very different. I'll be interested to see how you did it.

Here is my walkthrough for A207

Prelims

a) R12C7 = {69/78}
b) R2C12 = {13}
c) R23C9 = {49/58/67}, no 1,2,3
d) R4C56 = {29/38/47/56}, no 1
e) R5C12 = {29/38/47/56}, no 1
f) R5C56 = {17/26/35}, no 4,8,9
g) R6C45 = {29/38/47/56}, no 1
h) R8C12 = {69/78}
i) R89C7 = {49/58/67}
j) 10(3) cage at R2C3 = {127/136/145/235}, no 8,9
k) 20(3) cage at R6C1 = {389/479/569/578}, no 1,2
l) 13(4) cage in N8 = {1237/1246/1345}, no 8,9
m) 38(8) cage at R3C2 = {12345689}, no 7
n) And of course 45(9) cage at R4C9 = {123456789}

Steps resulting from Prelims
1a. Naked pair {13} in R2C12, locked for R2 and N1
1b. R23C9 = {49/58} (cannot be {67} which clashes with R12C7), no 6,7
1c. R89C7 = {49/58} (cannot be {67} which clashes with R12C7), no 6,7
1d. Killer pair 8,9 in R12C7 and R23C9, locked for N3
1e. Killer pair 8,9 in R12C7 and R89C7, locked for C7
1f. 13(4) cage in N8 = {1237/1246/1345}, 1 locked for N8

2. 45 rule on N3 2 innies R3C78 = 5 = {14/23}

3. 10(3) cage at R2C3 = {127/145/235} (cannot be {136} because 1,3 only in R3C4), no 6
3a. 1,3 only in R3C4 -> R3C4 = {13}
3b. Killer pair 1,3 in R3C4 and R3C78, locked for R3

4. 45 rule on C789 2 innies R37C7 = 5 = {14/23}

5. 14(3) cage in N1 = {248/257}, no 6,9, 2 locked for R1 and N1
5a. 6,9 in N1 only in R3C123, locked for R3, clean-up: no 4 in R2C9
5b. 10(3) cage at R2C3 (step 3) = {127/145/235}
5c. 2 of {127} must be in R2C4 -> no 7 in R2C4

6. 45 rule on R9 3 outies R8C578 = 9 = {135/234} (cannot be {126} because R8C7 only contains 4,5), 3 locked for R8, clean-up: no 4,5 in R9C7
6a. R8C7 = {45} -> no 4,5 in R8C58

7. 15(3) cage in N9 can only have one of 1,2,3 in R8C8 -> no 1,2,3 in R9C89

8. 2 in C9 only in R45678C9, locked for 45(9) cage at R4C9 -> no 2 in R567C8 + R6C7

9. 45 rule on N1 4 innies R2C3 + R3C123 = 27 = {4689/5679}
9a. 4 of {4689} must be in R2C3 -> no 4 in R3C123

10. 45 rule on N2 3(1+2) outies R2C3 + R3C7 + R4C6 = 15
10a. Max R2C3 = 7 -> min R3C7 + R4C6 = 8 -> min R4C6 = 5 (because R3C7 + R4C6 cannot be [44])

11. 45 rule on N8 3(1+2) outies R6C6 + R7C7 + R8C3 = 9
11a. Min R6C6 + R7C7 = 3 -> max R8C3 = 6
11b. Max R6C6 + R7C7 = 8 -> max R6C6 = 7
11c. Max R8C3 = 6 -> min R78C4 = 12, no 2 in R78C4

12. 45 rule on R12 2 innies R2C69 = 1 outie R3C4 + 13
12a. R3C4 = {13} -> R2C69 = 14,16 = {59}/[68/79], no 2,4, no 8 in R2C6

13. 45 rule on N9 4 innies R7C789 + R8C9 = 17 = {1268/1349/1358/1367/2357} (cannot be {1259/2348} which clash with R89C7, cannot be {1457/2456} which clash with R8C7)

14. 45 rule on C89 3 outies R456C7 = 12 = {147/156/237} (cannot be {246/345} which clash with R37C7)

15. R3C78 = 5 = {14/23} (step 2), R37C7 = 5 = {14/23} (step 5) -> R3C8 = R7C7, R4C78 + R5C7 = R7C89 + R8C9 Law of Leftovers, must contain the same 3 numbers -> 17(4) cage at R3C8 = R7C789 + R8C9 and must contain the same 4 numbers

16. R7C789 + R8C9 (step 13) = {1268/1349/1358/1367/2357} -> 17(4) cage at R3C8 = {1268/1349/1358/1367/2357} (step 15)
16a. 17(4) cage at R3C8 = {1268/1349/1358/1367} (cannot be {2357} because 2,3 cannot be in R3C8 + R4C7 (or R3C8 + R5C7) which would clash with R3C78 and R45C7 cannot be {57} because R456C7 (step 14) cannot contain both of 5,7)
16b. 17(4) cage at R3C8 = {1268/1349/1358/1367}, CPE no 1 in R56C8
16c. 17(4) cage at R3C8 = {1268/1349/1358/1367} -> R7C789 + R8C9 = {1268/1349/1358/1367} (step 15), 1 locked for N9
16d. R7C789 + R8C9 = {1268/1349/1358/1367}, CPE no 1 in R6C7

17. 17(4) cage at R3C8 (step 16a) = {1268/1349/1358/1367}
17a. 8,9 of {1268/1349/1358} must be in R4C8 -> no 2,4,5 in R4C8
17b. 4 of {1349} must be in R45C7 (R45C7 cannot be {13} which clashes with R37C7) -> no 4 in R3C8, clean-up: no 1 in R3C7 (step 2), no 4 in R7C7 (step 4)
17c. 2 of {1268} must be in R3C8 (R45C7 cannot be {26} because R456C7 (step 14) cannot contain both of 2,6) -> no 2 in R45C7

18. 2 in C7 only in R37C7 (step 4) = {23}, locked for C7, clean-up: no 1 in R3C8 (step 2)
18a. Naked pair {23} in R3C78, locked for R3 and N3 -> R3C4 = 1
18b. Naked pair {23} in R38C8, locked for C8
18c. Naked pair {23} in R7C7 + R8C8, locked for N9
18d. R3C4 = 1 -> R2C69 (step 12a) = 14 = [59/68/95], no 7
[There’s also an important CPE but I didn’t spot it for a long time.]

