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 Post subject: NC OE Outside Sudoku
PostPosted: Wed Jul 25, 2012 12:28 pm 
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Grand Master
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Joined: Wed Apr 30, 2008 9:45 pm
Posts: 694
Location: Saudi Arabia
Non-Consecutive Odd-Even Outside Sudoku

Only three givens (note all are odd). Needs reasonably serious NC work. Difficulty about 1.0.
Non-Consecutive: horizontally and vertically connected cells have values that are not consecutive.
Odd-Even: grey cells are even and white cells are odd.
Outside: the given is in the first three cells.

What is the maximum number of consecutive cells?
The minimum number solution gives 64 horizontal consecutives:
123456789
456789123
789123456
234567891
567891234
891234567
345678912
678912345
912345678
Whenever I switch to get a vertical one I lose a horizontal one.


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 Post subject: Re: NC OE Outside Sudoku
PostPosted: Sat Jul 28, 2012 11:49 pm 
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Grand Master
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Joined: Tue Jun 16, 2009 9:31 pm
Posts: 282
Location: California, out of London
Nice one HATMAN! It beats me how you make these. I had a lot of trouble finding a way into this. First time through I struggled for a long time before getting to a point where I realized I must have made a mistake. Second time I finally found a quick way in which made it roll right along.

So - here's my second time walkthrough ....

Hidden Text:
1. In n3 [r1c8,r2c7] between them must have at least one of (1379).
-> [r1c7,r2c8] cannot be {28}. Must contain at least one of (46).
-> Only place for 5 in n3 is r1c9.

Whichever even number is in r2c8 - its consecutive odd numbers must be in r1c9 and r3c7.
Since r1c9 = 5 -> [r2c8,r3c7] = [43] or [67]

Also 3 in c9 must be in r46c9.
-> r5c9 from (68)
-> 7 in c9 in r89c9.

2. Whatever even number is in r7c9 must go in r8c5 in n8.
The two odd numbers consecutive to that must be in r9c46 in n8.
-> Those same two numbers must be in r7c7 and r8c8 in n9.
-> Those same two numbers must be in r14c9 in c9.
But r1c9 is a 5 and r4c9 cannot be a 7 - must be a 3.

-> r9c46 = {35}
-> r8c5 = r7c9 = 4, r7c7 = 3, r8c8 = 5
-> r9c7 = 6, r9c8 = 2, r8c7 = 8

Also r3c7 = 7, r2c8 = 6
-> r5c79 = [26]

Also r4c8 = 7
-> r56c8 = [48]
-> r4c7 = 9, r6c79 = [51]
-> r7c8 = 1, r89c9 = {79}

Also r12c7 = [41]
-> r13c8 = [93]
-> r23c9 = [28]

Easier after this....

Don't know about max number of consecutives. I have to get back to work now ... :)


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 Post subject: Re: NC OE Outside Sudoku
PostPosted: Thu Aug 02, 2012 6:29 pm 
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Grand Master
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Joined: Wed Apr 30, 2008 9:45 pm
Posts: 694
Location: Saudi Arabia
That is the breakthrough I liked

Slightly different if r1c7 or r2c6 = 5 r1c7&r2c6 = 28 -> r1c7& r2c8 <> 1379 so B*gg*r*d

I found this out of JSudoku and liked it. With NC I check JSudoku rigorously, following Udosuk's comments on it doing human unlikely deductions on NC.

For me it is like being a wine maker - I love producing for the best.

I'm not quite up with the rest of you on solving - my comfort zone is about 1.0 - but of course I can follow a given solution - and if I dedicate sufficient time can look up and solve. My problem is time. I have two outstanding Kenyan Assassins but it is so long since I created them that I have to find the time to re-solve before I post.

Cheers


Maurice


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