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MeanDoku
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Author:  HATMAN [ Tue May 30, 2017 10:39 am ]
Post subject:  MeanDoku

A new variant see:

http://forum.enjoysudoku.com/post257549.html#p257549

my first attempt is not too difficult - I'll improve it and post here.

Author:  HATMAN [ Thu Jun 01, 2017 4:09 pm ]
Post subject:  Re: MeanDoku

MeanDoku 2H

I've removed some clues (from MeanDoku 2) - mainly equality as those are the most helpful.

This is a pleasant puzzle type - but it is easy to make mistakes.

I found the trapezoids difficult to see clearly so I have gone for colours:
Green: the average of the two adjacent cells is below five
Blue: the average of the two adjacent cells is five
Red: the average of the two adjacent cells is above five

NC: horizontally and vertically adjacent cells are non-consecutive.

Image

Solution:

915738246
647295813
382641597
869473152
531826974
274159638
426917385
158364729
793582461

Author:  azpaull [ Tue Jun 13, 2017 1:13 am ]
Post subject:  Re: MeanDoku

Really enjoyed this one, Hatman! Thanks!

Printed out your V2 and the very difficult-looking 3. Will give those a go.

(Am I wrong in thinking that a run-thru on these would be extremely long and difficult?)

Author:  wellbeback [ Sun Jun 18, 2017 5:43 pm ]
Post subject:  Re: MeanDoku

Thanks HATMAN! I found this new puzzle type quite tricky to get going, until I realized some implications of the puzzle rules which allowed me to think about it clearly.
Here's how I did it after that.
MeanDoku II - WT:
Implications from the puzzle rules:

(I1) A 1 cannot be on any cell with a Red Mark (RM), or a 9 in any cell with a Green Mark (GM). A 2 can have at most one RM (and that with a 9), etc.
(I2) Since the puzzle is NC - each GM must have at least one of (123) in the cells it straddles.
Similarly a RM must have at least one of (789) in the cells it straddles.
(I3) A Blue Mark (BM) must have one number smaller than 5 and one number larger than 5 in the cells it straddles.

1. n9
of the numbers (789)...
(I2) -> One in r89c7, one in r8c89
(I2) -> One in r7c8
(I3) -> One in r8c9

-> r8c8 and r9c9 both from (123)
-> r9c8 not from (123)
(I1) -> HS 1 in n9 -> r9c9 = 1
-> r8c9 = 9
-> HS 2 in n9 -> r8c8 = 2
-> r7c8 = 8
-> 7 in r89c7
-> 3 in r7c79

2. n8
(I1) -> HS 1 in n8 -> r7c5 = 1
(I2) One of (789) in r78c4, one in r78c6
(I2) -> one of (78) in r9c5. (Cannot be 9 since r9c56 cannot be [91])
-> 9 in r7c46
-> HS 2 in n8 -> r9c6 = 2
-> r9c5 = 8

3. n6
(I1) -> 1 in r4c78
8 in r7c8 -> r6c8 not from (789)
(I2) -> r6c9 from (78)
-> r5c9 not from (789)
(I2) -> r5c8 from (789). Only possibility is 7.
-> r56c8 = [73]
-> r6c9 = 8
(I1, I2) -> r5c7 = 9
r5c9 at least 4 -> (I2,NC) r4c79 = [12]
(NC) -> r6c7 = 6
-> r4c8,r5c9 = {45}

4. n3
(28) both in r123c7 -> r12c7 = {28}
(I1) -> 1 in r12c8 (adjacent to the 8)
(I1) -> r3c8 = 9
Since r3c9 is max 7 -> r2c9 is min 3
-> r1c9 is max 6
Also r1c9 is min 3 -> r2c9 is max 6
-> HS 7 in n3 -> r23c9 = [37]

5. c123
(I1) -> r8c3 = 8
(I1) -> r9c2 = 9
Also (I1, NC) -> r4c13 = [89]
-> r5c3 = 1
(I2) One of (789) in each of r12c1, r12c3, and r3c2
They can only be in that order 9,8,7
(I1) -> r1c2 = 1 -> r1c1 = 9
Also HS r6c2 = 7

6. Some more...
HS r2c8 = 1
-> r12c7 = [28]
-> (NC) -> r1c89 = [46], r3c7 = 5
-> r1c45 = {37}
-> r2c3 = 7
-> r1c36 = [58]
Also r9c8 = 6
-> r8c7 = 7, r7c9 = 5, r9c7 = 4
-> r4c8 = 5, r5c9 = 4
etc.