19. 1 in C7 only in R45C7, locked for N6
19a. 1 in 38(8) cage at R3C2 only in R456C3 + R7C23, CPE no 1 in R89C3
19b. 1 in C3 only in R4567C3, locked for 38(8) cage at R3C2, no 1 in R7C2

20. 3 in N2 only in 22(4) cage = {2389/3469/3568} (cannot be {3478} which clashes with R3C56, ALS block), no 7
20a. 7 in N2 only in R3C56, locked for R3 and 28(5) cage at R2C6 -> no 7 in R4C6

21. Hidden killer pair 4,7 in 14(3) cage and R2C3 for N1, 14(3) cage must contain one of 4,7 -> R2C3 = {47}, clean-up: no 4 in R2C4 (step 3)

22. 45 rule on R1 3 outies R2C578 = 18 = {279/459/468} (cannot be {567} which clashes with R2C69)
22a. 2 of {279} must be in R2C5, 9 of {459} must be in R2C7 -> no 9 in R2C5
22b. 7 of {279} must be in R2C8 -> no 7 in R2C7, clean-up: no 8 in R1C7

23. 45 rule on C123 2 innies R28C3 = 1 outie R5C4 + 4
23a. R28C3 cannot be [74] = 11 because no 7 in R5C4 -> no 4 in R8C3
23b. R28C3 = [42/45/46/72/75/76] = 6,9,10,12,13 -> R5C4 = {25689}, no 3,4

24. 3,4 in 38(8) cage at R3C2 only in R456C3 + R7C23, CPE no 3,4 in R9C3

25. 18(3) cage at R7C4 = {279/369/459/468/567} (cannot be {378} because R8C3 only contains 2,5,6)
25a. 5 of {459} must be in R8C3, 5 of {567} must be in R8C34 (R8C34 cannot be {67} which clashes with R8C12) -> no 5 in R7C4

26. 45 rule on R89 4 innies R8C3469 = 21 = {1569/1578/2469/2478} (cannot be {1479/2568} which clash with R8C12)
26a. 1 of {1569/1578} must be in R8C9 -> no 5 in R8C9
[Thanks Ed for pointing out that there was an error in my original step 26a, fortunately not a serious one so I only needed to rewrite this step.]

27. 22(4) cage in N2 (step 20) = {2389/3469/3568}
27aa. 22(4) cage = {2389} => R2C4 = 5 => no 5 in R3C56
27ab. 22(4) cage = {3469}, locked for N2 => R2C6 = 5 => no 5 in R3C56
27ac. 22(4) cage = {3568}, locked for N2 => no 5 in R3C56
27b. -> no 5 in R3C56
[Ed pointed out that this step can be written directly as
27. Killer quad 2,5,6,9 in 22(4) cage, R2C4 and R2C6, locked for N2]


28. R6C6 + R7C7 + R8C3 = 9 (step 11)
28a. R8C3 = {256} -> R6C6 + R7C7 = 3,4,7 = [12/13/43/52], no 2,3,6,7 in R6C6

29. 45 rule on N5 3 innies R46C6 + R5C4 = 15 = {159/168/249/456} (cannot be {258} because the two 11(2) cages in N5 must contain at least one of 2,5,8)
29a. 1,4 only in R6C6 -> R6C6 = {14}

30. R6C6 + R7C7 + R8C3 = 9 (step 11) = [126/135] (cannot be [432] which clashes with R8C38 = [23], combo blocker) -> R6C6 = 1, R8C3 = {56}, clean-up: no 7 in R5C56
30a. R46C6 + R5C4 (step 29) = {159/168}, no 2
30b. Killer pair 5,6 in R46C6 + R5C4 and R5C56, locked for N5
30c. R5C12 = {29/38/47} (cannot be {56} which clashes with R5C56), no 5,6
[Ed pointed out that the [432] permutation in step 30 is actually blocked by R8C8, another difficult to spot effect of R8C8, like the one that I only spotted in step 39.]

31. 2 in 38(8) cage at R3C2 only in R456C3 + R7C23, CPE no 2 in R9C3

32. R8C3469 (step 26) = {1569/1578/2469} (cannot be {2478} because R8C3 only contains 5,6)
32a. 1 of {1578} must be in R8C9 -> no 7,8 in R8C9
32b. 1 of {1569} must be in R8C9, 6 of {2469} must be in R8C3 -> no 6 in R8C9
32c. 2 of {2469} must be in R8C6 -> no 4 in R8C6

33. 45 rule on C123 2 remaining outies R25C4 = 1 innie R8C3 + 5
33a. R8C3 = {56} -> R25C4 = 10,11 = [28/29/56] (cannot be [55]) -> no 5 in R5C4, clean-up: no 9 in R4C6 (step 30a)

34. 45 rule on N7 4 innies R7C123 + R8C3 = 17 = {1259/1457/2456} (cannot be {1268/1367} which clash with R8C12, cannot be {1349/2348} because R8C3 only contains 5,6, cannot be {2357} which clashes with R7C7, cannot be {1358} which clashes with R7C7 + R8C3 = [53/62], combo blocker), no 3,8 in R7C123
34a. 1,2 of {1259} must be in R7C23 -> no 9 in R7C23

35. 3 in N7 only in R9C12, locked for R9
35a. 13(3) cage in N7 = {139/238/346}, no 5,7
35b. R9C3 = {689} -> no 6,8,9 in R9C12

36. 3 in C3 only in R456C3, locked for N4, clean-up: no 8 in R5C12

37. 20(3) cage at R6C1 = {479/569/578}
37a. 4 of {479} must be in R6C12 (R6C12 cannot be {79} which clashes with R5C12) -> no 4 in R7C1

38. Variable hidden killer pair 5,7 in 13(4) cage in N8 and 15(3) in N9 for R9, 13(4) cage in N8 cannot contain more than one of 5,7 -> 15(3) cage in N9 must contain at least one of 5,7 = {258/267/357} (cannot be {249/348} which don’t contain either of 5,7), no 4,9

[The next step has been available since step 18 but I’ve only just spotted it. It probably wouldn’t have made too much difference to my solving path until I reduced R8C3 to {56} in step 30.]

