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Para
 Post subject: Texas Jigsaw Killer 35
PostPosted: Sun Nov 09, 2008 9:58 pm 
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Posts: 62
Hi all

Here's the second one by my hand. It's not that hard either, but harder than the previous one. But I enjoyed solving it. Hope you do too. If someone else feels like making one too, go ahead. ;) Can't be the only one keeping this up.

Texas Jigsaw Killer 35

Image

Sumocue-code
Hidden Text:
SumoCueV1=21J0=27J1+1J1+1J1=12J2+4J2+4J2=15J2+7J2+0J0+0J0+1J0+1J1=15J2+13J3=16J2+15J3+7J2+0J0=9J0=15J1+20J1+13J4=15J3+23J3+15J3+15J2=25J0+19J0+19J0=12J1+30J4=14J4+23J4=29J3+34J3+27J5+27J5=3J1+38J1+32J4+32J6=13J6+42J3+34J3+27J5=19J5+46J4=11J4+48J4+32J6=19J7+34J7+34J7=18J8+46J5=8J5+56J5=18J4+51J6+51J6=21J7+61J7+54J8+54J5=24J8+65J5+58J8+58J6+61J7+61J7=13J7+54J8+65J8+65J8+65J8=13J8+76J6+76J6+71J6+71J7


Solution
Hidden Text:
634821975
927568413
456917238
813752649
792134856
169475382
245389761
381246597
578693124

Good luck

Para
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Ed
PostPosted: Tue Nov 18, 2008 9:03 am 
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Para wrote:
It's not that hard
Yes it is! Absolutely perfect hard. Had to use many of the fun jigsaw techniques that I find hard to see; LoL, weird CPE and cage blocks. But nothing outrageously technically difficult. Really enjoyed it. I'll give it a rating of Hard 1.25 since it took me a long, long time to finish. Didn't find the cracking move till step 31a.

Para wrote:
If someone else feels like making one too, go ahead. ;) Can't be the only one keeping this up.
I really appreciate you keeping this fine tradition alive. Thanks! I'll make one before the NY.

Walkthrough for TJK 35
(please let me know of any mistakes or things that could be clearer; [edit: thanks Andrew!])

Prelims
i. 9(3)r3c2: no 7,8,9
ii. 15(2)r3c3 = {69/78}
iii. 12(2)r4c4: no 1,2,6
iv. 14(4)r4c6: no 9
v. 3(2)r5c3 = {12}
vi. 13(2)r5c7: no 1,2,3
vii. 19(3)r6c2: no 1
viii. 11(2)r6c4: no 1
ix. 19(3)r6c7: no 1
x. 8(2)r7c3: no 4,8,9

1. 3(2)r5c3 = {12}: both locked for r5 and Nr1c2

2. LOL r1234: 4 outies r5c3489 = 4 innies r3c5 & r4c567
2a. 4 outies must have 1 & 2 -> 4 innies must have 1 & 2
2b. 1,2 locked for Nr3c5
2c. no 9 in r6c45

3. "45" Nr1c1: 2 innies r2c3 & r4c1 = h15(2) = {69/78}

4. 27(5)r1c2 = {34569/34578} = 345{69/78}
4a. 3,4,5 all locked for Nr1c2
4b. r4c5 = (345)

5. "45" Nr1c1 + Nr1c2: 2 innies r4c14 = h15(2) = [69]{78} (no 9 r4c1)
5a. no 6 r2c3 (h15(2)Nr1c1)

6. "45" c1234: r46c4 = h11(2) = [74/83]
6a. r4c5 = (45)
6b. r6c5 = (78)
6c. r4c1 = (78) (h15(2))
6d. r2c3 = (78) (h15(2))

7. naked pair {78} in r2c3+r4c1: both locked for Nr1c1

8. naked pair {78} in r4c14: both locked for r4

9. 15(2)r3c3 = {69} ({78} blocked by r4c4)
9a. both locked for Nr1c2 & r3

10. "45" Nr1c5: r23c8 + 2 = r2c5
10a. min r23c8 = {12} = 3 -> min r2c5 = 5
10b. max. r23c8 = 7: no 7,8,9

