Thanks
HATMANSemi-symmetric isn't my favourite type of clue, often harder than symmetric.
After an easy start it gets slow later when using semi-symmetry and groups of three adjacent numbers but I think I've managed to solve it.
Take care with semi-symmetry and groups of three adjacent numbers, it's easy to go wrong with them, and remember that each of the numbers in R6C6 and R7C6 must be in each of the nonets/triangles; if I'd remembered that sooner my solving path (not posted) would have been a bit shorter.