39. Naked pair {23} in R7C7 + R8C8, CPE no 2 in R8C6
39a. R8C58 = {23} (hidden pair in R8), R8C7 = 4 (step 6), R9C7 = 9, R8C9 = 1, clean-up: no 6 in R12C7, no 1 in 13(3) cage in N7 (step 35a)
39b. R12C7 = [78], clean-up: no 5 in R23C9
39c. R23C9 = [94], R2C6 = 5 (step 18d), R2C8 = 6, R1C9 = 5, R1C8 = 1, R2C4 = 2, R2C5 = 4, R2C3 = 7, clean-up: no 7 in R4C4, no 9 in R4C5, no 9 in R5C4 (step 30a), no 3 in R5C5, no 7 in R6C4, no 9 in R6C5
39d. 9 in 45(9) cage at R4C9 only in R56C8, locked for N6

40. Naked pair {78} in R3C56, locked for R3, N2 and 28(5) cage at R2C6 -> R4C6 = 6, R5C4 = 8, clean-up: no 3 in R4C45, no 2 in R5C56, no 3 in R6C45
40a. R5C56 = [53], R1C6 = 9

41. Killer pair 6,8 in R8C12 and R9C3, locked for N7 -> R8C3 = 5

42. R7C3 = 1 (hidden single in R7)
42a. 1 in N4 only in R4C12, locked for R4 -> R4C7 = 5, R6C7 = 6, R5C7 = 1
42b. 16(3) cage at R3C1 must contain 1 = {169} (only remaining combination, cannot be {178} because no 1,7,8 in R3C1) -> R4C12 = {19}, locked for R4 and N4, R3C1 = 6, R3C3 = 9, R3C2 = 5, clean-up: no 2 in R4C5, no 2 in R5C12, no 9 in R8C2
42c. R4C45 = [47]

and the rest is naked singles.

[R7C7 and R8C8 were very important in my solving path, with some of the steps involving them being hard to spot.]

Rating Comment. It was hard to decide what rating to give my walkthrough for A207; I'll go for Hard 1.5. I used a cloned cage, built up from a single clone plus LOL; also a very short forcing chain and a couple of combo blockers.
Ed's alternative breakthrough:
At the end of his WT Andrew wrote:
[R..C.. and R..C.. were very important in my solving path, with some of the steps involving them being hard to spot.]
Got another step to add to those cells! Plus, a very different way to get to Andrew's first placement. Thanks very much Andrew for finding another way through this one. It shows how long and difficult a puzzle it is without my two key steps (8 & 15), especially the second. I managed to find those two fairly quickly so didn't realise how resistant this puzzle could be.

I've used Andrew's steps up to the end of 7.

A207 alternate breakthrough 8 more steps

End of Andrew's step 7 here. Select and "Paste Into" A207 in SudokuSolver
.-------------------------------.-------------------------------.-------------------------------.
| 24578 24578 24578 | 13456789 13456789 13456789 | 6789 134567 134567 |
| 13 13 457 | 245 2456789 2456789 | 6789 24567 589 |
| 456789 45689 45689 | 13 24578 24578 | 1234 1234 458 |
:-------------------------------+-------------------------------+-------------------------------:
| 123456789 123456789 12345689 | 23456789 23456789 123456789 | 1234567 123456789 123456789 |
| 23456789 23456789 12345689 | 12345689 123567 123567 | 1234567 123456789 123456789 |
| 3456789 3456789 12345689 | 23456789 23456789 123456789 | 1234567 123456789 123456789 |
:-------------------------------+-------------------------------+-------------------------------:
| 3456789 12345689 12345689 | 23456789 23456789 23456789 | 1234 123456789 123456789 |
| 6789 6789 12456789 | 2456789 123 2456789 | 45 123 12456789 |
| 123456789 123456789 123456789 | 1234567 1234567 1234567 | 89 456789 456789 |
'-------------------------------.-------------------------------.-------------------------------'


8. from step 3, 10(3)r2c3 = {127/145/235} = [3->2....] (ie 3 in 10(3)r2c3 -> must have 2 in r2c4)
8a. since 3 in r3 is only in 10(3)r2c3 or in h5(2)r3c78 -> 2 locked for common peers (Locking Cages)
8b. ie, no 2 in r3c56

9. 2 in r3 only in h5(2)r3c78 = {23} only: both locked for n3, 3 locked for r3
9a. h5(2)r37c7 = {23} only: both locked for c7
9b. r3c4 = 1

10. 1 must be in 38(8)r3c2 -> no 1 in r89c3 (CPE)

11. "45" on c89: 1 outie r6c7 + 5 = 2 innies r34c8
11a. -> min r34c8 = 6 -> no 1,2,3 in r4c8 (can't be [33])

12. 2 & 3 in n6 only in 45(9) -> no 2,3 in r7c89 + r8c9

13. hidden pair 2,3 in n9 -> r8c8 = (23)

14. 15(3)n9; {348} blocked by 13(2)n9 = [4/8..]; {456} blocked by r8c7
14a. 15(3)n9 = {249/258/267/357} = [3->5..](no eliminations yet)

15. from step 6, h9(3)r8c578 = {135/234}
15a. but [153] blocked by 15(3)n9 (step 14a) (Blocking Cages)
15b. -> h9(3) = {234} only
15c. r8c7 = 4, 2 locked for r8
15d. r8c9 = 1 (hidden single r8)
15e. r9c7 = 9


Much easier now....but still with some work to do. Sorry I don't have time to go any further.
Ed's alternative way to do his step 15:
15. Since if 3->5 in 15(3)n9 (step 14)
15a. -> a possible hidden 8(2) at r8c8
15b. -> r8c78 <> sum to 8 (CCC)
15c. -> h9(3)r8c578: no 1 in r8c5