11. LOL c6789: 2 innies r4c67 = 2 outies r12c5
11a. 2 innies must have at least 1 of 1 or 2 for LOL r1234 (step 2)
11b. -> the only place for 1 or 2 in 2 outies r12c5 is in r1c5 = (12)
11c. NOTE: this also means that r4c67 has exactly 1 of (12)
11d. no 3,4 in r12c5 -> no 3,4 in r4c67
11e. no 7,8 in r4c67 -> no 7,8 in r2c5

12. hidden pair (12) for Nr3c5 (from step 11c) -> r3c5 = (12)

13. naked pair (12) in r13c5: both locked for c5
13a. no 1,2 in r3c9 (CPE sees both r13c5)

14. LOL r1234: 4 outies r5c3489 = 4 innies r3c5 & r4c567
14a. 4 innies don't have 3,7,8 -> 4 outies cannot have them in r5c89
14b. no (56) in r5c7

15. hidden killer pair (78) in Nr2c6: r2c6 & r3c67 must have both of 7 & 8 for Nr2c6
15a. r3c67 can only have 1 of 7 or 8 because of 15(3) -> r2c6 = (78)
15b. & 15(3)r3c6 must have 7 or 8 = {168/258/267/357}(no 4,9) (can't place {348} because of r4c7)
15c. 6 in {168} must be in r4c7 -> no 1 in r4c7

16. 9 in r4 only in Nr2c6: 9 locked for that N & for 29(5)r4c8
16a. no 4 in r5c7

17. naked pair {78} in r2c36: both locked for r2

18. hidden killer pair (78) in r3: r3c67 has at most one of 7/8 -> r3c9 = (78)

19. 15(3)r2c5: min. r2c6 + r3c5 = [71] = 8 -> max. r2c5 = 7 (no 9)

20. "45" Nr1c5: r23c8 + 2 = r2c5
20a. -> r23c8 = 3/4 = 1{2/3}
20b. 1 locked for c8 & Nr2c6 & 16(4)r2c7
20c. r23c8 & r3c9 = 10/11/12 -> r2c7 = (456)

21. "45" Nr1c5: 3 innies r2c57 & r3c9 = h18(3) = {468/567} (only valid combinations)
21. 6 locked for r2 & Nr1c5

22. r1c1 = 6 (hsingle r1)

23. 9 in Nr1c1 only in r2: 9 locked for r2
23a. 21(4)r1c1 = 69{15/24}(no 3)

24. "45" r123: r3c2 + 1 = r4c7
24a. NOTE: i/o [12] blocked by r3c5 = (12) which sees both r3c2 & r4c7!
24b. r3c2 = (45)
24c. r4c7 = (56)

25. 3 in Nr1c1 only in r4: 3 locked for r4

26. 3 in r3 only in Nr2c6: 3 locked for that N

27. 1 & 2 in r1 only in Nr1c5: no 1 or 2 in r2c9

28. hidden killer pair (12) in r2: r2c12 must have 1 of 1/2 for r2
28a. 21(4)r1c1 = 69{15/24} -> no 1 or 2 in r3c1

29. naked pair (45) in r3c12: both locked for r3 & Nr1c1

30. hidden pair (12) in Nr3c5 -> r4c6 = (12)
30a. CPE -> no 2 in r3c6

31. 15(3)r2c5 = {168/258/267} = [2/8..]
31a. 15(3)r3c6 = {267/357}(no 8) (NOTE: {258} = {28}[5] clashes with 15(3)r2c5 (step 31))
31b. 7 locked for r3 & Nr2c6

32. r3c9 = 8
32a. 16(4)r2c7 = 8{125/134} (no 6)

33. r2c6 = 8

34. r2c5 = 6 (hsingle r2)
34a. r3c5 = 1 (cage sum)

35. r1c5 & r4c6 = 2

36. naked pair {13} in r4c23: 1 locked for Nr1c1
36a. r3c2 = 5 (cage sum)
36b. r4c7 = 6 (i/o r1234)
36c. r3c67 = 9 = [72]
36d. r23c8 = [13] -> r2c7 = 4

37. r2c3 = 7
37a. r34c1 = [48]
37b. r4c45 = [75]

38. r6c4 = 4 (h11(2)r46c4)
38a. r6c5 = 7

39. 5&6 in Nr2c6 only in r5: 5&6 locked for r5
39a. CPE: no 5,6 in r6c8

40. r1c5 = 2
40a. r1c67 = 10 = {19/37) (no 5)