Author:  HATMAN [ Tue Jun 20, 2017 11:18 am ]
Post subject:  Re: MeanDoku

Wellbeback

My general approach to this puzzle type has been (I've been solving them in JSudoku.):
enter 10(2) cages around all blue squares
1-9 run: clear 1 from reds, clear 9 from greens - solve out
23-78 run: clear 2 from two reds and 3 from three reds, clear 8 from 2 greens and 7 from 3 greens - solve out
consider cells with red and green: cannot be too high or low
consider nonets with almost all clues for interactions


Maurice

Author:  Andrew [ Wed Aug 01, 2018 1:28 am ]
Post subject:  Re: MeanDoku

I only started trying MeanDoku NCs earlier this month, starting with the easiest one using the link in HATMAN's 30th May 2017 post, so I'm at least a year later than azpaull and wellbeback in trying them.

This is a good puzzle for anyone who hasn't tried solving MeanDoku NCs before.

Here is my walkthrough for the easier MeanDoku NC 2:
Cells adjacent to green marks must total less than 10, blue must total 10, red must total more than 10. Also NC so horizontally/vertically adjacent cells cannot be {12}, {23}, … {78}, {89}.

Note that at least one of the cells adjacent to each green mark must contain one of 1,2,3 as they cannot be {45}; similarly at least one of the cells adjacent to each red mark must contain one of 7,8,9 as they cannot be {56}. However I didn’t spot that property while I was solving this simpler version of the puzzle, and it wasn’t necessary to use it.

Prelims.
Delete 9 from cells either side of green marks.
Delete 5 from cells either side of blue marks.
Delete 1 from cells either side of red marks.
Clean-ups only as stated.

1. 1 in N9 only in R9C89, locked for R9
1a. 1 in R9C89 -> no 2 in R9C89 (NC)
1b. R7C5 = 1 (hidden single in N8), no 2 in R68C5 + R7C46 (NC)
1c. 1 in N7 only in R8C123 -> no 2 in R8C2 (NC)

2. 9 in N3 only in R3C789, locked for R3
2a. 9 in R3C789 -> no 8 in R3C8 (NC)
2b. 5 in N3 only in R2C8 + R3C789 -> no 4,6 in R3C8 (NC)

3. 1 in N6 only in R4C789, locked for R4
3a. 1 in R4C789 -> no 2 in R4C8 (NC)

4. 9 in N4 only in R4C13, locked for R4
4a. 9 in R4C13 -> no 8 in R4C2 (NC)

5. 9 in N7 only in R8C3 + R9C23 -> no 8 in R9C3 (NC)

[Time for some clean-ups.]
Starting with the blue marks
No 1 in R1C1 -> no 9 in R1C2
No 1 in R1C5 -> no 9 in R1C4
No 9 in R3C2 -> no 1 in R3C3
No 9 in R3C5 -> no 1 in R3C4
No 9 in R12C7 -> no 1 in R12C7
No 9 in R1C89 -> no 1 in R1C89
No 9 in R2C9 -> no 1 in R3C9
No 9 in R56C2 -> no 1 in R56C2
No 1 in R5C5 -> no 9 in R5C4
No 1 in R6C8 -> no 9 in R5C8
No 1,2 in R8C5 -> no 8,9 in R8C6
No 1 in R8C6 -> no 9 in R8C5
No 1 in R9C56 -> no 9 in R9C56
No 1 in R78C8 -> no 9 in R78C8
No 1 in R8C9 -> no 9 in R9C9
No 1 in R9C7 -> no 9 in R9C8
No 2 in R9C8 -> no 8 in R9C7
No 2 in R9C9 -> no 8 in R8C9
Next the green marks
No 1 in R1C78 -> no 8 in R1C78 -> no 2 in R1C9 + R2C7 (blue)
No 1,2 in R1C9 -> no 7,8 in R2C9 -> no 2,3 in R3C9 (blue)
No 1,2 in R2C7 -> no 7,8 in R2C8
No 1 in R4C2 -> no 8 in R5C2 -> no 2 in R6C2 (blue)
No 1,2 in R6C2 -> no 7,8 in R6C1
No 1 in R5C9 -> no 8 in R4C9
No 1 in R6C78 -> no 8 in R6C78 -> no 2 in R5C8 (blue)
No 1 in R7C12 -> no 8 in R78C12
And then the red marks
No 9 in R3C12 -> no 2 in R2C2 + R3C12 -> no 8 in R3C3 (blue)
No 9 in R5C8 -> no 2 in R5C79 -> no 7 in R4C9 (green)
No 9 in R5C9 -> no 2 in R6C9
No 8 in R6C7 -> no 3 in R5C7
No 8,9 in R6C8 -> no 3 in R6C9
No 9 in R7C8 -> no 2 in R7C79
No 9 in R8C5 -> no 2 in R9C5 -> no 8 in R9C6 (blue)
No 9 in R8C8 -> no 2 in R8C9 -> no 8 in R9C9 (blue)
No 9 in R9C5 -> no 2 in R9C4

