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 Post subject: Off-topic
PostPosted: Thu Dec 09, 2010 10:28 pm 
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Grand Master
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Posts: 251
Off-Topic
HATMAN wrote:
The name was started by Mike-Japan long ago - revision is probably a good idea.
*cages (non-repeat - unknown total) this seems a reasonable usage.
Star killer is not so clear - perhaps empty killer? However star killer has a nice ring to it.
I was thinking in reference to the tarek/udosuk killer line notation (if anybody remebers :cry: )
The star "*" would indicate an unknown sum or algebric result. the empty cells could have a "." vanilla treatment. I therefore go for "Star cages" to indicate unknown algebric result & no repeats. The killer convention is the default. Unless there are repeats, I don't think you need to state it. The repeats would make the star cages redundant.

I haven't thought about kenken yet but it shoud be possible.
OAK1 could look like this
Code:
fxbc>1c.v.vvv.v..a8>>6xv2/a8>v..vv..
fxbc>1
c.v.vv
v.v..a
8>>6xv
2/a8>v
..vv..


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 Post subject: Re: OAK
PostPosted: Fri Dec 10, 2010 12:52 pm 
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Grand Master
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Posts: 694
Location: Saudi Arabia
Simon

I agree with the + standard, it is just that JSudoku does not and I forgot to re-write the puzzles.

Ken-Ken is copywrited and they have been stroppy about it so Motris is obviously avoiding problems.

Tarek

I followed the one line description exchanges but did not get deeply involved - and the memory is not strong enough so you will need to give a bit more explanation.


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 Post subject: Re: OAK
PostPosted: Tue Dec 14, 2010 11:48 am 
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Master
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A 3-step crack-in for OAK #2 (each step is subdivided into 3 parts though):

3-step crack-in for OAK #2:
1a:
19+(3),4+(2),6+(2),18+(3) add up together to 47
--> R2C2 must be odd (R1+R2 total must be even)
--> R2C2={1/3/5/7/9} --> R1+R2 total =48/50/52/54/56
--> total of 1 row/column =24/25/26/27/28

1b:
1+(2)={01} so 2 of the values must be {0,1}
4+(2)={04/13} so 1 value must be {3/4}
24x(3)={138/146/226/234} so 1 value must be {3/6}
--> either {0,1,3} or {0,1,4,6} must be part of the values

1c:
Notice 0+1+3+8+9=21 & 0+1+4+6+9=20
--> {2} cannot be part of the values
(or max total sum of values =23/22 <24)
--> the set of 6 values must be from {0,1,3,4,5,6,7,8,9}

2a:
7-(2)={07/18} must include {0/1}
5+(3) must include {0/1} in R56C6
(or total sum =3+4+0 =7 >5)
--> R3456C6 must include both {0,1} of C6 --> R12C6<>{0,1}

2b:
7-(2)={07/18} must include {0/1}
--> 5+(3) cannot include both {0,1} in R56C6
--> min R56C6=0+3=3 --> max R6C5=5-3=2, must be {0/1}

2c:
7-(2)={07/18} must sum to 7/9
--> 18+(3),7-(2),5+(3) add up together to 30/32
Outies C6: min R16C5=30-28=2 --> R1C5<>{0,1}

3a:
19+(3): R1C2<>{0,1} (or max sum=1+8+9=18<19)
Hidden pair R1: R1C34={01}
R2C345 must include {0} of R2
Also 6+(3)<>{7,8,9} --> R2C345=4+6-0-1=9={036/045}

3b:
Hidden single R2: R2C2=1
--> total of 1 row/column =(47+1)/2 =24
Outies R1: R2C16=19+18+0+1-24=14={59/68}

3c:
R2: {7} cannot be part of the values
--> 7-(2)={18}, so 1 value must be 8
--> R2C16=14=[86] --> R2C345=9={045}
--> the set of 6 values must be {0,1,4,5,6,8}

Cracked.


I tried to present the steps as T&E-free as possible. Hope others would agree.

Apart from the initial confusion about cage symbol notation, its a very enjoyable puzzle. Thanks HATMAN! ;-)


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 Post subject: Re: OAK
PostPosted: Sat Dec 18, 2010 7:40 pm 
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Grand Master
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Posts: 694
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Good one - I missed the innies on R12 so my solution plodded on a bit more using interactions between the 19-18-17 cages.


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