41. r4c89 = {49}: 4 locked for Nr2c6
41a. no 9 in r5c7
41b. r5c9 + r6c89 = 16
41c. max. r56c9 = {56} = 11 -> min. r6c8 = 7
41d. r6c8 = 8
41e. r67c9 = 8 = [53/62] (r6c9 = (23)

42. r9c8 = 2 (hsingle Nr5c6)

43. 4 in Nr5c1 only in c2: locked for c2
43a. r1c3 = 4 (hsingle r1)

44. 8 in Nr3c5 only in c5: locked for c5

45. CPE on 8s in Nr7c1: no 8 in r8c4

46. 8 in Nr5c1 only in c2: 8 locked for c2
46a. r1c35 = [38]
46b. r2c4 = 5
46c. no 3 in r7c3

47. r2c9 = 3
47a. r1c89 = 12 = {57}: 7 locked for r1

48. r6c9 = 2
48a. r5c9 = 6 (cage sum)

49. r5c78 = [85]
49a. r5c56 = [34]

50. naked pair (79) in r5c12: both locked for Nr5c1
50a. r6c1 = 1 (cage sum)

51. r6c23 = [69] -> r7c2 = 4 (cage sum)

52. "45" c1: 3 outies r258 = 19 = [298]

53. 8(2)r7c3 = [53] (last permutation)

54. r6c67 = [53]
54a. r7c67 = 16 = [97]
rest is singles and cage sums

cheers
Ed
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Børge
PostPosted: Fri Dec 25, 2009 1:06 pm 
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TJK 35 images with udosuk Style Killer Cages and Ruud TJK#33 inspiration:
Image



Image



Image
Cages with cells in 3 jigsaw nonets:  pink
Cages with cells in 2 jigsaw nonets:  green, yellow and brown
Cages with cells in 1 jigsaw nonet:   red, blue and grey


					
						

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Loved the jigsaw pattern for this puzzle!

Here is my walkthrough for TJK 35:  
Prelims

a) R3C34 = {69/78}
b) R4C45 = {39/48/57}, no 1,2,6
c) R5C34 = {12}
d) R5C78 = {49/58/67}, no 1,2,3
e) R6C45 = {29/38/47/56}, no 1
f) R7C34 = {17/26/35}, no 4,8,9
g) 9(3) cage at R3C2 = {126/135/234}, no 7,8,9
h) 19(3) cage at R6C2 = {289/379/469/478/568}, no 1
i) 19(3) cage at R6C7 = {289/379/469/478/568}, no 1
j) 14(4) cage at R4C6 = {1238/1247/1256/1346/2345}, no 9

1. Naked pair {12} in R5C34, locked for R5 and NR1C2

2. 45 rule on NR1C1 2 innies R2C3 + R4C1 = 15 = {69/78}
2a. 27(5) cage at R1C2 = {34569/34578}, 3,4,5 locked for NR1C2, clean-up: no 7,8,9 in R4C5

3. Min R3C45 + R4C4 = 22 must contain 9, locked for NR1C2
3a. 27(5) cage at R1C2 (step 2) = {34569/34578}
3b. 9 of {34569} must be in R2C3 -> no 6 in R2C3, clean-up: no 9 in R4C1 (step 2)

4. 45 rule on R123 1 outie R4C7 = 1 innie R3C2 + 1, no 1,8,9 in R4C7

5. 45 rule on R789 1 innie R7C2 = 1 outie R6C7 + 1, no 9 in R6C7, no 2 in R7C2
5a. 45 rule on R789 3 innies R7C267 = 20 = {389/479/569/578}, no 2

6. Min R5C56 = 7 -> max R46C6 = 7, no 7,8 in R46C6

7. 45 rule on C1234 2 outies R46C5 = 12 = [39/48/57], R6C4 = {234}

8. 45 rule on C1 3 outies R258C2 = 19, no 1 in R28C5

9. Law of Leftovers (LoL) for C1234 two outies R89C5 must exactly equal two innies R6C34, no 1 in R6C34 -> no 1 in R89C5

10.  LoL for C6789 two outies R12C5 must exactly equal two innies R4C67, no 8,9 in R4C67 -> no 8,9 in R12C5

11. 27(5) cage at R1C2 = {34569/34578}, R2C3 + R4C1 = [78/87/96], R3C34 = {69/78} -> R2C3 + R4C1 and R3C34 must form naked quad {6789}, CPE no 6,7,8,9 in R3C12, clean-up: no 7 in R4C7 (step 4)
[It can be seen that R4C14 must be [69/78/87] which might be useful later, for example R4C14 contains both or neither of 7,8 -> R4C89 must contain both or neither of 7,8.]