6. R1C2 = 1 (hidden single in N1) -> R1C1 = 9 (blue), no 2 in R1C3, no 8 in R2C1 (NC)
Clean-ups: no 9 in R1C3 -> no 2 in R2C3 (red)
No 1,2 in R8C2 -> no 7 in R7C2 + R8C1 (green)

[I ought to have spotted this in step 1.]
7. 1 in R9C89 -> 9 in R8C9 or R9C7 (blue), locked for N9
Clean-ups: no 9 in R7C79 -> no 2 in R7C8 (red) -> no 8 in R8C8 (blue)
No 9 in R8C7 -> no 2 in R9C7 (red) -> no 8 in R9C8 (blue)
7a. 2 in N9 only in R8C78, locked for R8
7b. 2 in R8C78 -> no 3 in R8C78 (NC)
Clean-up: no 2 in R8C6 -> no 8 in R8C5 (blue)
No 3 in R8C8 -> no 7 in R7C8 (blue)
7c. R9C6 = 2 (hidden single in N8) -> R9C5 = 8 (blue) -> no 7 in R8C5, no 3 in R8C6, no 7,9 in R9C4, no 3 in R9C7 (NC)
Clean-up: no 8 in R135C5 -> no 2 in R135C4 (blue)
No 8 in R8C6 -> no 3 in R7C6 (red)
No 3 in R9C7 -> no 7 in R9C8 (blue)
7d. 2 in R7 only in R7C123 -> no 3 in R7C2 (NC)
7e. 9 in R7 only in R7C46, locked for N8
Clean-up: no 8,9 in R8C4 -> no 3 in R7C4 (red)

8. 2 in N9 only in R8C7 or in R78C8 = [82] (blue) -> no 8 in R8C7
8a. 8 in N9 only in R7C789, locked for R7
8b. R8C3 = 8 (hidden single in N7) -> no 7 in R7C3 + R8C24, no 7,9 in R9C3 (NC)
Clean-up: no 8 in R12C3 -> no 3 in R12C3 (red)
No 8 in R45C3 -> no 2 in R45C3 (blue)
No 7,8,9 in R8C4 -> no 4,5,6 in R7C4 (red + NC)
8c. R9C2 = 9 (hidden single in N7)
Clean-up: no 8,9 in R9C7 -> no 2 in R8C7 (red)
No 9 in R9C7 -> no 1 in R9C8 (blue)
8d. R89C9 = [91] (hidden pair in N9) -> no 8 in R7C9 (NC)
8e. R8C8 = 2 (hidden single in N9) -> R7C8 = 8 (blue) -> no 7 in R6C8 + R7C79, no 3 in R9C8 (NC)
Clean-up: no 2 in R1C8 -> no 8 in R1C9 (blue)
No 7 in R6C8 -> no 3 in R5C8 (blue)
No 8,9 in R5C8 -> no 3 in R5C9 (red)
No 2 in R6C8 -> no 7 in R6C7 (green)
No 7,8,9 in R6C8 -> no 4,5,6 in R6C9 (red + NC) -> no 7,8 in R5C9 (NC) -> no 5 in R4C9 (NC)
No 3 in R9C8 -> no 7 in R9C7 (blue)
8f. R8C7 = 7 (hidden single in N9) -> no 6 in R79C7 + R8C6 (NC)
8g. R9C78 = [46], R8C6 = 4 -> R8C5 = 6 (blue), no 5 in R7C6, no 5 in R8C4 (NC)
Clean-up: no 6 in R135C5 -> no 4 in R135C4 (blue)
No 6 in R1C8 -> no 4 in R1C9 (blue)
No 6 in R56C8 -> no 4 in R56C8 (blue)
8h. R8C124 = [153], R9C134 = [735] -> no 2 in R7C1, no 4,6 in R7C2, then no 5 in R6C1, no 3 in R6C2 (NC)
Clean-up: no 3 in R135C4 -> no 7 in R135C5 (blue)
No 3 in R3C3 -> no 7 in R3C2 (blue)
No 3 in R45C3 -> no 7 in R45C3 (blue)
No 3 in R6C2 -> no 7 in R5C2 (blue)
8i. R156C8 = [473] -> R1C9 = 6 (blue), R36C9 = [78] -> no 3 in R1C7, no 5 in R2C8, no 6 in R4C9, also no 3 in R2C7, no 2 in R2C9 (NC)
Clean-up: no 7 in R3C3 -> no 3 in R3C2 (blue)
No 7 in R5C4 -> no 3 in R5C5 (blue)
No 8 in R6C2 -> no 2 in R5C2 (blue)
8j. R12C7 = [28], R234C8 = [195], R2C9 = 3, R3C7 = 5, R456C7 = [196], R45C9 = [24], R1C5 = 3 -> R1C4 = 7 (blue), R1C36 = [58], R7C46 = [97], R3C46 = [61] -> R3C5 = 4 (blue), R5C5 = 2 -> R5C4 = 8 (blue), no 4,6 in R2C3, no 9 in R2C6, no 3 in R5C6 (NC)
8k. R2C3 = 7 -> no 6 in R2C2 (NC)