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PostPosted: Sun Oct 26, 2014 9:53 pm 
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Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1894
Location: Lethbridge, Alberta, Canada
Assassin 208 by Ed (March 2011) here
Puzzle Diagram:
Image
Puzzle Diagrams with "udosuk style Killer Cages":
Image     Image
Code: Select, Copy & Paste into solver:
3x3::k:4865:4865:4865:7682:2307:2307:3332:3332:2053:1286:1286:7682:7682:2307:4631:4631:5656:2053:2312:2312:3593:7682:7682:4631:7434:5656:2053:11531:3593:3593:6412:6412:6412:7434:5656:5656:11531:6925:6925:6925:6412:7434:7434:7434:3598:11531:2831:6925:1808:6412:2321:2321:3598:3598:11531:2831:6925:1808:11531:2322:4115:4115:4115:11531:11531:11531:11531:7956:2322:2322:2325:4118:2567:2567:2567:7956:7956:7956:7956:2325:4118:
Solution:
+-------+-------+-------+
| 2 9 8 | 5 4 3 | 6 7 1 |
| 4 1 7 | 9 2 6 | 5 8 3 |
| 6 3 5 | 1 8 7 | 2 9 4 |
+-------+-------+-------+
| 7 8 1 | 6 5 4 | 9 3 2 |
| 9 2 3 | 7 1 8 | 4 6 5 |
| 5 4 6 | 3 9 2 | 7 1 8 |
+-------+-------+-------+
| 1 7 9 | 4 3 5 | 8 2 6 |
| 8 6 4 | 2 7 1 | 3 5 9 |
| 3 5 2 | 8 6 9 | 1 4 7 |
+-------+-------+-------+
Quote:
Ed: One of the things I do to find interesting Assassins is try puzzles JSudoku solves (using "Deduce all moves") in a flash but SudokuSolver has a lot of trouble with. Unfortunately, I usually can't solve them so they have to get ditched. Fortunately, got to keep this one.
It takes me two key moves both similar in complexity to the last puzzle. Nothing heavy but still advanced moves. They are fairly common in walk-throughs here so am fairly hopeful that it will get a "fun" rating. It has big progress early so gets you hooked. However, it takes me about 30 steps to finally get it fully cracked so takes some patience.

Andrew: Thanks Ed for continuing to post Assassins! :D
Ed wrote:
...so am fairly hopeful that it will get a "fun" rating.
Not sure I'll go quite that far but the eliminations in the interestingly shaped 45(9) cage seemed fun; I don't think that's giving anything away.

Ed:
Andrew wrote:
Thanks Ed for continuing to post Assassins! :D
You're welcome! I'm really enjoying making them since I'm finding interesting puzzles without too much effort. Perhaps the non-symmetrical shapes with at least one big cage helps this. And I enjoy getting your feedback! I'm a couple ahead so should be able to continue fortnightly.
I missed Andrew's nifty blocks (18 and 21a) even though I looked hard in that area. Instead, my key move (16a) gets chunkier progress in the middle stages of this puzzle. Very satisfied.
I'll start with an alternate way to do Andrew's step 15a which is around the same difficulty level I guess.

Walkthrough by Andrew:
Thanks Ed for continuing to post Assassins! :D

Ed wrote:
...so am fairly hopeful that it will get a "fun" rating.
Not sure I'll go quite that far but the eliminations in the interestingly shaped 45(9) cage seemed fun; I don't think that's giving anything away.

Here is my walkthrough for A208

Prelims

a) R1C78 = {49/58/67}, no 1,2,3
b) R2C12 = {14/23}
c) R3C12 = {18/27/36/45}, no 9
d) R67C2 = {29/38/47/56}, no 1
e) R67C4 = {16/25/34}, no 7,8,9
f) R6C78 = {18/27/36/45}, no 9
g) R89C8 = {18/27/36/45}, no 9
h) R89C9 = {79}
i) 19(3) cage in N1 = {289/379/469/478/568}, no 1
j) 9(3) cage in N2 = {126/135/234}, no 7,8,9
k) 8(3) cage in N3 = {125/134}
l) 9(3) cage at R7C6 = {126/135/234}, no 7,8,9
m) 10(3) cage in N7 = {127/136/145/235}, no 8,9
n) 31(5) cage at R8C5 must contain 9
o) And of course 45(9) cage at R4C1 = {123456789}

Steps resulting from Prelims
1a. Naked pair {79} in R89C9, locked for C9 and N9, clean-up: no 2 in R89C8
1b. 8(3) cage in N3 = {125/134}, 1 locked for C9 and N3
1c. 9 in 31(5) cage at R8C5 only in R8C5 + R9C456, locked for N8
1d. 9 in R7 only in R7C123, locked for N7
1e. 9 in 45(9) cage at R4C1 only in R4567C1, locked for C1

2. 45 rule on R1 4 innies R1C4569 = 13 = {1237/1246/1345}, no 8,9

3. 45 rule on R1 2 innies R1C49 = 1 outie R2C5 + 4, IOU no 4 in R1C9

4. 45 rule on N1 2 innies R23C3 = 12 = {39/48/57}, no 1,2,6

5. 45 rule on N2 2 outies R2C37 = 12 = {39/48/57}, no 1,2,6

6. 45 rule on N9 2 innies R89C7 = 4 = {13}, locked for C7 and N9, clean-up: no 9 in R2C3 (step 5), no 3 in R3C3 (step 4), no 6,8 in R6C6, no 6,8 in R89C8
6a. Naked pair {45} in R89C8, locked for C8 and N9, clean-up: no 8,9 in R1C7
6b. Naked triple {268} in 16(3) cage in N9, locked for R7, clean-up: no 3,5,9 in R6C2, no 1,5 in R6C4
6c. 3 in N3 only in 8(3) cage + R23C8, CPE no 3 in R4C9

7. 9(3) cage at R7C6 = {135/234} (cannot be {126} because 2,6 only in R8C6), no 6, CPE no 3 in R8C45
7a. 2 of {234} must be in R8C6 -> no 4 in R8C6

8. 45 rule on R9 3 outies R8C589 = 21 = {489/579} (cannot be {678} because R8C8 only contains 4,5), no 1,2,6
8a. R8C8 = {45} -> no 4,5 in R8C5