12. 45 rule on R123 3 outies R4C237 = 10 =  {136/145/235}
12a. R4C237 + R4C5 must contain 3, locked for R4

[I’m glad that I found the interesting step 11 before I spotted the important next step …]
13. LoL for R6789 four outies R5C1267 must exactly equal four innies R6C345 + R7C5, no 1,2 in R5C1267 -> no 1,2 in R6C34 + R7C5, clean-up: no 9 in R6C5, no 3 in R4C5 (step 7), no 9 in R4C5
13a. R3C34 = {69} (cannot be {78} which clashes with R4C4), locked for R3 and NR1C2
13b. 27(5) cage at R1C2 (step 2) = {34578} (only remaining combination), no 9, clean-up: no 6 in R4C1 (step 2)
13c. Naked pair {78} in R4C14, locked for R4
13d. Naked pair {78} in R2C3 + R4C1, locked for NR1C1
13e. 9 in R4 only in R4C89, locked for NR2C6 and 29(5) cage at R4C89, no 9 in R6C89, clean-up: no 4 in R5C7
13f. LoL (step 9), no 2 in R6C34 -> no 2 in R89C5

14. LoL (step 10), no 7 in R4C67 -> no 7 in R12C5
14a. 1,2 in NR3C5 only in R3C5 + R4C67, CPE no 1 in R2C6, no 1,2 in R3C6
14b. 9 in NR3C5 only in R6C3 + R7C5, CPE no 9 in R7C2, clean-up: no 8 in R6C7 (step 5)

15. R4C237 (step 12) = {136/235} (cannot be {145} which clashes with R4C5), no 4, clean-up: no 3 in R3C2 (step 4)

16. R46C5 (step 7) = [48/57], R6C45 = [38/47] -> R4C5 + R6C4 must contain 4 (locking cages), locked for NR3C5
16a. LoL (step 10), no 4 in R4C67 -> no 4 in R12C5

17. Hidden killer pair 1,2 in R1C5 and 15(3) cage at R2C5 for C5, 15(3) cage cannot contain both of 1,2 -> R1C5 = {12}, 15(3) cage must contain one of 1,2 = {168/258/267}, no 3,4
17a. 1,2 of 15(3) cage must be in R23C5 -> no 2 in R2C6
17b. LoL (step 9), no 3 in R12C5 -> no 3 in R4C7, clean-up: no 2 in R3C2 (step 4)

18. 3 in R4 only in R4C23, locked for NR1C1
18a. 9(3) cage at R3C2 = {135/234}, no 6

19. 14(4) cage at R4C6 = {1238/1247/1256/1346/2345}
19a. 7 of {1247} must be in R5C5 -> no 7 in R5C6

20. 15(3) cage at R3C6 = {168/258/267/357} (cannot be {348} because R4C7 only contains 2,5,6, cannot be {456} which clashes with R3C2 + R4C7 = [45/56], step 4, IOD blocker), no 4
[Thanks Ed for correcting this step and my terminology.]

21. 3 in R3 only in R3C6789, CPE no 3 in R2C8 +R5C9
21a. 3 in NR2C6 only in R3C678, locked for R3

22. 45 rule on NR1C5 3 innies R2C57 + R3C9 = 18 = {189/279/459/468/567} (cannot be {369} because 3,9 only in R2C7, cannot be {378} because no 3,7,8 in R2C5), no 3
22a. 1,2 of {189/279} must be in R2C5 -> no 1,2 in R2C7 + R3C9

[First time through I made a careless, incorrect clean-up in an earlier step.  Now I’ll use a harder step, and another one later (step 27), to get back on track.]
23. Consider placement for 3 in R3
3 in R3C67 => 15(3) cage at R3C6 (step 20) = {357} = {37}5 => R3C2 = 4 (step 4) => 16(4) cage at R2C7 cannot be {1249} = 9{12}4
or R3C8 = 3 => 16(4) cage cannot also contain 9
-> no 9 in R2C7
23a. R2C57 + R3C9 (step 22) = {468/567}, no 1,2, 6 locked for R2 and NR1C5
23b. R13C5 = {12} (hidden pair in C5)
23c. 15(3) cage at R2C5 (step 17) = {168/258/267}
23d. 7,8 only in R2C6 -> R2C6 = {78}
23e. Naked pair {78} in R2C36, locked for R2