and the rest is naked singles, without using NC or coloured marks.

Author:  Andrew [ Wed Aug 01, 2018 1:35 am ]
Post subject:  Re: MeanDoku

Then I moved on to the harder version in this thread, which has fewer of the useful blue marks; one green mark has also been removed.

For this it's almost certainly necessary to use the key feature of MeanDoku NCs, as pointed out at the start of wellbeback's walkthrough. I started my solving path using more routine steps, while wellbeback jumped straight in with the key feature and, at least in one place, got more from that than I did.

Here is my walkthrough for MeanDoku 2H:
Cells adjacent to green marks must total less than 10, blue must total 10, red must total more than 10. Also NC so horizontally/vertically adjacent cells cannot be {12}, {23}, … {78}, {89}, so at least one of the cells adjacent to each green mark must contain one of 1,2,3 as they cannot be {45}; similarly at least one of the cells adjacent to each red mark must contain one of 7,8,9 as they cannot be {56}.

Prelims.
Delete 9 from cells either side of green marks.
Delete 5 from cells either side of blue marks.
Delete 1 from cells either side of red marks.
Clean-ups only as stated.

1. 1 in N9 only in R9C89, locked for R9
1a. 1 in R9C89 -> no 2 in R9C89 (NC)
1b. R7C5 = 1 (hidden single in N8), no 2 in R68C5 + R7C46 (NC)
1c. 1 in N7 only in R8C123 -> no 2 in R8C2 (NC)

2. 9 in N3 only in R3C789, locked for R3
2a. 9 in R3C789 -> no 8 in R3C8 (NC)

3. 1 in N6 only in R4C789, locked for R4
3a. 1 in R4C789 -> no 2 in R4C8 (NC)

4. 9 in N4 only in R4C13, locked for R4
4a. 9 in R4C13 -> no 8 in R4C2 (NC)

5. 9 in N7 only in R8C3 + R9C23 -> no 8 in R9C3 (NC)

6a. There are three groups of red marks in N1, 7,8,9 in one of R12C1 and in one of R12C3, then because there are two other red marks R3C2 = {78}, no other 7,8,9 in N1, no 7 in R4C2 (NC)
6b. There are five red marks in N6 which place 7,8,9 in three of R56C789, no 7,8 in R4C789
6c. There are three groups of red marks in N8, 7,8,9 in one of R78C4 and in one of R78C6, then because there are two other red marks R9C5 = {789}, no other 7,8,9 in N8
6d. There are five red marks in N9, 7,8,9 in one of R89C7, the three right-hand red marks require 7,8,9 in two of R78C89 but there’s another red mark between R7C78 -> 7,8,9 must be in R7C8 and R8C9 (they cannot be in both of R78C8 because of blue mark), no other 7,8,9 in N9, no 8 in R6C8 (NC)
6e. There are three groups of green marks in N3, 1,2,3 in one of R1C78, 1,2,3 in one of R12C9, 1,2,3 in one of R2C78 , no other 1,2,3 in N3
6f. There are three groups of green marks in N6, 1,2,3 in R4C78, 1,2,3 in R45C9 and 1,2,3 in R6C78, no other 1,2,3 in N6
[Even though there are six green marks in N4, I don’t think 1,2,3 can be placed at this stage. They may possibly be eliminated from R4C13 but I’ll leave that for now.]