9. 31(5) cage at R8C5 = {16789/34789/35689} (other combinations don’t contain 1 or 3), no 2, 8 locked for N8
9a. R9C7 = {13} -> no 1,3 in R9C456
9b. 2 in N8 only in R8C46, locked for R8

10. 2 in R9 only in 10(3) cage = {127/235}, no 4,6

11. 6 in R9 only in R9C456, locked for N8
11a. 31(5) cage at R8C5 (step 9) = {16789/35689}, no 4
11b. 6 in R8 only in R8C123, locked for 45(9) cage at R4C1, no 6 in R456C1

12. R9C8 = 4 (hidden single in R9), R8C8 = 5
12a. R8C589 (step 8) = {579} (only remaining combination) -> R8C59 = {79}, locked for R8
12b. 4 in R8 only in R8C1234, locked for 45(9) cage at R4C1, no 4 in R4567C1 + R7C5
12c. 8 in R8 only in R8C123, locked for 45(9) cage at R4C1, no 8 in R456C1

13. 9(3) cage at R7C6 (step 7) = {135/234}
13a. 4,5 only in R7C6 ->R7C6 = {45}
13b. R8C67 = {13/23}, 3 locked for R8

[I was slow spotting the next step but since it simplified the lower part of the grid I’ve re-worked this area to include it.]
14. 45 rule on N89 3 innies R7C45 + R8C4 = 9 = {135/234}, no 7, 3 locked for N8
14a. 1,2 of {135/234} must be in R8C4 -> R8C4 = {12}
14b. Naked pair {12} in R8C46, locked for R8 and N8 -> R8C7 = 3, R9C7 = 1, clean-up: no 6 in R6C4, no 7 in 10(3) cage in N7 (step 10)
14c. Naked triple {345} in R7C456, locked for R7 and N8, clean-up: no 6,7,8 in R6C2
14d. 7 in 45(9) cage at R4C1 only in R4567C1, locked for C1, clean-up: no 2 in R3C2

15. 1 in N1 only in R2C12 = {14} or R3C12 = {18} -> R3C12 = {18/36}/[27] (cannot be {45}, locking-out cages), no 4,5
15a. R2C12 = {14} or R3C12 = {18} -> R23C3 = [39/57/75] (cannot be {48}, locking-out cages), no 4,8, clean-up: no 4,8 in R2C7 (step 5)
[I hope I’ve now described these steps correctly.]
15b. Min R3C3 = 5 -> max R4C23 = 9, no 9 in R4C23

16. 19(3) cage in N1 = {289/469/568} (cannot be {379} which clashes with R23C3, cannot be {478} which clashes with R1C78), no 3,7
16a. 7 in N1 only in R2C3 + R3C23, CPE no 7 in R3C45
16b. 3 in R1 only in R1C4569 (step 2) = {1237/1345}, no 6

17. 45 rule on N36 2 innies R26C7 = 1 outie R5C6 + 4
17a. Min R26C7 = 7 -> min R5C6 = 3

18. 14(3) cage in N6 = {158/248/257/347/356} (cannot be {149/167} because 1,7,9 only in R6C8, cannot be {239} which clashes with 8(3) cage in N3), no 9
18a. 8 of {248} must be in R56C9 (R56C9 cannot be {24} which clashes with 8(3) cage in N3) -> no 8 in R6C8
18b. 6 of {356} must be in R56C9 (R56C9 cannot be {35} which clashes with 8(3) cage in N3) -> no 6 in R6C8

19. 45 rule on C89 2 innies R15C8 = 1 outie R7C7 + 5
19a. Max R7C7 = 8 -> max R15C8 = 13, min R1C8 = 6 -> max R5C8 = 7

20. Killer pair 4,5 in 8(3) cage in N3 and 14(3) cage in N6, locked for C9
[I ought to have spotted this killer pair while I was analysing step 18.]
20a. 22(4) cage at R2C8 = {1678/2389} -> R4C8 = {123} (R23C8 + R4C9 cannot contain both of 2,3 which would clash with 8(3) cage in N3 because R23C8 + R4C9 are common peers of the 8(3) cage)

21. 9 in N6 only in R45C7, locked for C7 and 29(5) cage at R3C7, no 9 in R5C6, clean-up: no 3 in R2C3 (step 5), no 9 in R3C3 (step 4)

22. Naked pair {57} in R2C37, locked for R2

23. Naked pair {57} in R23C3, locked for C3 and N1, clean-up: no 2 in R3C1

24. 19(3) cage in N1 (step 16) = {289/469}, 9 locked for R1, clean-up: no 4 in R1C7

25. Killer pair 5,7 in R1C78 and R2C7, locked for N3, clean-up: no 2 in 8(3) cage in N3

26. Naked triple {134} in 8(3) cage in N3, locked for C9 and N3

27. 22(4) cage at R2C8 (step 20a) = {2389} (only remaining combination) -> R4C8 = 3, R23C8 = {289}, R4C9 = {28}

28. 5 in C9 only in R56C9, locked for N6, clean-up: no 4 in R6C6
28a. 14(3) cage in N6 (step 18) = {158/257}, no 6
28b. Naked triple {258} in R456C9, locked for C9 and N6 -> R7C9 = 6, clean-up: no 1,7 in R6C6

29. Naked triple {289} in R237C8, locked for C8, clean-up: no 5 in R1C7
29a. Naked pair {67} in R1C78, locked for R1 and N3 -> R2C8 = 5, R23C3 = [75]

30. 19(3) cage in N1 (step 24) = {289} (only remaining combination), locked for R1 and N1, clean-up: no 3 in R2C12, no 1 in R3C12
30a. Naked pair {14} in R2C12, locked for R2 -> R2C9 = 3, R13C9 = [14]
30b. Naked pair {36} in R3C12, locked for R3

31. 9(3) cage in N2 = {234} (only remaining combination) -> R2C5 = 2, R1C56 = {34}, locked for R1 -> R1C4 = 5, clean-up: no 2 in R6C4

32. Naked pair {34} in R67C4, locked for C4

33. R2C7 = 5 -> R23C6 = 13 = [67]

34. 45 rule on N36 2 outies (no remaining innies) R56C6 = 10 = [82], R6C7 = 7, R1C78 = [67], R3C7 = 2, R56C8 = [61], R6C2 = 4, R7C2 = 7, R67C4 = [34], R78C6 = [51], R7C5 = 3, R7C78 = [82], R8C4 = 2, R9C6 = 9, R8C5 = 7, R89C9 = [97], R4C6 = 4, R45C7 = [94], R2C12 = [41]
34a. R8C3 = 4 (hidden single in R8)

35. 14(3) cage in N6 (step 28a) = {158} (only remaining combination) -> R56C9 = [58]

36. R5C23 = {23} (hidden pair in R5) = 5 -> R5C4 + R67C3 = 22 = [769]

and the rest is naked singles.