24. R2C57 + R3C9 (step 23a) = {468/567}
24a. 7,8 only in R3C9 -> R3C9 = {78}
24b. R2C7 + R3C9 = [48/57/67] (from combinations for R2C57 + R3C9) = 12,13 -> R23C8 = 3,4 = {12}/[13], 1 locked for C8 and NR2C6
24c. 4 in R3 only in R3C12, locked for NR1C1

25. R1C1 = 6 (hidden single in R1)
25a. 9 in NR1C1 only in R2C12, locked for R2
25b. 21(4) cage at R1C1 = {1569/2469}
25c. 4 of {2469} must be in R3C1 -> no 2 in R3C1

26. 15(3) cage at R3C6 (step 20) = {258/267/357}
26a. Killer pair 7,8 in R2C6 + R3C67, locked for NR2C6, clean-up: no 5,6 in R5C7

27. Naked pair {78} in R2C36, R2C3 must equal R4C4 (because of naked pair {78} in NR1C1)  -> R2C6 + R4C4 form naked pair {78}
27a. 15(3) cage at R3C6 (step 20) = {258/267} (cannot be {357} = {37}5 because R2C6 = 8, R4C45 = [75] clashes with R4C7), no 3, 2 locked for C7
27b. 2 in R34C7, CPE no 2 in R4C89

28. Naked quad {4569} in R45C89, locked for NR2C6
28a. Naked pair {78} in R23C6, locked for C6 and NR2C6 -> R3C7 = 2

29. R2C8 = 1, R3C8 = 3
29a. R23C8 = [13] = 4 -> R2C7 + R3C9 = 12 = [48/57], no 6
29b. R2C5 = 6 (hidden single in R2), R3C5 = 1, placed for NR3C5, R2C6 = 8 (cage sum), R3C6 = 7, R4C7 = 6 (cage sum), placed for NR3C5, R3C2 = 5 (step 4), placed for NR1C1, R4C23 = 4 = {13}

30. R2C3 = 7, R4C1 = 8, R4C4 = 7, R4C5 = 5, placed for NR3C5, R6C5 = 7 (step 7), R6C4 = 4, clean-up: no 3,7,8 in R7C2 (step 5), no 1 in R7C34

31. R3C9 = 8, R2C7 = 4 (cage sum), both placed for NR1C5
31a. R1C5 = 2, placed for NR1C5, R1C67 = 10 = [19/37/91], no 5, no 3 in R1C7

32. Naked pair {49} in R4C89, locked for NR2C6, clean-up: no 9 in R5C7
32a. Naked pair {56} in R5C89, locked for R5

33. R4C6 = 2 -> 14(4) cage at R4C6 = {1238/2345}, (cannot be {1256} because 5,6 only in R6C6)
33a. 1,5 only in R6C6 -> R6C6 = {15}
33b. 14(4) cage = {1238/2345}, 3 locked for R5

34. R4C1 = 8, 9 in R5 only in 24(4) cage at R4C1 = {1789} (only remaining combination because 2,3,5 only in R6C1) -> R6C1 = 1, placed for NR5C1, R5C12 = {79}, locked for R5 and NR5C1 -> R5C7 = 8, R5C8 = 5, R5C5 = 3, placed for NR3C5, R56C6 = [45], both placed for NR5C6

35. R6C7 = 3, placed for NR6C7, R7C2 = 4 (step 5), R5C9 = 6, R6C9 = 2, placed for NR6C7, R6C8 = 8, R6C2 = 6, placed for NR5C1, R6C3 = 9, placed for NR3C5, clean-up: no 2 in R7C34
35a. Naked pair {35} in R7C34, locked for R7 and NR5C1

36. R258C2 = 19 (step 8) = {289} (only remaining combination) -> R5C2 = 9, R2C2 = 2, R8C2 = 8

37. R6C7 = 3 -> R7C67 = 16 = [97], both placed for NR5C6 -> R9C7 = 1, R1C7 = 9, R1C6 = 1 (cage sum)

38. R7C5 = 8 -> R8C56 = 10 = [46]

and the rest is naked singles, without using the nonets.


					



						

						

							
							
							
						

						

							
				

				

					
		


		


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