[Time for some clean-ups.]
Starting with the blue marks
No 7,8 in R1C2 -> no 2,3 in R1C1
No 1 in R1C5 -> no 9 in R1C4
No 9 in R12C7 -> no 1 in R12C7
No 2,3 in R3C9 -> no 7,8 in R2C9
No 3 in R5C8 -> no 7 in R6C8
No 1 in R6C8 -> no 9 in R5C8
No 1,2,7,8 in R8C5 -> no 2,3,8,9 in R8C6
No 4,6 in R9C5 -> no 4,6 in R9C6
No 1 in R9C6 -> no 9 in R9C5
No 4,6 in R7C8 -> no 4,6 in R8C8
No 1 in R8C8 -> no 9 in R7C8
No 4,6 in R8C9 -> no 4,6 in R9C9
No 2 in R9C9 -> no 8 in R8C9
R8C8 = {23} -> no 2,3 in R8C7, no 3 in R9C8 (NC)
R9C6 = {23} -> no 2,3 in R9C7 (NC)
Next the green marks
No 1 in R1C7 -> no 8 in R1C8
No 1 in R2C7 -> no 8 in R2C8
No 1 in R4C2 -> no 8 in R5C2
No 1 in R6C8 -> no 8 in R6C7
No 1 in R7C12 -> no 8 in R78C12
And then the red marks
No 9 in R3C2 -> no 2 in R2C2 + R3C1
No 9 in R5C8 -> no 2 in R5C9
No 7,8,9 in R6C8 -> R6C9 = {789} -> no 8 in R5C9 (NC)
No 9 in R7C8 -> no 2 in R7C79
No 8,9 in R8C6 -> no 3 in R7C6
No 9 in R9C5 -> no 2 in R9C4

7a. R4C7 = 1 (hidden single in C7) -> no 2 in R4C6 (NC)
7b. R3C8 = 9 (hidden single in C8) -> no 8 in R3C79 (NC)
Clean-up: no 1,2 in R2C9 (blue)
7c. R8C8 = 2 (hidden single in N9) -> R7C8 = 8, (blue), no 1 in R9C8 (NC)
R9C8 = {456} -> no 5 in R9C7 (NC)
Clean-up: no 8 in R5C8 -> no 3 in R5C9 (red)
7d. R9C9 = 1 (hidden single in N9) -> R8C9 = 9 (blue)
7e. 3 in N9 only in R7C79, locked for R7
7f. 7 in N9 only in R89C7, locked for C7, no 6 in R89C7 (NC)
Clean-up: no 3 in R12C7 (blue)
7g. R5C7 = 9 (hidden single in N6) -> no 8 in R5C6 (NC)
7h. R6C9 = 8 (hidden single in N6) -> no 7 in R5C9 (NC)
7i. R5C8 = 7 (hidden single in N6) -> R6C8 = 3 (blue), no 6 in R4C8 + R5C9, no 2,4 in R6C7 (NC)
Clean-up: no 3 in R4C3 (blue)
7j. R4C9 = 2 (hidden single in N6)
Clean-up: no 8 in R5C3 (blue)
7k. R6C7 = 6 (hidden single in N6) -> no 5,7 in R6C6, no 5 in R7C7 (NC)
Clean-up: no 4 in R12C7 (blue)
7l. R7C7 = 3 (hidden single in C7) -> no 4 in R7C6 + R8C7 (NC)
7m. R8C7 = {57} -> no 6 in R8C6 (NC)
Clean-up: no 4 in R8C5 (blue)