Thanks Ed for the feedback about how I described step 15 and for correcting a couple of typos.

Rating Comment. I'll rate my walkthrough for A208 at Easy 1.5, based on my use of locking-out cages in step 15, the not particularly obvious killer pair in step 20 and the analysis in step 20a. I also avoided any temptation to give a lower rating because I found several important steps difficult to spot, even when they weren't technically difficult.

Step 15 could alternatively have been done using a combined cage R23C12 with the restriction that it must contain 1; I saw the locking-out cages first, plus I think they are the "cleaner" way to do this step.
Ed's alternative breakthrough:
Andrew wrote:
Thanks Ed for continuing to post Assassins! :D
You're welcome! I'm really enjoying making them since I'm finding interesting puzzles without too much effort. Perhaps the non-symmetrical shapes with at least one big cage helps this. And I enjoy getting your feedback! I'm a couple ahead so should be able to continue fortnightly.

I missed Andrew's nifty blocks (18 and 21a) even though I looked hard in that area. Instead, my key move (16a) gets chunkier progress in the middle stages of this puzzle. Very satisfied.

I'll start with an alternate way to do Andrew's step 15a which is around the same difficulty level I guess.

Alternate breakthrough for A208 7 steps

Alternative way to get the elimination in Andrew's 15a.

Before Andrew's step 15a here; use "Paste Into" A208 in SudokuSolver

.-------------------------------.-------------------------------.-------------------------------.
| 234568 23456789 23456789 | 1234567 123456 123456 | 4567 6789 1235 |
| 1234 1234 34578 | 123456789 123456 123456789 | 45789 236789 12345 |
| 12368 13678 45789 | 123456789 123456789 123456789 | 2456789 236789 12345 |
:-------------------------------+-------------------------------+-------------------------------:
| 123579 123456789 123456789 | 123456789 123456789 123456789 | 2456789 1236789 24568 |
| 123579 123456789 123456789 | 123456789 123456789 123456789 | 2456789 1236789 234568 |
| 123579 24 123456789 | 234 123456789 123457 | 245678 1236789 234568 |
:-------------------------------+-------------------------------+-------------------------------:
| 179 79 179 | 345 35 45 | 268 268 268 |
| 468 468 468 | 12 79 12 | 3 5 79 |
| 235 235 235 | 6789 6789 6789 | 1 4 79 |
'-------------------------------.-------------------------------.-------------------------------'

15a. r123c1 must have two of 4,6,8 for c1 since the only other place is r8c1 -> {48} blocked from h12(2)r23c3 (no 4,8)
15b. no 4,8 in r2c7 (h12(2)r2c37)
15c. 9 in n1 only in r1 or r3c3 (no eliminations yet)

16. "45" on n12: 1 outie r2c7 = 1 innie r3c3
16a. -> from step 15c. no 9 in r1c8 (Clone CPE)
16b. no 4 in r1c7

17. 9 in r1 only in n1: locked for n1
17a. no 3 in r2c3, no 9 in r2c7

18. Killer pair 5,7 in n3 in 15(2) + r2c7: both locked for n3

19. 8(3)n3 = {134} only: 3,4 locked for n3 & c9

20. 14(3)n6 = {158/257/356} ({167} blocked by 1,7 only in r6c8;{239} blocked by 3,9 only in r6c8)
20a. must have 5; 5 locked for n6 & c9
20b. must have 1/3/7 -> r6c8 = (137)
20c. no 4 in r6c6

21. 22(4)r2c8: {1678} blocked by 1,7 only in r4c8
21a. = {2389} only

Back to Andrew's step 27.


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PostPosted: Sun Oct 26, 2014 10:07 pm 
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Joined: Wed Apr 23, 2008 6:04 pm
Posts: 1894
Location: Lethbridge, Alberta, Canada
Assassin 209 by Ed (March 2011) here
Puzzle Diagram:
Image
Puzzle Diagrams with "udosuk style Killer Cages":
Image     Image
Code: Select, Copy & Paste into solver:
3x3::k:3073:3073:4354:2563:5636:5636:5636:4613:4613:3073:4354:4354:2563:3334:3334:5636:4613:4103:2312:8713:8713:8713:8713:8713:5636:5636:4103:2312:5386:5386:7435:7435:8713:8713:6668:4103:6925:5386:5386:7435:7435:7435:6668:6668:6668:6925:6925:8206:8206:7435:3343:3343:6668:2320:6925:5905:5905:8206:8206:8206:8206:8206:2320:6925:5905:5905:4114:3603:3603:5652:3349:3349:2326:2326:2326:4114:5652:5652:5652:5652:3349:
Solution:
+-------+-------+-------+
| 3 5 6 | 4 7 1 | 2 8 9 |
| 4 2 9 | 6 8 5 | 3 1 7 |
| 7 8 1 | 2 3 9 | 5 4 6 |
+-------+-------+-------+
| 2 6 5 | 8 1 7 | 4 9 3 |
| 9 3 7 | 5 2 4 | 8 6 1 |
| 1 4 8 | 3 9 6 | 7 2 5 |
+-------+-------+-------+
| 8 9 3 | 1 5 2 | 6 7 4 |
| 5 7 4 | 9 6 8 | 1 3 2 |
+-------+-------+-------+
Quote:
Ed: Technically easier than recent Assassins but took some good searching to find the way through. As usual, lots of nooks and crannies to explore.

