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Equality Killer Windoku FNC http://www.rcbroughton.co.uk/sudoku/forum/viewtopic.php?f=13&t=20 |
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Author: | udosuk [ Tue Apr 29, 2008 3:15 pm ] |
Post subject: | Equality Killer Windoku FNC |
Seeing that Richard created this section upon my request , I feel I owe him and the community here a puzzle at the very least. So here I will post one of my new creations here. It's also my favourite of the five ones in my latest series. And hopefully the great players here will not be baffled too much by the rules (Fers Non-Consecutiveness should not be too hard to figure out for players who have tried normal Non-Consecutive puzzles). Note the "Equality Killer" concept comes from Ms Miyuki Misawa's website in 2005. Also players who have visited www.killersudokuonline.com know they publish an "Inequality Killer" every week. This puzzle is not too hard once the players figure out the cage sum. Just for completeness I posted 4 other puzzles in this series elsewhere, available from these links: http://www.sudoku.com/boards/viewtopic.php?t=6061 http://www.djape.net/sudoku/forum/viewtopic.php?t=1276 And I also posted this puzzle in the Sudocue forum, as a tribute to Ruud: http://www.sudocue.net/forum/viewtopic.php?t=965 |
Author: | Glyn [ Thu May 01, 2008 8:20 pm ] |
Post subject: | Re: Equality Killer Windoku FNC |
Ok Matt Not a complete walkthrough yet, but enough to give the required cage sum. Don't know how to do the triple click trick so it's in Tiny type. Proposition 1 All 2-cell cages are {78} consecutive digits if 2-cell cage sum is 15. Proof Assume cage sum is 15. 5-cell cages are {12345}. TopRightPane=>r2c8&r4c678<>1,2,3,4,5 => r1c7=1,2,3,4 or 5=> r1c8=6,7,8 or 9. r1c8+r2c7=15, only combo is r1c8,r2c7={69} ({87} blocked by Ferz) r12c9={78} r89c7={78} ({69} combo blocked by r2c7) Top Right Pane {78} locked in r4c68 Cage sum 15 => r45c6={78} r5c5 sees the whole cage r5c234&r6c45={12345} => r5c5=6|7|8|9. On Row 5 Positions of 7,8 r5c9 blocked by pair r12c9, r5c8 blocked by pair r5c6+r9c7 (Right Stiles) and r5c5 by r45c6 => r5c16={78} => r56c1={78} Proposition 1 is true Proposition 2 All 2-cell cages cannot be consecutive digits A,B Proof Set r12c9=[AB] => r56c1=[BA] => r45c6=[BA] =>r89c7=[AB] Consider Top Stiles r2c9&r3c5=[BA] Examining r3c5&r4c6=[AB] consecutive digits blocked by Ferz. Proposition 2 is true 1)Cage sum cannot be 17 blocked by Proposition 2. 2)Cage sum cannot be 15 blocked by Proposition 1 and 2. 3)Cage sum equals 16. |
Author: | udosuk [ Mon May 05, 2008 4:04 am ] |
Post subject: | Re: Equality Killer Windoku FNC |
Finally, I've written my own complete walkthrough for this, aided with a few diagrams. Note I've used one proposition instead of two by Glyn, and then used some coloring tricks to determine the cage sum out of 2. Would have been nicer to do it without any proposition but don't think it's viable. Here is the complete walkthrough in hidden text: Hidden Text: |
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