8a. 7 in N3 only in R13C9 -> no 6 in R2C9 (NC)
Clean-up: no 4 in R3C9 (blue)
8b. R2C9 = {34} -> no 3,4 in R1C9, no 4 in R2C8 (NC)
8c. R2C9 = 3 (hidden single in N3) -> R3C9 = 7 (blue), R3C2 = 8
Clean-up: no 2 in R1C2 (blue)
8d. R1C9 = {56} -> no 5,6 in R1C8 (NC)
8e. R2C2 = {456} -> no 5 in R2C13 (NC)
8f. R3C7 = {45} -> no 4,5 in R3C6 (NC)
8g. R9C6 = 2 (hidden single in N8) -> R9C5 = 8 (blue)
Clean-up: no 2 in R1C4 (blue)
8h. 3 in N8 only in R8C45 + R9C4 -> no 4 in R8C4 (NC)
8i. R8C67 = [47/75] (cannot be [45] NC), 7 locked for R8
8j. R8C45 = [36/53/63] (cannot be [56] NC), 3 locked for R8 and N8
8k. R9C4 = {456} -> no 5 in R8C4 + R9C3 (NC)
8l. Naked pair {36} in R8C45, locked for R8 and N8
Clean-up: R8C4 = {36} -> R7C4 = {79} (red)
8m. R9C4 = {45} -> no 4 in R9C3 (NC)
8n. R8C3 = 8 (hidden single in R8) -> no 7 in R7C3, no 7,9 in R9C3 (NC)
Clean-up: no 2 in R5C3 (blue)
8o. R9C2 = 9 (hidden single in N7)
[I’d overlooked that it’s been hidden single in C8 for quite a while, since step 6a, but I don’t think it made much difference not spotting it earlier.]
8p. 7 in C2 only in R67C2 -> no 6 in R7C2 (NC)
8q. 2 in N5 only in R5C45 + R6C4 -> no 1,3 in R5C4 (NC)
8r. 2 in R3 only in R3C345 -> no 1,3 in R3C4 (NC)

9a. 8 in N4 only in R45C1 -> no 7,9 in R4C1 (NC)
9b. R4C3 = 9 (hidden single in N4) -> R5C1 = 1 (blue), no 8 in R4C4, no 2 in R5C24 + R6C3 (NC)
9c. R1C2 = 1 (hidden single in N1) -> R1C1 = 9 (blue), no 2 in R1C3 (NC)
Clean-up: no 8,9 in R1C3 -> no 2 in R2C3 (red)
No 8,9 in R2C3 -> no 3 in R1C3 (red)
[I forgot that R12C3 (red) must contain 7, with 8 and 9 already placed for N1, and therefore no 6 (NC), which would have simplified things slightly.]
9d. R8C1 = 1 (hidden single in N7), no 2 in R7C1 (NC)
9e. R8C2 = {45} -> no 4,5 in R7C2 (NC)
Clean-up: R8C2 = {45} -> no 7 in R7C2 (green)
9f. R7C2 = 2
9g. R6C2 = 7 (hidden single in C2) -> no 6 in R5C2 (NC)
Clean-up: R6C2 = 7 -> no 4,5 in R6C1 (green)
9h. R6C1 = 2 -> no 3 in R5C1 (NC)
Clean-up: R6C1 = 2 -> no 8 in R5C1 (green)
9i. R4C1 = 8 (hidden single in N4)
9j. R1C8 = 4, R3C7 = 5, R1C9 = 6, R2C8 = 1, R8C7 = 7, R8C6 = 4 -> R8C5 = 6 (blue)
9k. R6C3 = {45} -> no 4,5 in R6C4 + R7C3 (NC)

and the rest is naked singles, without using NC or coloured marks.

Author:  Quadrata [ Thu Nov 28, 2019 6:08 pm ]
Post subject:  Re: MeanDoku

Hi! This is David Nacin, author of the Meandoku being discussed here.  I was really excited to find people in this forum trying out one of my Sudoku variants.

I have to really thank Hatman before doing anything else for mentioning that it was tricky distinguishing the trapezoids in the original version I made for the MAA Focus.  It never occurred to me to color in the trapezoids with different colors.  Now I do that every single time, and my meandoku are much clearer because of it. Thanks! 

I wanted to toss out a few more places where you can find Meandoku in case anyone wanted to try some more.  There's another Meandoku at my blog:https://quadratablog.blogspot.com/2018/08/meandoku.html And a Meandoku was posted as part of a contest on Twitter: https://twitter.com/wpunj_edu/status/11 ... 3987743752 (Just ignore the article, the puzzle is below.)

I might post a few other of my Sudoku variants in the variants section here, and I'm looking forward to trying the Meandoku that Hatman made and posted as well!

Author:  HATMAN [ Fri Nov 29, 2019 6:51 pm ]
Post subject:  Re: MeanDoku

Welcome David

I've really enjoyed making these so please post any other puzzle ideas you have.

When I first saw your meandoku, I though "this just a small variation", however it gives very interesting and different to solve puzzles.

Please try my ORCs and Triankles.

Maurice

Author:  azpaull [ Tue Dec 03, 2019 11:42 pm ]
Post subject:  Re: MeanDoku

I'll second the welcome, David! You'll find this forum has a very friendly bunch of like-mindeds, and I do hope you'll become a regular. (There are also the non-puzzle-makers like me who enjoy trying the challenges creators like you post here!)

I've really enjoyed the Meandoku variant, and will check out your links.

--Paul

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