For anyone who uses JSudoku, below is a screen shot of it working on finding cage totals for a previous version of this cage pattern. Incredible numbers!:
Image

The final stats were
Code:
Generate Grid done in 17,317,171 milliseconds
1,392,059,856 nodes traversed

Andrew: Thanks Ed for a fun Assassin! :D
Ed wrote:
Technically easier than recent Assassins but took some good searching to find the way through. As usual, lots of nooks and crannies to explore.
That's a very good description of this puzzle. I didn't use any difficult steps but some of them took me a while to find.
Some time ago I typed up a table of combinations; they were very useful for the larger cages in this puzzle, including saving me the bother of typing the combinations again.

HATMAN: Very pleasant Ed
great combo eliminations and I liked the way:
the IOU in N3 helped sort out N6

Ed: Glad you enjoyed this one guys. I used a different breakthrough to Andrew's nice block. Missed that.

Walkthrough by Andrew:
Thanks Ed for a fun Assassin! :D

Ed wrote:
Technically easier than recent Assassins but took some good searching to find the way through. As usual, lots of nooks and crannies to explore.
That's a very good description of this puzzle. I didn't use any difficult steps but some of them took me a while to find.

Some time ago I typed up a table of combinations; they were very useful for the larger cages in this puzzle, including saving me the bother of typing the combinations again.

Here is my walkthrough for A209

Prelims

a) R12C4 = {19/28/37/46}, no 5
b) R2C56 = {49/58/67}, no 1,2,3
c) R34C1 = {18/27/36/45}, no 9
d) R6C67 = {49/58/67}, no 1,2,3
e) R67C9 = {18/27/36/45}, no 9
f) R89C4 = {79}
g) R8C56 = {59/68}
h) 9(3) cage in N7 = {126/135/234}, no 7,8,9
i) 22(6) cage at R1C5 = {123457}, no 6,8,9

Steps resulting from Prelims
1a. Naked pair {79} in R89C4, locked for C4 and N8, clean-up: no 1,3 in R12C4, no 5 in R8C56
1b. Naked pair {68} in R8C56, locked for R8 and N8
1c. 22(6) cage at R1C5 = {123457}, CPE no 1,2,3,4,5,7 in R1C89

2. R1C89 = {68/69/89} -> R2C8 = {134}

3. 45 rule on R12 2 outies R3C78 = 1 innie R2C9 + 2, IOU no 2 in R3C78
3a. Min R3C78 = 4 -> min R2C9 = 2

4. 45 rule on R89 2 outies R7C23 = 1 innie R8C1 + 7, IOU no 7 in R7C23
4a. 45 rule on R89 3 innies R8C123 = 16 = {259/349/457}, no 1
4b. Killer pair 7,9 in R8C123 and R8C4, locked for R8
4c. 1 in R8 only in R8C789, locked for N9, clean-up: no 8 in R6C9

5. 8 in N7 only in R7C123, locked for R7, clean-up: no 1 in R6C9
5a. 45 rule on N7, R8C123 = 16, R9C123 = 9 -> R7C123 = 20 = {389/578} (cannot be {479/569} which don’t contain 8), no 1,2,4,6
5b. 7 of {578} must be in R7C1 -> no 5 in R7C1
5c. R8C123 (step 4a) = {349/457} (cannot be {259} which clashes with R7C123), no 2, 4 locked for R8 and N7

6. 9(3) cage in N7 = {126} (hidden triple in N7), locked for R9

7. 2 in R8 only in R8C789, locked for N9, clean-up: no 7 in R6C9
7a. 1,2 in N8 only in R7C456, locked for 32(7) cage at R6C3, no 1,2 in R6C34

8. 45 rule on N7 2 innies R78C1 = 13 = [85/94]
8a. R34C1 = {18/27/36} (cannot be {45} which clashes with R8C1), no 4,5

9. R7C123 (step 5a) = {389} (only remaining combination), locked for R7 and N7, clean-up: no 6 in R6C9
9a. Naked triple {457} in R8C123, locked for R8 and N7 -> R89C4 = [97]
9b. 3 in C4 only in R3456C4, CPE no 3 in R4C6

10. 3 in N8 only in R9C56, locked for R9 and 22(5) cage at R8C7, no 3 in R8C7

11. 3 in N9 only in 13(3) cage = {139/238} -> R9C9 = {89}

12. 32(7) cage at R6C3 = {1234589/1234679/1235678}, 3 only in R6C34, locked for R6, clean-up: no 6 in R7C9
12a. 6 in N9 only in R7C78, locked for 32(7) cage, no 6 in R6C34
12b. 32(7) cage at R6C3 = {1234679/1235678} (only combinations containing 6)
12c. 3,8,9 only in R6C34 = R6C34 = [38/83/93], no 4,5,7
12d. 6,7 only in R7C78 = {67}, locked for R7, clean-up: no 2 in R6C9

13. Naked pair {45} in R67C9, locked for C9

14. 16(3) cage at R2C9 = {178/367} (cannot be {169/268} which clash with R19C9, ALS block), no 2,9, 7 locked for C9
14a. 9 in N3 only in R1C89, locked for R1
14b. R1C89 = {69/89} -> R2C8 = {13}

15. 45 rule on C9 4 innies R1589C9 = 20 = {1289/2369}
15a. 1,2,3 only in R58C9 -> R5C9 = {123}

16. 2 in N3 only in R12C7, locked for C7 -> R8C7 = 1
16a. 2,4,5 in N3 only in R123C7 + R3C8, locked for 22(5) cage at R1C5, no 2,4,5 in R1C56

[The next CPE has been available since step 1 but I’ve only just spotted it. It is, however, more powerful now.]
17. 1 in N2 only in R1C56 + R3C456, CPE no 1 in R3C8
17a. 1 in 22(5) cage at R1C5 only in R1C56, locked for R1 and N2
[OOPS! I’ve realised, after looking at Ed’s alternative breakthrough, that this CPE should have been for 1,3 in N2. :oops: ]

18. R8C89 = {23} -> R9C9 = 8 (step 11)

19. 16(3) cage at R2C9 (step 14) = {367} (only remaining combination), locked for C9 -> R1C9 = 9, R8C89 = [32], R5C9 = 1, R2C8 = 1, R1C8 = 8 (cage sum) , clean-up: no 2 in R2C4
19a. 6 in N3 only in R23C9 -> no 6 in R4C9

20. 45 rule on N47 2 innies R4C1 + R6C3 = 10 = [19/28/73], no 3,6,8 in R4C1, clean-up: no 1,3,6 in R3C1

21. 1 in N1 only in R3C23, locked for 34(7) cage at R3C2, no 1 in R4C6
21a. 45 rule for N1 3 innies R3C123 = 16 = {178} (only remaining combination, cannot be {169} because 1,6,9 only in R3C23), locked for R3 and N1, clean-up: no 7 in R4C1, no 3 in R6C3 (step 20)

22. R6C4 = 3 (hidden single in R6)
22a. 45 rule on N5 2 remaining innies R46C6 = 13 = {49/58/67}, no 2

23. 1,2 in N6 only in 26(5) cage = {12689} -> R5C7 = 8, R456C8 = {269}, locked for C8 and N6 -> R7C78 = [67], clean-up: no 4,5,7 in R6C6, no 6,8,9 in R4C6 (step 22a)
23a. 3 in N6 only in R4C79, locked for R4
23b. R9C7 = 9 (hidden single in N9)

24. 12(3) cage in N1 = {246/345}, no 9, 4 locked for N1
24a. 3 of {345} must be in R12C1 (R12C1 cannot be {45} which clashes with R8C1), no 3 in R1C2
24b. 9 in N1 only in R2C23, locked for R2, clean-up: no 4 in R2C56
24c. Killer pair 6,8 in R12C4 and R2C56, locked for N2

25. 34(7) cage at R3C2 = {1234789} (only remaining combination), no 5
25a. Naked triple {347} in R4C679, locked for R4
25b. 4 in R4 only in R4C67, locked for 34(7) cage at R3C2 -> R3C4 = 2, clean-up: no 8 in R2C4
25c. Naked pair {46} in R12C4, locked for C4 and N2 -> R5C4 = 5, R7C4 = 1, R4C4 = 8, clean-up: no 7 in R2C56, no 5 in R6C7
25d. Naked pair {39} in R3C56, locked for R3, N2 and 34(7) cage at R3C2, no 3 in R4C7 -> R3C9 = 6
25e. Naked pair {47} in R4C67, locked for R4 and 34(7) cage at R3C2, no 7 in R3C23 -> R4C9 = 3, R2C9 = 7

26. Naked pair {47} in R46C7, locked for C7 and N6 -> R3C78 = [54], R67C9 = [54], R9C8 = 5

27. 32(7) cage at R6C3 (step 12b) = {1235678} (only remaining combination) -> R6C3 = 8, R3C23 = [81], R3C1 = 7, R4C1 = 2

28. R7C1 = 8 (hidden single in R7), R8C1 = 5 (step 8)

29. 45 rule on N4 3 remaining innies R5C1 + R6C12 = 14 = {149/167} (cannot be {347} = 3{47} which clashes with R6C7), no 3, 1 locked for R6 and N4
29a. 7 of {167} must be in R6C2 -> no 6 in R6C2

30. 3 in C1 only in R12C1 -> 12(3) cage in N1 (step 24) = {345} (only remaining combination) -> R1C2 = 5, R12C1 = {34}, locked for C1 and N1

31. Naked pair {69} in R4C2 and R5C1, locked for N4 -> R6C1 = 1, R9C1 = 6, R5C1 = 9, R6C2 = 4 (step 29), R6C7 = 7, R6C6 = 6

and the rest is naked singles.

Rating Comment. I'll rate my walkthrough for A209 at Easy 1.25. I used a couple of ALS blocks in one step, also CPEs and lots of locked candidates for the large cages.
Ed's alternative breakthrough:
Glad you enjoyed this one guys. I used a different breakthrough to Andrew's nice block. Missed that.

Alternate cracker for A209 6 steps
.-------------------------------.-------------------------------.-------------------------------.
| 123456789 123456789 123456789 | 2468 123457 123457 | 123457 689 689 |
| 123456789 123456789 123456789 | 2468 456789 456789 | 123457 134 236789 |
| 123678 123456789 123456789 | 1234568 123456789 123456789 | 13457 13457 1236789 |
:-------------------------------+-------------------------------+-------------------------------:
| 123678 123456789 123456789 | 1234568 123456789 12456789 | 123456789 123456789 1236789 |
| 123456789 123456789 123456789 | 1234568 123456789 123456789 | 123456789 123456789 1236789 |
| 12456789 12456789 389 | 38 12456789 456789 | 456789 12456789 45 |
:-------------------------------+-------------------------------+-------------------------------:
| 89 389 389 | 1245 1245 1245 | 67 67 45 |
| 45 457 457 | 9 68 68 | 12 123 123 |
| 126 126 126 | 7 345 345 | 4589 4589 89 |
'-------------------------------.-------------------------------.-------------------------------'


Andrew's end of step 13 above. Select marks and "Paste Into" A209 in SudokuSolver

14. 1&3 in n2 only in r1c56 + r3c456 -> no 1,3 in r3c78 (CPE)

15. "45" on r12: 2 outies r3c78 - 2 = 1 innie r2c9
15a. ->max r3c78 = 11 -> r3c78 = {45/47} = 9/11
15b. 4 locked for r3 and n3 and 22(6)r1c5
15c. r3c78 = 9/11 -> r2c9 = (79)

16. 16(3)r2c9 must have 7/9 for r2c9 = {169/178/367}(no 2)
16a. has only one of 7/9 -> no 7,9 in r34c9

17. 2 in n3 only in r12c7: 2 locked for c7 and for 22(6)r1c5
17a. r8c7 = 1

18. r8c89 = {23} -> r9c9 = 8 (cage sum)

19. 16(3)r2c9 = {169/367}; must use 6
19a. 6 locked for c9
19b. r1c9 = 9

Back to middle of Andrew's step 19 for the rest.


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